Find the factors of 128 to simplify the term.

We can rewrite the expression as the square roots of these factors.

Simplify.

When it comes to adding and subtracting square roots, you can only do it if the radicands (the numbers inside), are the same. This boils the question down to:

Now we add the constants, the numbers on the outside, together. The radicands stay the same:

When adding or subtracting radicals, the radicand value must be equal. Since and are not the same, we leave the answer as it is. Answer is .

Adding and subtracting radicals cannot be done without having the same number under the same type of radical. These numbers first need to be simplified so that they have the same number under the radical before adding the coefficients. Look for perfect squares that divide into the number under the radical because those can be simplified.

Now take the square root of the perfect squares. Note that when the numbers come out of the square root they multiply with any coefficients outside that radical.

Since all the terms have the same radical, now their coefficients can be added

When adding and subtracting radicals, make the sure radicand or inside the square root are the same.

If they are the same, just add the numbers in front of the radical.

Since they are not the same, the answer is just the problem stated.

When multiplying radicals, you can combine them and multiply the numbers inside the radical.

Multiply the numerator and denominator by the denominator.

Reduce the fraction.

The answer is:

This expression can either be split into common factors of perfect squares, or this can be multiplied as one term.

For the simplest method, we will multiply the two numbers in radical form to combine as one radical.

The square root of a number is another number multiplied by itself to achieve the number in the square root.

The answer is:

We can take the square roots of the numerator and denominator separately. Thus, we get:

Moving radical from the denominator to the numerator:

Factoring:

Simplifying: