Study Mathematical Modeling in ACT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
All flashcards Flashcard 1: Find the circumference of a circle with diameter 10. Answer: Circumference = 10 π 10\text{π} 10 π . Circumference equals π times diameter.
Flashcard 2: If y y y varies inversely with x x x and y = 5 y=5 y = 5 when x = 8 x=8 x = 8 , what is y y y when x = 10 x=10 x = 10 ? Answer: y = 4 y=4 y = 4 . Since k = x y = 40 k=xy=40 k = x y = 40 , when x = 10 x=10 x = 10 , y = 4 y=4 y = 4 .
Flashcard 3: What is the formula for the volume of a cylinder? Answer: Volume = πr 2 × height \text{πr}^2 \times \text{height} πr 2 × height . Base area times height for cylinder volume.
Flashcard 4: State the formula for compound interest. Answer: Amount = Principal × (1 + r n \frac{r}{n} n r )^(nt). Interest compounded n n n times per year for t t t years.
Flashcard 5: What is the midpoint formula between points ( x 1 , y 1 ) (x_1,y_1) ( x 1 , y 1 ) and ( x 2 , y 2 ) (x_2,y_2) ( x 2 , y 2 ) ? Answer: ( x 1 + x 2 2 , y 1 + y 2 2 ) \left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right) ( 2 x 1 + x 2 , 2 y 1 + y 2 ) . Average of x-coordinates and y-coordinates.
Flashcard 6: What is the formula for the surface area of a sphere? Answer: Surface Area = 4 π r 2 4\pi r^2 4 π r 2 . Four times the area of a great circle.
Flashcard 7: Find the distance between points (3, 4) and (6, 8). Answer: 5 5 5 . Use distance formula: ( 6 − 3 ) 2 + ( 8 − 4 ) 2 = 9 + 16 = 5 \sqrt{(6-3)^2 + (8-4)^2} = \sqrt{9+16} = 5 ( 6 − 3 ) 2 + ( 8 − 4 ) 2 = 9 + 16 = 5 .
Flashcard 8: What is the weighted average model for mean of values x 1 , x 2 x_1,x_2 x 1 , x 2 with weights w 1 , w 2 w_1,w_2 w 1 , w 2 ? Answer: w 1 x 1 + w 2 x 2 w 1 + w 2 \frac{w_1x_1+w_2x_2}{w_1+w_2} w 1 + w 2 w 1 x 1 + w 2 x 2 . Sum of weighted values divided by total weights.
Flashcard 9: What is the slope formula between points ( x 1 , y 1 ) (x_1,y_1) ( x 1 , y 1 ) and ( x 2 , y 2 ) (x_2,y_2) ( x 2 , y 2 ) ? Answer: m = y 2 − y 1 x 2 − x 1 m=\frac{y_2-y_1}{x_2-x_1} m = x 2 − x 1 y 2 − y 1 . Rise over run between two points.
Flashcard 10: What is the formula for the area of a trapezoid? Answer: Area = 1 2 \frac{1}{2} 2 1 (base₁ + base₂) × height. Average of parallel sides times height.
Flashcard 11: Find the slope of the line through points (2, 3) and (5, 11). Answer: Slope = 8 3 \frac{8}{3} 3 8 . Change in y over change in x: 11 − 3 5 − 2 = 8 3 \frac{11-3}{5-2} = \frac{8}{3} 5 − 2 11 − 3 = 3 8 .
Flashcard 12: Given A = 50 ( 1.1 ) t A=50(1.1)^t A = 50 ( 1.1 ) t , what is A A A when t = 0 t=0 t = 0 ? Answer: 50 50 50 . Initial value when exponent equals zero.
Flashcard 13: What is the formula for the sum of the interior angles of a polygon? Answer: Sum = ( n − 2 ) × 180 (n-2) × 180 ( n − 2 ) × 180 . Each interior angle contributes to ( n − 2 ) × 180 (n-2) × 180 ( n − 2 ) × 180 degrees total.
Flashcard 14: Find the surface area of a cube with side length 4. Answer: Surface Area = 96. Cube surface area: 6 s 2 = 6 ( 16 ) = 96 6s^2 = 6(16) = 96 6 s 2 = 6 ( 16 ) = 96 .
Flashcard 15: Find the area of a circle with radius 4. Answer: Area = 16 π 16\text{π} 16 π . Use A = π r 2 A = \text{π}r^2 A = π r 2 with r = 4 r = 4 r = 4 .
Flashcard 16: What is the formula for the perimeter of a rectangle? Answer: Perimeter = 2(length + width). Sum of all four sides of a rectangle.
Flashcard 17: What is the volume model for a rectangular prism with dimensions L L L , W W W , and H H H ? Answer: V = L W H V=LWH V = L W H . Product of all three dimensions.
Flashcard 18: Identify the formula for the circumference of a circle. Answer: Circumference = 2 π r 2\pi r 2 π r . Perimeter formula where r r r is the radius.
Flashcard 19: What is the Pythagorean Theorem? Answer: a 2 + b 2 = c 2 a^2 + b^2 = c^2 a 2 + b 2 = c 2 . Sum of squares of legs equals hypotenuse squared.
Flashcard 20: Identify the best model type when y y y changes by a constant percent per unit increase in x x x . Answer: Exponential model. Constant percent change indicates exponential relationship.
Flashcard 21: If y y y varies inversely with x x x and y = 5 y=5 y = 5 when x = 8 x=8 x = 8 , what is y y y when x = 10 x=10 x = 10 ? Answer: y = 4 y=4 y = 4 . Since k = x y = 40 k=xy=40 k = x y = 40 , when x = 10 x=10 x = 10 , y = 4 y=4 y = 4 .
Flashcard 22: A quantity decays 20 % 20\% 20% per step; write the factor b b b in y = a b x y=a b^x y = a b x . Answer: b = 0.8 b=0.8 b = 0.8 . Decrease of 20% means 80% remains.
Flashcard 23: What is the distance formula between points ( x 1 , y 1 ) (x_1,y_1) ( x 1 , y 1 ) and ( x 2 , y 2 ) (x_2,y_2) ( x 2 , y 2 ) ? Answer: d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} d = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 . Pythagorean theorem applied to coordinate plane.
Flashcard 24: For the exponential model y = 200 ( 1.05 ) t y=200(1.05)^t y = 200 ( 1.05 ) t , what is the growth factor per unit t t t ? Answer: 1.05 1.05 1.05 . The base of the exponential function.
Flashcard 25: Calculate the slope for points (2,3) and (4,7). Answer: Slope = 2. Apply slope formula: 7 − 3 4 − 2 = 2 \frac{7-3}{4-2} = 2 4 − 2 7 − 3 = 2 .
Flashcard 26: What is the exponential growth/decay model with initial value a a a and factor b b b ? Answer: y = a b x y=ab^x y = a b x . Where a a a is initial value and b b b is growth/decay factor.
Flashcard 27: What is the quadratic formula? Answer: x = − b ± √ ( b 2 − 4 a c ) 2 a x = \frac{-b \, ± \, \text{√}(b^2 - 4ac)}{2a} x = 2 a − b ± √ ( b 2 − 4 a c ) . Solves a x 2 + b x + c = 0 ax^2 + bx + c = 0 a x 2 + b x + c = 0 for any quadratic.
Flashcard 28: What is the formula for the area of a rectangle? Answer: A r e a = l e n g t h × w i d t h Area = length \times width A re a = l e n g t h × w i d t h . Base formula for calculating space inside a rectangle.
Flashcard 29: Calculate the Fahrenheit for 25°C. Answer: F = 77 F = 77 F = 77 . Apply conversion: 9 5 ( 25 ) + 32 = 77 \frac{9}{5}(25) + 32 = 77 5 9 ( 25 ) + 32 = 77 .
Flashcard 30: Identify the best model type when the change in y y y is a constant amount per unit increase in x x x . Answer: Linear model. Constant rate of change indicates linear relationship.
Flashcard 31: Calculate the volume of a sphere with radius 2. Answer: Volume = 32 3 π \frac{32}{3}\pi 3 32 π . Sphere volume: 4 3 π ( 2 3 ) = 32 3 π \frac{4}{3}\pi(2^3) = \frac{32}{3}\pi 3 4 π ( 2 3 ) = 3 32 π .
Flashcard 32: What is the density model relating mass m m m , density ρ \rho ρ , and volume V V V ? Answer: ρ = m V \rho=\frac{m}{V} ρ = V m . Mass per unit volume relationship.
Flashcard 33: Identify the best model type when the change in y y y is a constant amount per unit increase in x x x . Answer: Linear model. Constant rate of change indicates linear relationship.
Flashcard 34: What is the formula for compound interest? Answer: A = P ( 1 + r n ) n t A = P(1 + \frac{r}{n})^{nt} A = P ( 1 + n r ) n t . Principal grows with rate r r r , compounded n n n times.
Flashcard 35: What is the formula for the future value of an annuity? Answer: FV = Pmt × ( 1 + r ) n − 1 r \frac{(1 + r)^n - 1}{r} r ( 1 + r ) n − 1 . Sum of equal payments growing at rate r r r for n n n periods.
Flashcard 36: What is the point-slope form of a line with slope m m m through ( x 1 , y 1 ) (x_1,y_1) ( x 1 , y 1 ) ? Answer: y − y 1 = m ( x − x 1 ) y-y_1=m(x-x_1) y − y 1 = m ( x − x 1 ) . Uses known point and slope to define the line.
Flashcard 37: Identify the vertex form of a quadratic equation. Answer: y = a ( x − h ) 2 + k y = a(x-h)^2 + k y = a ( x − h ) 2 + k . Parabola with vertex at ( h , k ) (h,k) ( h , k ) .
Flashcard 38: Convert 120 degrees to radians. Answer: 2 π 3 \frac{2\pi}{3} 3 2 π radians. Multiply by π 180 \frac{\pi}{180} 180 π : 120 × π 180 = 2 π 3 120 \times \frac{\pi}{180} = \frac{2\pi}{3} 120 × 180 π = 3 2 π
Flashcard 39: How do you find the volume of a rectangular prism? Answer: Volume = length × width × height. Multiply all three dimensions for 3D space.
Flashcard 40: State the formula for the Pythagorean theorem. Answer: a 2 + b 2 = c 2 a^2 + b^2 = c^2 a 2 + b 2 = c 2 . Relates the sides of a right triangle.
Flashcard 41: What is the meaning of the intercept b b b in a linear model y = m x + b y=mx+b y = m x + b ? Answer: Value of y y y when x = 0 x=0 x = 0 . Where the line crosses the y-axis.
Flashcard 42: What is the area of a triangle with base 6 and height 4? Answer: Area = 12. Triangle area: 1 2 ( 6 ) ( 4 ) = 12 \frac{1}{2}(6)(4) = 12 2 1 ( 6 ) ( 4 ) = 12 .
Flashcard 43: State the quadratic formula. Answer: x = − b ± √ ( b 2 − 4 a c ) 2 a x = \frac{-b \, \text{±} \, \text{√}(b^2 - 4ac)}{2a} x = 2 a − b ± √ ( b 2 − 4 a c ) . Solves a x 2 + b x + c = 0 ax^2 + bx + c = 0 a x 2 + b x + c = 0 for any quadratic.
Flashcard 44: What is the slope formula between points ( x 1 , y 1 ) (x_1,y_1) ( x 1 , y 1 ) and ( x 2 , y 2 ) (x_2,y_2) ( x 2 , y 2 ) ? Answer: m = y 2 − y 1 x 2 − x 1 m=\frac{y_2-y_1}{x_2-x_1} m = x 2 − x 1 y 2 − y 1 . Rise over run between two points.
Flashcard 45: State the midpoint formula for two points. Answer: Midpoint = ( x 1 + x 2 2 , y 1 + y 2 2 ) \text{Midpoint} = \bigg(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\bigg) Midpoint = ( 2 x 1 + x 2 , 2 y 1 + y 2 ) . Average the x-coordinates and y-coordinates.
Flashcard 46: Identify the formula for the surface area of a cylinder. Answer: Surface Area = 2 π r ( h + r ) 2πr(h + r) 2 π r ( h + r ) . Two circular ends plus curved side surface.
Flashcard 47: Find the equation of a line with slope 2 through point (1, 3). Answer: y − 3 = 2 ( x − 1 ) y - 3 = 2(x - 1) y − 3 = 2 ( x − 1 ) . Point-slope form: y − y 1 = m ( x − x 1 ) y - y_1 = m(x - x_1) y − y 1 = m ( x − x 1 ) .
Flashcard 48: What is the area model for a triangle with base b b b and height h h h ? Answer: A = 1 2 b h A=\frac{1}{2}bh A = 2 1 bh . Half the product of base and height.
Flashcard 49: If y y y varies directly with x x x and y = 18 y=18 y = 18 when x = 6 x=6 x = 6 , what is k k k in y = k x y=kx y = k x ? Answer: k = 3 k=3 k = 3 . From 18 = k ( 6 ) 18=k(6) 18 = k ( 6 ) , so k = 3 k=3 k = 3 .
Flashcard 50: Find the area of a rectangle with length 7 and width 3. Answer: Area = 21. Rectangle area: 7 × 3 = 21 7 \times 3 = 21 7 × 3 = 21 .
Flashcard 51: What is the formula for the area of a parallelogram? Answer: Area = base × height \text{base} \times \text{height} base × height . Same as rectangle when sides are perpendicular.
Flashcard 52: What is the vertex form of a quadratic model with vertex ( h , k ) (h,k) ( h , k ) ? Answer: y = a ( x − h ) 2 + k y=a(x-h)^2+k y = a ( x − h ) 2 + k . Parabola with vertex at ( h , k ) (h,k) ( h , k ) and stretch factor a a a .
Flashcard 53: Identify the best model type when x y xy x y is constant for varying x x x and y y y . Answer: Inverse variation. Product remains constant as variables change.
Flashcard 54: What is the formula for the area of a sector of a circle? Answer: Area = θ 360 × π r 2 \frac{\theta}{360} \times \pi r^2 360 θ × π r 2 . Fraction of full circle times total area.
Flashcard 55: Identify the intercept b b b for the model y = − 3 x + 7 y=-3x+7 y = − 3 x + 7 . Answer: b = 7 b=7 b = 7 . The constant term in slope-intercept form.
Flashcard 56: What is the general form of a linear equation? Answer: A x + B y = C Ax + By = C A x + B y = C . Standard form with integer coefficients.
Flashcard 57: Determine the y-intercept of the equation y = 3 x + 4 y = 3x + 4 y = 3 x + 4 . Answer: 4 4 4 . The constant term in y = m x + b y = mx + b y = m x + b form.
Flashcard 58: Determine the equation of a line with slope 3 and y-intercept 5. Answer: y = 3 x + 5 y = 3x + 5 y = 3 x + 5 . Slope-intercept form with m = 3 m=3 m = 3 , b = 5 b=5 b = 5 .
Flashcard 59: What is the compound interest model for principal P P P at rate r r r compounded n n n times for t t t years? Answer: A = P ( 1 + r n ) n t A=P\left(1+\frac{r}{n}\right)^{nt} A = P ( 1 + n r ) n t . Accounts for compounding frequency and time.
Flashcard 60: What is the formula for the perimeter of a rectangle? Answer: Perimeter = 2 ( length + width ) 2(\text{length} + \text{width}) 2 ( length + width ) . Sum of all four sides of rectangle.
Flashcard 61: Solve for y y y : 3 y − 2 = 10 3y - 2 = 10 3 y − 2 = 10 . Answer: y = 4 y = 4 y = 4 . Add 2 to both sides, then divide by 3.
Flashcard 62: What is the formula for the area of a triangle? Answer: Area = 1 2 \frac{1}{2} 2 1 base × height. Half the base times perpendicular height.
Flashcard 63: What is the direct variation model relating y y y to x x x with constant k k k ? Answer: y = k x y=kx y = k x . When y y y is proportional to x x x .
Flashcard 64: Identify the formula for converting Celsius to Fahrenheit. Answer: F = 9 5 C + 32 F = \frac{9}{5}C + 32 F = 5 9 C + 32 . Multiply by 9 5 \frac{9}{5} 5 9 then add 32 degrees.
Flashcard 65: Convert 300 degrees to radians. Answer: 5 π 3 \frac{5\pi}{3} 3 5 π radians. Multiply by π 180 \frac{\pi}{180} 180 π : 300 × π 180 = 5 π 3 300 × \frac{\pi}{180} = \frac{5\pi}{3} 300 × 180 π = 3 5 π
Flashcard 66: Identify the best model type when y y y is proportional to x 2 x^2 x 2 . Answer: Quadratic model. Square relationship creates parabolic shape.
Flashcard 67: What is the average rate of change of f f f from x = a x=a x = a to x = b x=b x = b ? Answer: f ( b ) − f ( a ) b − a \frac{f(b)-f(a)}{b-a} b − a f ( b ) − f ( a ) . Slope of secant line between two points.
Flashcard 68: Find the linear model y = m x + b y=mx+b y = m x + b through ( 0 , 3 ) (0,3) ( 0 , 3 ) and ( 4 , 11 ) (4,11) ( 4 , 11 ) . Answer: y = 2 x + 3 y=2x+3 y = 2 x + 3 . Slope m = 11 − 3 4 − 0 = 2 m=\frac{11-3}{4-0}=2 m = 4 − 0 11 − 3 = 2 , y-intercept b = 3 b=3 b = 3 .
Flashcard 69: Calculate the volume of a sphere with radius 2. Answer: Volume = 32 3 π \frac{32}{3}\text{π} 3 32 π . Sphere volume: 4 3 π ( 2 3 ) = 32 3 π \frac{4}{3}\text{π}(2^3) = \frac{32}{3}\text{π} 3 4 π ( 2 3 ) = 3 32 π .
Flashcard 70: For the exponential model y = 200 ( 1.05 ) t y=200(1.05)^t y = 200 ( 1.05 ) t , what is the growth factor per unit t t t ? Answer: 1.05 1.05 1.05 . The base of the exponential function.
Flashcard 71: What is the volume of a cube with side length 5? Answer: Volume = 125. Cube volume is s 3 = 5 3 = 125 s^3 = 5^3 = 125 s 3 = 5 3 = 125 .
Flashcard 72: What is the average rate of change of f f f from x = a x=a x = a to x = b x=b x = b ? Answer: f ( b ) − f ( a ) b − a \frac{f(b)-f(a)}{b-a} b − a f ( b ) − f ( a ) . Slope of secant line between two points.
Flashcard 73: How do you calculate the slope of a line from its equation y = m x + b y = mx + b y = m x + b ? Answer: Slope = m m m . Coefficient of x x x in slope-intercept form.
Flashcard 74: Identify the best model type when y y y changes by a constant percent per unit increase in x x x . Answer: Exponential model. Constant percent change indicates exponential relationship.
Flashcard 75: Find the midpoint of the segment with endpoints (2, 3) and (4, 7). Answer: ( 3 , 5 ) (3, 5) ( 3 , 5 ) . Average the x-coordinates and y-coordinates separately.
Flashcard 76: Identify the formula for the surface area of a cylinder. Answer: Surface Area = 2 π r ( h + r ) 2πr(h + r) 2 π r ( h + r ) . Two circular ends plus curved side surface.
Flashcard 77: State the quadratic formula. Answer: x = − b ± √ ( b 2 − 4 a c ) 2 a x = \frac{-b \, \text{±} \, \text{√}(b^2 - 4ac)}{2a} x = 2 a − b ± √ ( b 2 − 4 a c ) . Solves a x 2 + b x + c = 0 ax^2 + bx + c = 0 a x 2 + b x + c = 0 for any quadratic.
Flashcard 78: What is the formula for acceleration? Answer: Acceleration = change in velocity time \frac{\text{change in velocity}}{\text{time}} time change in velocity . Rate of change of velocity with respect to time.
Flashcard 79: What is the distance formula between two points? Answer: d = √ ( ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 ) d = \text{√}((x_2 - x_1)^2 + (y_2 - y_1)^2) d = √ (( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 ) . Pythagorean theorem applied to coordinate plane.
Flashcard 80: Identify the formula for the slope of a line given two points. Answer: Slope = y 2 − y 1 x 2 − x 1 \frac{y_2 - y_1}{x_2 - x_1} x 2 − x 1 y 2 − y 1 . Rise over run between two coordinate points.
Flashcard 81: What is the formula for the perimeter of a rectangle? Answer: Perimeter = 2(length + width). Sum of all four sides of a rectangle.
Flashcard 82: What is the formula for the volume of a sphere? Answer: Volume = 4 3 π r 3 \frac{4}{3}πr³ 3 4 π r 3 . Four-thirds times pi times radius cubed.
Flashcard 83: What is the uniform motion model relating distance d d d , rate r r r , and time t t t ? Answer: d = r t d=rt d = r t . Distance equals rate times time at constant speed.
Flashcard 84: What is the formula for the volume of a cone? Answer: Volume = 1 3 π r 2 h \frac{1}{3} \pi r^2 h 3 1 π r 2 h . One-third of cylinder volume formula.
Flashcard 85: What is the formula for the volume of a cylinder? Answer: Volume = πr 2 × height \text{πr}^2 \times \text{height} πr 2 × height . Base area times height for cylinder volume.
Flashcard 86: What is the formula for the area of a rectangle? Answer: Area = length × width. Base formula for calculating space inside a rectangle.
Flashcard 87: State the formula for the Pythagorean theorem. Answer: a 2 + b 2 = c 2 a^2 + b^2 = c^2 a 2 + b 2 = c 2 . Relates the sides of a right triangle.
Flashcard 88: What is the compound interest model for principal P P P at rate r r r compounded n n n times for t t t years? Answer: A = P ( 1 + r n ) n t A=P\left(1+\frac{r}{n}\right)^{nt} A = P ( 1 + n r ) n t . Accounts for compounding frequency and time.
Flashcard 89: What is the formula to convert Celsius to Fahrenheit? Answer: F = 9 5 \frac{9}{5} 5 9 C + 32. Multiply Celsius by 9 5 \frac{9}{5} 5 9 then add 32.
Flashcard 90: What is the formula for the future value of an annuity? Answer: F V = P m t × ( 1 + r ) n − 1 r FV = Pmt \times \frac{(1 + r)^n - 1}{r} F V = P m t × r ( 1 + r ) n − 1 . Sum of equal payments growing at rate r r r for n n n periods.
Flashcard 91: What is the standard form of a quadratic model in x x x ? Answer: y = a x 2 + b x + c y=ax^2+bx+c y = a x 2 + b x + c . General form of quadratic with coefficients a a a , b b b , c c c .
Flashcard 92: What is the formula for compound interest? Answer: A = P ( 1 + r n ) n t A = P(1 + \frac{r}{n})^{nt} A = P ( 1 + n r ) n t . Principal grows with rate r r r , compounded n n n times.
Flashcard 93: What is the perimeter model for a rectangle with length L L L and width W W W ? Answer: P = 2 L + 2 W P=2L+2W P = 2 L + 2 W . Sum of all four sides of rectangle.
Flashcard 94: What is the slope-intercept form for a linear model relating y y y to x x x ? Answer: y = m x + b y=mx+b y = m x + b . Linear equation with m m m as slope and b b b as y-intercept.
Flashcard 95: Find the linear model y = m x + b y=mx+b y = m x + b through ( 0 , 3 ) (0,3) ( 0 , 3 ) and ( 4 , 11 ) (4,11) ( 4 , 11 ) . Answer: y = 2 x + 3 y=2x+3 y = 2 x + 3 . Slope m = 11 − 3 4 − 0 = 2 m=\frac{11-3}{4-0}=2 m = 4 − 0 11 − 3 = 2 , y-intercept b = 3 b=3 b = 3 .
Flashcard 96: State the formula for the volume of a sphere. Answer: Volume = 4 3 π r 3 \frac{4}{3} π r^3 3 4 π r 3 . Four-thirds π times radius cubed.
Flashcard 97: If f ( x ) = 3 x 2 − 12 x + 5 f(x)=3x^2-12x+5 f ( x ) = 3 x 2 − 12 x + 5 , what is the x x x -coordinate of the vertex for this quadratic model? Answer: x = 2 x=2 x = 2 . Vertex x-coordinate is − b 2 a = 12 6 = 2 \frac{-b}{2a}=\frac{12}{6}=2 2 a − b = 6 12 = 2 .
Flashcard 98: Find the area of a circle with radius 4. Answer: Area = 16 π 16\text{π} 16 π . Use A = π r 2 A = \text{π}r^2 A = π r 2 with r = 4 r = 4 r = 4 .
Flashcard 99: What is the simple interest model for principal P P P at annual rate r r r for t t t years? Answer: A = P ( 1 + r t ) A=P(1+rt) A = P ( 1 + r t ) . Interest calculated only on principal amount.
Flashcard 100: What is the perimeter model for a rectangle with length L L L and width W W W ? Answer: P = 2 L + 2 W P=2L+2W P = 2 L + 2 W . Sum of all four sides of rectangle.