TACHS Quiz: Angle Relationships
2 questions · exam conditions
0:00
Angle RelationshipsQuestion 1 of 2

Refer to the figure. Two chords AB\overline{AB} and CD\overline{CD} of a circle intersect inside the circle at point PP. Arc ACAC (not containing BB or DD) measures 84°84° and arc BDBD (not containing AA or CC) measures 46°46°. What is the measure of APC\angle APC?

Question graphic
19°19°
38°38°
65°65°
130°130°
← Back to quizzes

TACHS Quiz

TACHS Quiz: Angle Relationships

Practice Angle Relationships in TACHS with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Angle Relationships, giving you a quick way to practice the rules, question types, and explanations that matter most for TACHS.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Refer to the figure. Two chords AB\overline{AB} and CD\overline{CD} of a circle intersect inside the circle at point PP. Arc ACAC (not containing BB or DD) measures 84°84° and arc BDBD (not containing AA or CC) measures 46°46°. What is the measure of APC\angle APC?

  1. 19°19°
  2. 38°38°
  3. 65°65° (correct answer)
  4. 130°130°
Explanation: The measure of an angle formed by two chords intersecting inside a circle equals half the sum of the intercepted arcs: APC=12(84°+46°)=12(130°)=65°\angle APC = \frac{1}{2}(84°+46°) = \frac{1}{2}(130°) = 65°. (A) 19°19° uses the external-angle formula (half the difference). (B) 38°38° is half of 76°76°, a miscalculation. (D) 130°130° is the sum of arcs without halving.

Question 2

In the figure, PA\overline{PA} is tangent to the circle at AA, and PBC\overline{PBC} is a secant passing through the circle, with BB closer to PP. If arc ACAC (far arc, not containing BB) =148°= 148° and arc ABAB (near arc, not containing CC) =62°= 62°, what is the measure of APC\angle APC?

  1. 43°43° (correct answer)
  2. 105°105°
  3. 86°86°
  4. 74°74°
Explanation: The angle formed by a tangent and a secant from an external point equals half the difference of the intercepted arcs: APC=12(far arcnear arc)=12(148°62°)=12(86°)=43°\angle APC = \frac{1}{2}(\text{far arc} - \text{near arc}) = \frac{1}{2}(148°-62°) = \frac{1}{2}(86°) = 43°. (B) 105°105° is half the sum. (C) 86°86° is the difference without halving. (D) 74°74° is half of 148°148°.