Solve for area of a triangle - 7th Grade Math

Card 0 of 20

Question

Calculate the area of the provided figure.

Answer

In order to solve this problem, we need to recall the area formula for a triangle:

$A=\frac{b\times h}{2}$

Now that we have the correct formula, we can substitute in our known values and solve:

$A=\frac{14\times5}{2}$

$A=35\textup{ in}^2$

Compare your answer with the correct one above

Question

What is the area of the triangle pictured above?

Answer

The area of a triangle is calculated using the formula $Area = \frac{1}{2}(Base\times Height)$ . Importantly, the height is a perpendicular line between the base and the opposite point. In a right triangle like this one, you're in luck: the triangle as drawn already has that perpendicular line as one of the two sides. So here we will calculate $\frac{1}{2}(8\times 6)$ . That gives us an answer of 24.

Compare your answer with the correct one above

Question

In triangle ABC above, the distance between point A and point D is 10 inches, and the area of the triangle is 20 square inches. What is the length of side BC?

Answer

The area of a triangle can be calculated using the formula Area = 1/2 * Base * Height. Here you're given two of the unknowns in that formula:

Area = 20

Height = 10

So you can plug those into the area formula to solve for Base, the only remaining unknown:

20 = 1/2 * Base * 10

That means that 20 = 5 * Base, so Base = 4.

Compare your answer with the correct one above

Question

In triangle ABC, side BC measures 12 meters, and the shortest straight-line distance between point A and side BC is 5 meters long. What is the area of triangle ABC?

Answer

The area of a triangle can be calculated using the formula $Area = \frac{1}{2}Base\times Height$ . The height of a triangle is a perpendicular line connecting the base and its opposite point; in any acute or right triangle - a triangle with no angles greater than 90 degrees - the height is also the shortest line between the base and the opposite point. Here that means that if you use BC = 12 as your base, then the distance of 5 between BC and point A is the height. That means that you can calculate the area:

$Area=\frac{1}{2}(12\times 5)=\frac{1}{2}(60)=30$

Compare your answer with the correct one above

Question

The pictured right triangle has sides of 7, 24, and 25. What is the area of that triangle?

Answer

The area of a triangle can be calculated using the formula $Area = \frac{1}{2}(Base)(Height)$ . Note that the height of any triangle is a perpendicular line between the base and its opposite angle; in a right triangle that's very convenient, because the right angle gives you that perpendicular relationship between two sides. So you can use 24 as the base and 7 as the height here. That means that the area is:

$Area =\frac{1}{2}(24)(7)=84$

Compare your answer with the correct one above

Question

Calculate the area of the provided figure.

Answer

In order to solve this problem, we need to recall the area formula for a triangle:

$A=\frac{b\times h}{2}$

Now that we have the correct formula, we can substitute in our known values and solve:

$A=\frac{14\times5}{2}$

$A=35\textup{ in}^2$

Compare your answer with the correct one above

Question

What is the area of the triangle pictured above?

Answer

The area of a triangle is calculated using the formula $Area = \frac{1}{2}(Base\times Height)$ . Importantly, the height is a perpendicular line between the base and the opposite point. In a right triangle like this one, you're in luck: the triangle as drawn already has that perpendicular line as one of the two sides. So here we will calculate $\frac{1}{2}(8\times 6)$ . That gives us an answer of 24.

Compare your answer with the correct one above

Question

In triangle ABC above, the distance between point A and point D is 10 inches, and the area of the triangle is 20 square inches. What is the length of side BC?

Answer

The area of a triangle can be calculated using the formula Area = 1/2 * Base * Height. Here you're given two of the unknowns in that formula:

Area = 20

Height = 10

So you can plug those into the area formula to solve for Base, the only remaining unknown:

20 = 1/2 * Base * 10

That means that 20 = 5 * Base, so Base = 4.

Compare your answer with the correct one above

Question

In triangle ABC, side BC measures 12 meters, and the shortest straight-line distance between point A and side BC is 5 meters long. What is the area of triangle ABC?

Answer

The area of a triangle can be calculated using the formula $Area = \frac{1}{2}Base\times Height$ . The height of a triangle is a perpendicular line connecting the base and its opposite point; in any acute or right triangle - a triangle with no angles greater than 90 degrees - the height is also the shortest line between the base and the opposite point. Here that means that if you use BC = 12 as your base, then the distance of 5 between BC and point A is the height. That means that you can calculate the area:

$Area=\frac{1}{2}(12\times 5)=\frac{1}{2}(60)=30$

Compare your answer with the correct one above

Question

The pictured right triangle has sides of 7, 24, and 25. What is the area of that triangle?

Answer

The area of a triangle can be calculated using the formula $Area = \frac{1}{2}(Base)(Height)$ . Note that the height of any triangle is a perpendicular line between the base and its opposite angle; in a right triangle that's very convenient, because the right angle gives you that perpendicular relationship between two sides. So you can use 24 as the base and 7 as the height here. That means that the area is:

$Area =\frac{1}{2}(24)(7)=84$

Compare your answer with the correct one above

Question

Calculate the area of the provided figure.

Answer

In order to solve this problem, we need to recall the area formula for a triangle:

$A=\frac{b\times h}{2}$

Now that we have the correct formula, we can substitute in our known values and solve:

$A=\frac{14\times5}{2}$

$A=35\textup{ in}^2$

Compare your answer with the correct one above

Question

What is the area of the triangle pictured above?

Answer

The area of a triangle is calculated using the formula $Area = \frac{1}{2}(Base\times Height)$ . Importantly, the height is a perpendicular line between the base and the opposite point. In a right triangle like this one, you're in luck: the triangle as drawn already has that perpendicular line as one of the two sides. So here we will calculate $\frac{1}{2}(8\times 6)$ . That gives us an answer of 24.

Compare your answer with the correct one above

Question

In triangle ABC above, the distance between point A and point D is 10 inches, and the area of the triangle is 20 square inches. What is the length of side BC?

Answer

The area of a triangle can be calculated using the formula Area = 1/2 * Base * Height. Here you're given two of the unknowns in that formula:

Area = 20

Height = 10

So you can plug those into the area formula to solve for Base, the only remaining unknown:

20 = 1/2 * Base * 10

That means that 20 = 5 * Base, so Base = 4.

Compare your answer with the correct one above

Question

In triangle ABC, side BC measures 12 meters, and the shortest straight-line distance between point A and side BC is 5 meters long. What is the area of triangle ABC?

Answer

The area of a triangle can be calculated using the formula $Area = \frac{1}{2}Base\times Height$ . The height of a triangle is a perpendicular line connecting the base and its opposite point; in any acute or right triangle - a triangle with no angles greater than 90 degrees - the height is also the shortest line between the base and the opposite point. Here that means that if you use BC = 12 as your base, then the distance of 5 between BC and point A is the height. That means that you can calculate the area:

$Area=\frac{1}{2}(12\times 5)=\frac{1}{2}(60)=30$

Compare your answer with the correct one above

Question

The pictured right triangle has sides of 7, 24, and 25. What is the area of that triangle?

Answer

The area of a triangle can be calculated using the formula $Area = \frac{1}{2}(Base)(Height)$ . Note that the height of any triangle is a perpendicular line between the base and its opposite angle; in a right triangle that's very convenient, because the right angle gives you that perpendicular relationship between two sides. So you can use 24 as the base and 7 as the height here. That means that the area is:

$Area =\frac{1}{2}(24)(7)=84$

Compare your answer with the correct one above

Question

Calculate the area of the provided figure.

Answer

In order to solve this problem, we need to recall the area formula for a triangle:

$A=\frac{b\times h}{2}$

Now that we have the correct formula, we can substitute in our known values and solve:

$A=\frac{14\times5}{2}$

$A=35\textup{ in}^2$

Compare your answer with the correct one above

Question

What is the area of the triangle pictured above?

Answer

The area of a triangle is calculated using the formula $Area = \frac{1}{2}(Base\times Height)$ . Importantly, the height is a perpendicular line between the base and the opposite point. In a right triangle like this one, you're in luck: the triangle as drawn already has that perpendicular line as one of the two sides. So here we will calculate $\frac{1}{2}(8\times 6)$ . That gives us an answer of 24.

Compare your answer with the correct one above

Question

In triangle ABC above, the distance between point A and point D is 10 inches, and the area of the triangle is 20 square inches. What is the length of side BC?

Answer

The area of a triangle can be calculated using the formula Area = 1/2 * Base * Height. Here you're given two of the unknowns in that formula:

Area = 20

Height = 10

So you can plug those into the area formula to solve for Base, the only remaining unknown:

20 = 1/2 * Base * 10

That means that 20 = 5 * Base, so Base = 4.

Compare your answer with the correct one above

Question

In triangle ABC, side BC measures 12 meters, and the shortest straight-line distance between point A and side BC is 5 meters long. What is the area of triangle ABC?

Answer

The area of a triangle can be calculated using the formula $Area = \frac{1}{2}Base\times Height$ . The height of a triangle is a perpendicular line connecting the base and its opposite point; in any acute or right triangle - a triangle with no angles greater than 90 degrees - the height is also the shortest line between the base and the opposite point. Here that means that if you use BC = 12 as your base, then the distance of 5 between BC and point A is the height. That means that you can calculate the area:

$Area=\frac{1}{2}(12\times 5)=\frac{1}{2}(60)=30$

Compare your answer with the correct one above

Question

The pictured right triangle has sides of 7, 24, and 25. What is the area of that triangle?

Answer

The area of a triangle can be calculated using the formula $Area = \frac{1}{2}(Base)(Height)$ . Note that the height of any triangle is a perpendicular line between the base and its opposite angle; in a right triangle that's very convenient, because the right angle gives you that perpendicular relationship between two sides. So you can use 24 as the base and 7 as the height here. That means that the area is:

$Area =\frac{1}{2}(24)(7)=84$

Compare your answer with the correct one above

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Solve for area of a triangle - 7th Grade Math

Calculate the area of the provided figure.

In order to solve this problem, we need to recall the area formula for a triangle: Now that we have the correct formula, we can substitute in our known values and solve:

What is the area of the triangle pictured above?

In triangle ABC above, the distance between point A and point D is 10 inches, and the area of the triangle is 20 square inches. What is the length of side BC?

In triangle ABC, side BC measures 12 meters, and the shortest straight-line distance between point A and side BC is 5 meters long. What is the area of triangle ABC?

The pictured right triangle has sides of 7, 24, and 25. What is the area of that triangle?

Calculate the area of the provided figure.

In order to solve this problem, we need to recall the area formula for a triangle: Now that we have the correct formula, we can substitute in our known values and solve:

What is the area of the triangle pictured above?

In triangle ABC above, the distance between point A and point D is 10 inches, and the area of the triangle is 20 square inches. What is the length of side BC?

In triangle ABC, side BC measures 12 meters, and the shortest straight-line distance between point A and side BC is 5 meters long. What is the area of triangle ABC?

The pictured right triangle has sides of 7, 24, and 25. What is the area of that triangle?

Calculate the area of the provided figure.

In order to solve this problem, we need to recall the area formula for a triangle: Now that we have the correct formula, we can substitute in our known values and solve:

What is the area of the triangle pictured above?

In triangle ABC above, the distance between point A and point D is 10 inches, and the area of the triangle is 20 square inches. What is the length of side BC?

In triangle ABC, side BC measures 12 meters, and the shortest straight-line distance between point A and side BC is 5 meters long. What is the area of triangle ABC?

The pictured right triangle has sides of 7, 24, and 25. What is the area of that triangle?

Calculate the area of the provided figure.

In order to solve this problem, we need to recall the area formula for a triangle: Now that we have the correct formula, we can substitute in our known values and solve:

What is the area of the triangle pictured above?

In triangle ABC above, the distance between point A and point D is 10 inches, and the area of the triangle is 20 square inches. What is the length of side BC?

In triangle ABC, side BC measures 12 meters, and the shortest straight-line distance between point A and side BC is 5 meters long. What is the area of triangle ABC?

The pictured right triangle has sides of 7, 24, and 25. What is the area of that triangle?

In order to solve this problem, we need to recall the area formula for a triangle:

$A=\frac{b\times h}{2}$

Now that we have the correct formula, we can substitute in our known values and solve:

$A=\frac{14\times5}{2}$

$A=35\textup{ in}^2$

In order to solve this problem, we need to recall the area formula for a triangle:

$A=\frac{b\times h}{2}$

Now that we have the correct formula, we can substitute in our known values and solve:

$A=\frac{14\times5}{2}$

$A=35\textup{ in}^2$

In order to solve this problem, we need to recall the area formula for a triangle:

$A=\frac{b\times h}{2}$

Now that we have the correct formula, we can substitute in our known values and solve:

$A=\frac{14\times5}{2}$

$A=35\textup{ in}^2$

In order to solve this problem, we need to recall the area formula for a triangle:

$A=\frac{b\times h}{2}$

Now that we have the correct formula, we can substitute in our known values and solve:

$A=\frac{14\times5}{2}$

$A=35\textup{ in}^2$