Waves

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Questions 1 - 10

A note is played with a wavelength of . If the speed of sound is $340.29\frac{m}{s}$ , what is the frequency of the note?

Explanation

The relationship between velocity, frequency, and wavelength is:

$v=f\lambda$

Plug in the given information to solve:

$v=f\lambda$

$340.29\frac{m}{s}=f*0.444m$

$\frac{340.29\frac{m}{s}}{0.444m}=f$

A symphony tunes to an oboe playing a note at . If the speed of sound is $340.29\frac{m}{s}$ , what is the wavelength of this note?

Explanation

The relationship between velocity, frequency, and wavelength is:

$v=f\lambda$

Plug in the given information to solve:

$v=f\lambda$

$340.29\frac{m}{s}=440Hz*\lambda$

$\frac{340.29\frac{m}{s}}{440Hz}=\lambda$

$0.773m=\lambda$

A certain type of radiation on the electromagnetic spectrum has a period of $10^{-9}s$ . What is the wavelength of this radiation?

$c=3*10^8\frac{m}{s}$

$3*10^{17}m$

$3*10^{-17}m$

$3*10^{1.125}m$

Explanation

The velocity of a wave is equal to the product of the wavelength and frequency:

$v=\lambda f$

We can rearrange this formula to solve for the wavelength.

$\lambda=\frac{c}{f}$

We also know that the period is the inverse of the frequency:

$T=\frac{1}{f}$

Substitute this into the equation for wavelength.

$\lambda=c*T$

Now we can use our given values for the period and the velocity to solve for the wavelength.

$\lambda=(3*10^8\frac{m}{s})*(10^{-9}s)$

$\lambda=0.3m$

A microwave has a wavelength of . What is the frequency of the wave?

$c=3*10^8\frac{m}{s}$

$3*10^{10}Hz$

$3*10^{-11}Hz$

$3*10^{-6}Hz$

Explanation

The velocity of a wave is equal to the product of the wavelength and frequency:

$v=\lambda f$

We can rearrange this formula to solve for the frequency.

$f=\frac{v}{\lambda}$

Since microwaves are on the electromagnetic spectrum, their velocity will be equal to the speed of light. We are given the wavelength. Using these values, we are able to solve for the frequency.

$f=\frac{3*10^8\frac{m}{s}}{0.01m}$

$f=3*10^{10}Hz$

A certain type of radiation on the electromagnetic spectrum has a period of $10^{-17}s$ . What is the wavelength of this radiation?

$c=3*10^8\frac{m}{s}$

$3*10^{-9}m$

$3*10^{8}m$

$3*10^{-17}m$

$3*10^{-25}m$

$3*10^{-2.125}m$

Explanation

The velocity of a wave is equal to the product of the wavelength and frequency:

$v=\lambda f$

We can rearrange this formula to solve for the wavelength.

$\lambda=\frac{c}{f}$

We also know that the period is the inverse of the frequency:

$T=\frac{1}{f}$

Substitute this into the equation for wavelength.

$\lambda=c*T$

Now we can use our given values for the period and the velocity to solve for the wavelength.

$\lambda=(3*10^8\frac{m}{s})*(10^{-17}s)$

$\lambda=3*10^{-9}m$

A flute plays a note with a frequency of . What is the period of this note?

Explanation

Period is the inverse of frequency:

$T=\frac{1}{f}$ .

Given the frequency, we simply need to take the reciprocal in order to find the period.

$T=\frac{1}{481Hz}$

A saxophone plays a B-flat at in normal air at $20^\circ C$ . What is the wavelength of the note?

$v_{sound}=343\frac{m}{s}$

Explanation

Remember that the velocity of a wave is always equal to the wavelength times the frequency:

$v=\lambda*f$

All sound waves will travel with the same velocity, the speed of sound. Using this value and the given frequency, we can calculate the wavelength.

$343\frac{m}{s}=\lambda*466.16Hz$

$\frac{343\frac{m}{s}}{466.16Hz}=\lambda$

$0.74m=\lambda$

The period of a wave is . What is the frequency?

$\frac{1}{13}Hz$

We need to know the wavelength in order to solve

We need to know the velocity of the wave in order to solve

Explanation

Frequency is the reciprocal of period.

$f=\frac{1}{T}$

We are given the period, so we simply need to take the reciprocal to solve for the frequency.

$f=\frac{1}{13s}$

$f=\frac{1}{13}Hz$

A wave has a period of . What is the frequency of this wave?

Explanation

Frequency is equal to the reciprocal of the period:

$f=\frac{1}{T}$

Given the period, we can invert it to find the frequency.

$f=\frac{1}{3s}$

A cat meows with a frequency of . What is the wavelength of this sound?

$v_{sound}=340.29\frac{m}{s}$

There is insufficient information to solve

Explanation

The relationship between velocity, wavelength, and frequency is:

$v=f\lambda$

We know the speed of sound and the frequency of the sound, allowing us to solve for the wavelength.

$340.29\frac{m}{s}=(512Hz)\lambda$

$\lambda=\frac{340.29\frac{m}{s}}{512Hz}$

$\lambda=0.66m$

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