Study Trigonometry in ACT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards Flashcard 1: What is cos ( π 3 ) \cos\left(\frac{\pi}{3}\right) cos ( 3 π ) ? Answer: 1 2 \frac{1}{2} 2 1 . From 60° angle in 30-60-90 triangle.
Flashcard 2: What is the angle of depression if the adjacent side is 1 and the opposite side is 1? Answer: 45 degrees. Equal opposite and adjacent sides create a 45° angle.
Flashcard 3: What is the secant of a 60-degree angle? Answer: 2 2 2 . Secant is 1 cos ( 60 ∘ ) = 1 1 / 2 \frac{1}{\cos(60^\circ)} = \frac{1}{1/2} c o s ( 6 0 ∘ ) 1 = 1/2 1
Flashcard 4: What is the arc length formula for a circle with radius r r r and central angle θ \theta θ (in radians)? Answer: s = r θ s=r\theta s = r θ . Arc length equals radius times central angle in radians.
Flashcard 5: What is the cotangent of an angle in terms of tangent? Answer: cot θ = 1 tan θ \text{cot} \theta = \frac{1}{\text{tan} \theta} cot θ = tan θ 1 . Cotangent is the reciprocal of tangent.
Flashcard 6: What is sin ( 2 π ) \sin(2\pi) sin ( 2 π ) on the unit circle? Answer: 0 0 0 . At 2 π 2\pi 2 π , back to (1,0), so sine is 0.
Flashcard 7: What is the value of cos ( 90 o ) \text{cos}(90^\text{o}) cos ( 9 0 o ) ? Answer:
At 90°, there's no horizontal component.
Flashcard 8: What are the side ratios for a 45 ∘ 45^\circ 4 5 ∘ -45 ∘ 45^\circ 4 5 ∘ -90 ∘ 90^\circ 9 0 ∘ triangle (legs to hypotenuse)? Answer: 1 : 1 : 2 1:1:\sqrt{2} 1 : 1 : 2 . Isosceles right triangle with legs of 1 and hypotenuse 2 \sqrt{2} 2 .
Flashcard 9: What is the period of y = tan ( B x ) y=\tan(Bx) y = tan ( B x ) in terms of B B B ? Answer: π ∣ B ∣ \frac{\pi}{|B|} ∣ B ∣ π . Tangent has period π \pi π , so with coefficient B B B it's π ∣ B ∣ \frac{\pi}{|B|} ∣ B ∣ π .
Flashcard 10: What is the cosine of a 0-degree angle? Answer:
At 0°, the point is at (1,0) on the unit circle.
Flashcard 11: Find the value of tan − 1 ( 1 ) \text{tan}^{-1}(1) tan − 1 ( 1 ) in degrees. Answer: 45 o 45^\text{o} 4 5 o . Inverse tangent of 1 gives the angle where tan ( θ ) = 1 \tan(\theta) = 1 tan ( θ ) = 1 .
Flashcard 12: What is the degree-to-radian conversion formula for an angle θ \theta θ in degrees? Answer: θ rad = θ ∘ ⋅ π 180 \theta_{\text{rad}}=\theta_{\circ}\cdot\frac{\pi}{180} θ rad = θ ∘ ⋅ 180 π . Multiply degrees by π 180 \frac{\pi}{180} 180 π to convert to radians.
Flashcard 13: What is sin ( 2 π ) \sin(2\pi) sin ( 2 π ) on the unit circle? Answer: 0 0 0 . At 2 π 2\pi 2 π , back to (1,0), so sine is 0.
Flashcard 14: What is cos ( π 2 ) \cos\left(\frac{\pi}{2}\right) cos ( 2 π ) on the unit circle? Answer: 0 0 0 . At π 2 \frac{\pi}{2} 2 π , the point is at (0,1), so cosine is 0.
Flashcard 15: What is the sine of an angle whose secant is 2? Answer: 3 2 \frac{\sqrt{3}}{2} 2 3 . If sec = 2 \sec = 2 sec = 2 , then cos = 1 2 \cos = \frac{1}{2} cos = 2 1 , use Pythagorean identity.
Flashcard 16: State the double angle formula for sine. Answer: sin ( 2 θ ) = 2 sin ( θ ) cos ( θ ) \text{sin}(2\theta) = 2\text{sin}(\theta)\text{cos}(\theta) sin ( 2 θ ) = 2 sin ( θ ) cos ( θ ) . Double angle formula using product-to-sum identity.
Flashcard 17: What is the cosecant of a 30-degree angle? Answer: 2 2 2 . Cosecant is 1 sin ( 30 ° ) = 1 1 / 2 \frac{1}{\sin(30°)} = \frac{1}{1/2} s i n ( 30° ) 1 = 1/2 1 .
Flashcard 18: What is the secant of a 90-degree angle? Answer: Undefined. Division by zero makes secant undefined.
Flashcard 19: What is the sine of a 30 o 30^\text{o} 3 0 o angle? Answer: 1 2 \frac{1}{2} 2 1 . This is a special angle value from the 30-60-90 triangle.
Flashcard 20: What is the range of the cosine function? Answer: [-1, 1]. Cosine oscillates between -1 and 1 for all angles.
Flashcard 21: What is the radian-to-degree conversion formula for an angle θ \theta θ in radians? Answer: θ ∘ = θ rad ⋅ 180 π \theta_{\circ}=\theta_{\text{rad}}\cdot\frac{180}{\pi} θ ∘ = θ rad ⋅ π 180 . Multiply radians by 180 π \frac{180}{\pi} π 180 to convert to degrees.
Flashcard 22: What is the secant of an angle in terms of cosine? Answer: sec θ = 1 cos θ \text{sec} \theta = \frac{1}{\text{cos} \theta} sec θ = cos θ 1 . Secant is the reciprocal of cosine.
Flashcard 23: What is the reciprocal of tangent? Answer: Cotangent. Reciprocal function: cot ( θ ) = 1 tan ( θ ) \cot(\theta) = \frac{1}{\tan(\theta)} cot ( θ ) = t a n ( θ ) 1 .
Flashcard 24: What is sin ( 0 ) \sin(0) sin ( 0 ) on the unit circle? Answer: 0 0 0 . At angle 0, the point is at (1,0), so sine is 0.
Flashcard 25: What is the arc length formula for a circle with radius r r r and central angle θ \theta θ (in radians)? Answer: s = r θ s=r\theta s = r θ . Arc length equals radius times central angle in radians.
Flashcard 26: What is the cosecant of an angle in terms of sine? Answer: csc θ = 1 sin θ \text{csc} \theta = \frac{1}{\text{sin} \theta} csc θ = sin θ 1 . Cosecant is the reciprocal of sine.
Flashcard 27: What is the cosine of a 90 o 90^\text{o} 9 0 o angle? Answer:
At 90°, the adjacent side is zero.
Flashcard 28: What is the value of tan ( 0 o ) \text{tan}(0^\text{o}) tan ( 0 o ) ? Answer:
At 0°, opposite side has zero length.
Flashcard 29: State the Pythagorean identity for sine and cosine. Answer: sin 2 θ + cos 2 θ = 1 \text{sin}^2 \theta + \text{cos}^2 \theta = 1 sin 2 θ + cos 2 θ = 1 . Fundamental identity from the unit circle definition.
Flashcard 30: What is the radian-to-degree conversion formula for an angle θ \theta θ in radians? Answer: θ ∘ = θ rad ⋅ 180 π \theta_{\circ}=\theta_{\text{rad}}\cdot\frac{180}{\pi} θ ∘ = θ rad ⋅ π 180 . Multiply radians by 180 π \frac{180}{\pi} π 180 to convert to degrees.
Flashcard 31: What is tan ( π 6 ) \tan\left(\frac{\pi}{6}\right) tan ( 6 π ) ? Answer: 3 3 \frac{\sqrt{3}}{3} 3 3 . sin ( π / 6 ) cos ( π / 6 ) = 1 / 2 3 / 2 = 1 3 \frac{\sin(\pi/6)}{\cos(\pi/6)} = \frac{1/2}{\sqrt{3}/2} = \frac{1}{\sqrt{3}} c o s ( π /6 ) s i n ( π /6 ) = 3 /2 1/2 = 3 1 .
Flashcard 32: What is the cosecant of a 30-degree angle? Answer: 2 2 2 . Cosecant is 1 sin ( 30 ° ) = 1 1 / 2 \frac{1}{\sin(30°)} = \frac{1}{1/2} s i n ( 30° ) 1 = 1/2 1 .
Flashcard 33: What is the amplitude of y = A sin ( B x ) y=A\sin(Bx) y = A sin ( B x ) or y = A cos ( B x ) y=A\cos(Bx) y = A cos ( B x ) in terms of A A A ? Answer: ∣ A ∣ |A| ∣ A ∣ . Maximum distance from equilibrium position is ∣ A ∣ |A| ∣ A ∣ .
Flashcard 34: Find the angle if the tangent is 1. Provide the acute angle. Answer: 45 degrees. Use inverse tangent to find the reference angle.
Flashcard 35: What is the sector area formula for radius r r r and central angle θ \theta θ (in radians)? Answer: A = 1 2 r 2 θ A=\frac{1}{2}r^2\theta A = 2 1 r 2 θ . Sector area is half the product of radius squared and angle.
Flashcard 36: What is the angle of elevation if the opposite side is 1 and the adjacent side is 3 \sqrt{3} 3 ? Answer: 30 degrees. Use tan − 1 ( 1 3 ) \tan^{-1}(\frac{1}{\sqrt{3}}) tan − 1 ( 3 1 ) to find the angle.
Flashcard 37: Convert π 2 \frac{\text{π}}{2} 2 π radians to degrees. Answer: 90 degrees. π 2 \frac{\pi}{2} 2 π radians equals 90° by definition.
Flashcard 38: What is the period of y = cos ( 2 x ) y = \cos(2x) y = cos ( 2 x ) ? Answer: π \pi π . Period formula: 2 π ∣ b ∣ \frac{2\pi}{|b|} ∣ b ∣ 2 π where b = 2 b = 2 b = 2 .
Flashcard 39: What is the cotangent of a 45-degree angle? Answer:
At 45°, sine equals cosine, so their ratio is 1.
Flashcard 40: State the Pythagorean identity for cotangent and cosecant. Answer: 1 + cot 2 θ = csc 2 θ 1 + \text{cot}^2 \theta = \text{csc}^2 \theta 1 + cot 2 θ = csc 2 θ . Derived from the Pythagorean identity and reciprocals.
Flashcard 41: What is the cosine of an angle whose cosecant is 2? Answer: 3 2 \frac{\sqrt{3}}{2} 2 3 . If csc = 2 \csc = 2 csc = 2 , then sin = 1 2 \sin = \frac{1}{2} sin = 2 1 , use Pythagorean identity.
Flashcard 42: What is sin ( π 4 ) \sin\left(\frac{\pi}{4}\right) sin ( 4 π ) ? Answer: 2 2 \frac{\sqrt{2}}{2} 2 2 . From 45° angle in 45-45-90 triangle.
Flashcard 43: What is the cosine of a 60-degree angle? Answer: 1 2 \frac{1}{2} 2 1 . 60° is a special angle in the unit circle.
Flashcard 44: What is the tangent of a 45-degree angle? Answer:
45° creates an isosceles right triangle.
Flashcard 45: Convert π 3 \frac{\text{π}}{3} 3 π radians to degrees. Answer: 60 degrees. Multiply radians by 180 π \frac{180}{\pi} π 180 .
Flashcard 46: State the Pythagorean identity for tangent and secant. Answer: 1 + tan 2 θ = sec 2 θ 1 + \text{tan}^2 \theta = \text{sec}^2 \theta 1 + tan 2 θ = sec 2 θ . Derived from the Pythagorean identity and reciprocals.
Flashcard 47: What is the tangent of 0 o 0^\text{o} 0 o ? Answer:
Since sin ( 0 ° ) = 0 \sin(0°) = 0 sin ( 0° ) = 0 and cos ( 0 ° ) = 1 \cos(0°) = 1 cos ( 0° ) = 1 .
Flashcard 48: Find the angle if the sine is 1 2 \frac{1}{2} 2 1 . Provide the acute angle. Answer: 30 degrees. Use inverse sine to find the reference angle.
Flashcard 49: Find the angle if the sine is 1 2 \frac{1}{2} 2 1 . Provide the acute angle. Answer: 30 degrees. Use inverse sine to find the reference angle.
Flashcard 50: State the formula for the tangent of an angle. Answer: tan θ = sin θ cos θ \text{tan} \theta = \frac{\text{sin} \theta}{\text{cos} \theta} tan θ = cos θ sin θ . Tangent equals the ratio of sine to cosine.
Flashcard 51: What is the degree-to-radian conversion formula for an angle θ \theta θ in degrees? Answer: θ rad = θ ∘ ⋅ π 180 \theta_{\text{rad}}=\theta_{\circ}\cdot\frac{\pi}{180} θ rad = θ ∘ ⋅ 180 π . Multiply degrees by π 180 \frac{\pi}{180} 180 π to convert to radians.
Flashcard 52: What is sin ( 0 ) \sin(0) sin ( 0 ) on the unit circle? Answer: 0 0 0 . At angle 0, the point is at (1,0), so sine is 0.
Flashcard 53: Find the angle if the cosine is 1 2 \frac{1}{2} 2 1 . Provide the acute angle. Answer: 60 degrees. Use inverse cosine to find the reference angle.
Flashcard 54: State the reciprocal identity for tangent. Answer: tan θ = 1 cot θ \text{tan} \theta = \frac{1}{\text{cot} \theta} tan θ = cot θ 1 . Tangent and cotangent are reciprocals.
Flashcard 55: State the co-function identity for sine and cosine. Answer: sin ( θ ) = cos ( 90 o − θ ) \text{sin}(\theta) = \text{cos}(90^\text{o} - \theta) sin ( θ ) = cos ( 9 0 o − θ ) . Complementary angles have swapped sine and cosine.
Flashcard 56: What is tan ( π 3 ) \tan\left(\frac{\pi}{3}\right) tan ( 3 π ) ? Answer: 3 \sqrt{3} 3 . sin ( π / 3 ) cos ( π / 3 ) = 3 / 2 1 / 2 = 3 \frac{\sin(\pi/3)}{\cos(\pi/3)} = \frac{\sqrt{3}/2}{1/2} = \sqrt{3} c o s ( π /3 ) s i n ( π /3 ) = 1/2 3 /2 = 3 .
Flashcard 57: State the Pythagorean identity for sine and cosine. Answer: sin 2 θ + cos 2 θ = 1 \text{sin}^2 \theta + \text{cos}^2 \theta = 1 sin 2 θ + cos 2 θ = 1 . Fundamental identity from the unit circle definition.
Flashcard 58: What is the tangent of a 45 o 45^\text{o} 4 5 o angle? Answer:
In a 45-45-90 triangle, opposite and adjacent sides are equal.
Flashcard 59: What is cos ( 2 π ) \cos(2\pi) cos ( 2 π ) on the unit circle? Answer: 1 1 1 . At 2 π 2\pi 2 π , back to (1,0), so cosine is 1.
Flashcard 60: What is the cosine of a 60 o 60^\text{o} 6 0 o angle? Answer: 1 2 \frac{1}{2} 2 1 . From the 30-60-90 triangle, cos ( 60 ° ) = sin ( 30 ° ) \cos(60°) = \sin(30°) cos ( 60° ) = sin ( 30° ) .
Flashcard 61: What is the cosine of a 60-degree angle? Answer: 1 2 \frac{1}{2} 2 1 . 60° is a special angle in the unit circle.
Flashcard 62: Find the angle if the tangent is 1. Provide the acute angle. Answer: 45 degrees. Use inverse tangent to find the reference angle.
Flashcard 63: What is the period of y = sin ( B x ) y=\sin(Bx) y = sin ( B x ) or y = cos ( B x ) y=\cos(Bx) y = cos ( B x ) in terms of B B B ? Answer: 2 π ∣ B ∣ \frac{2\pi}{|B|} ∣ B ∣ 2 π . Time for one complete cycle is 2 π ∣ B ∣ \frac{2\pi}{|B|} ∣ B ∣ 2 π .
Flashcard 64: What is the sine of a 90-degree angle? Answer:
At 90°, the point is at the top of the unit circle.
Flashcard 65: Convert 180 degrees to radians. Answer: π \pi π . 180° equals π \pi π radians by definition.
Flashcard 66: What is the cosine of 0 o 0^\text{o} 0 o ? Answer:
At 0°, the adjacent side equals the hypotenuse.
Flashcard 67: What is the angle of elevation if the opposite side is 1 and the adjacent side is √3 \text{√3} √3 ? Answer: 30 degrees. Use tan − 1 ( 1 3 ) \tan^{-1}(\frac{1}{\sqrt{3}}) tan − 1 ( 3 1 ) to find the angle.
Flashcard 68: What is the secant of a 90-degree angle? Answer: Undefined. Division by zero makes secant undefined.
Flashcard 69: Convert π 3 \frac{\text{π}}{3} 3 π radians to degrees. Answer: 60 degrees. Multiply radians by 180 π \frac{180}{\pi} π 180 .
Flashcard 70: For which angle is sin θ = 1 \text{sin} \theta = 1 sin θ = 1 ? Answer: 90 o 90^\text{o} 9 0 o . Sine reaches its maximum value of 1 at 90°.
Flashcard 71: What is the sine of a 30-degree angle? Answer: 1 2 \frac{1}{2} 2 1 . 30° is a special angle in the unit circle.
Flashcard 72: What is the value of sin ( 0 o ) \text{sin}(0^\text{o}) sin ( 0 o ) ? Answer:
At 0°, there's no vertical component.
Flashcard 73: What is the sine of 180 o 180^\text{o} 18 0 o ? Answer:
At 180°, we're on the negative x-axis where y = 0.
Flashcard 74: Convert 45 degrees to radians. Answer: π 4 \frac{\text{π}}{4} 4 π . Multiply degrees by π 180 \frac{\pi}{180} 180 π .
Flashcard 75: What is the sine of 0 o 0^\text{o} 0 o ? Answer:
At 0°, the opposite side is zero.
Flashcard 76: What is sin ( π 2 ) \sin\left(\frac{\pi}{2}\right) sin ( 2 π ) on the unit circle? Answer: 1 1 1 . At π 2 \frac{\pi}{2} 2 π , the point is at (0,1), so sine is 1.
Flashcard 77: What is the cosecant of a 0-degree angle? Answer: Undefined. Division by zero makes cosecant undefined.
Flashcard 78: State the double angle formula for cosine. Answer: cos ( 2 θ ) = cos 2 ( θ ) − sin 2 ( θ ) \text{cos}(2\theta) = \text{cos}^2(\theta) - \text{sin}^2(\theta) cos ( 2 θ ) = cos 2 ( θ ) − sin 2 ( θ ) . Double angle formula from cosine addition identity.
Flashcard 79: What are the side ratios for a 45 ∘ 45^\circ 4 5 ∘ -45 ∘ 45^\circ 4 5 ∘ -90 ∘ 90^\circ 9 0 ∘ triangle (legs to hypotenuse)? Answer: 1 : 1 : 2 1:1:\sqrt{2} 1 : 1 : 2 . Isosceles right triangle with legs of 1 and hypotenuse 2 \sqrt{2} 2 .
Flashcard 80: What is the sector area formula for radius r r r and central angle θ \theta θ (in radians)? Answer: A = 1 2 r 2 θ A=\frac{1}{2}r^2\theta A = 2 1 r 2 θ . Sector area is half the product of radius squared and angle.
Flashcard 81: What are the side ratios for a 30 ∘ 30^\circ 3 0 ∘ -60 ∘ 60^\circ 6 0 ∘ -90 ∘ 90^\circ 9 0 ∘ triangle (short:long:hyp)? Answer: 1 : 3 : 2 1:\sqrt{3}:2 1 : 3 : 2 . Half of an equilateral triangle: short leg, long leg, hypotenuse.
Flashcard 82: What are the right-triangle definitions of sin ( θ ) \sin(\theta) sin ( θ ) , cos ( θ ) \cos(\theta) cos ( θ ) , and tan ( θ ) \tan(\theta) tan ( θ ) ? Answer: sin = opp hyp , cos = adj hyp , tan = opp adj \sin=\frac{\text{opp}}{\text{hyp}},\ \cos=\frac{\text{adj}}{\text{hyp}},\ \tan=\frac{\text{opp}}{\text{adj}} sin = hyp opp , cos = hyp adj , tan = adj opp . SOH-CAH-TOA: ratios of opposite, adjacent sides to hypotenuse.
Flashcard 83: What is the tangent of a 45-degree angle? Answer:
45° creates an isosceles right triangle.
Flashcard 84: What is the period of y = tan ( B x ) y=\tan(Bx) y = tan ( B x ) in terms of B B B ? Answer: π ∣ B ∣ \frac{\pi}{|B|} ∣ B ∣ π . Tangent has period π \pi π , so with coefficient B B B it's π ∣ B ∣ \frac{\pi}{|B|} ∣ B ∣ π .
Flashcard 85: What is the cosecant of a 0-degree angle? Answer: Undefined. Division by zero makes cosecant undefined.
Flashcard 86: What is cos ( π ) \cos(\pi) cos ( π ) on the unit circle? Answer: − 1 -1 − 1 . At π \pi π , the point is at (-1,0), so cosine is -1.
Flashcard 87: What is tan ( π 4 ) \tan\left(\frac{\pi}{4}\right) tan ( 4 π ) ? Answer: 1 1 1 . sin ( π / 4 ) cos ( π / 4 ) = 2 / 2 2 / 2 = 1 \frac{\sin(\pi/4)}{\cos(\pi/4)} = \frac{\sqrt{2}/2}{\sqrt{2}/2} = 1 c o s ( π /4 ) s i n ( π /4 ) = 2 /2 2 /2 = 1 .
Flashcard 88: What are the side ratios for a 30 ∘ 30^\circ 3 0 ∘ -60 ∘ 60^\circ 6 0 ∘ -90 ∘ 90^\circ 9 0 ∘ triangle (short:long:hyp)? Answer: 1 : 3 : 2 1:\sqrt{3}:2 1 : 3 : 2 . Half of an equilateral triangle: short leg, long leg, hypotenuse.
Flashcard 89: What is the cotangent of a 0-degree angle? Answer: Undefined. Division by zero makes cotangent undefined.
Flashcard 90: What is the sine of a 90 o 90^\text{o} 9 0 o angle? Answer:
At 90°, the opposite side equals the hypotenuse.
Flashcard 91: What is sin ( π ) \sin(\pi) sin ( π ) on the unit circle? Answer: 0 0 0 . At π \pi π , the point is at (-1,0), so sine is 0.
Flashcard 92: What is cos ( π ) \cos(\pi) cos ( π ) on the unit circle? Answer: − 1 -1 − 1 . At π \pi π , the point is at (-1,0), so cosine is -1.
Flashcard 93: What is the period of y = sin ( B x ) y=\sin(Bx) y = sin ( B x ) or y = cos ( B x ) y=\cos(Bx) y = cos ( B x ) in terms of B B B ? Answer: 2 π ∣ B ∣ \frac{2\pi}{|B|} ∣ B ∣ 2 π . Time for one complete cycle is 2 π ∣ B ∣ \frac{2\pi}{|B|} ∣ B ∣ 2 π .
Flashcard 94: What is the tangent of a 90-degree angle? Answer: Undefined. Division by zero makes tangent undefined.
Flashcard 95: What is the formula for the distance between two points ( x 1 , y 1 ) (x_1,y_1) ( x 1 , y 1 ) and ( x 2 , y 2 ) (x_2,y_2) ( x 2 , y 2 ) in the plane? Answer: d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 . Pythagorean theorem applied to coordinate differences.
Flashcard 96: Convert π 2 \frac{\text{π}}{2} 2 π radians to degrees. Answer: 90 degrees. π 2 \frac{\pi}{2} 2 π radians equals 90° by definition.
Flashcard 97: What is the sine of a 30-degree angle? Answer: 1 2 \frac{1}{2} 2 1 . 30° is a special angle in the unit circle.
Flashcard 98: What is the tangent of 180 o 180^\text{o} 18 0 o ? Answer:
Since sin ( 180 ° ) = 0 \sin(180°) = 0 sin ( 180° ) = 0 and cos ( 180 ° ) = − 1 \cos(180°) = -1 cos ( 180° ) = − 1 .
Flashcard 99: What is the cotangent of a 45-degree angle? Answer:
At 45°, sine equals cosine, so their ratio is 1.
Flashcard 100: What is tan ( π 4 ) \tan\left(\frac{\pi}{4}\right) tan ( 4 π ) ? Answer: 1 1 1 . sin ( π / 4 ) cos ( π / 4 ) = 2 / 2 2 / 2 = 1 \frac{\sin(\pi/4)}{\cos(\pi/4)} = \frac{\sqrt{2}/2}{\sqrt{2}/2} = 1 c o s ( π /4 ) s i n ( π /4 ) = 2 /2 2 /2 = 1 .