Call Now to Set Up Tutoring:

(847) 840-2442

Create an account to track your scores
and create your own practice tests:

Create an Account Create a Practice Test

All HiSET: Math Resources

125 Practice Tests Question of the Day Flashcards Learn by Concept

Want to review HiSET: Math but don’t feel like sitting for a whole test at the moment? Varsity Tutors has you covered with thousands of different HiSET: Math flashcards! Our HiSET: Math flashcards allow you to practice with as few or as many questions as you like. Get some studying in now with our numerous HiSET: Math flashcards.

Flashcards: Properties of polygons and circles

Pool shape

A quadrilateral is shown, and the angle measures of 3 interior angles are given. Find x, the missing angle measure.

$94^{\circ}$

$33^{\circ}$

$52^{\circ}$

$228^{\circ}$

$128^{\circ}$

Report an Error Copyright Notice

Flashcards: Properties of polygons and circles

A quadrilateral is shown, and the angle measures of 3 interior angles are given. Find x, the missing angle measure.

Your answer:

$94^{\circ}$

Your answer:

$33^{\circ}$

Your answer:

$52^{\circ}$

Your answer:

$228^{\circ}$

Correct answer:

$128^{\circ}$

Explanation:

The sum of the measures of the interior angles of a quadrilateral is 360 degrees. The sum of the measures of the interior angles of any polygon can be determined using the following formula:

$Sum \ of\ Interior \ Angles = 180^{\circ}(n-2)$ , where is the number of sides.

For example, with a quadrilateral, which has 4 sides, you obtain the following calculation:

$Sum \ of\ Interior \ Angles = 180^{\circ}(4-2)=180^{\circ}\cdot2=360^{\circ}$

Solving for requires setting up an algebraic equation, adding all 4 angles to equal 360 degrees:

$50^{\circ}+67^{\circ}+115^{\circ}+x^{\circ}=360^{\circ}$

Solving for is straightforward: subtract the values of the 3 known angles from both sides:

$x^{\circ}= 360^{\circ}-50^{\circ}-67^{\circ}-115^{\circ}$

$x^{\circ}=128^{\circ}$

Flashcards: Properties of polygons and circles

Intercepted 2

is the center of the above circle. Calculate $m \angle AOB$ .

$120^{\circ }$

$135^{\circ }$

$125^{\circ }$

$140^{\circ }$

$130^{\circ }$

Report an Error Copyright Notice

Flashcards: Properties of polygons and circles

is the center of the above circle. Calculate $m \angle AOB$ .

Your answer:

$120^{\circ }$

Your answer:

$125^{\circ }$

Your answer:

$140^{\circ }$

Your answer:

$130^{\circ }$

Correct answer:

$135^{\circ }$

Explanation:

$\angle AOB$ is the central angle that intercepts $\overarc{AB}$ , so

$m \angle AOB = m \overarc{AB}$ .

Therefore, we need to find $m \overarc{AB}$ to obtain our answer.

If the sides of an angle with vertex outside the circle are both tangent to the circle, the angle formed is half the difference of the measures of the arcs. Therefore,

$\frac{m \overarc{ACB} - m \overarc{AB} }{2} = m \angle AVB$

Letting $x= m \overarc{AB}$ , since the total arc measure of a circle is 360 degrees,

$m \overarc{ACB} = 360 - x$

We are also given that

$m \angle AVB = 45$

Making substitutions, and solving for :

$\frac{(360- x )- x }{2} =45$

$\frac{360- 2 x }{2} =45$

Multiply both sides by 2:

$\frac{360- 2 x }{2} \cdot 2 =45 \cdot 2$

360- 2 x = 90

Subtract 360 from both sides:

360- 2 x - 360 = 90 - 360

-2x = -270

Divide both sides by :

$-2x \div (-2) = -270 \div (-2)$

x = 135 ,

the measure of $\overarc{AB}$ and, consequently, that of $\angle AOB$ .

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

View Tutors

Thomas
Certified Tutor

Minot State University, Bachelor of Science, Computer Science.

View Tutors

Michael
Certified Tutor

DePaul University, Bachelor's, Computer Science.

View Tutors

Ryan
Certified Tutor

University of Illinois at Urbana-Champaign, Bachelor of Science, Logistics and Materials Management.

Popular Subjects

LSAT Tutors in San Francisco-Bay Area, French Tutors in San Diego, Spanish Tutors in New York City, Statistics Tutors in New York City, LSAT Tutors in Atlanta, GMAT Tutors in Boston, SAT Tutors in Los Angeles, Math Tutors in New York City, Algebra Tutors in New York City, Computer Science Tutors in San Francisco-Bay Area

Popular Courses & Classes

Spanish Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in Los Angeles, LSAT Courses & Classes in Phoenix, GRE Courses & Classes in Washington DC, ACT Courses & Classes in New York City, GMAT Courses & Classes in San Francisco-Bay Area, ACT Courses & Classes in Dallas Fort Worth, GMAT Courses & Classes in Boston, ISEE Courses & Classes in Boston, Spanish Courses & Classes in San Francisco-Bay Area

Popular Test Prep

SAT Test Prep in Philadelphia, ACT Test Prep in San Francisco-Bay Area, ISEE Test Prep in Chicago, LSAT Test Prep in San Diego, GRE Test Prep in Denver, SSAT Test Prep in Phoenix, ISEE Test Prep in New York City, SAT Test Prep in Washington DC, MCAT Test Prep in Phoenix, GMAT Test Prep in Washington DC

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Create an account to track your scores
and create your own practice tests:

All HiSET: Math Resources

Flashcards: Properties of polygons and circles

Flashcards: Properties of polygons and circles

Flashcards: Properties of polygons and circles

Flashcards: Properties of polygons and circles

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback:

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Create an account to track your scores and create your own practice tests:

All HiSET: Math Resources

Flashcards: Properties of polygons and circles

Flashcards: Properties of polygons and circles

Flashcards: Properties of polygons and circles

Flashcards: Properties of polygons and circles

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Create an account to track your scores
and create your own practice tests: