Prealgebra Quiz: Parallel Lines And Transversals
2 questions · exam conditions
0:00
Parallel Lines And TransversalsQuestion 1 of 2

Two parallel lines are cut by two different transversals. The first transversal creates an angle of 72°72° with the first parallel line. The second transversal creates an angle with the second parallel line that is 18°18° more than half the corresponding angle formed by the first transversal. What is the measure of this angle on the second parallel line?

36°36°
54°54°
72°72°
90°90°
← Back to quizzes

Prealgebra Quiz

Prealgebra Quiz: Parallel Lines And Transversals

Practice Parallel Lines And Transversals in Prealgebra with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Parallel Lines And Transversals, giving you a quick way to practice the rules, question types, and explanations that matter most for Prealgebra.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Two parallel lines are cut by two different transversals. The first transversal creates an angle of 72°72° with the first parallel line. The second transversal creates an angle with the second parallel line that is 18°18° more than half the corresponding angle formed by the first transversal. What is the measure of this angle on the second parallel line?

  1. 36°36°
  2. 54°54° (correct answer)
  3. 72°72°
  4. 90°90°
Explanation: The first transversal creates a 72°72° angle with the first parallel line. The corresponding angle on the second parallel line is also 72°72° (corresponding angles are equal when parallel lines are cut by a transversal). The second transversal creates an angle that is 18°18° more than half of this corresponding angle: 72°2+18°=36°+18°=54°\frac{72°}{2} + 18° = 36° + 18° = 54°. Choice A gives only half of 72°72°. Choice C gives the original 72°72° angle. Choice D results from incorrectly calculating 72°+18°=90°72° + 18° = 90°.

Question 2

Two parallel lines are intersected by a transversal. One pair of corresponding angles has measures (5a+10)°(5a + 10)° and (7a−30)°(7a - 30)°. A pair of alternate exterior angles formed by the same transversal has measures (3b+20)°(3b + 20)° and (b+60)°(b + 60)°. What is the value of a+ba + b?

  1. 2020
  2. 4040 (correct answer)
  3. 6060
  4. 8080
Explanation: Corresponding angles are equal: 5a+10=7a−305a + 10 = 7a - 30. Solving: 40=2a40 = 2a, so a=20a = 20. Alternate exterior angles are equal: 3b+20=b+603b + 20 = b + 60. Solving: 2b=402b = 40, so b=20b = 20. Therefore a+b=20+20=40a + b = 20 + 20 = 40. Choice A gives only the value of aa or bb. Choice C results from incorrectly adding the angle measures instead of the variables. Choice D results from calculation errors like a=b=40a = b = 40.