2nd Grade Math Quiz: Add And Subtract Within 1000
20 questions · exam conditions
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Add And Subtract Within 1000Question 1 of 20

What is 392+185392 + 185?

567
477
577
587
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2nd Grade Math Quiz

2nd Grade Math Quiz: Add And Subtract Within 1000

Practice Add And Subtract Within 1000 in 2nd Grade Math with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Add And Subtract Within 1000, giving you a quick way to practice the rules, question types, and explanations that matter most for 2nd Grade Math.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

What is 392+185392 + 185?

  1. 567
  2. 477
  3. 577 (correct answer)
  4. 587
Explanation: Adding 392 and 185 gives 577. Choice A is off by 10, a common error when regrouping the tens incorrectly. Choice B is off by 100, from a mistake regrouping the hundreds. Choice D is off by 10 in the other direction, from adding one extra ten.

Question 2

What is 468+257468 + 257?

  1. 725 (correct answer)
  2. 625
  3. 715
  4. 735
Explanation: This question tests 2nd grade understanding of adding and subtracting within 1000 using strategies based on place value, properties of operations, and standard algorithms with regrouping (CCSS 2.NBT.B.7: Add and subtract within 1000, using concrete models or drawings and strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; relate the strategy to a written method. Understand that in adding or subtracting three-digit numbers, one adds or subtracts hundreds and hundreds, tens and tens, ones and ones). When adding three-digit numbers like 347 + 286, use place value: add ones (7+6=13, write 3 carry 1), add tens (4+8+1=13, write 3 carry 1), add hundreds (3+2+1=6), result 633. When subtracting like 563 - 278, use regrouping: ones (can't do 3-8, regroup 6 tens 3 ones to 5 tens 13 ones, 13-8=5), tens (can't do 5-7, regroup 5 hundreds 5 tens to 4 hundreds 15 tens, 15-7=8), hundreds (4-2=2), result 285. Multiple regroupings often needed. In this problem, student must add 468 + 257, requiring regrouping in ones and tens. To solve, use standard algorithm—align by place value, add ones (8+7=15, carry 1), add tens (6+5+1=12, carry 1), add hundreds (4+2+1=7), answer 725. Choice B is correct because adding 468+257 with regrouping correctly—ones 8+7=15 (write 5 carry 1), tens 6+5+1=12 (write 2 carry 1), hundreds 4+2+1=7, giving 725. This accurately uses regrouping across multiple places. Choice A represents didn't carry correctly in addition (forgot to add carried 1 in hundreds, got 715 instead of 725). This error typically happens when students don't carry/borrow correctly, forget to regroup across multiple places, subtract in wrong direction when borrowing, misunderstand place value, confuse operations, don't handle zeros correctly. To help students: Practice standard algorithm with clear alignment. Use vertical format, align by place value. For addition: 'Start with ones. 7+6=13. That's more than 10, so regroup: write 3 in ones, carry 1 ten to tens column. Now tens: 4+8=12, plus carried 1 = 13. Regroup: write 3 in tens, carry 1 hundred. Hundreds: 3+2=5, plus carried 1=6. Answer: 633.' For subtraction: 'Start with ones. Can we do 3-8? No, so regroup: borrow 1 ten from tens (6 tens becomes 5 tens), add 10 ones (3 ones becomes 13 ones). Now: 13-8=5. Tens: can we do 5-7? No, regroup: borrow 1 hundred (5 hundreds becomes 4), add 10 tens (5 tens becomes 15 tens). Now: 15-7=8. Hundreds: 4-2=2. Answer: 285.' Use base-ten blocks to show regrouping visually: trade 1 rod for 10 units, trade 1 flat for 10 rods. Practice regrouping with zeros: 400-137 requires regrouping from hundreds to tens to ones. Teach place value strategy: break apart, add/subtract by place. Use number line for mental math visualization. For word problems, identify operation (joining=add, separating/comparing=subtract). Watch for: not regrouping when needed, regrouping incorrectly, subtracting smaller from larger without borrowing, place value errors, handling zeros incorrectly, wrong operation.

Question 3

School had 476 students. 238 more enrolled. How many now?

  1. 704
  2. 714 (correct answer)
  3. 694
  4. 734
Explanation: This question tests 2nd grade understanding of adding and subtracting within 1000 using strategies based on place value, properties of operations, and standard algorithms with regrouping (CCSS 2.NBT.B.7: Add and subtract within 1000, using concrete models or drawings and strategies based on place value, properties of operations, and/or the relationship between addition and subtraction; relate the strategy to a written method. Understand that in adding or subtracting three-digit numbers, one adds or subtracts hundreds and hundreds, tens and tens, ones and ones). When adding three-digit numbers like 347+286347 + 286, use place value: add ones (7+6=137+6=13, write 3 carry 1), add tens (4+8+1=134+8+1=13, write 3 carry 1), add hundreds (3+2+1=63+2+1=6), result 633. When subtracting like 563−278563 - 278, use regrouping: ones (can't do 3-8, regroup 6 tens 3 ones to 5 tens 13 ones, 13−8=513-8=5), tens (can't do 5-7, regroup 5 hundreds 5 tens to 4 hundreds 15 tens, 15−7=815-7=8), hundreds (4−2=24-2=2), result 285. Multiple regroupings often needed. Place value strategy: break into hundreds, tens, ones, add/subtract separately, combine. Mental math: use compensation (563−278→563−300+22=263+22=285563-278 \rightarrow 563-300+22 = 263+22=285). Number line: jump by hundreds, then tens, then ones. In this problem, it's a word problem where the school had 476 students and 238 more enrolled, requiring addition to find total now; to solve, use standard algorithm—align by place value, add ones (6+8=146+8=14, carry 1), add tens (7+3+1=117+3+1=11, carry 1), add hundreds (4+2+1=74+2+1=7), answer 714. Choice B is correct because adding 476+238476+238 with regrouping correctly—ones 6+8=146+8=14 (write 4 carry 1), tens 7+3+1=117+3+1=11 (write 1 carry 1), hundreds 4+2+1=74+2+1=7, giving 714. This accurately uses regrouping across multiple places. Choice A represents wrong operation (subtracted instead of adding, got 704 or similar error). This error typically happens when students confuse operations in word problems. To help students: Practice standard algorithm with clear alignment. Use vertical format, align by place value. For addition: 'Start with ones. 7+6=137+6=13. That's more than 10, so regroup: write 3 in ones, carry 1 ten to tens column. Now tens: 4+8=124+8=12, plus carried 1=1313. Regroup: write 3 in tens, carry 1 hundred. Hundreds: 3+2=53+2=5, plus carried 1=6. Answer: 633.' For subtraction: 'Start with ones. Can we do 3-8? No, so regroup: borrow 1 ten from tens (6 tens becomes 5 tens), add 10 ones (3 ones becomes 13 ones). Now: 13−8=513-8=5. Tens: can we do 5-7? No, regroup: borrow 1 hundred (5 hundreds becomes 4), add 10 tens (5 tens becomes 15 tens). Now: 15−7=815-7=8. Hundreds: 4−2=24-2=2. Answer: 285.' Use base-ten blocks to show regrouping visually: trade 1 rod for 10 units, trade 1 flat for 10 rods. Practice regrouping with zeros: 400−137400-137 requires regrouping from hundreds to tens to ones. Teach place value strategy: break apart, add/subtract by place. Use number line for mental math visualization. For word problems, identify operation (joining=add, separating/comparing=subtract). Watch for: not regrouping when needed, regrouping incorrectly, subtracting smaller from larger without borrowing, place value errors, handling zeros incorrectly, wrong operation.

Question 4

What number added to 347 equals 633?

  1. 280
  2. 633
  3. 347
  4. 286 (correct answer)
Explanation: Since 347 plus 286 equals 633, 286 is the missing number. Choice A, 280, is close but does not make the equation true. Choice B, 633, is the total itself, not the missing addend. Choice C, 347, is the number already given in the problem.

Question 5

What is 700−358700 - 358?

  1. 442
  2. 452
  3. 352
  4. 342 (correct answer)
Explanation: Subtracting 358 from 700 gives 342. Choice A comes from not regrouping across the hundreds place correctly. Choice B is off by 110 from a larger regrouping mistake. Choice C is off by 10 from a smaller regrouping error in the tens place.

Question 6

What is 563−278563 - 278?

  1. 295295
  2. 315315
  3. 285285 (correct answer)
  4. 345345
Explanation: 563 - 278 = 285, so Choice C is correct. Choice A is wrong because it does not regroup the tens correctly. Choice B is wrong because it does not regroup the hundreds correctly. Choice D is wrong because it is too far from the correct answer to reflect a small subtraction error.

Question 7

What is 704−268704 - 268?

  1. 436 (correct answer)
  2. 442
  3. 446
  4. 536
Explanation: Subtracting 268 from 704 gives 436. Choice B, 442, is off by a small regrouping error. Choice C, 446, is also off due to a regrouping error. Choice D, 536, is much too large for this subtraction.

Question 8

What is 438+169438 + 169?

  1. 597
  2. 617
  3. 707
  4. 607 (correct answer)
Explanation: Adding 438 and 169 gives 607. Choice A, 597, is too small by 10. Choice B, 617, is off by 10 in the other direction. Choice C, 707, mistakenly carries an extra hundred.

Question 9

Solve: 357+289357 + 289. Use the standard algorithm.

  1. 646 (correct answer)
  2. 636
  3. 746
  4. 556
Explanation: Adding the ones, tens, and hundreds with regrouping gives 357+289=646357 + 289 = 646, so A is correct. Choice B is ten less, which can happen when a carried digit is dropped while regrouping the tens. Choice C is one hundred too high, which can happen from an extra carry into the hundreds place. Choice D is far too low and would result from mixing up addition with subtraction.

Question 10

Calculate 709−465709 - 465. Regroup if needed.

  1. 274
  2. 244 (correct answer)
  3. 254
  4. 344
Explanation: 244 is correct because subtracting 465 from 709 with proper regrouping gives 244. Choice A, 274, comes from a regrouping mistake in the tens place. Choice C, 254, comes from a small error in the ones place after regrouping. Choice D, 344, comes from failing to regroup the hundreds place correctly.

Question 11

Find the difference: 603 minus 287.

  1. 326
  2. 426
  3. 316 (correct answer)
  4. 310
Explanation: Subtracting 287 from 603 gives 316. Choice A, 326, comes from a borrowing error in the tens place. Choice B, 426, comes from a borrowing error in the hundreds place. Choice D, 310, comes from a small subtraction slip in the ones place.

Question 12

What is 500−137500 - 137?

  1. 363 (correct answer)
  2. 373
  3. 343
  4. 463
Explanation: Subtracting 137 from 500 gives 363. Choice B, 373, is off by a regrouping error. Choice C, 343, is also off due to a regrouping error. Choice D, 463, is much too large for this subtraction.

Question 13

Find the missing number: 347+?=633347 + ? = 633.

  1. 280
  2. 347
  3. 286 (correct answer)
  4. 633
Explanation: 633 minus 347 equals 286, so 286 is the missing number. 280 is close but 6 too low. 347 is one of the numbers already given in the problem, not the missing number. 633 is the total shown in the problem, not the amount being added.

Question 14

What is 352+489352 + 489?

  1. 831
  2. 841 (correct answer)
  3. 851
  4. 741
Explanation: Adding 352 and 489 gives 841. Choice A is off by 10 from a mistake carrying a regrouped ten. Choice C is off by 10 in the other direction. Choice D is off by 100 from a mistake regrouping the hundreds.

Question 15

What is 586−239586 - 239?

  1. 447
  2. 337
  3. 357
  4. 347 (correct answer)
Explanation: Subtracting 239 from 586 gives 347. Choice A is off by 100 from a mistake regrouping the hundreds. Choice B is off by 10 in the other direction. Choice C is off by 10 from an error in the tens place.

Question 16

Jamal had 912 marbles and gave away 485. How many are left?

  1. 427 (correct answer)
  2. 417
  3. 437
  4. 527
Explanation: Subtracting 485 from 912 leaves 427 marbles. Choice B is 10 less than the correct amount. Choice C is 10 more than the correct amount. Choice D comes from not regrouping correctly across place values.

Question 17

What number, minus 276276, equals 419419?

  1. 685
  2. 143
  3. 705
  4. 695 (correct answer)
Explanation: Since the missing number minus 276 equals 419, add back: 419+276=695419+276=695. Choice A is ten less than the correct sum. Choice B is what you get if you subtract instead of add (419−276=143419-276=143). Choice C is ten more than the correct sum.

Question 18

Solve: 803−467803 - 467.

  1. 336 (correct answer)
  2. 436
  3. 346
  4. 266
Explanation: Subtracting 467 from 803 with regrouping gives 336. Choice B, 436, comes from a borrowing error in the hundreds place. Choice C, 346, comes from a borrowing error in the tens place. Choice D, 266, comes from compounding regrouping mistakes across multiple place values.

Question 19

What is 478+256478 + 256?

  1. 624
  2. 734 (correct answer)
  3. 744
  4. 724
Explanation: Adding 478 and 256 gives 734. Choice A, 624, comes from a regrouping error in the hundreds place. Choice C, 744, comes from a carrying mistake that adds one too many. Choice D, 724, comes from a carrying mistake that adds one too few.

Question 20

The library had 563 books. 278 were checked out. How many books are left?

  1. 315
  2. 285 (correct answer)
  3. 841
  4. 345
Explanation: Subtracting the checked-out books from the total gives 563−278=285563 - 278 = 285, so B is correct. Choice A comes from a regrouping slip while subtracting across place values. Choice C comes from adding the two numbers instead of subtracting them. Choice D is a different regrouping slip that overstates how many books remain.