SSAT Upper Level Quantitative Quiz: Unit Conversions

7 questions · exam conditions

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Unit ConversionsQuestion 1 of 7

A fabric store sells ribbon by the yard, but a craft project requires 180 centimeters of ribbon. If ribbon costs $2.40 per yard, what is the minimum cost to buy enough ribbon? (1 inch = 2.54 centimeters, 1 yard = 36 inches)

$4.32

$4.80

$7.20

$432.00

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SSAT Upper Level Quantitative Quiz

SSAT Upper Level Quantitative Quiz: Unit Conversions

Practice Unit Conversions in SSAT Upper Level Quantitative with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Unit Conversions, giving you a quick way to practice the rules, question types, and explanations that matter most for SSAT Upper Level Quantitative.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

$4.32
$4.80 (correct answer)
$7.20
$432.00

Explanation: Convert 180 cm to inches: 180 ÷ 2.54 = 70.87 inches. Convert to yards: 70.87 ÷ 36 = 1.97 yards. Since ribbon is sold by the yard, need 2 yards minimum. Cost = 2 × $2.40 = $4.80. Choice A uses 1.8 yards. Choice C uses 3 yards. Choice D has decimal error.

Question 2

A pharmaceutical company produces liquid medicine in 250-milliliter bottles. If a patient needs to take 1.5 teaspoons three times daily, how many complete days will one bottle last? (1 teaspoon = 4.93 milliliters)

11 days (correct answer)
17 days
25 days
34 days

Explanation: Daily dosage: 1.5 tsp × 3 = 4.5 tsp/day. Convert to mL: 4.5 × 4.93 = 22.185 mL/day. Days = 250 ÷ 22.185 = 11.27, so 11 complete days. Choice B uses single dose calculation. Choice C forgets the 3-times-daily factor. Choice D has calculation errors.

Question 3

A weather station records that 2.8 inches of rain fell during a storm. If this rain were collected over a flat roof area of 1,500 square feet, how many gallons of water would be collected? (1 cubic foot = 7.48 gallons)

218 gallons
349 gallons
2,618 gallons (correct answer)
31,460 gallons

Explanation: This problem tests your ability to convert between different units of measurement and work with volume calculations. When you see questions involving rainfall collection, you're essentially calculating the volume of water by treating the rain as forming a rectangular prism over the collection area. To find the volume of collected water, you multiply the area by the depth. First, convert the rainfall depth to feet:

2.8 \text{ inches} \div 12 = 0.233\overline{3} \text{ feet}

. Then calculate the volume:

1,500 \text{ sq ft} \times 0.233\overline{3} \text{ ft} = 350 \text{ cubic feet}

. Finally, convert to gallons:

350 \text{ cubic feet} \times 7.48 \text{ gallons/cubic foot} = 2,620 \text{ gallons}

, which rounds to answer choice C) 2,618 gallons. Answer A) 218 gallons likely results from forgetting to convert inches to feet and using 2.8 feet directly as the depth. Answer B) 349 gallons represents the volume in cubic feet (350) without converting to gallons using the given conversion factor. Answer D) 31,460 gallons comes from using 2.8 inches as if it were 2.8 feet, then properly converting to gallons. When solving unit conversion problems, always write out each step clearly and double-check that you're using the correct units throughout. The key trap here is forgetting to convert inches to feet before calculating volume—rainfall is typically measured in inches, but area calculations for volume usually require consistent units like feet.

Question 4

A water tank holds 450 liters when full. If water flows out at a rate of 3.5 gallons per minute, how long will it take to empty a full tank? (1 gallon = 3.785 liters)

34.1 minutes (correct answer)
128.6 minutes
9.2 minutes
1,703.3 minutes

Explanation: Convert flow rate to liters: 3.5 gal/min × 3.785 L/gal = 13.25 L/min. Time = 450 L ÷ 13.25 L/min = 34.0 minutes. Choice B uses the original gallon rate with liters. Choice C divides incorrectly. Choice D multiplies instead of divides.

Question 5

A recipe calls for 2.5 cups of flour. If Sarah only has a measuring spoon that holds 2 tablespoons, how many scoops will she need? (1 cup = 16 tablespoons)

15 scoops
20 scoops (correct answer)
30 scoops
40 scoops

Explanation: Convert cups to tablespoons: 2.5 cups × 16 tbsp/cup = 40 tbsp total needed. Since each scoop is 2 tbsp: 40 ÷ 2 = 20 scoops. Choice A forgot to account for the 2-tablespoon capacity. Choice C multiplied instead of dividing by 2. Choice D is the total tablespoons, not scoops.

Question 6

A car's fuel efficiency is rated at 35 miles per gallon. If gasoline costs $4.20 per gallon, what is the cost per mile to operate this vehicle, expressed in cents?

8.3 cents per mile
147.0 cents per mile
14.7 cents per mile
12.0 cents per mile (correct answer)

Explanation: Unit rate problems like this one require you to convert between different units and rates systematically. When you see fuel efficiency and cost questions, you're looking to find cost per mile by combining the given rates. Start with what you know: the car gets 35 miles per gallon, and gas costs $4.20 per gallon. To find the cost per mile, you need to determine how much gas (and therefore how much money) is needed for one mile of driving. If the car travels 35 miles on 1 gallon, then for 1 mile it uses $

\frac{1}{35}

gallon. Since each gallon costs

4.20, the cost per mile is:

\frac{\$4.20}{35} = \$0.12

Converting to cents: $0.12 × 100 = 12.0 cents per mile. Looking at the wrong answers: Choice A (8.3 cents) likely comes from incorrectly using 35 ÷ 4.20 instead of 4.20 ÷ 35. Choice B (147.0 cents) results from multiplying 35 × 4.20 instead of dividing, giving the total cost for a full tank rather than cost per mile. Choice C (14.7 cents) appears to come from rounding errors or mixing up the decimal placement when converting 4.20 ÷ 35. For unit rate problems, always set up your division carefully: put the total cost in the numerator and the total distance in the denominator. Double-check that your final units make sense—here you want cents per mile, not miles per cent or total costs.

Question 7

A runner completes a 10-kilometer race in 42 minutes. What is the runner's average speed in miles per hour? (1 kilometer = 0.621 miles)

8.1 mph
14.3 mph
8.9 mph (correct answer)
5.3 mph

Explanation: Speed problems require converting units carefully and applying the distance-speed-time relationship. When you see different units in the question versus the answer choices, unit conversion is always your first priority. To find average speed, you need distance divided by time:

\text{Speed} = \frac{\text{Distance}}{\text{Time}}

. Here, you have 10 kilometers in 42 minutes, but the answer choices are in miles per hour, so you must convert both units. First, convert distance:

10 \text{ km} \times 0.621 \frac{\text{miles}}{\text{km}} = 6.21 \text{ miles}

Next, convert time:

42 \text{ minutes} \times \frac{1 \text{ hour}}{60 \text{ minutes}} = 0.7 \text{ hours}

Now calculate speed:

\frac{6.21 \text{ miles}}{0.7 \text{ hours}} = 8.87 \approx 8.9 \text{ mph}

Looking at the wrong answers: Choice A (8.1 mph) likely comes from a calculation error, possibly rounding incorrectly during the conversion steps. Choice B (14.3 mph) suggests using the original 10 km without converting to miles, then somehow manipulating the time incorrectly. Choice D (5.3 mph) appears to result from converting incorrectly in the opposite direction or making an error in the time conversion. For SSAT speed problems, always organize your work in three steps: identify what units you need, convert all measurements to those units, then apply the formula. Double-check that your final answer makes intuitive sense—a 10K in 42 minutes is a decent recreational pace, so around 9 mph is reasonable.