Basic Statistics

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Algebra II › Basic Statistics

Questions 1 - 10

Determine the mean of the numbers:

$\textup{The mean cannot be determined.}$

Explanation

Add all the numbers.

The mean is the average of all the numbers, which means dividing this number by five will give the average.

$\frac{160}{5} =32$

The answer is:

Determine the range of the following numbers:

Explanation

The range is defined as the difference of the highest and lowest numbers.

The highest number is 41.

The lowest number is 3.

Subtract both numbers.

The answer is:

Determine the range of the numbers:

Explanation

The range is the difference between the highest and lowest numbers.

The highest number is 11.

The smallest number is negative three.

Subtract both numbers. Use parentheses to embrace the negative value.

The answer is:

Determine the mean of the numbers:

$\textup{The mean cannot be determined.}$

Explanation

Add all the numbers.

The mean is the average of all the numbers, which means dividing this number by five will give the average.

$\frac{160}{5} =32$

The answer is:

varies directly with $x^{2}$ . If , what is if ?

Explanation

1. Since varies directly with $x^{2}$ :

$y=Kx^{2}$ with K being some constant.

2. Solve for K using the x and y values given:

$75=K(5^{2})$

3. Use the equation you solved for to find the value of y:

$y=3x^{2}$

$y=3(10^{2})$

Determine the range of the following numbers:

Explanation

The range is defined as the difference of the highest and lowest numbers.

The highest number is 41.

The lowest number is 3.

Subtract both numbers.

The answer is:

varies directly with $x^{2}$ . If , what is if ?

Explanation

1. Since varies directly with $x^{2}$ :

$y=Kx^{2}$ with K being some constant.

2. Solve for K using the x and y values given:

$75=K(5^{2})$

3. Use the equation you solved for to find the value of y:

$y=3x^{2}$

$y=3(10^{2})$

Determine the mean of the numbers: $[\frac{1}{3},3%, \frac{1}{30}]$

$\frac{119}{900}$

$\frac{119}{300}$

$\frac{1}{30}$

$\frac{19}{30}$

$\frac{19}{90}$

Explanation

The mean is the average of all the numbers. Convert the percentage to a fraction by removing the percentage and divide the number by 100.

$[\frac{1}{3},3%, \frac{1}{30}]\rightarrow[\frac{1}{3}, \frac{3}{100},\frac{1}{30}]$

Convert all fractions to a common denominator. Write out the factors for the denominators.

The common denominator is 300.

$\frac{1}{3}+ \frac{3}{100}+\frac{1}{30}= \frac{1(100)}{3(100)}+ \frac{3(3)}{100(3)}+\frac{1(10)}{30(10)}$

Simplify the fractions.

$\frac{100}{300}+\frac{9}{300}+\frac{10}{300} = \frac{119}{300}$

There are three numbers in the data set. Divide the fraction by three.

$\frac{ \frac{119}{300}}{3}= \frac{119}{300} \div 3 = \frac{119}{300}\times \frac{1}{3} = \frac{119}{900}$

The answer is: $\frac{119}{900}$

Determine the mean of the numbers:

$\textup{The mean cannot be determined.}$

Explanation

Add all the numbers.

The mean is the average of all the numbers, which means dividing this number by five will give the average.

$\frac{160}{5} =32$

The answer is:

varies directly with $x^{2}$ . If , what is if ?

Explanation

1. Since varies directly with $x^{2}$ :

$y=Kx^{2}$ with K being some constant.

2. Solve for K using the x and y values given:

$75=K(5^{2})$

3. Use the equation you solved for to find the value of y:

$y=3x^{2}$

$y=3(10^{2})$

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