### All ACT Math Resources

## Example Questions

### Example Question #2344 : Act Math

The solution of is the set of all real numbers such that:

**Possible Answers:**

**Correct answer:**

Square both sides of the equation:

Then Solve for x:

Therefore,

### Example Question #2345 : Act Math

What is the product of and

**Possible Answers:**

**Correct answer:**

Multiplying complex numbers is like multiplying binomials, you have to use foil. The only difference is, when you multiply the two terms that have in the them you can simplify the to negative 1. Foil is first, outside, inside, last

First

Outside:

Inside

Last

Add them all up and you get

### Example Question #2346 : Act Math

Simplify the following:

**Possible Answers:**

**Correct answer:**

Begin this problem by doing a basic FOIL, treating just like any other variable. Thus, you know:

Recall that since , . Therefore, you can simplify further:

### Example Question #2347 : Act Math

Complex numbers take the form , where is the real term in the complex number and is the nonreal (imaginary) term in the complex number.

Distribute:

**Possible Answers:**

**Correct answer:**

This equation can be solved very similarly to a binomial like . Distribution takes place into both the real and nonreal terms inside the complex number, where applicable.

### Example Question #2348 : Act Math

Complex numbers take the form , where is the real term in the complex number and is the nonreal (imaginary) term in the complex number.

Distribute and solve:

**Possible Answers:**

**Correct answer:**

This problem can be solved very similarly to a binomial like .

### Example Question #2349 : Act Math

Complex numbers take the form , where is the real term in the complex number and is the nonreal (imaginary) term in the complex number.

Which of the following is equivalent to ?

**Possible Answers:**

**Correct answer:**

When dealing with complex numbers, remember that .

If we square , we thus get .

Yet another exponent gives us **OR **.

But when we hit , we discover that

Thus, we have a repeating pattern with powers of , with every 4 exponents repeating the pattern. This means any power of evenly divisible by 4 will equal 1, any power of divisible by 4 with a remainder of 1 will equal , and so on.

Thus,

Since the remainder is 3, we know that .

### Example Question #21 : Complex Numbers

Simplify if possible. Leave no complex numbers in the denominator.

**Possible Answers:**

**Correct answer:**

Solving this problem requires eliminating the nonreal term of the denominator. Our best bet for this is to cancel the nonreal term out by using the *conjugate* of the denominator.

Remember that for all binomials , there exists a conjugate such that .

This can also be applied to complex conjugates, which will eliminate the nonreal portion entirely (since )!

Multiply both terms by the denominator's conjugate.

** **Simplify. Note** .**

FOIL the numerator.

Combine and simplify.

** **Simplify the fraction.

Thus, .

### Example Question #2 : How To Multiply Complex Numbers

Simplify the following:

**Possible Answers:**

**Correct answer:**

Begin by treating this just like any normal case of FOIL. Notice that this is really the form of a difference of squares. Therefore, the distribution is very simple. Thus:

Now, recall that . Therefore, is . Based on this, we can simplify further:

### Example Question #3 : How To Multiply Complex Numbers

Which of the following is equal to ?

**Possible Answers:**

**Correct answer:**

Remember that since , you know that is . Therefore, is or . This makes our question very easy.

is the same as or

Thus, we know that is the same as or .