### All ACT Math Resources

## Example Questions

### Example Question #32 : Quadrilaterals

Two rectangles are similar. The perimeter of the first rectangle is 36. The perimeter of the second is 12. If the base length of the second rectangle is 4, what is the height of the first rectangle?

**Possible Answers:**

2

10

4

8

6

**Correct answer:**

6

Solve for the height of the second rectangle.

Perimeter = 2B + 2H

12 = 2(4) + 2H

12 = 8 + 2H

4 = 2H

H = 2

If they are similar, then the base and height are proportionally equal.

B_{1}/H_{1} = B_{2}/H_{2}

4/2 = B_{2}/H_{2}

2 = B_{2}/H_{2}

B_{2} = 2H_{2}

Use perimeter equation then solve for H:

Perimeter = 2B + 2H

36 = 2 B_{2} + 2 H_{2}

36 = 2 (2H_{2}) + 2 H_{2}

36 = 4H_{2} + 2 H_{2}

36 = 6H_{2}

H_{2} = 6

### Example Question #1 : How To Find If Rectangles Are Similar

Two rectangles are similar. The first rectangle has a perimeter of and the second has a perimeter of . If the first rectangle has a length of , what the length of the second rectangle?

**Possible Answers:**

**Correct answer:**

1. Create a proportion comparing the two given rectangles:

2. Solve for the length of the second rectangle by cross-multiplying:

### Example Question #2 : How To Find If Rectangles Are Similar

The width of a rectangle is 5 times the length of the rectangle. The width of the rectangle is 30. What is the perimeter of the rectangle?

**Possible Answers:**

**Correct answer:**

If the width is 5 times the length, and the width is 30, then the length is 6. The perimeter of a rectangle is 2 x width + 2 x length. 2 x 30 + 2 x 6 = 72.

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