Symmetry
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Pre-Calculus › Symmetry
Is the following function symmetrical about the y axis (is it an even function)?
Yes
No
Insufficient Information
Not a function
Explanation
For a function to be even, it must satisfy the equality
Likewise if a function is even, it is symmetrical about the y-axis
Therefore, the function is not even, and so the answer is No
Is the following function symmetrical about the y axis (is it an even function)?
Yes
No
Insufficient Information
Not a function
Explanation
For a function to be even, it must satisfy the equality
Likewise if a function is even, it is symmetrical about the y-axis
Therefore, the function is not even, and so the answer is No
Algebraically check for symmetry with respect to the x-axis, y axis, and the origin.
Symmetrical about the x-axis
Symmetrical about the y-axis
Symmetrical about the origin
No symmetry
Explanation
For a function to be symmetrical about the y-axis, it must satisfy
so there is not symmetry about the y-axis
For a function to be symmetrical about the x-axis, it must satisfy
so there is symmetry about the x-axis
For a function to be symmetrical about the origin, you must replace y with (-y) and x with (-x) and the resulting function must be equal to the original function.
-So there is no symmetry about the origin, and the answer is Symmetrical about the x-axis
Algebraically check for symmetry with respect to the x-axis, y axis, and the origin.
Symmetrical about the x-axis
Symmetrical about the y-axis
Symmetrical about the origin
No symmetry
Explanation
For a function to be symmetrical about the y-axis, it must satisfy
so there is not symmetry about the y-axis
For a function to be symmetrical about the x-axis, it must satisfy
so there is symmetry about the x-axis
For a function to be symmetrical about the origin, you must replace y with (-y) and x with (-x) and the resulting function must be equal to the original function.
-So there is no symmetry about the origin, and the answer is Symmetrical about the x-axis
Algebraically check for symmetry with respect to the x-axis, y axis, and the origin.
Symmetry about the x-axis, y-axis, and origin
Symmetry about the x-axis
Symmetry about the x-axis, and y-axis
Symmetry about the y-axis
Symmetry about the y-axis and origin
Explanation
For a function to be symmetrical about the y-axis, it must satisfy so there is symmetry about the y-axis
For a function to be symmetrical about the x-axis, it must satisfy
so there is not symmetry about the x-axis
For a function to be symmetrical about the origin, you must replace y with (-y) and x with (-x) and the resulting function must be equal to the original function.
So there is no symmetry about the origin.
Algebraically check for symmetry with respect to the x-axis, y axis, and the origin.
Symmetry about the x-axis, y-axis, and origin
Symmetry about the x-axis
Symmetry about the x-axis, and y-axis
Symmetry about the y-axis
Symmetry about the y-axis and origin
Explanation
For a function to be symmetrical about the y-axis, it must satisfy so there is symmetry about the y-axis
For a function to be symmetrical about the x-axis, it must satisfy
so there is not symmetry about the x-axis
For a function to be symmetrical about the origin, you must replace y with (-y) and x with (-x) and the resulting function must be equal to the original function.
So there is no symmetry about the origin.
Yes
No
There is insufficient information to determine the answer
The given information does not include a function
Yes
No
There is insufficient information to determine the answer
The given information does not include a function
Is the following function symmetric across the y-axis? (Is it an even function?)
Yes
No
There is not enough information to determine
I don't know!
That's not a function!
Explanation
One way to determine algebraically if a function is an even function, or symmetric about the y-axis, is to substitute in for
. When we do this, if the function is equivalent to the original, then the function is an even function. If not, it is not an even function.
For our function:
Since this matches the original, our function is symmetric across the y-axis.
Is the following function symmetric across the y-axis? (Is it an even function?)
Yes
No
There is not enough information to determine
I don't know!
That's not a function!
Explanation
One way to determine algebraically if a function is an even function, or symmetric about the y-axis, is to substitute in for
. When we do this, if the function is equivalent to the original, then the function is an even function. If not, it is not an even function.
For our function:
Since this matches the original, our function is symmetric across the y-axis.