Home

Tutoring

Subjects

Live Classes

Study Coach

Essay Review

On-Demand Courses

Colleges

Games


Sign up

Log in

Opening subject page...

Loading your content

Practice

  • All Subjects
  • Algebra Flashcards
  • SAT Math Practice Tests
  • Math Question of the Day
  • Live Classes
  • On-Demand Courses

Varsity Tutors

  • Find a Tutor
  • Test Prep
  • Online Classes
  • K-12 Learning
  • College Search
  • VarsityTutors.com

© 2026 Varsity Tutors. All rights reserved.

← Back to quizzes

Physics Quiz

Physics Quiz: Analyze Wave Amplitude And Energy

Practice Analyze Wave Amplitude And Energy in Physics with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

Question 1 / 20

0 of 20 answered

A loudspeaker produces a sound wave at a fixed frequency. When the volume knob is turned up, the sound wave’s amplitude increases from A1A_1A1​ to 2A12A_12A1​ while the listener stays at the same distance. If sound intensity (and energy transfer rate) is proportional to amplitude squared, I∝A2I \propto A^2I∝A2, by what factor does the sound intensity change?

Select an answer to continue

What this quiz covers

This quiz focuses on Analyze Wave Amplitude And Energy, giving you a quick way to practice the rules, question types, and explanations that matter most for Physics.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A loudspeaker produces a sound wave at a fixed frequency. When the volume knob is turned up, the sound wave’s amplitude increases from A1A_1A1​ to 2A12A_12A1​ while the listener stays at the same distance. If sound intensity (and energy transfer rate) is proportional to amplitude squared, I∝A2I \propto A^2I∝A2, by what factor does the sound intensity change?

  1. It increases by a factor of 2.
  2. It increases by a factor of 4. (correct answer)
  3. It increases by a factor of 8.
  4. It decreases by a factor of 2.

Explanation: This question tests understanding of the relationship between wave amplitude and sound intensity. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. When amplitude doubles from A₁ to 2A₁, we calculate the intensity change using the squared relationship: I_new/I_original = (A_new/A_original)² = (2A₁/A₁)² = 2² = 4, so the intensity increases by a factor of 4 (quadruples), not by a factor of 2—this is why a sound that is twice as loud in amplitude requires 4 times as much energy to produce. Choice B is correct because it properly applies the squared relationship E ∝ A² to show energy factor is square of amplitude factor. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that doubling amplitude doubles energy, when actually the relationship is quadratic (E ∝ A²) so doubling amplitude quadruples energy—this is why the answer is a factor of 4, not 2. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why increasing speaker volume slightly requires significantly more power, why tsunamis with modest height increase carry devastating energy, and why a magnitude 7 earthquake (10× amplitude of magnitude 6) releases roughly 32× more energy (actually 10^1.5 in total energy released).

Question 2

A water wave in a wave tank has amplitude A1=0.20 mA_1 = 0.20\text{ m}A1​=0.20 m (measured from equilibrium to crest). A second wave in the same tank has energy per unit area that is 9 times larger than the first. Assuming wave energy is proportional to amplitude squared, E∝A2E \propto A^2E∝A2, what is the amplitude factor A2/A1A_2/A_1A2​/A1​?

  1. 999
  2. 333 (correct answer)
  3. 9/2\sqrt{9}/29​/2
  4. 13\tfrac{1}{3}31​

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. If energy increases by a factor of 9, we solve for amplitude change: E₂/E₁ = (A₂/A₁)² = 9, taking square root of both sides gives A₂/A₁ = √9 = 3, so amplitude must increase by a factor of 3—for example, to increase energy 4-fold requires only doubling the amplitude because 2² = 4. Choice B is correct because it accurately uses square root relationship to find amplitude change from energy change. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that 9-fold energy requires 9-fold amplitude, when actually the relationship is quadratic (E ∝ A²) so 9-fold energy requires only 3-fold amplitude—this is why the answer is a factor of 3, not 9. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why increasing speaker volume slightly requires significantly more power, why tsunamis with modest height increase carry devastating energy, and why a magnitude 7 earthquake (10× amplitude of magnitude 6) releases roughly 32× more energy (actually 10^1.5 in total energy released).

Question 3

A student compares two waves on the same rope and claims: “If I double the amplitude, I double the energy.” Which statement best describes the correct amplitude–energy relationship for these rope waves (holding other conditions constant)?

  1. Energy is proportional to amplitude: E∝AE \propto AE∝A.
  2. Energy is proportional to the square of amplitude: E∝A2E \propto A^2E∝A2. (correct answer)
  3. Energy is inversely proportional to amplitude: E∝1AE \propto \tfrac{1}{A}E∝A1​.
  4. Energy is proportional to the cube of amplitude: E∝A3E \propto A^3E∝A3.

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. The mathematical relationship is E = kA² where k is a constant depending on the medium, frequency, and other wave properties—the key insight is the squared dependence, which appears in intensity of sound (I ∝ A²), power in water waves (P ∝ A²), and brightness of light (brightness ∝ A²), all reflecting the fundamental E ∝ A² relationship. Choice B is correct because it correctly identifies that energy is proportional to amplitude squared. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that doubling amplitude doubles energy, when actually the relationship is quadratic (E ∝ A²) so doubling amplitude quadruples energy—this is why the student's claim is wrong. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Real-world applications of E ∝ A²: in sound, doubling the amplitude creates a sound that's 4 times more intense but only perceived as slightly louder due to logarithmic human hearing; in earthquakes, each step up in Richter scale represents 10× more amplitude but about 32× more energy (roughly 10^1.5); in water waves, doubling wave height quadruples the energy, explaining why large tsunami waves are so devastating despite not looking enormously tall when viewed from space.

Question 4

A sound wave at fixed frequency has intensity proportional to amplitude squared: I∝A2I \propto A^2I∝A2. A microphone measures intensity I1I_1I1​ when the amplitude is A1A_1A1​. If the measured intensity becomes I2=9I1I_2 = 9I_1I2​=9I1​, by what factor did the amplitude change?

  1. Amplitude increased by a factor of 9
  2. Amplitude increased by a factor of 4.5
  3. Amplitude increased by a factor of 3 (correct answer)
  4. Amplitude increased by a factor of 9/2\sqrt{9}/29​/2

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. For energy increasing: If intensity (energy-related) increases by a factor of 9, we solve for amplitude change: I₂/I₁ = (A₂/A₁)² = 9, taking square root of both sides gives A₂/A₁ = √9 = 3, so amplitude must increase by a factor of 3—for example, to increase energy 4-fold requires only doubling the amplitude because 2² = 4. Choice C is correct because it accurately uses square root relationship to find amplitude change from energy change. Choice A incorrectly assumes energy is proportional to amplitude squared but then fails to take the square root, claiming a factor of 9 for amplitude when it's actually √9 = 3. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why increasing speaker volume slightly requires significantly more power, why tsunamis with modest height increase carry devastating energy, and why a magnitude 7 earthquake (10× amplitude of magnitude 6) releases roughly 32× more energy (actually 10^1.5 in energy scaling).

Question 5

A string wave has energy proportional to the square of its amplitude: E∝A2E \propto A^2E∝A2. Which statement correctly describes the amplitude–energy relationship (with frequency unchanged)?

  1. Energy is proportional to amplitude: E∝AE \propto AE∝A
  2. Energy is proportional to the square of amplitude: E∝A2E \propto A^2E∝A2 (correct answer)
  3. Energy is inversely proportional to amplitude: E∝1/AE \propto 1/AE∝1/A
  4. Energy is proportional to the cube of amplitude: E∝A3E \propto A^3E∝A3

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. For identifying relationship: The mathematical relationship is E = kA² where k is a constant depending on the medium, frequency, and other wave properties—the key insight is the squared dependence, which appears in intensity of sound (I ∝ A²), power in water waves (P ∝ A²), and brightness of light (brightness ∝ A²), all reflecting the fundamental E ∝ A² relationship. Choice B is correct because it correctly identifies that energy is proportional to amplitude squared. Choice A incorrectly treats the relationship as linear (E ∝ A), but actually the relationship is quadratic (E ∝ A²)—this distinction is crucial because it determines that tripling amplitude increases energy 9-fold (3² = 9) not 3-fold. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Real-world applications of E ∝ A²: in sound, doubling the amplitude creates a sound that's 4 times more intense but only perceived as slightly louder due to logarithmic human hearing; in earthquakes, each step up in Richter scale represents 10× more amplitude but about 32× more energy (roughly 10^1.5); in water waves, doubling wave height quadruples the energy, explaining why large tsunami waves are so devastating despite not looking enormously tall when viewed from space.

Question 6

A pulse travels on a rope where the energy carried is E=kA2E = kA^2E=kA2 (same rope and tension, so kkk is constant). If the amplitude changes from A1A_1A1​ to A2=0.5A1A_2 = 0.5A_1A2​=0.5A1​, what is the ratio E2/E1E_2/E_1E2​/E1​?

  1. E2/E1=1/2E_2/E_1 = 1/2E2​/E1​=1/2
  2. E2/E1=1/4E_2/E_1 = 1/4E2​/E1​=1/4 (correct answer)
  3. E2/E1=2E_2/E_1 = 2E2​/E1​=2
  4. E2/E1=4E_2/E_1 = 4E2​/E1​=4

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. When amplitude halves from A₁ to A₂ = 0.5A₁, we calculate the energy change using the squared relationship: E₂/E₁ = (A₂/A₁)² = (0.5)² = 0.25 = 1/4, so the energy decreases to one-fourth, which is why reducing the pulse height by half reduces the energy carried to a quarter on the same rope. Choice B is correct because it properly applies the squared relationship E ∝ A² to show energy factor is square of amplitude factor. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that halving amplitude halves energy, when actually the relationship is quadratic (E ∝ A²) so halving amplitude quarters energy—this is why the answer is a factor of 1/4, not 1/2. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Real-world applications of E ∝ A²: in sound, doubling the amplitude creates a sound that's 4 times more intense but only perceived as slightly louder due to logarithmic human hearing; in earthquakes, each step up in Richter scale represents 10× more amplitude but about 32× more energy (roughly 10^1.5); in water waves, doubling wave height quadruples the energy, explaining why large tsunami waves are so devastating despite not looking enormously tall when viewed from space.

Question 7

A loudspeaker produces a 500 Hz sound wave in air. With the frequency held constant, the wave energy transferred is proportional to the square of the amplitude: E∝A2E \propto A^2E∝A2. If the speaker’s sound-wave amplitude increases from A1=0.20 mmA_1 = 0.20\ \text{mm}A1​=0.20 mm to A2=0.60 mmA_2 = 0.60\ \text{mm}A2​=0.60 mm, by what factor does the wave energy change?

  1. Increases by a factor of 3
  2. Increases by a factor of 9 (correct answer)
  3. Decreases by a factor of 3
  4. Increases by a factor of 6

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. When amplitude increases from 0.20 mm to 0.60 mm, we calculate the energy change using the squared relationship: E₂/E₁ = (A₂/A₁)² = (0.60/0.20)² = 3² = 9, so the energy increases by a factor of 9, which is why increasing the speaker's vibration extent by three times requires nine times more energy to produce the sound wave. Choice B is correct because it properly applies the squared relationship E ∝ A² to show the energy factor is the square of the amplitude factor. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that tripling amplitude increases energy by a factor of 3, when actually the relationship is quadratic (E ∝ A²) so tripling amplitude increases energy nine-fold—this is why the answer is a factor of 9, not 3. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A triples, E increases by 3² = 9), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why increasing speaker volume slightly requires significantly more power, why tsunamis with modest height increase carry devastating energy, and why a magnitude 7 earthquake (10× amplitude of magnitude 6) releases roughly 32× more energy (actually 10^1.5 in energy scaling).

Question 8

On a rope, a student wants to double the energy carried by a traveling wave without changing the wave speed or frequency. If E∝A2E \propto A^2E∝A2, what factor change in amplitude is required (A2/A1A_2/A_1A2​/A1​)?

  1. 222
  2. 2\sqrt{2}2​ (correct answer)
  3. 12\tfrac{1}{2}21​
  4. 12\tfrac{1}{\sqrt{2}}2​1​

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy on a rope. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. If energy increases by a factor of 2, we solve for amplitude change: E₂/E₁ = (A₂/A₁)² = 2, taking square root of both sides gives A₂/A₁ = √2, so amplitude must increase by a factor of √2—for example, to increase energy 4-fold requires only doubling the amplitude because 2² = 4. Choice B is correct because it correctly uses the square root relationship to find the amplitude change from the energy change, accurately calculating √2. Choice A incorrectly assumes a linear relationship (E ∝ A), suggesting amplitude doubles for doubling energy, when actually it's quadratic, so amplitude increases by √2—this is why the answer is √2, not 2. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: if asked how amplitude changes when energy changes, take the square root of the energy factor (if E doubles, A increases by √2), and always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear. Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why snapping a rope harder (larger A) imparts much more energy to the wave.

Question 9

Two ocean surface waves pass a buoy. Wave A has amplitude AA=1.5 mA_A = 1.5\ \text{m}AA​=1.5 m and Wave B has amplitude AB=0.5 mA_B = 0.5\ \text{m}AB​=0.5 m (same wavelength and speed). If energy is proportional to amplitude squared (E∝A2E \propto A^2E∝A2), what is the ratio EA/EBE_A/E_BEA​/EB​?

  1. 333
  2. 999 (correct answer)
  3. 13\tfrac{1}{3}31​
  4. 19\tfrac{1}{9}91​

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy in ocean waves. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. For comparing waves: Wave A with amplitude A_A = 1.5 m and Wave B with amplitude A_B = 0.5 m have energy ratio E_A/E_B = (A_A/A_B)² = (1.5/0.5)² = 3² = 9, meaning Wave A carries 9 times as much energy as Wave B despite having only three times the amplitude. Choice B is correct because it accurately calculates that tripling the amplitude increases energy 9-fold, properly applying the squared relationship E ∝ A². Choice A incorrectly treats the relationship as linear (E ∝ A), claiming the ratio is 3, when actually the relationship is quadratic (E ∝ A²) so the ratio is 9—this distinction is crucial because it determines that tripling amplitude increases energy 9-fold not 3-fold. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: if asked how energy changes when amplitude changes, square the amplitude factor (if A triples, E increases by 3² = 9), and always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear. Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why larger ocean waves can cause much more erosion and damage to coastlines.

Question 10

A physics student summarizes how wave energy depends on amplitude for a wave on a string, holding frequency constant. Which statement is correct?

  1. Energy is proportional to amplitude: E∝AE \propto AE∝A
  2. Energy is proportional to amplitude squared: E∝A2E \propto A^2E∝A2 (correct answer)
  3. Energy is inversely proportional to amplitude: E∝1AE \propto \tfrac{1}{A}E∝A1​
  4. Energy is proportional to amplitude cubed: E∝A3E \propto A^3E∝A3

Explanation: This question tests understanding of the fundamental relationship between wave amplitude and wave energy on a string. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. The mathematical relationship is E = kA² where k is a constant depending on the medium, frequency, and other wave properties—the key insight is the squared dependence, which appears in intensity of sound (I ∝ A²), power in water waves (P ∝ A²), and brightness of light (brightness ∝ A²), all reflecting the fundamental E ∝ A² relationship. Choice B is correct because it properly identifies that energy is proportional to amplitude squared (E ∝ A²). Choice A incorrectly treats the relationship as linear (E ∝ A), when actually the relationship is quadratic (E ∝ A²)—this distinction is crucial because it determines that doubling amplitude increases energy 4-fold not 2-fold. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear. Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why a magnitude 7 earthquake (10× amplitude of magnitude 6) releases roughly 32× more energy (actually ~10^1.5 in total energy released).

Question 11

Sound waves from a loudspeaker are measured at a fixed distance while the frequency stays the same. If the speaker’s sound wave amplitude increases from A1A_1A1​ to 2A12A_12A1​, by what factor does the sound intensity (and energy carried per unit time per area) change, given that I∝A2I \propto A^2I∝A2?

  1. Increases by a factor of 2
  2. Increases by a factor of 4 (correct answer)
  3. Decreases by a factor of 2
  4. Increases by a factor of 8

Explanation: This question tests understanding of the relationship between wave amplitude and sound intensity, which is a measure of energy flux. Sound intensity is proportional to the amplitude squared: I ∝ A², meaning if you double the amplitude (A → 2A), the intensity increases by a factor of 4 (I → 4I), and this relationship holds for all waves where energy depends on the square of the displacement. When the amplitude increases from A₁ to 2A₁, we calculate the intensity change using the squared relationship: I_new/I_original = (2A₁/A₁)² = 2² = 4, so the intensity increases by a factor of 4, which explains why amplifying sound requires disproportionately more power. Choice B is correct because it properly applies the squared relationship I ∝ A² to show the intensity factor is the square of the amplitude factor. Choice A incorrectly treats the relationship as linear (I ∝ A), claiming that doubling amplitude doubles intensity, when actually the relationship is quadratic (I ∝ A²) so doubling amplitude quadruples intensity—this is why the answer is a factor of 4, not 2. To solve amplitude-energy problems, remember the formula I₂/I₁ = (A₂/A₁)²: if asked how intensity changes when amplitude changes, square the amplitude factor (if A doubles, I increases by 2² = 4), and always check your answer makes sense—larger amplitude must mean more intensity, and the relationship is stronger than linear. Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why increasing speaker volume slightly requires significantly more power.

Question 12

Two water waves in a wave tank have the same wavelength and speed. Wave 1 has height (amplitude) A1=0.20 mA_1 = 0.20\ \text{m}A1​=0.20 m and Wave 2 has A2=0.60 mA_2 = 0.60\ \text{m}A2​=0.60 m. If wave energy is proportional to amplitude squared (E∝A2E \propto A^2E∝A2), how do their energies compare (ratio E2/E1E_2/E_1E2​/E1​)?

  1. 333
  2. 999 (correct answer)
  3. 19\tfrac{1}{9}91​
  4. 666

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy in water waves. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. For comparing waves: Wave 1 with amplitude A₁ = 0.20 m and Wave 2 with amplitude A₂ = 0.60 m have energy ratio E₂/E₁ = (A₂/A₁)² = (0.60/0.20)² = 3² = 9, meaning Wave 2 carries 9 times as much energy as Wave 1 despite having only three times the amplitude. Choice B is correct because it accurately calculates that tripling the amplitude increases energy 9-fold, properly applying the squared relationship E ∝ A². Choice A incorrectly treats the relationship as linear (E ∝ A), claiming the ratio is 3, when actually the relationship is quadratic (E ∝ A²) so the ratio is 9—this distinction is crucial because it determines that tripling amplitude increases energy 9-fold not 3-fold. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: if asked how energy changes when amplitude changes, square the amplitude factor (if A triples, E increases by 3² = 9), and always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear. Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why tsunamis with modest height increase carry devastating energy.

Question 13

An electromagnetic wave (light) has intensity proportional to the square of the electric field amplitude: I∝A2I \propto A^2I∝A2. If the amplitude is reduced to half its original value (frequency unchanged), what happens to the intensity?

  1. It becomes 1/21/21/2 as large
  2. It becomes 1/41/41/4 as large (correct answer)
  3. It becomes 2 times as large
  4. It becomes 4 times as large

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you halve the amplitude (A → A/2), the energy decreases by a factor of 4 (E → E/4)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. When amplitude is reduced to half its original value (A → A/2), we calculate the intensity change using the squared relationship: I₂/I₁ = (A₂/A₁)² = (A/2 / A)² = (1/2)² = 1/4, so the intensity becomes 1/4 as large—halving the amplitude reduces intensity to one-quarter of its original value. Choice B is correct because it properly applies the squared relationship I ∝ A² to show that halving amplitude reduces intensity to 1/4. Choice A incorrectly treats the relationship as linear (I ∝ A), claiming that halving amplitude halves intensity, when actually the relationship is quadratic (I ∝ A²) so halving amplitude reduces intensity to one-quarter—this is why the answer is 1/4, not 1/2. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A is halved, E becomes (1/2)² = 1/4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E becomes 1/4, A becomes √(1/4) = 1/2), and (3) always check your answer makes sense—smaller amplitude must mean less energy, and the relationship is stronger than linear (energy decreases faster than amplitude). Physical intuition: the squared relationship makes sense because wave energy depends on both how far the electric field oscillates (amplitude) and how much energy is stored in the field—both effects scale with amplitude, so total intensity scales as amplitude squared; this is why dimming a light by reducing the electric field amplitude to half produces a light that appears much dimmer than half brightness, as it actually has only 1/4 the intensity.

Question 14

Two seismic waves from different earthquakes are measured at the same station. The ground displacement amplitude of Wave X is 5 times the amplitude of Wave Y, and both waves have similar frequency content for this comparison. Using E∝A2E \propto A^2E∝A2, what is the energy ratio EX/EYE_X/E_YEX​/EY​?

  1. 555
  2. 101010
  3. 252525 (correct answer)
  4. 1/251/251/25

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. For comparing waves: Wave X has amplitude 5 times that of Wave Y, so we calculate the energy ratio E_X/E_Y = (A_X/A_Y)² = 5² = 25—Wave X has 5 times the amplitude of Wave Y, so it carries 25 times as much energy despite having only 5 times the ground displacement. Choice C is correct because it properly applies the squared relationship E ∝ A² to show that having 5 times the amplitude means 25 times the energy. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that 5 times the amplitude means 5 times the energy, when actually the relationship is quadratic (E ∝ A²) so 5 times the amplitude means 25 times the energy—this is why the answer is a factor of 25, not 5. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A increases 5-fold, E increases by 5² = 25), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 25-fold, A increases by √25 = 5), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Real-world applications of E ∝ A²: in earthquakes, a seismic wave with 5 times the ground displacement carries 25 times more energy, explaining why seemingly modest increases in earthquake magnitude (which relates to amplitude) result in dramatically more destructive power—this is why a magnitude 7 earthquake (roughly 10× the amplitude of magnitude 6) releases about 32× more total energy.

Question 15

A lab handout states that for waves of the same type traveling in the same medium (with frequency unchanged), the energy carried by the wave depends on amplitude according to E=kA2E = kA^2E=kA2 for some constant kkk. Which statement correctly describes the relationship between amplitude and energy?

  1. Energy is proportional to amplitude: E∝AE \propto AE∝A
  2. Energy is proportional to amplitude squared: E∝A2E \propto A^2E∝A2 (correct answer)
  3. Energy is inversely proportional to amplitude: E∝1/AE \propto 1/AE∝1/A
  4. Energy is proportional to amplitude cubed: E∝A3E \propto A^3E∝A3

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. For identifying the relationship: The mathematical relationship is E = kA² where k is a constant depending on the medium, frequency, and other wave properties—the key insight is the squared dependence, which appears in intensity of sound (I ∝ A²), power in water waves (P ∝ A²), and brightness of light (brightness ∝ A²), all reflecting the fundamental E ∝ A² relationship stated in the problem. Choice B is correct because it correctly identifies that energy is proportional to amplitude squared, matching the given formula E = kA². Choice A incorrectly states a linear relationship E ∝ A, which would mean doubling amplitude doubles energy, when the correct relationship E ∝ A² means doubling amplitude quadruples energy—this distinction is crucial because it determines that increasing amplitude has a much stronger effect on energy than a simple proportional relationship would suggest. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 4-fold, A increases by √4 = 2), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this universal E ∝ A² relationship applies to all wave types because it emerges from the fundamental physics of oscillating systems storing energy in both kinetic and potential forms.

Question 16

A sound wave’s energy carried per unit time (and intensity at a fixed point) follows E∝A2E \propto A^2E∝A2. A speaker’s amplitude control is increased so the amplitude becomes 1.5 times the original value, with frequency unchanged. By what factor does the energy carried by the wave change?

  1. Increases by a factor of 1.5
  2. Increases by a factor of 2.25 (correct answer)
  3. Increases by a factor of 3.0
  4. Decreases by a factor of 2.25

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you increase amplitude by 1.5 times (A → 1.5A), the energy increases by a factor of 2.25 (E → 2.25E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. When amplitude becomes 1.5 times the original value, we calculate the energy change using the squared relationship: E₂/E₁ = (A₂/A₁)² = (1.5A/A)² = 1.5² = 2.25, so the energy increases by a factor of 2.25—increasing amplitude by 50% (factor of 1.5) increases energy by 125% (factor of 2.25). Choice B is correct because it properly applies the squared relationship E ∝ A² to show that increasing amplitude by a factor of 1.5 increases energy by 1.5² = 2.25. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that increasing amplitude by 1.5 times increases energy by 1.5 times, when actually the relationship is quadratic (E ∝ A²) so 1.5 times the amplitude means 2.25 times the energy—this is why the answer is a factor of 2.25, not 1.5. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A increases by 1.5, E increases by 1.5² = 2.25), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 2.25-fold, A increases by √2.25 = 1.5), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Real-world applications of E ∝ A²: in sound systems, increasing the speaker cone displacement by just 50% (1.5×) requires 2.25 times as much power—this explains why small increases in volume control can lead to significant increases in power consumption, and why audio amplifiers need substantial power reserves to handle even modest increases in output level.

Question 17

A loudspeaker produces a sound wave in air. The speaker is adjusted so the wave’s amplitude increases from A1=0.20 mmA_1 = 0.20\ \text{mm}A1​=0.20 mm to A2=0.60 mmA_2 = 0.60\ \text{mm}A2​=0.60 mm while frequency stays the same. For sound waves, the energy carried is proportional to the square of amplitude: E∝A2E \propto A^2E∝A2. By what factor does the wave’s energy change?

  1. Increases by a factor of 3
  2. Increases by a factor of 9 (correct answer)
  3. Increases by a factor of 1.5
  4. Decreases by a factor of 9

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. When amplitude increases from A₁ = 0.20 mm to A₂ = 0.60 mm, we calculate the energy change using the squared relationship: E₂/E₁ = (A₂/A₁)² = (0.60/0.20)² = 3² = 9, so the energy increases by a factor of 9—the amplitude tripled, so energy increased by 3² = 9. Choice B is correct because it properly applies the squared relationship E ∝ A² to show that tripling the amplitude increases energy by a factor of 9. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that tripling amplitude triples energy, when actually the relationship is quadratic (E ∝ A²) so tripling amplitude increases energy ninefold—this is why the answer is a factor of 9, not 3. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A triples, E increases by 3² = 9), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Real-world applications of E ∝ A²: in sound, tripling the amplitude creates a sound that's 9 times more intense but only perceived as moderately louder due to logarithmic human hearing; this explains why a speaker needs 9 times more power to triple the displacement of the speaker cone, making high-volume audio systems power-hungry.

Question 18

A water wave tank produces surface waves of the same wavelength and speed. Wave A has height (amplitude) AA=0.50 mA_A = 0.50\ \text{m}AA​=0.50 m and Wave B has height AB=1.50 mA_B = 1.50\ \text{m}AB​=1.50 m. If the energy carried by the waves is proportional to amplitude squared, E∝A2E \propto A^2E∝A2, how do their energies compare (ratio EB/EAE_B/E_AEB​/EA​)?

  1. 333
  2. 999 (correct answer)
  3. 1/31/31/3
  4. 1/91/91/9

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. For comparing waves: Wave A has amplitude A_A = 0.50 m and Wave B has amplitude A_B = 1.50 m, so we calculate the energy ratio E_B/E_A = (A_B/A_A)² = (1.50/0.50)² = 3² = 9—Wave B has three times the amplitude of Wave A, so it carries 9 times as much energy despite having only three times the height. Choice B is correct because it properly applies the squared relationship E ∝ A² to show that tripling amplitude increases energy 9-fold. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that tripling amplitude triples energy, when actually the relationship is quadratic (E ∝ A²) so tripling amplitude increases energy ninefold—this is why the answer is a factor of 9, not 3. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A triples, E increases by 3² = 9), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Real-world applications of E ∝ A²: in water waves, tripling wave height increases the energy ninefold, explaining why a 1.5-meter tsunami carries 9 times more energy than a 0.5-meter wave—this quadratic relationship is why even modest increases in tsunami height lead to dramatically more destructive power, as the force on structures and the ability to move debris scales with the wave's energy content.

Question 19

For a sound wave at constant frequency, which statement correctly describes how the wave’s energy depends on amplitude?

  1. Energy is proportional to amplitude: E∝AE \propto AE∝A
  2. Energy is proportional to the square of amplitude: E∝A2E \propto A^2E∝A2 (correct answer)
  3. Energy is inversely proportional to amplitude: E∝1/AE \propto 1/AE∝1/A
  4. Energy is proportional to the cube of amplitude: E∝A3E \propto A^3E∝A3

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. The mathematical relationship is E = kA² where k is a constant depending on the medium, frequency, and other wave properties—the key insight is the squared dependence, which appears in intensity of sound (I ∝ A²), power in water waves (P ∝ A²), and brightness of light (brightness ∝ A²), all reflecting the fundamental E ∝ A² relationship. Choice B is correct because it correctly identifies that energy is proportional to amplitude squared. Choice A incorrectly treats the relationship as linear (E ∝ A), claiming that doubling amplitude doubles energy, when actually the relationship is quadratic (E ∝ A²) so doubling amplitude quadruples energy—this distinction is crucial because it determines that tripling amplitude increases energy 9-fold (3² = 9) not 3-fold. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Real-world applications of E ∝ A²: in sound, doubling the amplitude creates a sound that's 4 times more intense but only perceived as slightly louder due to logarithmic human hearing; in earthquakes, each step up in Richter scale represents 10× more amplitude but about 32× more energy (roughly 10^1.5); in water waves, doubling wave height quadruples the energy, explaining why large tsunami waves are so devastating despite not looking enormously tall when viewed from space.

Question 20

A light (electromagnetic) wave has intensity I∝A2I \propto A^2I∝A2. If the intensity increases by a factor of 16 (for example, a spotlight appears much brighter), by what factor did the wave’s amplitude increase?

  1. 2
  2. 4 (correct answer)
  3. 8
  4. 16

Explanation: This question tests understanding of the relationship between wave amplitude and wave energy. Wave energy is proportional to the amplitude squared: E ∝ A², which means if you double the amplitude (A → 2A), the energy increases by a factor of 4 (E → 4E), and if you triple the amplitude (A → 3A), the energy increases by a factor of 9 (E → 9E)—this squared relationship is fundamental to all types of waves including sound, water, seismic, and light waves. If intensity increases by a factor of 16, we solve for amplitude change: I₂/I₁ = (A₂/A₁)² = 16, taking square root of both sides gives A₂/A₁ = √16 = 4, so amplitude must increase by a factor of 4—to increase intensity 16-fold requires only quadrupling the amplitude because 4² = 16. Choice B is correct because it accurately uses square root relationship to find amplitude change from intensity change. Choice D incorrectly reverses the relationship, confusing the intensity factor (16) with the amplitude factor (4)—when intensity increases 16-fold, amplitude increases only 4-fold (not 16-fold) because we must take the square root: A₂/A₁ = √(I₂/I₁) = √16 = 4. To solve amplitude-energy problems, remember the formula E₂/E₁ = (A₂/A₁)²: (1) if asked how energy changes when amplitude changes, square the amplitude factor (if A doubles, E increases by 2² = 4), (2) if asked how amplitude changes when energy changes, take the square root of the energy factor (if E increases 9-fold, A increases by √9 = 3), and (3) always check your answer makes sense—larger amplitude must mean more energy, and the relationship is stronger than linear (energy grows faster than amplitude). Physical intuition: the squared relationship makes sense because wave energy depends on both how far particles oscillate (amplitude) and how fast they oscillate back—both effects scale with amplitude, so total energy scales as amplitude squared; this is why increasing speaker volume slightly requires significantly more power, why tsunamis with modest height increase carry devastating energy, and why a magnitude 7 earthquake (10× amplitude of magnitude 6) releases roughly 32× more energy (actually 10² in displacement but ~32× in total energy released).