Place Value and Properties of Operations to Add and Subtract

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1st Grade Math › Place Value and Properties of Operations to Add and Subtract

Questions 1 - 10

1

$\frac{\begin{array}[b]{r}80\ -\ 20\end{array}}{ \ \ \space}$

Explanation

$\frac{\begin{array}[b]{r}80\ -\ 20\end{array}}{ \ \ \space}$

When we subtract two digit numbers, we always start with the ones place, on the right, and work our way to the left.

$\frac{\begin{array}[b]{r}80\ -\ 20\end{array}}{ \ \ \ \space60}$

2

Add:

$\frac{\begin{array}[b]{r}11\ +\ 46\end{array}}{ \ \ \space}$

Explanation

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}1{\color{Red} 1}\ +\ 4{\color{Red} 6}\end{array}}{ \ \ \ \ \ \space7}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 1}1\ +\ {\color{Red} 4}6\end{array}}{ \ \ \ \space57}$

The final answer is

3

Solve the following:

$\frac{\begin{array}[b]{r}18\ +\ 51\end{array}}{ \ \ \space}$

Explanation

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}1{\color{Red} 8}\ +\ 5{\color{Red} 1}\end{array}}{ \ \ \ \ \ \space9}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 1}8\ +\ {\color{Red} 5}1\end{array}}{ \ \ \ \space69}$

The final answer is

4

Add:

$\frac{\begin{array}[b]{r}43\ +\ 15\end{array}}{ \ \ \space}$

Explanation

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}4{\color{Red} 3}\ +\ 1{\color{Red} 5}\end{array}}{ \ \ \ \ \ \space8}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 4}3\ +\ {\color{Red} 1}5\end{array}}{ \ \ \ \space58}$

The final answer is

5

Add:

$\frac{\begin{array}[b]{r}19\ +\ 30\end{array}}{ \ \ \space}$

Explanation

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}1{\color{Red} 9}\ +\ 3{\color{Red} 0}\end{array}}{ \ \ \ \ \ \space9}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 1}9\ +\ {\color{Red} 3}0\end{array}}{ \ \ \ \space49}$

The final answer is

6

Add:

$\frac{\begin{array}[b]{r}37\ +\ 31\end{array}}{ \ \ \space}$

Explanation

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}3{\color{Red} 7}\ +\ 3{\color{Red} 1}\end{array}}{ \ \ \ \ \ \space8}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 3}7\ +\ {\color{Red} 3}1\end{array}}{ \ \ \ \space68}$

The final answer is

7

$\frac{\begin{array}[b]{r}70\ +\ 10\end{array}}{ \ \ \space}$

Explanation

When we add to a two digit number, the only number that changes in our answer is the tens position, and it will always go up by . Mentally, we can add to the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}70\ +\ 10\end{array}}{ \ \ \ \space80}$

8

$\frac{\begin{array}[b]{r}75\ -\ 10\end{array}}{ \ \ \space}$

Explanation

When we subtract from a two digit number, the only number that changes in our answer is the tens position, and it will always go down by . Mentally, we can subtract from the number in the tens place to find our answer.

$\frac{\begin{array}[b]{r}75\ -\ 10\end{array}}{ \ \ \ \ \space65}$

9

Add:

$\frac{\begin{array}[b]{r}43\ +\ 15\end{array}}{ \ \ \space}$

Explanation

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}4{\color{Red} 3}\ +\ 1{\color{Red} 5}\end{array}}{ \ \ \ \ \ \space8}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 4}3\ +\ {\color{Red} 1}5\end{array}}{ \ \ \ \space58}$

The final answer is

10

Add:

$\frac{\begin{array}[b]{r}51\ +\ 12\end{array}}{ \ \ \space}$

Explanation

When we add two digit numbers, we start by adding the numbers in the ones place.

$\frac{\begin{array}[b]{r}5{\color{Red} 1}\ +\ 1{\color{Red} 2}\end{array}}{ \ \ \ \ \ \space3}$

Next, we need to add the numbers in the tens place.

$\frac{\begin{array}[b]{r}{\color{Red} 5}1\ +\ {\color{Red} 1}2\end{array}}{ \ \ \ \ \space63}$

The final answer is

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