Card 0 of 549
Expand the following expression:
(B – 2) (B + 4)
Here we use FOIL:
Firsts: B * B = B2
Outer: B * 4 = 4B
Inner: –2 * B = –2B
Lasts: –2 * 4 = –8
All together this yields
B2 + 2B – 8
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What is the product of the two real solutions of x2 + 5x = 6?
x2 + 5x – 6 = 0 factors to (x+6)(x**–**1) = 0.
Therefore, the two real solutions are x = **–**6 and x = 1. Their product is simply **–**6.
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Which of the following is equivalent to (2g – 3h)2?
Use FOIL: (2g – 3h)(2g – 3h) = 4g2 – 6gh – 6gh + 9h2 = 4g2 – 12gh + 9h2
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FOIL:
By FOIL (First Outer Inner Last), we obtain –8_x_2 – 8_x_ – 6_x_ – 6.
Simplify: –8_x_2 – 14_x_ – 6
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What is the value of (5 + 3_i_)(6 – 2_i_)?
We FOIL the equation to obtain 30 – 10_i_ + 18_i_ – 6_i_2, combining like terms and substituting i_2 = –1, we obtain 36 + 8_i.
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Distribute:
FOIL using the distributive property:
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Distribute:
FOIL using the distributive property:
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Distribute:
To FOIL using the distributive property, multiply the first terms together, then the outer terms, then the inner terms, and finally, the last terms.
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Expand the following expression:
(f + 4) (f – 4)
using FOIL:
First: f x f = f2
Outer: f x – 4 = –4f
Intter: 4 x f = 4f
Lasts: 4 x – 4 = –16
Adding it all up:
f2 – 4f +4f – 16
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Given that i2 = –1, what is the value of (6 + 3i)(6 – 3i)?
We start by foiling out the original equation, giving us 36 – 9(i2). Next, substitute 36 – 9(–1). This equals 36 + 9 = 45.
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For all x, (4_x –_ 3)2 =
To solve this problem, you should FOIL: (4_x_ – 3)(4_x_ – 3) = 16_x_2 – 12_x –_ 12_x_ + 9 = 16_x_2 – 24_x_ + 9.
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Solve for .
To solve this equation, first distribute on the right side of the equation.
Then, subtract from both sides.
Then divide both sides by .
Another method for solving this problem is to plug in the answer choices and solve.
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A rectangle's length L is 3 inches shorter than its width, W. What is an appropriate expression for the area of the rectangle in terms of W?
The length is equal to W – 3
The area of a rectangle is length x width.
So W * (W – 3) = W2 – 3W
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Expand the following expression: (x+3) (x+2)
This simply requires us to recall our rules from FOIL
First: X multiplied by X yields x2
Outer: X multplied by 2 yields 2x
Inner: 3 multiplied by x yields 3x
Lasts: 2 multiplied by 3 yields 6
Add it all together and we have x2 + 2x + 3x + 6
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Expand the following expression:
FOIL and we get:
Then multiply it by and get:
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Use FOIL on the following expression:
x(x + 1)(x – 1)
FOIL (First, Outside, Inside, Last): (x + 1)(x – 1) which is (x2 – 1) then multiply it by x, which is (x3 – x)
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Multiply: (4_x_ + 3)(2_x_ + 4)
To solve you must use FOIL (first outer inner last)
Multiply 4_x_ and 2_x_ to get 8x²
Multiply 4_x_ and 4 to get 16_x_
Multiply 3 and 2_x_ to get 6_x_
Multiply 3 and 4 to get 12
Add the common terms and the awnser is 8_x_² + 22_x_ + 12
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Multiply the complex numbers:
.
Expanding out gives .
We know that so when we substitute that in we get
.
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What is the greatest common factor in the evaluated expression below?
This is essentially a multi-part question that at first may seem confusing, until it's realized that the question only involves basic algebra, or more specifically, using FOIL and greatest common factor concepts.
First, we must use FOIL (first, outside, inside, last), to evaluate the given expression: ⋅
First:
Outside:
Inside:
Last:
Now add all of the terms together:
Which simplifies to:
Now, we must see what is greatest common factor shared between each of these two terms. They are both divisible by as well as
.
Therefore, is the greatest common factor.
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Use the FOIL method to find the product. The answer must be in standard form.
Use the FOIL method to find the product. The answer must be in standard form.
Step 1: Use the FOIL method
First:
Outside:
Inside:
Last:
Add these to find the product:
Step 2: Write the product in standard form
Standard form means the terms are written from highest degree to lowest degree. You find the degree of a term by adding the exponents in the term.
Therefore:
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