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Precalculus Quiz

Precalculus Quiz: Add Vectors In Different Ways

Practice Add Vectors In Different Ways in Precalculus with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

Question 1 / 20

0 of 20 answered

Vectors u⃗=⟨3,−2⟩\vec{u} = \langle 3, -2 \rangleu=⟨3,−2⟩ and v⃗=⟨−1,4⟩\vec{v} = \langle -1, 4 \ranglev=⟨−1,4⟩ are added using the parallelogram rule. If the parallelogram has vertices at the origin, point PPP, point QQQ, and point RRR, where OP⃗=u⃗\vec{OP} = \vec{u}OP=u and OQ⃗=v⃗\vec{OQ} = \vec{v}OQ​=v, what are the coordinates of vertex RRR?

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What this quiz covers

This quiz focuses on Add Vectors In Different Ways, giving you a quick way to practice the rules, question types, and explanations that matter most for Precalculus.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Vectors u⃗=⟨3,−2⟩\vec{u} = \langle 3, -2 \rangleu=⟨3,−2⟩ and v⃗=⟨−1,4⟩\vec{v} = \langle -1, 4 \ranglev=⟨−1,4⟩ are added using the parallelogram rule. If the parallelogram has vertices at the origin, point PPP, point QQQ, and point RRR, where OP⃗=u⃗\vec{OP} = \vec{u}OP=u and OQ⃗=v⃗\vec{OQ} = \vec{v}OQ​=v, what are the coordinates of vertex RRR?

  1. R=(2,2)R = (2, 2)R=(2,2), representing the sum u⃗+v⃗\vec{u} + \vec{v}u+v (correct answer)
  2. R=(4,−6)R = (4, -6)R=(4,−6), representing the difference u⃗−v⃗\vec{u} - \vec{v}u−v
  3. R=(−4,6)R = (-4, 6)R=(−4,6), representing the difference v⃗−u⃗\vec{v} - \vec{u}v−u
  4. R=(3,4)R = (3, 4)R=(3,4), representing the diagonal of the parallelogram

Explanation: In the parallelogram rule, if we place vectors u⃗\vec{u}u and v⃗\vec{v}v at the origin with endpoints at P(3,−2)P(3, -2)P(3,−2) and Q(−1,4)Q(-1, 4)Q(−1,4), then the fourth vertex RRR completes the parallelogram. Since OR⃗=OP⃗+OQ⃗=u⃗+v⃗\vec{OR} = \vec{OP} + \vec{OQ} = \vec{u} + \vec{v}OR=OP+OQ​=u+v, we have R=(3+(−1),−2+4)=(2,2)R = (3 + (-1), -2 + 4) = (2, 2)R=(3+(−1),−2+4)=(2,2). Choice B incorrectly subtracts the vectors. Choice C gives the wrong order of subtraction. Choice D incorrectly uses individual components rather than vector addition.

Question 2

Two forces F1⃗=⟨8,6⟩\vec{F_1} = \langle 8, 6 \rangleF1​​=⟨8,6⟩ and F2⃗=⟨−3,4⟩\vec{F_2} = \langle -3, 4 \rangleF2​​=⟨−3,4⟩ act on an object. The magnitude of the resultant force is closest to which value?

  1. 151515 units, obtained by adding the individual magnitudes
  2. 555 units, obtained by subtracting the smaller from larger magnitude
  3. 10.810.810.8 units, obtained by component-wise addition then magnitude calculation (correct answer)
  4. 7.27.27.2 units, obtained by averaging the two individual magnitudes

Explanation: The resultant force is F1⃗+F2⃗=⟨8−3,6+4⟩=⟨5,10⟩\vec{F_1} + \vec{F_2} = \langle 8-3, 6+4 \rangle = \langle 5, 10 \rangleF1​​+F2​​=⟨8−3,6+4⟩=⟨5,10⟩. Its magnitude is 52+102=125≈10.8\sqrt{5^2 + 10^2} = \sqrt{125} \approx 10.852+102​=125​≈10.8. Choice A incorrectly adds magnitudes: ∣F1⃗∣+∣F2⃗∣=10+5=15|\vec{F_1}| + |\vec{F_2}| = 10 + 5 = 15∣F1​​∣+∣F2​​∣=10+5=15. Choice B incorrectly subtracts magnitudes. Choice D incorrectly averages the magnitudes. This demonstrates that the magnitude of a sum is typically not the sum of magnitudes.

Question 3

Two vectors p⃗\vec{p}p​ and q⃗\vec{q}q​ have magnitudes ∣p⃗∣=7|\vec{p}| = 7∣p​∣=7 and ∣q⃗∣=3|\vec{q}| = 3∣q​∣=3. The angle between them is 120°120°120°. If a student incorrectly calculates the magnitude of p⃗+q⃗\vec{p} + \vec{q}p​+q​ as 101010, what conceptual error did they make?

  1. They computed the magnitude of the difference p⃗−q⃗\vec{p} - \vec{q}p​−q​ instead of the sum
  2. They used the wrong formula, applying ∣p⃗+q⃗∣2=∣p⃗∣2−∣q⃗∣2+2∣p⃗∣∣q⃗∣cos⁡(120°)|\vec{p} + \vec{q}|^2 = |\vec{p}|^2 - |\vec{q}|^2 + 2|\vec{p}||\vec{q}|\cos(120°)∣p​+q​∣2=∣p​∣2−∣q​∣2+2∣p​∣∣q​∣cos(120°)
  3. They calculated the magnitude using 120°120°120° instead of its supplement 60°60°60°
  4. They added the magnitudes directly, ignoring the angle between the vectors entirely (correct answer)

Explanation: When finding the magnitude of a vector sum, you need to account for both the magnitudes of the individual vectors AND the angle between them. This isn't simple arithmetic addition. The correct approach uses the law of cosines for vectors: ∣p⃗+q⃗∣2=∣p⃗∣2+∣q⃗∣2+2∣p⃗∣∣q⃗∣cos⁡(θ)|\vec{p} + \vec{q}|^2 = |\vec{p}|^2 + |\vec{q}|^2 + 2|\vec{p}||\vec{q}|\cos(\theta)∣p​+q​∣2=∣p​∣2+∣q​∣2+2∣p​∣∣q​∣cos(θ). With ∣p⃗∣=7|\vec{p}| = 7∣p​∣=7, ∣q⃗∣=3|\vec{q}| = 3∣q​∣=3, and θ=120°\theta = 120°θ=120°: ∣p⃗+q⃗∣2=72+32+2(7)(3)cos⁡(120°)=49+9+42(−12)=58−21=37|\vec{p} + \vec{q}|^2 = 7^2 + 3^2 + 2(7)(3)\cos(120°) = 49 + 9 + 42(-\frac{1}{2}) = 58 - 21 = 37∣p​+q​∣2=72+32+2(7)(3)cos(120°)=49+9+42(−21​)=58−21=37 So ∣p⃗+q⃗∣=37≈6.08|\vec{p} + \vec{q}| = \sqrt{37} \approx 6.08∣p​+q​∣=37​≈6.08, not 10. Looking at the incorrect answer of 10: this equals 7+37 + 37+3, which reveals the error. Choice D correctly identifies that the student simply added the magnitudes directly (∣p⃗∣+∣q⃗∣=7+3=10|\vec{p}| + |\vec{q}| = 7 + 3 = 10∣p​∣+∣q​∣=7+3=10), completely ignoring the angle between the vectors. Choice A is wrong because ∣p⃗−q⃗∣=37|\vec{p} - \vec{q}| = \sqrt{37}∣p​−q​∣=37​ as well (the cosine term has the same result). Choice B describes an impossible formula with subtraction instead of addition. Choice C suggests using 60°60°60° instead of 120°120°120°, but this would give ∣p⃗+q⃗∣=79≈8.89|\vec{p} + \vec{q}| = \sqrt{79} \approx 8.89∣p​+q​∣=79​≈8.89, not 10. Remember: Vector addition is NOT scalar addition. When vectors aren't parallel, their magnitudes don't simply add. Always use the vector addition formula that incorporates the angle between them.

Question 4

For vectors u=⟨2,0⟩\mathbf{u}=\langle 2,0\rangleu=⟨2,0⟩ and v=⟨0,2⟩\mathbf{v}=\langle 0,2\ranglev=⟨0,2⟩, how does ∥u+v∥\lVert \mathbf{u}+\mathbf{v} \rVert∥u+v∥ compare to ∥u∥+∥v∥\lVert \mathbf{u} \rVert + \lVert \mathbf{v} \rVert∥u∥+∥v∥?

  1. ∥u+v∥>∥u∥+∥v∥\lVert \mathbf{u}+\mathbf{v} \rVert > \lVert \mathbf{u} \rVert + \lVert \mathbf{v} \rVert∥u+v∥>∥u∥+∥v∥
  2. ∥u+v∥=∥u∥+∥v∥\lVert \mathbf{u}+\mathbf{v} \rVert = \lVert \mathbf{u} \rVert + \lVert \mathbf{v} \rVert∥u+v∥=∥u∥+∥v∥
  3. ∥u+v∥<∥u∥+∥v∥\lVert \mathbf{u}+\mathbf{v} \rVert < \lVert \mathbf{u} \rVert + \lVert \mathbf{v} \rVert∥u+v∥<∥u∥+∥v∥ (correct answer)
  4. ∥u+v∥\lVert \mathbf{u}+\mathbf{v} \rVert∥u+v∥ cannot be compared to ∥u∥+∥v∥\lVert \mathbf{u} \rVert + \lVert \mathbf{v} \rVert∥u∥+∥v∥ without a calculator

Explanation: This question tests understanding of the relationship between vector magnitude and vector addition. An important property of vector addition is that the magnitude of the sum is typically not equal to the sum of the magnitudes: |u + v| ≤ |u| + |v|, with equality only when the vectors point in exactly the same direction. For vectors u = ⟨2, 0⟩ and v = ⟨0, 2⟩, we first compute u + v = ⟨2 + 0, 0 + 2⟩ = ⟨2, 2⟩. Computing |u + v| requires calculating √(2² + 2²) = √8 = 2√2 ≈ 2.83, which is less than |u| + |v| = 2 + 2 = 4. Choice C is correct because |u + v| = 2√2 < 4 = |u| + |v|, since the vectors are perpendicular (one points east, one points north) rather than in the same direction. Choice B incorrectly assumes that |u + v| = |u| + |v|, but vector magnitude addition doesn't work this way—the magnitude of a sum depends on the angle between the vectors. Remember that |u + v| ≠ |u| + |v| in general: the magnitude of a vector sum depends on both the magnitudes and the angle between the vectors, reaching its maximum (|u| + |v|) only when vectors point the same direction.

Question 5

Based on the description, u\mathbf{u}u is 333 units east and v\mathbf{v}v is 444 units north (so u=⟨3,0⟩\mathbf{u}=\langle 3,0\rangleu=⟨3,0⟩ and v=⟨0,4⟩\mathbf{v}=\langle 0,4\ranglev=⟨0,4⟩). How does ∥u+v∥\lVert \mathbf{u}+\mathbf{v} \rVert∥u+v∥ compare to ∥u∥+∥v∥\lVert \mathbf{u} \rVert+\lVert \mathbf{v} \rVert∥u∥+∥v∥?​

  1. ∥u+v∥=∥u∥+∥v∥\lVert \mathbf{u}+\mathbf{v} \rVert = \lVert \mathbf{u} \rVert+\lVert \mathbf{v} \rVert∥u+v∥=∥u∥+∥v∥
  2. ∥u+v∥>∥u∥+∥v∥\lVert \mathbf{u}+\mathbf{v} \rVert > \lVert \mathbf{u} \rVert+\lVert \mathbf{v} \rVert∥u+v∥>∥u∥+∥v∥
  3. ∥u+v∥<∥u∥+∥v∥\lVert \mathbf{u}+\mathbf{v} \rVert < \lVert \mathbf{u} \rVert+\lVert \mathbf{v} \rVert∥u+v∥<∥u∥+∥v∥ (correct answer)
  4. ∥u+v∥=∥u∥−∥v∥\lVert \mathbf{u}+\mathbf{v} \rVert = \lVert \mathbf{u} \rVert-\lVert \mathbf{v} \rVert∥u+v∥=∥u∥−∥v∥

Explanation: This question tests understanding of vector addition using multiple methods, focusing on the magnitude relationship. An important property of vector addition is that the magnitude of the sum is typically not equal to the sum of the magnitudes: |u + v| ≤ |u| + |v|, with equality only when the vectors point in exactly the same direction. Computing |u + v| requires first finding the components of the sum ⟨3, 4⟩, then calculating √(3² + 4²) = 5, which is less than |u| + |v| = 3 + 4 = 7. Choice C is correct because it properly applies the formula with specific values. Choice A incorrectly assumes that |u + v| = |u| + |v|, but vector magnitude addition doesn't work this way—the magnitude of a sum depends on the angle between the vectors. Remember that |u + v| ≠ |u| + |v| in general: the magnitude of a vector sum depends on both the magnitudes and the angle between the vectors, reaching its maximum (|u| + |v|) only when vectors point the same direction. All three methods (component-wise, end-to-end, parallelogram) give the same result because they're equivalent ways of representing the same mathematical operation—choose the method that best fits the context or presentation.

Question 6

A drone moves according to three displacement vectors: v1⃗=⟨6,0⟩\vec{v_1} = \langle 6, 0 \ranglev1​​=⟨6,0⟩ m, v2⃗=⟨0,8⟩\vec{v_2} = \langle 0, 8 \ranglev2​​=⟨0,8⟩ m, and v3⃗=⟨−6,0⟩\vec{v_3} = \langle -6, 0 \ranglev3​​=⟨−6,0⟩ m. Using the end-to-end method, what is the magnitude of the total displacement after all three moves?

  1. 202020 m, obtained by adding all three individual displacement magnitudes together
  2. 888 m, since the horizontal components cancel and only vertical displacement remains (correct answer)
  3. 101010 m, obtained by using the Pythagorean theorem on the original triangle
  4. 000 m, since the drone returns to its original horizontal position

Explanation: When working with vector displacement problems, you need to understand that the end-to-end method means adding vectors component-wise to find the resultant vector, then calculating its magnitude. Let's add the three displacement vectors component by component:

  • x-components: 6+0+(−6)=06 + 0 + (-6) = 06+0+(−6)=0
  • y-components: 0+8+0=80 + 8 + 0 = 80+8+0=8
The resultant displacement vector is ⟨0,8⟩\langle 0, 8 \rangle⟨0,8⟩ m. The magnitude of this vector is simply 02+82=8\sqrt{0^2 + 8^2} = 802+82​=8 m. Since the horizontal components completely cancel out (+6+6+6 and −6-6−6), only the vertical displacement of 888 m remains. Choice A incorrectly adds the magnitudes of individual vectors (6+8+6=206 + 8 + 6 = 206+8+6=20) rather than using vector addition. You can't just add magnitudes when vectors point in different directions. Choice C mentions using the Pythagorean theorem on "the original triangle," but this doesn't make sense in the context of sequential displacements. While 62+82=10\sqrt{6^2 + 8^2} = 1062+82​=10 would be correct for finding the hypotenuse of a right triangle with legs 6 and 8, it doesn't apply to this step-by-step motion. Choice D incorrectly focuses only on horizontal position, ignoring that the drone moved vertically and stayed there. Returning to the original horizontal position doesn't mean zero total displacement. Study tip: For vector problems, always work component-wise first. Add all x-components together, add all y-components together, then find the magnitude of the resulting vector. Don't add individual magnitudes unless all vectors point in the same direction.

Question 7

For vectors u=⟨3,4⟩\mathbf{u}=\langle 3,4\rangleu=⟨3,4⟩ and v=⟨−1,2⟩\mathbf{v}=\langle -1,2\ranglev=⟨−1,2⟩, using component-wise addition, what is u+v\mathbf{u}+\mathbf{v}u+v (in component form)?​​

  1. ⟨2,6⟩\langle 2,6\rangle⟨2,6⟩ (correct answer)
  2. ⟨4,2⟩\langle 4,2\rangle⟨4,2⟩
  3. ⟨−3,8⟩\langle -3,8\rangle⟨−3,8⟩
  4. ⟨−3,2⟩\langle -3,2\rangle⟨−3,2⟩

Explanation: This question tests understanding of vector addition using the component-wise method. Vectors are added component-wise: for u = ⟨u₁, u₂⟩ and v = ⟨v₁, v₂⟩, the sum u + v = ⟨u₁ + v₁, u₂ + v₂⟩, meaning we add the horizontal components together and the vertical components together separately. For vectors u = ⟨3, 4⟩ and v = ⟨-1, 2⟩, we compute u + v = ⟨3 + (-1), 4 + 2⟩ = ⟨2, 6⟩. Choice A is correct because it shows the component-wise calculation. Choice C multiplies corresponding components together instead of adding them, computing ⟨3*(-1), 4*2⟩ = ⟨-3, 8⟩, which is not a standard vector operation. Key to vector addition: when using component form, add x-components together and y-components together separately—treat each component independently, like combining horizontal and vertical motions. All three methods (component-wise, end-to-end, parallelogram) give the same result because they're equivalent ways of representing the same mathematical operation—choose the method that best fits the context or presentation.

Question 8

For vectors u=⟨3,0⟩\mathbf{u}=\langle 3,0\rangleu=⟨3,0⟩ and v=⟨0,4⟩\mathbf{v}=\langle 0,4\ranglev=⟨0,4⟩, what is the magnitude ∥u+v∥\lVert \mathbf{u}+\mathbf{v} \rVert∥u+v∥?​

  1. 777
  2. 555 (correct answer)
  3. 7\sqrt{7}7​
  4. 25\sqrt{25}25​

Explanation: This question tests understanding of vector addition using multiple methods, focusing on the magnitude of the sum. An important property of vector addition is that the magnitude of the sum is typically not equal to the sum of the magnitudes: |u + v| ≤ |u| + |v|, with equality only when the vectors point in exactly the same direction. Computing |u + v| requires first finding the components of the sum ⟨3, 4⟩, then calculating √(3² + 4²) = √(9 + 16) = √25 = 5, which is less than |u| + |v| = 3 + 4 = 7. Choice B is correct because it properly applies the formula with specific values. Choice A incorrectly assumes that |u + v| = |u| + |v|, but vector magnitude addition doesn't work this way—the magnitude of a sum depends on the angle between the vectors. Remember that |u + v| ≠ |u| + |v| in general: the magnitude of a vector sum depends on both the magnitudes and the angle between the vectors, reaching its maximum (|u| + |v|) only when vectors point the same direction. All three methods (component-wise, end-to-end, parallelogram) give the same result because they're equivalent ways of representing the same mathematical operation—choose the method that best fits the context or presentation.

Question 9

Two vectors u⃗=⟨a,3⟩\vec{u} = \langle a, 3 \rangleu=⟨a,3⟩ and v⃗=⟨2,b⟩\vec{v} = \langle 2, b \ranglev=⟨2,b⟩ are added to produce u⃗+v⃗=⟨5,7⟩\vec{u} + \vec{v} = \langle 5, 7 \rangleu+v=⟨5,7⟩. What are the values of aaa and bbb?

  1. a=5a = 5a=5 and b=7b = 7b=7, by incorrectly setting unknowns equal to sum
  2. a=3a = 3a=3 and b=4b = 4b=4, from solving the component equations (correct answer)
  3. a=2a = 2a=2 and b=3b = 3b=3, by confusing given values with unknowns
  4. a=4a = 4a=4 and b=3b = 3b=3, by switching the roles of the components

Explanation: When you encounter vector addition problems, remember that vectors are added component-wise. Each corresponding component (x with x, y with y) adds separately to create the resulting vector. To find the unknown values, you need to set up equations for each component. Since u⃗+v⃗=⟨a,3⟩+⟨2,b⟩=⟨5,7⟩\vec{u} + \vec{v} = \langle a, 3 \rangle + \langle 2, b \rangle = \langle 5, 7 \rangleu+v=⟨a,3⟩+⟨2,b⟩=⟨5,7⟩, you can write:

  • For the x-component: a+2=5a + 2 = 5a+2=5
  • For the y-component: 3+b=73 + b = 73+b=7
Solving these equations gives you a=3a = 3a=3 and b=4b = 4b=4, which matches choice B. Let's examine why the other options are incorrect. Choice A suggests a=5a = 5a=5 and b=7b = 7b=7, which comes from mistakenly thinking the unknowns equal the final sum components directly—this ignores that other values are being added to them. Choice C gives a=2a = 2a=2 and b=3b = 3b=3, which happens when you confuse the given values in the problem with what you're solving for. Choice D shows a=4a = 4a=4 and b=3b = 3b=3, which occurs when you accidentally switch which equation corresponds to which component. The key strategy for vector addition problems is to work systematically: write out the component equations separately, then solve each one independently. This prevents confusion about which numbers go where and ensures you're actually solving for the unknowns rather than just copying values from the problem.

Question 10

Three vectors a⃗=⟨2,1⟩\vec{a} = \langle 2, 1 \ranglea=⟨2,1⟩, b⃗=⟨−1,3⟩\vec{b} = \langle -1, 3 \rangleb=⟨−1,3⟩, and c⃗=⟨4,−2⟩\vec{c} = \langle 4, -2 \ranglec=⟨4,−2⟩ are to be added. A student claims that (a⃗+b⃗)+c⃗=⟨5,2⟩(\vec{a} + \vec{b}) + \vec{c} = \langle 5, 2 \rangle(a+b)+c=⟨5,2⟩. Which statement best describes this result?

  1. Incorrect, vectors must be added using the parallelogram rule, not component-wise addition
  2. Incorrect, the correct sum should be ⟨6,3⟩\langle 6, 3 \rangle⟨6,3⟩ based on proper component addition
  3. Correct, and the same result would be obtained using any grouping of the vectors (correct answer)
  4. Correct for this grouping, but a⃗+(b⃗+c⃗)\vec{a} + (\vec{b} + \vec{c})a+(b+c) would yield a different result

Explanation: When you encounter vector addition problems, remember that vectors can be added component-wise and that addition is both commutative and associative, meaning order and grouping don't matter. Let's verify the student's calculation of (a⃗+b⃗)+c⃗(\vec{a} + \vec{b}) + \vec{c}(a+b)+c. First, add a⃗+b⃗\vec{a} + \vec{b}a+b: ⟨2,1⟩+⟨−1,3⟩=⟨2+(−1),1+3⟩=⟨1,4⟩\langle 2, 1 \rangle + \langle -1, 3 \rangle = \langle 2 + (-1), 1 + 3 \rangle = \langle 1, 4 \rangle⟨2,1⟩+⟨−1,3⟩=⟨2+(−1),1+3⟩=⟨1,4⟩. Then add c⃗\vec{c}c: ⟨1,4⟩+⟨4,−2⟩=⟨1+4,4+(−2)⟩=⟨5,2⟩\langle 1, 4 \rangle + \langle 4, -2 \rangle = \langle 1 + 4, 4 + (-2) \rangle = \langle 5, 2 \rangle⟨1,4⟩+⟨4,−2⟩=⟨1+4,4+(−2)⟩=⟨5,2⟩. The student's answer is correct. Now let's examine each option. Choice A is wrong because component-wise addition IS the correct method for adding vectors in component form—the parallelogram rule is just a geometric visualization of the same operation. Choice B is incorrect because it suggests the wrong sum; as we calculated above, ⟨5,2⟩\langle 5, 2 \rangle⟨5,2⟩ is indeed correct, not ⟨6,3⟩\langle 6, 3 \rangle⟨6,3⟩. Choice D is wrong because it claims different groupings yield different results, but vector addition is associative—a⃗+(b⃗+c⃗)\vec{a} + (\vec{b} + \vec{c})a+(b+c) gives the same result as (a⃗+b⃗)+c⃗(\vec{a} + \vec{b}) + \vec{c}(a+b)+c. Choice C correctly identifies that the student's calculation is right and recognizes the associative property of vector addition. Study tip: Remember that vector addition follows the same rules as regular addition—it's commutative and associative. You can add vectors in any order or grouping and get the same result.

Question 11

Points AAA, BBB, and CCC form an end-to-end vector path where AB→=⟨2,1⟩\overrightarrow{AB}=\langle 2,1\rangleAB=⟨2,1⟩ and BC→=⟨3,4⟩\overrightarrow{BC}=\langle 3,4\rangleBC=⟨3,4⟩. Using the vectors given, what is AC→\overrightarrow{AC}AC (in component form)?

  1. ⟨1,−3⟩\langle 1,-3\rangle⟨1,−3⟩
  2. ⟨5,5⟩\langle 5,5\rangle⟨5,5⟩ (correct answer)
  3. ⟨6,4⟩\langle 6,4\rangle⟨6,4⟩
  4. ⟨5,4⟩\langle 5,4\rangle⟨5,4⟩

Explanation: This question tests understanding of vector addition using the end-to-end method. The end-to-end (or head-to-tail) method of vector addition involves placing the tail of the second vector at the head of the first vector; the resultant vector then goes from the tail of the first vector to the head of the second vector. Starting with vector AB = ⟨2, 1⟩ from point A to point B, we place vector BC = ⟨3, 4⟩ so its tail is at B, terminating at point C. The sum AB + BC gives us AC, which geometrically represents the combined displacement from A to C. For vectors AB = ⟨2, 1⟩ and BC = ⟨3, 4⟩, we compute AC = ⟨2 + 3, 1 + 4⟩ = ⟨5, 5⟩. Choice B is correct because it shows the component-wise calculation of the path from A to C. Choice A subtracts the vectors instead of adding them, calculating ⟨2 - 3, 1 - 4⟩ = ⟨-1, -3⟩, which would represent going backwards along the path. All three methods (component-wise, end-to-end, parallelogram) give the same result because they're equivalent ways of representing the same mathematical operation—choose the method that best fits the context or presentation.

Question 12

A ship travels from port A to port B following displacement vector d1⃗=⟨12,5⟩\vec{d_1} = \langle 12, 5 \rangled1​​=⟨12,5⟩ km, then from port B to port C following d2⃗=⟨−4,7⟩\vec{d_2} = \langle -4, 7 \rangled2​​=⟨−4,7⟩ km. If the ship had traveled directly from A to C, what would be the bearing (angle from positive x-axis) of this direct path?

  1. 56.3°56.3°56.3°, calculated from the total displacement vector components (correct answer)
  2. 33.7°33.7°33.7°, calculated from the average of the two displacement angles
  3. 48.4°48.4°48.4°, calculated from the sum of individual displacement angles
  4. 22.6°22.6°22.6°, calculated from the difference of displacement magnitudes

Explanation: The total displacement is d1⃗+d2⃗=⟨12−4,5+7⟩=⟨8,12⟩\vec{d_1} + \vec{d_2} = \langle 12-4, 5+7 \rangle = \langle 8, 12 \rangled1​​+d2​​=⟨12−4,5+7⟩=⟨8,12⟩. The bearing is arctan⁡(12/8)=arctan⁡(1.5)≈56.3°\arctan(12/8) = \arctan(1.5) \approx 56.3°arctan(12/8)=arctan(1.5)≈56.3°. Choice B incorrectly averages the individual angles (arctan⁡(5/12)≈22.6°\arctan(5/12) \approx 22.6°arctan(5/12)≈22.6° and arctan⁡(7/−4)≈119.7°\arctan(7/-4) \approx 119.7°arctan(7/−4)≈119.7°). Choice C incorrectly adds individual displacement angles. Choice D uses the angle of just the first displacement vector.

Question 13

Vectors u=⟨2,3⟩\mathbf{u}=\langle 2,3\rangleu=⟨2,3⟩ and v=⟨−2,−3⟩\mathbf{v}=\langle -2,-3\ranglev=⟨−2,−3⟩ are additive inverses. What is u+v\mathbf{u}+\mathbf{v}u+v?

  1. ⟨4,6⟩\langle 4,6\rangle⟨4,6⟩
  2. ⟨0,0⟩\langle 0,0\rangle⟨0,0⟩ (correct answer)
  3. ⟨−4,−6⟩\langle -4,-6\rangle⟨−4,−6⟩
  4. ⟨0,1⟩\langle 0,1\rangle⟨0,1⟩

Explanation: This question tests understanding of vector addition using the component-wise method with additive inverses. Vectors are added component-wise: for u = ⟨u₁, u₂⟩ and v = ⟨v₁, v₂⟩, the sum u + v = ⟨u₁ + v₁, u₂ + v₂⟩, meaning we add the horizontal components together and the vertical components together separately. For vectors u = ⟨2, 3⟩ and v = ⟨-2, -3⟩, we compute u + v = ⟨2 + (-2), 3 + (-3)⟩ = ⟨0, 0⟩. Choice B is correct because additive inverse vectors have opposite components that cancel when added: 2 + (-2) = 0 and 3 + (-3) = 0, resulting in the zero vector. Choice A adds the absolute values instead of the signed values, computing ⟨|2| + |-2|, |3| + |-3|⟩ = ⟨4, 6⟩, which ignores the negative signs. Key to vector addition: when using component form, add x-components together and y-components together separately—treat each component independently, and remember that additive inverses always sum to the zero vector ⟨0, 0⟩.

Question 14

For vectors u=⟨−6,2⟩\mathbf{u}=\langle -6,2\rangleu=⟨−6,2⟩ and v=⟨1,−5⟩\mathbf{v}=\langle 1,-5\ranglev=⟨1,−5⟩, what is u+v\mathbf{u}+\mathbf{v}u+v (in component form)?

  1. ⟨−5,−3⟩\langle -5,-3\rangle⟨−5,−3⟩ (correct answer)
  2. ⟨−7,7⟩\langle -7,7\rangle⟨−7,7⟩
  3. ⟨−6,−10⟩\langle -6,-10\rangle⟨−6,−10⟩
  4. ⟨−6,2⟩\langle -6,2\rangle⟨−6,2⟩

Explanation: This question tests understanding of vector addition using the component-wise method with negative components. Vectors are added component-wise: for u = ⟨u₁, u₂⟩ and v = ⟨v₁, v₂⟩, the sum u + v = ⟨u₁ + v₁, u₂ + v₂⟩, meaning we add the horizontal components together and the vertical components together separately. For vectors u = ⟨-6, 2⟩ and v = ⟨1, -5⟩, we compute u + v = ⟨-6 + 1, 2 + (-5)⟩ = ⟨-5, -3⟩. Choice A is correct because it shows the component-wise calculation: the x-components give -6 + 1 = -5, and the y-components give 2 + (-5) = -3. Choice B subtracts the vectors instead of adding them, calculating ⟨-6 - 1, 2 - (-5)⟩ = ⟨-7, 7⟩, which gives u - v rather than u + v. Key to vector addition: when using component form, add x-components together and y-components together separately—treat each component independently, being careful with negative signs.

Question 15

A boat’s velocity relative to the water is ⟨5,0⟩\langle 5,0\rangle⟨5,0⟩ m/s and the current’s velocity is ⟨0,2⟩\langle 0,2\rangle⟨0,2⟩ m/s. Using component-wise addition, what is the resultant velocity vector ⟨5,0⟩+⟨0,2⟩\langle 5,0\rangle+\langle 0,2\rangle⟨5,0⟩+⟨0,2⟩?

  1. ⟨5,2⟩\langle 5,2\rangle⟨5,2⟩ (correct answer)
  2. ⟨5,0⟩\langle 5,0\rangle⟨5,0⟩
  3. ⟨0,2⟩\langle 0,2\rangle⟨0,2⟩
  4. ⟨10,0⟩\langle 10,0\rangle⟨10,0⟩

Explanation: This question tests understanding of vector addition using the component-wise method. Vectors are added component-wise: for u = ⟨u₁, u₂⟩ and v = ⟨v₁, v₂⟩, the sum u + v = ⟨u₁ + v₁, u₂ + v₂⟩, meaning we add the horizontal components together and the vertical components together separately. For vectors ⟨5, 0⟩ and ⟨0, 2⟩, we compute the sum = ⟨5 + 0, 0 + 2⟩ = ⟨5, 2⟩. Choice A is correct because it shows the component-wise calculation with specific values. Choice D adds only one component correctly but makes an arithmetic or sign error in the other component, leading to ⟨10, 0⟩ as if doubling the horizontal. Key to vector addition: when using component form, add x-components together and y-components together separately—treat each component independently, like combining horizontal and vertical motions. All three methods (component-wise, end-to-end, parallelogram) give the same result because they're equivalent ways of representing the same mathematical operation—choose the method that best fits the context or presentation.

Question 16

For vectors u=⟨3,0⟩\mathbf{u}=\langle 3,0\rangleu=⟨3,0⟩ and v=⟨0,4⟩\mathbf{v}=\langle 0,4\ranglev=⟨0,4⟩, what is the magnitude of u+v\mathbf{u}+\mathbf{v}u+v?

  1. 777
  2. 555 (correct answer)
  3. 7\sqrt{7}7​
  4. 25\sqrt{25}25​

Explanation: This question tests understanding of vector addition using component-wise addition and magnitude calculation. Vectors are added component-wise: for u = ⟨u₁, u₂⟩ and v = ⟨v₁, v₂⟩, the sum u + v = ⟨u₁ + v₁, u₂ + v₂⟩, meaning we add the horizontal components together and the vertical components together separately. For vectors u = ⟨3, 0⟩ and v = ⟨0, 4⟩, we compute u + v = ⟨3 + 0, 0 + 4⟩ = ⟨3, 4⟩. Computing |u + v| requires first finding the components of the sum ⟨3, 4⟩, then calculating √(3² + 4²) = √(9 + 16) = √25 = 5. Choice B is correct because it shows the proper magnitude calculation of the resultant vector. Choice A incorrectly assumes that |u + v| = |u| + |v|, but vector magnitude addition doesn't work this way—the magnitude of a sum depends on the angle between the vectors, which in this case are perpendicular. Remember that |u + v| ≠ |u| + |v| in general: the magnitude of a vector sum depends on both the magnitudes and the angle between the vectors, reaching its maximum (|u| + |v|) only when vectors point the same direction.

Question 17

Vectors u=⟨3,0⟩\mathbf{u}=\langle 3,0\rangleu=⟨3,0⟩ and v=⟨0,4⟩\mathbf{v}=\langle 0,4\ranglev=⟨0,4⟩ are perpendicular. What is the magnitude of u+v\mathbf{u}+\mathbf{v}u+v?

  1. 777
  2. 555 (correct answer)
  3. 7\sqrt{7}7​
  4. 34\sqrt{34}34​

Explanation: This question tests understanding of vector addition using component-wise method and magnitude calculation. An important property of vector addition is that the magnitude of the sum is typically not equal to the sum of the magnitudes: |u + v| ≤ |u| + |v|, with equality only when the vectors point in exactly the same direction. For vectors u = ⟨3, 0⟩ and v = ⟨0, 4⟩, we compute u + v = ⟨3 + 0, 0 + 4⟩ = ⟨3, 4⟩. Computing |u + v| requires first finding the components of the sum ⟨3, 4⟩, then calculating √(3² + 4²) = √(9 + 16) = √25 = 5, which is less than |u| + |v| = 3 + 4 = 7. Choice B is correct because it properly applies the magnitude formula to the sum vector ⟨3, 4⟩. Choice A incorrectly assumes that |u + v| = |u| + |v|, but vector magnitude addition doesn't work this way—the magnitude of a sum depends on the angle between the vectors. Remember that |u + v| ≠ |u| + |v| in general: the magnitude of a vector sum depends on both the magnitudes and the angle between the vectors, reaching its maximum (|u| + |v|) only when vectors point the same direction.

Question 18

Vectors u=⟨1,−2⟩\mathbf{u}=\langle 1,-2\rangleu=⟨1,−2⟩, v=⟨4,3⟩\mathbf{v}=\langle 4,3\ranglev=⟨4,3⟩, and w=⟨−2,1⟩\mathbf{w}=\langle -2,1\ranglew=⟨−2,1⟩ are given. Using component-wise addition, what is u+v+w\mathbf{u}+\mathbf{v}+\mathbf{w}u+v+w?

  1. ⟨3,2⟩\langle 3,2\rangle⟨3,2⟩ (correct answer)
  2. ⟨7,2⟩\langle 7,2\rangle⟨7,2⟩
  3. ⟨3,0⟩\langle 3,0\rangle⟨3,0⟩
  4. ⟨−5,−4⟩\langle -5,-4\rangle⟨−5,−4⟩

Explanation: This question tests understanding of vector addition using the component-wise method with three vectors. Vectors are added component-wise: for multiple vectors, we add all corresponding components together separately. For vectors u = ⟨1, -2⟩, v = ⟨4, 3⟩, and w = ⟨-2, 1⟩, we compute u + v + w = ⟨1 + 4 + (-2), -2 + 3 + 1⟩ = ⟨3, 2⟩. Choice A is correct because it shows the component-wise calculation: the x-components give 1 + 4 - 2 = 3, and the y-components give -2 + 3 + 1 = 2. Choice B adds only the first two vectors correctly but makes an error with the third, computing ⟨1 + 4 + 2, -2 + 3 + 1⟩ = ⟨7, 2⟩, likely misreading the sign of w's first component. All three methods (component-wise, end-to-end, parallelogram) give the same result because they're equivalent ways of representing the same mathematical operation—for multiple vectors, component-wise addition is often the most efficient approach.

Question 19

A parallelogram has vertices at O(0,0)O(0,0)O(0,0), A(5,2)A(5,2)A(5,2), B(7,6)B(7,6)B(7,6), and C(2,4)C(2,4)C(2,4). If OA⃗\vec{OA}OA and OC⃗\vec{OC}OC represent two vectors being added using the parallelogram rule, which point represents the sum of these vectors?

  1. Point (3.5,4)(3.5, 4)(3.5,4), which is the midpoint of diagonal OBOBOB
  2. Point (3.5,3)(3.5, 3)(3.5,3), which is the center of the parallelogram
  3. Point (2.5,3)(2.5, 3)(2.5,3), which is the midpoint of diagonal ACACAC
  4. Point B(7,6)B(7,6)B(7,6), which is the fourth vertex of the parallelogram (correct answer)

Explanation: When you encounter vector addition with parallelograms, remember that the parallelogram rule states that if two vectors form adjacent sides of a parallelogram starting from the same point, their sum is represented by the diagonal vector from that starting point to the opposite vertex. Here, vectors OA⃗=(5,2)\vec{OA} = (5,2)OA=(5,2) and OC⃗=(2,4)\vec{OC} = (2,4)OC=(2,4) both start at origin O(0,0)O(0,0)O(0,0). To find their sum using the parallelogram rule, you need to identify which point represents the end of the diagonal that starts at OOO. We can verify this algebraically: OA⃗+OC⃗=(5,2)+(2,4)=(7,6)\vec{OA} + \vec{OC} = (5,2) + (2,4) = (7,6)OA+OC=(5,2)+(2,4)=(7,6), which corresponds exactly to point B(7,6)B(7,6)B(7,6). This makes perfect sense because in parallelogram OACBOACBOACB, the diagonal from OOO to BBB represents the vector sum. Choice A incorrectly identifies the midpoint of diagonal OBOBOB, but vector addition gives you the endpoint of the resultant vector, not its midpoint. Choice B points to the center of the parallelogram, which has no special meaning in vector addition. Choice C suggests the midpoint of diagonal ACACAC, but this diagonal doesn't start from the origin where our vectors begin, making it irrelevant to the sum OA⃗+OC⃗\vec{OA} + \vec{OC}OA+OC. The answer is D: Point B(7,6)B(7,6)B(7,6). Key takeaway: In the parallelogram rule for vector addition, the sum always points from the common starting point to the opposite vertex of the parallelogram—never to midpoints or centers.

Question 20

Two vectors are drawn from the origin: u=⟨4,0⟩\mathbf{u}=\langle 4,0\rangleu=⟨4,0⟩ and v=⟨0,3⟩\mathbf{v}=\langle 0,3\ranglev=⟨0,3⟩. Using the parallelogram rule, what is u+v\mathbf{u}+\mathbf{v}u+v in component form?

  1. ⟨4,3⟩\langle 4,3\rangle⟨4,3⟩ (correct answer)
  2. ⟨1,12⟩\langle 1,12\rangle⟨1,12⟩
  3. ⟨4,−3⟩\langle 4,-3\rangle⟨4,−3⟩
  4. ⟨3,4⟩\langle 3,4\rangle⟨3,4⟩

Explanation: This question tests understanding of vector addition using the parallelogram rule. The parallelogram rule for adding vectors involves placing both vectors tail-to-tail at a common initial point, completing a parallelogram using the vectors as adjacent sides, and taking the diagonal from the initial point as the sum. When both vectors u = ⟨4, 0⟩ and v = ⟨0, 3⟩ start from the same point, they form two adjacent sides of a parallelogram; the diagonal of this parallelogram starting from the common initial point represents u + v = ⟨4, 3⟩. Choice A is correct because it properly applies the formula with specific values in component form. Choice C subtracts the vectors instead of adding them, calculating ⟨4 - 0, 0 - 3⟩, which gives a different vector. The parallelogram rule shows why vector addition is commutative (u + v = v + u): both diagonals of the parallelogram represent the same sum, just constructed in different orders. All three methods (component-wise, end-to-end, parallelogram) give the same result because they're equivalent ways of representing the same mathematical operation—choose the method that best fits the context or presentation.