### All ACT Math Resources

## Example Questions

### Example Question #81 : Trigonometry

What is the sine of ?

**Possible Answers:**

**Correct answer:**

Sine can be found using the SOH CAH TOA method. For sine we do .

### Example Question #2 : How To Find The Sine Of An Angle

See right triangle ABC. If the length AB is 8 and the length of BC is 6, what is the sine of angle A?

**Possible Answers:**

6

0.8

10

1

0.6

**Correct answer:**

0.6

Sine A = Opposite / Hypotenuse = BC / AC

To find AC, use Pythagorean Theorum

AB^{2} + BC^{2} = AC^{2}

8^{2} + 6^{2} = AC^{2}

64 + 36 = AC^{2}

100 = AC^{2}

AC = 10

Sine A = BC / AC = 6 / 10 = 0.6

### Example Question #31 : Sine

Solve for over the interval

**Possible Answers:**

Q = π or does not exist 2

Q = π or 2π

Q = π or 3π 2 2

Q = 3π or does not exist 2

**Correct answer:**

Q = 3π or does not exist 2

Substitute x = sinQ and solve the new equation x^{2} + 3x = –2 by factoring. Be sure to change variables back to Q. As a result, sinQ = –1 or sinQ = –2. This function is bounded between –1 and 1 so sinQ can never be –2 and sinQ is –1 only at 3π/2 or 270 °.

### Example Question #1 : How To Find The Sine Of An Angle

If , , and , what is the sine of ?

**Possible Answers:**

**Correct answer:**

Recall that sin = opposite / hypotenuse. Based on the figure shown, we see that is the opposite side needed and is the hypotenuse. Plug these values in to solve.

### Example Question #1 : How To Find The Sine Of An Angle

Triangle shown is a right triangle. If line and line , what is the sine of the angle at ?

**Possible Answers:**

**Correct answer:**

Now solve for using Pythagorean Theorem:

### Example Question #81 : Trigonometry

If , and if is an angle between and degrees, which of the following equals ?

**Possible Answers:**

**Correct answer:**

An angle between and degrees means that the angle is located in the second quadrant.

The tangent function is derived from taking the side opposite to the angle and dividing by the side adjacent to the angle (, as shown in the image).

Hence, the side is units long and side is units high. Therefore, according to Pythagorean Theorem rules, the side must be units long (since ).

The sine function is positive in the second quadrant. It is also equivalent to the side opposite the angle () divided by the hypotenuse ().

This makes .

### Example Question #81 : Trigonometry

A sine function has a period of , a -intercept of , an amplitude of and no phase shift. These describe which of these equations?

**Possible Answers:**

**Correct answer:**

Looking at this form of a sine function:

We can draw the following conclusions:

- because the amplitude is specified as .
- because of the specified period of since .
- because the problem specifies there is no phase shift.
- because the -intercept of a sine function with no phase shift is .

Bearing these in mind, is the only function that fits all four of those.

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