### All High School Math Resources

## Example Questions

### Example Question #7 : Quadrilaterals

The rectangular bathroom floor in Michael’s house is ten feet by twelve feet. He wants to purchase square tiles that are four inches long and four inches wide to cover the bathroom floor. If each square tile costs $2.50, how much money will Michael need to spend in order to purchase enough tiles to cover his entire bathroom floor?

**Possible Answers:**

$4800

$5400

$2700

$1080

$1920

**Correct answer:**

$2700

The dimensions for the bathroom are given in feet, but the dimensions of the tiles are given in inches; therefore, we need to convert the dimensions of the bathroom from feet to inches, because we can’t compare measurements easily unless we are using the same type of units.

Because there are twelve inches in a foot, we need to multiply the number of feet by twelve to convert from feet to inches.

10 feet = 10 x 12 inches = 120 inches

12 feet = 12 x 12 inches = 144 inches

This means that the bathroom floor is 120 inches by 144 inches. The area of Michael’s bathroom is therefore 120 x 144 in^{2} = 17280 in^{2}.

Now, we need to find the area of the tiles in square inches and calculate how many tiles it would take to cover 17280 in^{2}.

Each tile is 4 in by 4 in, so the area of each tile is 4 x 4 in^{2}, or 16 in^{2}.

If there are 17280 in^{2} to be covered, and each tile is 16 in^{2}, then the number of tiles we need is 17280 ÷ 16, which is 1080 tiles.

The question ultimately asks us for the cost of all these tiles; therefore, we need to multiply 1080 by 2.50, which is the price of each tile.

The total cost = 1080 x 2.50 dollars = 2700 dollars.

The answer is $2700.

### Example Question #8 : Quadrilaterals

Ron has a fixed length of wire that he uses to make a lot. On Monday, he uses the wire to make a rectangular lot. On Tuesday, he uses the same length of wire to form a square-shaped lot. Ron notices that the square lot has slightly more area, and he determines that the difference between the areas of the two lots is sixteen square units. What is the positive difference, in units, between the length and the width of the lot on Monday?

**Possible Answers:**

10

12

4

8

6

**Correct answer:**

8

Let’s say that the rectangular lot on Monday has a length of *l* and a width of *w*. The area of a rectangular is the product of the length and the width, so we can write the area of the lot on Monday as *lw*.

Next, we need to find an expression for the area of the lot on Tuesday. We are told that the lot is in the shape of a square and that it uses the same length of wire. If the length of the wire used is the same on both days, then the perimeter will have to remain the same. In other words, the perimeter of the square will equal the perimeter of the rectangle. The perimeter of a rectangle is given by 2*l* + 2*w*.

We also know that if *s* is the length of a side of a square, then the perimeter is 4*s*, because each side of the square is congruent. Let’s write an equation that sets the perimeter of the rectangle and the square equal.

2*l* + 2*w* = 4*s*

If we divide both sides by 4 and then simplify the expression, then we can write the length of the square as follows:

### Example Question #1 : How To Find The Area Of A Rectangle

A rectangle has a width of 2*x*. If the length is five more than 150% of the width, what is the area of the rectangle?

**Possible Answers:**

5*x* + 10

6*x*^{2} + 5

5*x* + 5

6*x*^{2} + 10*x*

10(*x* + 1)

**Correct answer:**

6*x*^{2} + 10*x*

Given that *w* = 2*x* and *l* = 1.5*w* + 5, a substitution will show that *l* = 1.5(2*x*) + 5 = 3*x* + 5.

*A* = *lw* = (3*x* + 5)(2*x*) = 6*x*^{2} + 10*x*

### Example Question #2 : How To Find The Area Of A Rectangle

Rectangle *ABCD* is shown in the figure above. Points *A* and *B* lie on the graph of *y* = 64 – *x*^{2} , and points *C* and *D* lie on the graph of *y* = *x*^{2} – 36. Segments *AD* and *BC* are both parallel to the *y*-axis. The *x*-coordinates of points *A* and *B* are equal to –*k* and *k*, respectively. If the value of *k* changes from 2 to 4, by how much will the area of rectangle *ABCD* increase?

**Possible Answers:**

88

544

272

176

352

**Correct answer:**

176

### Example Question #3 : How To Find The Area Of A Rectangle

George wants to paint the walls in his room blue. The ceilings are 10 ft tall and a carpet 12 ft by 15 ft covers the floor. One gallon of paint covers 400 and costs $40. One quart of paint covers 100 and costs $15. How much money will he spend on the blue paint?

**Possible Answers:**

**Correct answer:**

The area of the walls is given by

One gallon of paint covers 400 and the remaining 140 would be covered by two quarts.

So one gallon and two quarts of paint would cost

### Example Question #4 : How To Find The Area Of A Rectangle

Daisy gets new carpet for her rectangluar room. Her floor is . The carpet sells for $5 per square yard. How much did she spend on her carpet?

**Possible Answers:**

**Correct answer:**

Since the room measurements are 7 yards by 8 yards. The area of the floor is thus 56 square yards. It would cost .

### Example Question #5 : How To Find The Area Of A Rectangle

The length of a rectangular rug is five more than twice its width. The perimeter of the rug is 40 ft. What is the area of the rug?

**Possible Answers:**

**Correct answer:**

For a rectangle, and where is the width and is the length.

Let and .

So the equation to solve becomes or .

Thus and , so the area is .

### Example Question #1 : How To Find The Area Of A Rectangle

The length of a rectangle is 5 times its width. Its width is 3 inches long. What is the area of the rectangle in square inches?

**Possible Answers:**

**Correct answer:**45

The length is 5 x 3 = 15 inches. Multiplied by the width of 3 inches, yields 45 in^{2}.

### Example Question #2 : How To Find The Area Of A Rectangle

A rectangle’s base is twice its height. If the base is 8” long, what is the area of the rectangle?

**Possible Answers:**

12 in^{2}

32 in^{2}

16 in^{2}

64 in^{2}

24 in^{2}

**Correct answer:**

32 in^{2}

Rectangle

*B* = 2*H*

*B* = 8”

*H* = *B*/2 = 8/2 = 4”

Area = *B* x *H* = 8” X 4” = 32 in^{2}

### Example Question #3 : How To Find The Area Of A Rectangle

The length of a rectangle is two more than twice the width. The perimeter is 58ft. What is the area of the rectangle?

**Possible Answers:**

**Correct answer:**

For a rectangle, and , where is the length and is the width.

Let be equal to the width. We know that the length is equal to "two more than twice with width."

The equation to solve for the perimeter becomes .

Now that we know the width, we can solve for the length.

Now we can find the area using .

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