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Precalculus Quiz

Precalculus Quiz: Finding Components Of Vectors

Practice Finding Components Of Vectors in Precalculus with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

Question 1 / 20

0 of 20 answered

A robot moves along a path defined by vectors. It starts at S(1,4)S(1, 4)S(1,4) and moves to T(7,1)T(7, 1)T(7,1), then to U(−2,8)U(-2, 8)U(−2,8). What are the components of the vector that would take the robot directly from its starting position to its final position?

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What this quiz covers

This quiz focuses on Finding Components Of Vectors, giving you a quick way to practice the rules, question types, and explanations that matter most for Precalculus.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A robot moves along a path defined by vectors. It starts at S(1,4)S(1, 4)S(1,4) and moves to T(7,1)T(7, 1)T(7,1), then to U(−2,8)U(-2, 8)U(−2,8). What are the components of the vector that would take the robot directly from its starting position to its final position?

  1. (5,−3)(5, -3)(5,−3)
  2. (−3,4)(-3, 4)(−3,4) (correct answer)
  3. (6,−3)(6, -3)(6,−3)
  4. (−9,7)(-9, 7)(−9,7)

Explanation: When you see a vector problem involving multiple movements, focus on the net displacement—the single vector that connects the starting point directly to the final destination, regardless of the path taken. The robot starts at S(1,4)S(1, 4)S(1,4) and ends at U(−2,8)U(-2, 8)U(−2,8) after passing through point TTT. To find the displacement vector from start to finish, you subtract the starting coordinates from the ending coordinates: SU→=U−S=(−2,8)−(1,4)=(−3,4)\overrightarrow{SU} = U - S = (-2, 8) - (1, 4) = (-3, 4)SU=U−S=(−2,8)−(1,4)=(−3,4). This gives you the components of the vector that would take the robot directly from SSS to UUU. Looking at the wrong answers: Choice A, (5,−3)(5, -3)(5,−3), appears to be the vector from SSS to TTT with a sign error. Choice C, (6,−3)(6, -3)(6,−3), is actually the vector ST→=(7,1)−(1,4)=(6,−3)\overrightarrow{ST} = (7, 1) - (1, 4) = (6, -3)ST=(7,1)−(1,4)=(6,−3)—this only gets you to the intermediate point TTT, not the final destination. Choice D, (−9,7)(-9, 7)(−9,7), is the vector TU→=(−2,8)−(7,1)=(−9,7)\overrightarrow{TU} = (-2, 8) - (7, 1) = (-9, 7)TU=(−2,8)−(7,1)=(−9,7), which represents the second leg of the journey from TTT to UUU, not the complete displacement. The correct answer is B, (−3,4)(-3, 4)(−3,4). Study tip: For displacement problems, always work with initial and final positions only. The intermediate points are irrelevant for finding the net displacement vector. Remember: displacement equals final position minus initial position.

Question 2

The directed line segment from M(2,2)M(2, 2)M(2,2) to N(2,−4)N(2, -4)N(2,−4) represents a vector. Based on the coordinates, what is the component form of MN→\overrightarrow{MN}MN?

  1. ⟨0,6⟩\langle 0, 6\rangle⟨0,6⟩
  2. ⟨0,−6⟩\langle 0, -6\rangle⟨0,−6⟩ (correct answer)
  3. ⟨−6,0⟩\langle -6, 0\rangle⟨−6,0⟩
  4. ⟨2,−4⟩\langle 2, -4\rangle⟨2,−4⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. A directed line segment from point M to point N represents a vector whose components are the differences in coordinates: ⟨final x - initial x, final y - initial y⟩. Using the formula for components, we substitute the given coordinates: ⟨x₂ - x₁, y₂ - y₁⟩ = ⟨2 - 2, -4 - 2⟩ = ⟨0, -6⟩. Choice B is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨2 - 2, -4 - 2⟩ = ⟨0, -6⟩. Choice A reverses the subtraction order, calculating ⟨x₁ - x₂, y₁ - y₂⟩, which gives the opposite vector (same magnitude, opposite direction). The horizontal component 0 tells us the vector moves 0 units left/right, and the vertical component -6 tells us it moves 6 units down. Key to finding vector components: always subtract initial point from terminal point (terminal - initial), and remember that the first component is the change in x, the second is the change in y.

Question 3

Points AAA, BBB, and CCC form a triangle where A(−2,5)A(-2, 5)A(−2,5), B(3,−1)B(3, -1)B(3,−1), and C(1,7)C(1, 7)C(1,7). If AB⃗+BC⃗=AD⃗\vec{AB} + \vec{BC} = \vec{AD}AB+BC=AD, what are the coordinates of point DDD?

  1. (−1,6)(-1, 6)(−1,6)
  2. (6,1)(6, 1)(6,1)
  3. (2,11)(2, 11)(2,11)
  4. (1,7)(1, 7)(1,7) (correct answer)

Explanation: When you see vector addition problems involving triangles, remember that vectors represent both magnitude and direction, and they follow the head-to-tail rule for addition. First, let's find the vectors. AB⃗\vec{AB}AB goes from A(−2,5)A(-2, 5)A(−2,5) to B(3,−1)B(3, -1)B(3,−1), so AB⃗=(3−(−2),−1−5)=(5,−6)\vec{AB} = (3-(-2), -1-5) = (5, -6)AB=(3−(−2),−1−5)=(5,−6). Similarly, BC⃗\vec{BC}BC goes from B(3,−1)B(3, -1)B(3,−1) to C(1,7)C(1, 7)C(1,7), giving us BC⃗=(1−3,7−(−1))=(−2,8)\vec{BC} = (1-3, 7-(-1)) = (-2, 8)BC=(1−3,7−(−1))=(−2,8). Now we can find AD⃗\vec{AD}AD: AB⃗+BC⃗=(5,−6)+(−2,8)=(3,2)\vec{AB} + \vec{BC} = (5, -6) + (-2, 8) = (3, 2)AB+BC=(5,−6)+(−2,8)=(3,2). Since AD⃗=(3,2)\vec{AD} = (3, 2)AD=(3,2) and starts at A(−2,5)A(-2, 5)A(−2,5), point DDD is at (−2,5)+(3,2)=(1,7)(-2, 5) + (3, 2) = (1, 7)(−2,5)+(3,2)=(1,7). Notice something interesting: DDD has the same coordinates as point CCC! This makes geometric sense because AB⃗+BC⃗=AC⃗\vec{AB} + \vec{BC} = \vec{AC}AB+BC=AC by the triangle rule, so AD⃗=AC⃗\vec{AD} = \vec{AC}AD=AC, meaning DDD and CCC are the same point. Choice A (−1,6)(-1, 6)(−1,6) represents a common arithmetic error in vector addition. Choice B (6,1)(6, 1)(6,1) might come from incorrectly adding coordinates directly without proper vector subtraction. Choice C (2,11)(2, 11)(2,11) could result from sign errors or mixing up the order of operations. Strategy tip: In vector problems, always double-check that your final answer makes geometric sense. When vectors form a closed path (like AB⃗+BC⃗+CA⃗=0⃗\vec{AB} + \vec{BC} + \vec{CA} = \vec{0}AB+BC+CA=0), this often leads to elegant solutions where points coincide.

Question 4

A vector has initial point A(5,−1)A(5, -1)A(5,−1) and terminal point B(0,3)B(0, 3)B(0,3). For the vector described, what is the component form of AB→\overrightarrow{AB}AB?

  1. ⟨5,−4⟩\langle 5, -4 \rangle⟨5,−4⟩
  2. ⟨0,3⟩\langle 0, 3 \rangle⟨0,3⟩
  3. ⟨−5,4⟩\langle -5, 4 \rangle⟨−5,4⟩ (correct answer)
  4. ⟨−4,5⟩\langle -4, 5 \rangle⟨−4,5⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. To find vector components, calculate the change in x (horizontal displacement) and the change in y (vertical displacement) by subtracting initial from terminal: horizontal component = x₂ - x₁, vertical component = y₂ - y₁. Using the formula for components, we substitute the given coordinates: ⟨0 - 5, 3 - (-1)⟩ = ⟨-5, 4⟩. Choice C is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨0 - 5, 3 - (-1)⟩ = ⟨-5, 4⟩. Choice A reverses the subtraction order, calculating ⟨5 - 0, -1 - 3⟩, which gives the opposite vector (same magnitude, opposite direction). Remember that vector components are not the same as point coordinates—components represent displacement (change in position), while coordinates represent location. The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion.

Question 5

Point AAA is located at (0,3)(0, 3)(0,3) and point BBB is located at (5,3)(5, 3)(5,3). For the vector described, what is the component form of AB→\overrightarrow{AB}AB?

  1. ⟨5,0⟩\langle 5, 0\rangle⟨5,0⟩ (correct answer)
  2. ⟨−5,0⟩\langle -5, 0\rangle⟨−5,0⟩
  3. ⟨0,5⟩\langle 0, 5\rangle⟨0,5⟩
  4. ⟨5,3⟩\langle 5, 3\rangle⟨5,3⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. A directed line segment from point A to point B represents a vector whose components are the differences in coordinates: ⟨final x - initial x, final y - initial y⟩. The horizontal component 5 - 0 = 5 tells us the vector moves 5 units right, and the vertical component 3 - 3 = 0 tells us it moves 0 units up or down. Choice A is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨5 - 0, 3 - 3⟩ = ⟨5, 0⟩. Choice B reverses the subtraction order, calculating ⟨x₁ - x₂, y₁ - y₂⟩, which gives the opposite vector (same magnitude, opposite direction). Key to finding vector components: always subtract initial point from terminal point (terminal - initial), and remember that the first component is the change in x, the second is the change in y. Check your work by visualizing: if point B is to the right of point A, the horizontal component should be positive; if B is above A, the vertical component should be positive.

Question 6

Point AAA is located at (1,6)(1, 6)(1,6) and point BBB is located at (−3,2)(-3, 2)(−3,2). For the vector described, what is the component form of AB→\overrightarrow{AB}AB?

  1. ⟨−4,−4⟩\langle -4, -4\rangle⟨−4,−4⟩ (correct answer)
  2. ⟨4,4⟩\langle 4, 4\rangle⟨4,4⟩
  3. ⟨−3,2⟩\langle -3, 2\rangle⟨−3,2⟩
  4. ⟨−4,4⟩\langle -4, 4\rangle⟨−4,4⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. To find vector components, calculate the change in x (horizontal displacement) and the change in y (vertical displacement) by subtracting initial from terminal: horizontal component = x₂ - x₁, vertical component = y₂ - y₁. For a vector from A(1, 6) to B(-3, 2), we calculate the horizontal component as -3 - 1 = -4, and the vertical component as 2 - 6 = -4, giving us the component form ⟨-4, -4⟩. Choice A is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨-3 - 1, 2 - 6⟩ = ⟨-4, -4⟩. Choice B reverses the subtraction order, calculating ⟨x₁ - x₂, y₁ - y₂⟩, which gives the opposite vector (same magnitude, opposite direction). The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion. Remember that vector components are not the same as point coordinates—components represent displacement (change in position), while coordinates represent location.

Question 7

A vector has initial point A(5,−1)A(5, -1)A(5,−1) and terminal point B(0,3)B(0, 3)B(0,3). For the vector described, what is the component form of AB→\overrightarrow{AB}AB?​

  1. ⟨5,−4⟩\langle 5, -4 \rangle⟨5,−4⟩
  2. ⟨0,3⟩\langle 0, 3 \rangle⟨0,3⟩
  3. ⟨−5,4⟩\langle -5, 4 \rangle⟨−5,4⟩ (correct answer)
  4. ⟨−4,5⟩\langle -4, 5 \rangle⟨−4,5⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. To find vector components, calculate the change in x (horizontal displacement) and the change in y (vertical displacement) by subtracting initial from terminal: horizontal component = x₂ - x₁, vertical component = y₂ - y₁. Using the formula for components, we substitute the given coordinates: ⟨0 - 5, 3 - (-1)⟩ = ⟨-5, 4⟩. Choice C is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨0 - 5, 3 - (-1)⟩ = ⟨-5, 4⟩. Choice A reverses the subtraction order, calculating ⟨5 - 0, -1 - 3⟩, which gives the opposite vector (same magnitude, opposite direction). Remember that vector components are not the same as point coordinates—components represent displacement (change in position), while coordinates represent location. The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion.

Question 8

The directed line segment from M(7,−1)M(7, -1)M(7,−1) to N(2,4)N(2, 4)N(2,4) represents a vector. For the vector described, what is the component form?

  1. ⟨−5,5⟩\langle -5, 5 \rangle⟨−5,5⟩ (correct answer)
  2. ⟨5,−5⟩\langle 5, -5 \rangle⟨5,−5⟩
  3. ⟨2,4⟩\langle 2, 4 \rangle⟨2,4⟩
  4. ⟨9,3⟩\langle 9, 3 \rangle⟨9,3⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. To find vector components, calculate the change in x (horizontal displacement) and the change in y (vertical displacement) by subtracting initial from terminal: horizontal component = x₂ - x₁, vertical component = y₂ - y₁. For a vector from M(7, -1) to N(2, 4), we calculate the horizontal component as 2 - 7 = -5, and the vertical component as 4 - (-1) = 5, giving us the component form ⟨-5, 5⟩. Choice A is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨2 - 7, 4 - (-1)⟩ = ⟨-5, 5⟩. Choice B reverses the subtraction order, calculating ⟨x₁ - x₂, y₁ - y₂⟩, which gives the opposite vector (same magnitude, opposite direction). Check your work by visualizing: if point B is to the right of point A, the horizontal component should be positive; if B is above A, the vertical component should be positive. Key to finding vector components: always subtract initial point from terminal point (terminal - initial), and remember that the first component is the change in x, the second is the change in y.

Question 9

A vector has initial point A(−6,1)A(-6, 1)A(−6,1) and terminal point B(−2,7)B(-2, 7)B(−2,7). What is the component form of AB→\overrightarrow{AB}AB?

  1. ⟨4,6⟩\langle 4, 6 \rangle⟨4,6⟩ (correct answer)
  2. ⟨−4,−6⟩\langle -4, -6 \rangle⟨−4,−6⟩
  3. ⟨−2,7⟩\langle -2, 7 \rangle⟨−2,7⟩
  4. ⟨−8,8⟩\langle -8, 8 \rangle⟨−8,8⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. The component form of a vector from point A(x₁, y₁) to point B(x₂, y₂) is found by subtracting the initial point's coordinates from the terminal point's coordinates: ⟨x₂ - x₁, y₂ - y₁⟩. For a vector from A(-6, 1) to B(-2, 7), we calculate the horizontal component as -2 - (-6) = 4, and the vertical component as 7 - 1 = 6, giving us the component form ⟨4, 6⟩. Choice A is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨-2 - (-6), 7 - 1⟩ = ⟨4, 6⟩. Choice B reverses the subtraction order, calculating ⟨-6 - (-2), 1 - 7⟩, which gives the opposite vector (same magnitude, opposite direction). Key to finding vector components: always subtract initial point from terminal point (terminal - initial), and remember that the first component is the change in x, the second is the change in y. The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion.

Question 10

A surveyor measures the position of three landmarks. Landmark A is at (0,0)(0, 0)(0,0), landmark B is at (8,6)(8, 6)(8,6), and landmark C is at (5,−2)(5, -2)(5,−2). If a fourth landmark D is positioned such that AC⃗=2AD⃗\vec{AC} = 2\vec{AD}AC=2AD, what are the coordinates of landmark D?

  1. (5,−2)(5, -2)(5,−2)
  2. (10,−4)(10, -4)(10,−4)
  3. (2.5,−1)(2.5, -1)(2.5,−1) (correct answer)
  4. (−2.5,1)(-2.5, 1)(−2.5,1)

Explanation: When you encounter vector equations with landmarks or points, you're working with vector algebra where vectors represent displacements between points. The key insight is that AC⃗=2AD⃗\vec{AC} = 2\vec{AD}AC=2AD means vector AC⃗\vec{AC}AC is twice as long as vector AD⃗\vec{AD}AD in the same direction. First, find vector AC⃗\vec{AC}AC. Since A is at (0,0)(0,0)(0,0) and C is at (5,−2)(5,-2)(5,−2), we have AC⃗=(5−0,−2−0)=(5,−2)\vec{AC} = (5-0, -2-0) = (5, -2)AC=(5−0,−2−0)=(5,−2). Now use the given relationship AC⃗=2AD⃗\vec{AC} = 2\vec{AD}AC=2AD. This means AD⃗=12AC⃗=12(5,−2)=(2.5,−1)\vec{AD} = \frac{1}{2}\vec{AC} = \frac{1}{2}(5, -2) = (2.5, -1)AD=21​AC=21​(5,−2)=(2.5,−1). Since AD⃗\vec{AD}AD represents the displacement from A to D, and A is at the origin, the coordinates of D are simply (2.5,−1)(2.5, -1)(2.5,−1). Looking at the wrong answers: A) (5,−2)(5, -2)(5,−2) gives you the coordinates of point C, which happens when students confuse AC⃗\vec{AC}AC with the position of D. B) (10,−4)(10, -4)(10,−4) results from incorrectly thinking AD⃗=2AC⃗\vec{AD} = 2\vec{AC}AD=2AC instead of the given relationship. D) (−2.5,1)(-2.5, 1)(−2.5,1) comes from incorrectly applying the negative of the correct vector, possibly from confusion about vector direction. The correct answer is C) (2.5,−1)(2.5, -1)(2.5,−1). Strategy tip: When working with vector equations involving positions, always distinguish between vectors (displacements) and points (coordinates). Write out the vector components explicitly before applying any given relationships, and remember that if a vector starts at the origin, its components directly give the endpoint coordinates.

Question 11

For the vector from A(1,0)A(1, 0)A(1,0) to B(1,−5)B(1, -5)B(1,−5), what is the component form of AB→\overrightarrow{AB}AB?

  1. ⟨0,5⟩\langle 0, 5 \rangle⟨0,5⟩
  2. ⟨1,−5⟩\langle 1, -5 \rangle⟨1,−5⟩
  3. ⟨0,−5⟩\langle 0, -5 \rangle⟨0,−5⟩ (correct answer)
  4. ⟨−5,0⟩\langle -5, 0 \rangle⟨−5,0⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. A directed line segment from point A to point B represents a vector whose components are the differences in coordinates: ⟨final x - initial x, final y - initial y⟩. The horizontal component 1 - 1 = 0 tells us the vector moves 0 units left or right, and the vertical component -5 - 0 = -5 tells us it moves 5 units down. Choice C is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨1 - 1, -5 - 0⟩ = ⟨0, -5⟩. Choice A reverses the subtraction order, calculating ⟨1 - 1, 0 - (-5)⟩, which gives the opposite vector (same magnitude, opposite direction). To avoid errors, clearly label which point is initial and which is terminal, then methodically compute x₂ - x₁ for the horizontal component and y₂ - y₁ for the vertical component. The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion.

Question 12

A vector has initial point A(−3,4)A(-3, 4)A(−3,4) and terminal point B(2,−1)B(2, -1)B(2,−1). For the vector described, what is the component form of AB→\overrightarrow{AB}AB?

  1. ⟨2,−1⟩\langle 2, -1 \rangle⟨2,−1⟩
  2. ⟨5,−5⟩\langle 5, -5 \rangle⟨5,−5⟩ (correct answer)
  3. ⟨−5,5⟩\langle -5, 5 \rangle⟨−5,5⟩
  4. ⟨−1,4⟩\langle -1, 4 \rangle⟨−1,4⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. The component form of a vector from point A(x_1, y_1) to point B(x_2, y_2) is found by subtracting the initial point's coordinates from the terminal point's coordinates: ⟨x2−x1,y2−y1⟩\langle x_2 - x_1, y_2 - y_1 \rangle⟨x2​−x1​,y2​−y1​⟩. For a vector from A(-3, 4) to B(2, -1), we calculate the horizontal component as 2−(−3)=52 - (-3) = 52−(−3)=5, and the vertical component as −1−4=−5-1 - 4 = -5−1−4=−5, giving us the component form ⟨5,−5⟩\langle 5, -5 \rangle⟨5,−5⟩. Choice B is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨2−(−3),−1−4⟩=⟨5,−5⟩\langle 2 - (-3), -1 - 4 \rangle = \langle 5, -5 \rangle⟨2−(−3),−1−4⟩=⟨5,−5⟩. Choice A reverses the subtraction order, calculating ⟨−3−2,4−(−1)⟩\langle -3 - 2, 4 - (-1) \rangle⟨−3−2,4−(−1)⟩, which gives the opposite vector (same magnitude, opposite direction). Key to finding vector components: always subtract initial point from terminal point (terminal - initial), and remember that the first component is the change in x, the second is the change in y. To avoid errors, clearly label which point is initial and which is terminal, then methodically compute x_2 - x_1 for the horizontal component and y_2 - y_1 for the vertical component.

Question 13

Given points A(−1,2)A(-1, 2)A(−1,2) and B(2,−4)B(2, -4)B(2,−4), what is the component form of vector AB→\overrightarrow{AB}AB?

  1. ⟨3,6⟩\langle 3, 6 \rangle⟨3,6⟩
  2. ⟨1,−2⟩\langle 1, -2 \rangle⟨1,−2⟩
  3. ⟨3,−6⟩\langle 3, -6 \rangle⟨3,−6⟩ (correct answer)
  4. ⟨−3,−6⟩\langle -3, -6 \rangle⟨−3,−6⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. The component form of a vector from point A(x₁, y₁) to point B(x₂, y₂) is found by subtracting the initial point's coordinates from the terminal point's coordinates: ⟨x₂ - x₁, y₂ - y₁⟩. Using the formula for components, we substitute the given coordinates: ⟨2 - (-1), -4 - 2⟩ = ⟨2 + 1, -4 - 2⟩ = ⟨3, -6⟩. Choice C is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨2 - (-1), -4 - 2⟩ = ⟨3, -6⟩. Choice D reverses the subtraction order, calculating ⟨x₁ - x₂, y₁ - y₂⟩, which gives the opposite vector (same magnitude, opposite direction). Remember that vector components are not the same as point coordinates—components represent displacement (change in position), while coordinates represent location. The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion.

Question 14

Based on the coordinates, if the initial point is A(−4,0)A(-4, 0)A(−4,0) and the terminal point is B(3,5)B(3, 5)B(3,5), what are the vector components of the vector from AAA to BBB?

  1. ⟨7,5⟩\langle 7, 5 \rangle⟨7,5⟩ (correct answer)
  2. ⟨−7,−5⟩\langle -7, -5 \rangle⟨−7,−5⟩
  3. ⟨−1,5⟩\langle -1, 5 \rangle⟨−1,5⟩
  4. ⟨3,5⟩\langle 3, 5 \rangle⟨3,5⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. A directed line segment from point A to point B represents a vector whose components are the differences in coordinates: ⟨final x - initial x, final y - initial y⟩. The horizontal component 3 - (-4) = 7 tells us the vector moves 7 units right, and the vertical component 5 - 0 = 5 tells us it moves 5 units up. Choice A is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨3 - (-4), 5 - 0⟩ = ⟨7, 5⟩. Choice B reverses the subtraction order, calculating ⟨x₁ - x₂, y₁ - y₂⟩, which gives the opposite vector (same magnitude, opposite direction). Key to finding vector components: always subtract initial point from terminal point (terminal - initial), and remember that the first component is the change in x, the second is the change in y. To avoid errors, clearly label which point is initial and which is terminal, then methodically compute x₂ - x₁ for the horizontal component and y₂ - y₁ for the vertical component.

Question 15

Given points A(3,−4)A(3, -4)A(3,−4) and B(−1,2)B(-1, 2)B(−1,2), what are the components of the vector from AAA to BBB?

  1. ⟨−1,2⟩\langle -1, 2 \rangle⟨−1,2⟩
  2. ⟨2,−1⟩\langle 2, -1 \rangle⟨2,−1⟩
  3. ⟨−4,6⟩\langle -4, 6 \rangle⟨−4,6⟩ (correct answer)
  4. ⟨4,−6⟩\langle 4, -6 \rangle⟨4,−6⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. To find vector components, calculate the change in x (horizontal displacement) and the change in y (vertical displacement) by subtracting initial from terminal: horizontal component = x₂ - x₁, vertical component = y₂ - y₁. Using the formula for components, we substitute the given coordinates: ⟨-1 - 3, 2 - (-4)⟩ = ⟨-4, 6⟩. Choice C is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨-1 - 3, 2 - (-4)⟩ = ⟨-4, 6⟩. Choice D reverses the subtraction order, calculating ⟨3 - (-1), -4 - 2⟩, which gives the opposite vector (same magnitude, opposite direction). Remember that vector components are not the same as point coordinates—components represent displacement (change in position), while coordinates represent location. The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion.

Question 16

A vector v⃗\vec{v}v has initial point P(2,−3)P(2, -3)P(2,−3) and terminal point Q(7,1)Q(7, 1)Q(7,1). If this vector is translated so that its initial point becomes R(−1,4)R(-1, 4)R(−1,4), what are the coordinates of the new terminal point?

  1. (4,8)(4, 8)(4,8) (correct answer)
  2. (6,0)(6, 0)(6,0)
  3. (−6,0)(-6, 0)(−6,0)
  4. (8,−7)(8, -7)(8,−7)

Explanation: First, find the components of vector v⃗\vec{v}v: v⃗=(7−2,1−(−3))=(5,4)\vec{v} = (7-2, 1-(-3)) = (5, 4)v=(7−2,1−(−3))=(5,4). When a vector is translated, its components remain the same. If the new initial point is R(−1,4)R(-1, 4)R(−1,4) and the vector components are (5,4)(5, 4)(5,4), then the new terminal point is (−1+5,4+4)=(4,8)(-1+5, 4+4) = (4, 8)(−1+5,4+4)=(4,8). Choice B incorrectly uses the original terminal point coordinates. Choice C represents the negative of the correct displacement. Choice D results from subtracting instead of adding the components.

Question 17

An object moves from position (2,2)(2, 2)(2,2) to position (−3,6)(-3, 6)(−3,6) in the coordinate plane. Which vector correctly represents the displacement from the initial point to the terminal point?​

  1. ⟨5,−4⟩\langle 5, -4 \rangle⟨5,−4⟩
  2. ⟨−5,4⟩\langle -5, 4 \rangle⟨−5,4⟩ (correct answer)
  3. ⟨−1,8⟩\langle -1, 8 \rangle⟨−1,8⟩
  4. ⟨−3,6⟩\langle -3, 6 \rangle⟨−3,6⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. To find vector components, calculate the change in x (horizontal displacement) and the change in y (vertical displacement) by subtracting initial from terminal: horizontal component = x₂ - x₁, vertical component = y₂ - y₁. Using the formula for components, we substitute the given coordinates: ⟨-3 - 2, 6 - 2⟩ = ⟨-5, 4⟩. Choice B is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨-3 - 2, 6 - 2⟩ = ⟨-5, 4⟩. Choice A reverses the subtraction order, calculating ⟨2 - (-3), 2 - 6⟩, which gives the opposite vector (same magnitude, opposite direction). Remember that vector components are not the same as point coordinates—components represent displacement (change in position), while coordinates represent location. Check your work by visualizing: if point B is to the right of point A, the horizontal component should be positive; if B is above A, the vertical component should be positive.

Question 18

Point AAA is located at (1,−5)(1, -5)(1,−5) and point BBB is located at (4,−1)(4, -1)(4,−1). For the vector described, what is the component form of AB→\overrightarrow{AB}AB?

  1. ⟨3,4⟩\langle 3, 4 \rangle⟨3,4⟩ (correct answer)
  2. ⟨−3,−4⟩\langle -3, -4 \rangle⟨−3,−4⟩
  3. ⟨5,−6⟩\langle 5, -6 \rangle⟨5,−6⟩
  4. ⟨4,−1⟩\langle 4, -1 \rangle⟨4,−1⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. To find vector components, calculate the change in x (horizontal displacement) and the change in y (vertical displacement) by subtracting initial from terminal: horizontal component = x₂ - x₁, vertical component = y₂ - y₁. The horizontal component 4 - 1 = 3 tells us the vector moves 3 units right, and the vertical component -1 - (-5) = 4 tells us it moves 4 units up. Choice A is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨4 - 1, -1 - (-5)⟩ = ⟨3, 4⟩. Choice B reverses the subtraction order, calculating ⟨1 - 4, -5 - (-1)⟩, which gives the opposite vector (same magnitude, opposite direction). Remember that vector components are not the same as point coordinates—components represent displacement (change in position), while coordinates represent location. The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion.

Question 19

A vector has initial point A(1,6)A(1, 6)A(1,6) and terminal point B(1,−2)B(1, -2)B(1,−2). For the vector described, what is the component form of AB→\overrightarrow{AB}AB?

  1. ⟨0,8⟩\langle 0, 8 \rangle⟨0,8⟩
  2. ⟨0,−8⟩\langle 0, -8 \rangle⟨0,−8⟩ (correct answer)
  3. ⟨2,4⟩\langle 2, 4 \rangle⟨2,4⟩
  4. ⟨1,−2⟩\langle 1, -2 \rangle⟨1,−2⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. To find vector components, calculate the change in x (horizontal displacement) and the change in y (vertical displacement) by subtracting initial from terminal: horizontal component = x₂ - x₁, vertical component = y₂ - y₁. For a vector from A(1, 6) to B(1, -2), we calculate the horizontal component as 1 - 1 = 0, and the vertical component as -2 - 6 = -8, giving us the component form ⟨0, -8⟩. Choice B is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨1 - 1, -2 - 6⟩ = ⟨0, -8⟩. Choice A reverses the subtraction order, calculating ⟨x₁ - x₂, y₁ - y₂⟩, which gives the opposite vector (same magnitude, opposite direction). The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion. Check your work by visualizing: if point B is to the right of point A, the horizontal component should be positive; if B is above A, the vertical component should be positive.

Question 20

The directed line segment from P(5,0)P(5, 0)P(5,0) to Q(−1,3)Q(-1, 3)Q(−1,3) represents vector v⃗\vec{v}v. Based on the coordinates, what are the components of v⃗\vec{v}v?

  1. ⟨4,3⟩\langle 4, 3\rangle⟨4,3⟩
  2. ⟨−6,3⟩\langle -6, 3\rangle⟨−6,3⟩ (correct answer)
  3. ⟨6,−3⟩\langle 6, -3\rangle⟨6,−3⟩
  4. ⟨−1,3⟩\langle -1, 3\rangle⟨−1,3⟩

Explanation: This question tests understanding of how to find vector components by subtracting the coordinates of the initial point from the coordinates of the terminal point. To find vector components, calculate the change in x (horizontal displacement) and the change in y (vertical displacement) by subtracting initial from terminal: horizontal component = x₂ - x₁, vertical component = y₂ - y₁. For a vector from P(5, 0) to Q(-1, 3), we calculate the horizontal component as -1 - 5 = -6, and the vertical component as 3 - 0 = 3, giving us the component form ⟨-6, 3⟩. Choice B is correct because it properly subtracts the initial point coordinates from the terminal point coordinates: ⟨-1 - 5, 3 - 0⟩ = ⟨-6, 3⟩. Choice C reverses the subtraction order, calculating ⟨x₁ - x₂, y₁ - y₂⟩, which gives the opposite vector (same magnitude, opposite direction). Key to finding vector components: always subtract initial point from terminal point (terminal - initial), and remember that the first component is the change in x, the second is the change in y. The negative sign in a component is meaningful: negative horizontal component means leftward motion, negative vertical component means downward motion.