### All Calculus 2 Resources

## Example Questions

### Example Question #54 : Taylor And Maclaurin Series

Suppose that . Calculate .

**Possible Answers:**

**Correct answer:**

Let's find the power series of centered at to find . We have

This series is much easier to differentiate than the expression . We must look at term , which is the only constant term left after differentiating 48 times. This is the only important term, because when we plug in , all of the non-constant terms are zero. So we must have

### Example Question #55 : Taylor And Maclaurin Series

What is the value of the following infinite series?

**Possible Answers:**

**Correct answer:**

We can recognize this series as since the power series is

with the value plugged into since

.

So then we have

.

### Example Question #56 : Taylor And Maclaurin Series

What is the value of the following infinite series?

**Possible Answers:**

The infinite series diverges.

**Correct answer:**

The infinite series can be computed easily by splitting up the two components of the numerator:

Now we recall the MacLaurin series for the exponential function , which is

which converges for all . We can see that the two infinite series are with , respectively. So we have

### Example Question #57 : Taylor And Maclaurin Series

Find the value of the infinite series.

**Possible Answers:**

The series does not converge.

**Correct answer:**

We can evaluate the series

by recognizing it as a power series of a known function with a value plugged in for . In particular, it looks similar to :

After manipulating the series, we get

.

Now it suffices to evalute , which is .

So the infinite series has value

.

### Example Question #58 : Taylor And Maclaurin Series

Find the value of the following infinite series:

**Possible Answers:**

**Correct answer:**

After doing the following manipulation:

We can see that this is the power series

with plugged in.

So we have

### Example Question #53 : Taylor And Maclaurin Series

Find the value of the following series.

**Possible Answers:**

Divergent.

**Correct answer:**

We can split up the sum to get

.

We know that the power series for is

and that each sum,

and

are simply with plugged in, respectively.

Thus,

.

### Example Question #60 : Taylor And Maclaurin Series

Find the value of the infinite series.

**Possible Answers:**

Infinite series does not converge.

**Correct answer:**

The series

looks similar to the series for , which is

but the series we want to simplify starts at , so we can fix this by adding a and subtracting a , to leave the value unchanged, i.e.,

.

So now we have with , which gives us .

So then we have:

### Example Question #61 : Taylor And Maclaurin Series

Write out the first two terms of the Maclaurin series of the following function:

**Possible Answers:**

**Correct answer:**

The Maclaurin series of a function is simply the Taylor series of a function, but about x=0 (so a=0 in the formula):

To write out the first two terms (n=0 and n=1), we must find the first derivative of the function (because the zeroth derivative is the function itself):

The derivative was found using the following rule:

Next, use the general form, plugging in n=0 for the first term and n=1 for the second term:

### Example Question #1 : Maclaurin Series

Find the Maclaurin series for the function:

**Possible Answers:**

**Correct answer:**

Write Maclaurin series generated by a function f. The Maclaurin series is centered at for the Taylor series.

Evaluate the function and the derivatives of at .

Substitute the values into the power series. The series pattern can be seen as alternating and increasing order.

### Example Question #3092 : Calculus Ii

Find the first three terms of the Maclaurin series for the following function:

**Possible Answers:**

**Correct answer:**

The Maclaurin series of a function is simply the Taylor series for the function about a=0:

First, we can find the zeroth, first, and second derivatives of the function (n=0, 1, and 2 are the first three terms).

Plugging these values into the formula we get the following.

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