Use the square of a sum pattern, substituting for and for in the pattern:

or

Recall that the equation for compounded interest (with quarterly compounding) is:

Where is the balance, is the rate of interest, is the number of years, and is the number of times it is compounded per year.

Thus, for our data, we need to know:

This is approximately .

Start by simplifying the numerator and denominator separately. In the numerator, (c3)2 is equal to c6. In the denominator, c2 * c4 equals c6 as well. Dividing the numerator by the denominator, c6/c6, gives an answer of 1, because the numerator and the denominator are the equivalent.

If n=4, then 64(4/12)=64(1/3)=4. Then, 4=mŸ4(1+m)/(m+4). If 2 is substituted for m, then 4=2Ÿ4(1+2)/(2+4)=2Ÿ41/2=2Ÿ√4=2Ÿ2=4.

C is computing the exponent, while A and B are equivalent due to properties of fractional exponents.

Remember that...

When two variables with exponents are multiplied, you can simplify the expression by adding the exponents together. In this particular problem, the correct answer is found by adding the exponents 5 and 5, yielding .

C is computing the exponent, while A and B are equivalent due to properties of fractional exponents.

Remember that...

Use the square of a sum pattern, substituting for and for in the pattern:

or

Recall that the equation for compounded interest (with quarterly compounding) is:

Where is the balance, is the rate of interest, is the number of years, and is the number of times it is compounded per year.

Thus, for our data, we need to know:

This is approximately .

First, reduce all values to a common base using properties of exponents.

Plugging back into the equation-

Using the formula

We can reduce our equation to

So,