5th Grade Math - Interpret Division of a Unit Fraction by a Whole Number : CCSS.Math.Content.5.NF.B.7a

Erica has $\frac{1}{2}lb$ of gummy candies that she wants to divide evenly into bags. How much will each bag of gummy candies weigh?

$\frac{1}{10}lb$

$\frac{5}{2}lb$

$\frac{1}{5}lb$

$\frac{4}{3}lb$

$\frac{1}{7}lb$

Explanation

We are splitting $\frac{1}{2}$ into equal groups, so we are dividing $\frac{1}{2}$ by .

To solve $\frac{1}{2}\div5$ we multiply by the reciprocal.

$\frac{1}{2}\times\frac{1}{5}=\frac{1}{10}$

1 10

Melissa has $\frac{1}{2}lb$ of gummy candies that she wants to divide evenly into bags. How much will each bag of gummy candies weigh?

$\frac{1}{6}lb$

$\frac{1}{3}lb$

$\frac{1}{12}lb$

$\frac{3}{2}lb$

$\frac{1}{5}lb$

Explanation

We are splitting $\frac{1}{2}$ into equal groups, so we are dividing $\frac{1}{2}$ by .

To solve $\frac{1}{2}\div3$ we multiply by the reciprocal.

$\frac{1}{2}\times\frac{1}{3}=\frac{1}{6}$

1 6

David has $\frac{1}{3}lb$ of peanuts that he wants to divide evenly into bags. How much will each bag of peanuts weigh?

$\frac{1}{15}lb$

$\frac{5}{3}lb$

$\frac{8}{3}lb$

$\frac{3}{8}lb$

$\frac{1}{5}lb$

Explanation

We are splitting $\frac{1}{3}$ into equal groups, so we are dividing $\frac{1}{3}$ by .

To solve $\frac{1}{3}\div5$ we multiply by the reciprocal.

$\frac{1}{3}\times\frac{1}{5}=\frac{1}{15}$

1 15

Christine has $\frac{1}{2}lb$ of gummy candies that she wants to divide evenly into bags. How much will each bag of gummy candies weigh?

$\frac{1}{14}lb$

$\frac{14}{2}lb$

$\frac{8}{7}lb$

$\frac{2}{7}lb$

$\frac{1}{4}lb$

Explanation

We are splitting $\frac{1}{2}$ into equal groups, so we are dividing $\frac{1}{2}$ by .

To solve $\frac{1}{2}\div7$ we multiply by the reciprocal.

$\frac{1}{2}\times\frac{1}{7}=\frac{1}{14}$

1 14

Melissa has $\frac{1}{2}lb$ of gummy candies that she wants to divide evenly into bags. How much will each bag of gummy candies weigh?

$\frac{1}{16}lb$

$\frac{16}{2}lb$

$\frac{1}{7}lb$

$\frac{1}{6}lb$

$\frac{1}{9}lb$

Explanation

We are splitting $\frac{1}{2}$ into equal groups, so we are dividing $\frac{1}{2}$ by .

To solve $\frac{1}{2}\div8$ we multiply by the reciprocal.

$\frac{1}{2}\times\frac{1}{8}=\frac{1}{16}$

1 16

Tim has $\frac{1}{3}lb$ of peanuts that he wants to divide evenly into bags. How much will each bag of peanuts weigh?

$\frac{1}{21}lb$

$\frac{7}{2}lb$

$\frac{7}{3}lb$

$\frac{1}{28}lb$

$\frac{1}{7}lb$

Explanation

We are splitting $\frac{1}{3}$ into equal groups, so we are dividing $\frac{1}{3}$ by .

To solve $\frac{1}{3}\div7$ we multiply by the reciprocal.

$\frac{1}{3}\times\frac{1}{7}=\frac{1}{21}$

1 21

Tim has $\frac{1}{3}lb$ of peanuts that he wants to divide evenly into bags. How much will each bag of peanuts weigh?

$\frac{1}{24}lb$

$\frac{1}{30}lb$

$\frac{1}{8}lb$

$\frac{8}{3}lb$

$\frac{3}{37}lb$

Explanation

We are splitting $\frac{1}{3}$ into equal groups, so we are dividing $\frac{1}{3}$ by .

To solve $\frac{1}{3}\div8$ we multiply by the reciprocal.

$\frac{1}{3}\times\frac{1}{8}=\frac{1}{24}$

1 24

Erica has $\frac{1}{2}lb$ of gummy candies that she wants to divide evenly into bags. How much will each bag of gummy candies weigh?

$\frac{1}{22}lb$

$\frac{1}{12}lb$

$\frac{1}{9}lb$

$\frac{11}{}2lb$

$\frac{1}{11}lb$

Explanation

We are splitting $\frac{1}{2}$ into equal groups, so we are dividing $\frac{1}{2}$ by .

To solve $\frac{1}{2}\div11$ we multiply by the reciprocal.

$\frac{1}{2}\times\frac{1}{11}=\frac{1}{22}$

1 22

Tim has $\frac{1}{3}lb$ of peanuts that he wants to divide evenly into bags. How much will each bag of peanuts weigh?

$\frac{1}{6}lb$

$\frac{1}{3}lb$

$\frac{1}{2}lb$

$\frac{2}{3}lb$

$\frac{3}{2}lb$

Explanation

We are splitting $\frac{1}{3}$ into equal groups, so we are dividing $\frac{1}{3}$ by .

To solve $\frac{1}{3}\div2$ we multiply by the reciprocal.

$\frac{1}{3}\times\frac{1}{2}=\frac{1}{6}$

1 6

Tim has $\frac{1}{3}lb$ of peanuts that he wants to divide evenly into bags. How much will each bag of peanuts weigh?

$\frac{1}{9}lb$

$\frac{9}{3}lb$

$\frac{1}{6}lb$

$\frac{3}{9}lb$

$\frac{2}{9}lb$

Explanation

We are splitting $\frac{1}{3}$ into equal groups, so we are dividing $\frac{1}{3}$ by .

To solve $\frac{1}{3}\div3$ we multiply by the reciprocal.

$\frac{1}{3}\times\frac{1}{3}=\frac{1}{9}$

1 9

Interpret Division of a Unit Fraction by a Whole Number : CCSS.Math.Content.5.NF.B.7a

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