The phrase " times as long" tells you that we are going to multiply by .

Let's have represent how long it takes Sara to get dressed.

Think: minutes 4 times would be how many minutes?

The phrase " times as long" tells you that we are going to multiply by .

Let's have represent how long it takes Sara to get dressed.

Think: minutes 4 times would be how many minutes?

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 85 is the multiplier and 35 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 5 and 5

Then, we multiply 5 and 3 and add the 2 that was carried

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 8 and 5

Then, we multiply 8 and 3and add the 4 that was carried

Finally, we add the two products together to find our final answer

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 78 is the multiplier and 42 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 8 and 2

Then, we multiply 8 and 4 and add the 1 that was carried

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 7 and 2

Then, we multiply 7 and 4and add the 1 that was carried

Finally, we add the two products together to find our final answer

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 78 is the multiplier and 42 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 8 and 2

Then, we multiply 8 and 4 and add the 1 that was carried

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 7 and 2

Then, we multiply 7 and 4and add the 1 that was carried

Finally, we add the two products together to find our final answer

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 13 is the multiplier and 85 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 5

Then, we multiply 3 and 8 and add the 1 that was carried

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 1 and 5

Then, we multiply 1 and 8

Finally, we add the two products together to find our final answer

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 85 is the multiplier and 35 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 5 and 5

Then, we multiply 5 and 3 and add the 2 that was carried

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 8 and 5

Then, we multiply 8 and 3and add the 4 that was carried

Finally, we add the two products together to find our final answer

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 13 is the multiplier and 85 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 3 and 5

Then, we multiply 3 and 8 and add the 1 that was carried

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 1 and 5

Then, we multiply 1 and 8

Finally, we add the two products together to find our final answer

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 40 is the multiplier and 71 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 0 and 1

Then, we multiply 0 and 7

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 4 and 1

Then, we multiply 4 and 7

Finally, we add the two products together to find our final answer

In order to solve this problem using multiplication, we must multiply each digit of the multiplier by each digit of the multiplicand to get the answer, which is called the product.

For this problem, 40 is the multiplier and 71 is the multiplicand. We start with the multiplier, and multiply the digit in the ones place by each digit of the multiplicand.

First, we multiply 0 and 1

Then, we multiply 0 and 7

Now, we multiply the digit in the tens place of the multiplier by each digit of the multiplicand. In order to do this, we need to start a new line in our math problem and put a 0 as a place holder in the ones position.

Next, we multiply 4 and 1

Then, we multiply 4 and 7

Finally, we add the two products together to find our final answer