Carbonyl Reactions
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Organic Chemistry › Carbonyl Reactions
What is the product of the following reaction?
and
Explanation
The reaction uses a Grignard reagent's nucleophilic carbon to attack the carbon in carbon dioxide. Following treatment with water the resulting molecule (a carboxylate anion, of the form ) the carboxylate oxygen will be protonated, and the result is a carboxylic acid. Thus, the resulting molecule is a benzene ring with a carboxyl group attached (this is also known as benzoic acid).
What is the product of the following reaction?
and
Explanation
The reaction uses a Grignard reagent's nucleophilic carbon to attack the carbon in carbon dioxide. Following treatment with water the resulting molecule (a carboxylate anion, of the form ) the carboxylate oxygen will be protonated, and the result is a carboxylic acid. Thus, the resulting molecule is a benzene ring with a carboxyl group attached (this is also known as benzoic acid).
What is the product of this reaction?
Explanation
This is a classic esterification reaction. Esterfication occurs when a carboxylic acid and an alcohol are reacted together. Only one answer choice is an ester.
What is the product of this reaction?
Explanation
This is a classic esterification reaction. Esterfication occurs when a carboxylic acid and an alcohol are reacted together. Only one answer choice is an ester.
What is the final organic product of the reaction shown?
III
I
II
IV
V
Explanation
First step: esterification
Second step: reduction
Third step: neutralization
Fourth step: oxidation to aldehyde
Fifth step: alkene metathesis
What is the final organic product of the reaction shown?
III
I
II
IV
V
Explanation
First step: esterification
Second step: reduction
Third step: neutralization
Fourth step: oxidation to aldehyde
Fifth step: alkene metathesis
Determine the major product of the given intramolecular aldol reaction.
II
I
III
IV
None of these
Explanation
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
What is the product of the reaction shown?
IV
I
II
III
V
Explanation
First step: bromination across the double bond
Second step: double dehydrohalogenation and removal of terminal alkyne hydrogen
Third step: neutralization of the molecule
Fourth/fifth step: hydroboration/oxidation, followed by keto/enol tautomerization
Determine the major product of the given intramolecular aldol reaction.
II
I
III
IV
None of these
Explanation
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
What is the product of the reaction shown?
IV
I
II
III
V
Explanation
First step: bromination across the double bond
Second step: double dehydrohalogenation and removal of terminal alkyne hydrogen
Third step: neutralization of the molecule
Fourth/fifth step: hydroboration/oxidation, followed by keto/enol tautomerization