All questions
Question 1
Consider the constrained optimization: minimize f(x,y)=(x−3)2+(y−4)2 subject to x+y=5. The Lagrange multiplier at the solution is λ=−1. A student argues: "Since λ<0, increasing the constraint constant will decrease the objective function, which contradicts the fact that we're moving away from the unconstrained minimum at (3,4)." What is the flaw in this reasoning?
- The student incorrectly calculated the sign of the Lagrange multiplier
- The student confused the constrained minimum with the unconstrained minimum
- The student correctly identified a contradiction, indicating an error in the problem setup
- The student failed to consider that moving away from unconstrained minimum can still decrease the constrained objective value (correct answer)
Explanation: When analyzing Lagrange multipliers in constrained optimization, you need to understand what the multiplier's sign tells you about how changes in the constraint affect the objective function.
The student's reasoning contains a subtle but critical flaw. They correctly note that λ=−1<0 means increasing the constraint constant (changing x+y=5 to x+y=5+ϵ) will decrease the objective function value. They also correctly observe that this moves the feasible region further from the unconstrained minimum at (3,4). However, they incorrectly assume this creates a contradiction.
Here's the key insight: moving away from the unconstrained minimum doesn't automatically mean the constrained objective value must increase. The constraint forces you onto a different point entirely, and the geometry of both the objective function and constraint determines the net effect. In this problem, the particular direction of movement (determined by the constraint line x+y=5) happens to decrease the objective function value even though you're moving away from (3,4).
Option A is wrong because λ=−1 is given as correct. Option B misses the point—the student understands the difference between constrained and unconstrained minima. Option C incorrectly validates the student's flawed reasoning when no contradiction actually exists.
Study tip: When interpreting Lagrange multipliers, focus on the local relationship between constraint changes and objective function changes. The sign of λ tells you about this local sensitivity, regardless of global geometry like distance from unconstrained optima. Question 2
A company maximizes its profit function P(L,K) subject to a budgetary constraint C(L,K) = B. For the current budget B = 50000, the maximum profit is $2,100,000. Using the method of Lagrange multipliers, the value of the multiplier is found to be λ = 45. If the budget is increased to B = 51000, what is the approximate new maximum profit?
- $2,100,045
- $2,145,000 (correct answer)
- $2,055,000
- $2,100,000 / 45
Explanation: The Lagrange multiplier λ represents the rate of change of the optimal value of the objective function with respect to the constraint constant. Here, λ = dP_{max}/dB. The change in the budget is ΔB = 51000 - 50000 = 1000. The approximate change in maximum profit is ΔP_{max} ≈ λ * ΔB = 45 * 1000 = 45000. The new approximate maximum profit is the original profit plus this change: $2,100,000 + $45,000 = $2,145,000.
Question 3
The potential energy E(x,y) of a particle is minimized while it is constrained to a path g(x,y) = c. For c = 4, the minimum energy is E_{min} = 12 joules. The corresponding Lagrange multiplier is λ = -3.5 J/m. What is the approximate minimum energy if the constraint is changed to g(x,y) = 3.8?
- 11.3 J
- 12.7 J (correct answer)
- 11.6 J
- 12.4 J
Explanation: The Lagrange multiplier λ approximates the rate of change of the minimum value with respect to the constraint constant c. The change in the constraint is Δc = 3.8 - 4.0 = -0.2 m. The approximate change in minimum energy is ΔE_{min} ≈ λ * Δc = (-3.5 J/m) * (-0.2 m) = +0.7 J. The new approximate minimum energy is E_{new} ≈ E_{min} + ΔE_{min} = 12 J + 0.7 J = 12.7 J.
Question 4
A factory's daily production P is measured in widgets. The cost of production C, a function of inputs x and y, is measured in dollars. To solve the problem of maximizing production for a fixed cost C = k, a Lagrange multiplier λ is used. What are the units of λ?
- Dollars
- Dollars per widget
- Widgets
- Widgets per dollar (correct answer)
Explanation: When you encounter Lagrange multiplier problems, focus on understanding what λ represents: the rate of change of the objective function with respect to the constraint level. Here, you're maximizing production P subject to a fixed cost constraint C(x,y) = k.
The Lagrange multiplier λ equals ∂k∂P, meaning it tells you how much additional production you could achieve if you increased your budget by one dollar. Since P is measured in widgets and k (the cost constraint) is measured in dollars, λ has units of dollarwidgets, making (D) Widgets per dollar correct.
Let's examine why the other options fail: (A) Dollars would imply λ represents some absolute monetary value, but multipliers are always rates of change, not absolute quantities. (B) Dollars per widget represents the inverse relationship - this would tell you the cost per additional widget rather than the production gain per additional dollar. (C) Widgets suggests λ measures an absolute production quantity, but again, Lagrange multipliers measure sensitivity, not totals.
Think of λ as your "bang for your buck" - if λ = 3, spending one more dollar on production inputs would yield 3 additional widgets. This economic interpretation makes the widgets-per-dollar units intuitive.
Study tip: For any Lagrange multiplier problem, always check units by remembering that λ = ∂(constraint level)∂(objective). The units will always be objective function units divided by constraint parameter units. Question 5
The maximum value of a function f(x,y) subject to a constraint g(x,y) = 100 is 750. When the constraint is changed to g(x,y) = 102, the maximum value of f becomes approximately 741. Based on this information, what is the best estimate for the Lagrange multiplier λ associated with the original problem?
- -9.0
- 4.5
- -4.5 (correct answer)
- -0.22
Explanation: When you encounter constrained optimization problems with changing constraint values, you're dealing with the economic interpretation of Lagrange multipliers. The Lagrange multiplier λ represents the rate of change of the optimal value with respect to changes in the constraint level.
The key insight is that λ approximates how much the maximum value of f changes when the constraint value increases by one unit. You can estimate λ using the formula: λ ≈ (change in optimal value)/(change in constraint value).
Here, when the constraint changed from g(x,y) = 100 to g(x,y) = 102, the maximum value dropped from 750 to 741. So: λ ≈ (741 - 750)/(102 - 100) = -9/2 = -4.5.
The negative sign makes economic sense—as the constraint becomes more restrictive (higher constraint value), the maximum achievable value of f decreases.
Looking at the wrong answers: (A) -9.0 represents the total change in the objective function but ignores that this change occurred over 2 units of constraint change, not 1. (B) 4.5 has the correct magnitude but wrong sign—this would suggest the maximum increases as the constraint tightens, which contradicts the given data. (D) -0.22 appears to invert the calculation, computing (change in constraint)/(change in optimal value) instead.
The answer is (C) -4.5.
Remember: Lagrange multipliers measure sensitivity—how responsive your objective function is to constraint changes. Always check that the sign makes intuitive sense given whether tightening the constraint helps or hurts your objective.
Question 6
A company wishes to maximize production P(x,y) subject to two separate constraints: a budget constraint B(x,y) ≤ 50000 and a resource constraint R(x,y) ≤ 300. Analyzing each constraint as an equality, the Lagrange multiplier for the budget constraint is λ_B = 1.2, and for the resource constraint is λ_R = 2.5. If the company can afford to increase the budget by $1000 or increase the resource limit by 400 units for the same cost, which is the better strategy to increase production?
- Increase the budget, as
λ_B is smaller, indicating it is a less restrictive constraint. - Increase the resources, as it yields an approximate production increase of 1000 units.
- Increase the budget, as it yields an approximate production increase of 1200 units. (correct answer)
- Both strategies are equally effective.
Explanation: When you encounter Lagrange multiplier problems with multiple constraints, remember that each multiplier tells you the marginal benefit per unit increase in that constraint's limit. The multiplier represents how much the objective function (production, in this case) increases when you relax the constraint by one unit.
For the budget constraint, λB=1.2 means production increases by approximately 1.2 units per additional dollar. Since the company can increase the budget by $1000, the expected production increase is $1000×1.2=1200 $ units.
For the resource constraint, \lambda_R = 2.5 means production increases by 2.5 units per additional resource unit. With an increase of 400 resource units, the expected production increase is 400 \times 2.5 = 1000 units.
Answer C is correct because increasing the budget yields approximately 1200 additional production units, which exceeds the 1000 units from increasing resources.
Answer A misinterprets what the multiplier values mean—a smaller \lambda doesn't indicate a "less restrictive" constraint, but rather lower marginal benefit per unit increase. Answer B correctly calculates the resource strategy's benefit (1000 units) but fails to recognize that the budget strategy yields more. Answer D is wrong because 1200 ≠ 1000.
Study tip: Always multiply the Lagrange multiplier by the proposed change in the constraint limit to find the approximate change in your objective function. The strategy with the highest resulting value is optimal. Question 7
A power plant minimizes its operating cost C(x,y) in dollars per hour, subject to the constraint that its power output P(x,y) is exactly k megawatts (MW). For an output of k=500 MW, the Lagrange multiplier is found to be λ = 400. Which of the following is the most accurate interpretation of this value?
- To increase the power output from 500 MW to 501 MW, the minimum operating cost will increase by approximately $400/hour. (correct answer)
- To increase the power output from 500 MW to 501 MW, the minimum operating cost will decrease by approximately $400/hour.
- The minimum cost to produce 500 MW of power is $400/hour.
- For every $400/hour increase in cost, the power output will increase by 1 MW.
Explanation: The problem is to minimize cost C subject to a production constraint P=k. The Lagrange multiplier λ = dC_{min}/dk. A positive λ means that increasing the constraint k will increase the minimum value of the objective function C. Specifically, a λ=400 means that increasing the required output k by 1 MW will increase the minimum cost C_{min} by approximately $400/hour.
Question 8
A student is maximizing a utility function U(x,y) subject to a budget constraint B(x,y) = M. For a budget M = 100, they find the maximum utility is 50 utils and the Lagrange multiplier is λ = 0.8. The student is then asked to find the maximum utility for a new budget of M = 105. They calculate the new utility to be 50 + 0.8 * (5) = 54. Which statement best describes the student's result?
- The result of 54 is an exact value for the new maximum utility.
- The result of 54 is an approximation of the new maximum utility. (correct answer)
- The true maximum utility must be less than 54.
- The calculation is incorrect; the change in utility should be
5 / 0.8.
Explanation: The Lagrange multiplier provides a linear approximation of the change in the optimal value. The formula ΔU_{max} ≈ λ * ΔM is an approximation, not an exact equality, because the rate of change λ is itself a function of M and is only constant for linear problems. Therefore, the calculated value of 54 is an estimate, not an exact value.
Question 9
Let M(k) be the maximum value of a function f(x,y) subject to the constraint g(x,y)=k. The equation ∇f = λ∇g is used to find the maximum. Which expression correctly relates the Lagrange multiplier λ to the function M(k)?
λ = M(k)λ = M'(k) (correct answer)λ = -M'(k)λ is independent of M(k)
Explanation: The function M(k) gives the optimal (maximum) value of f for a given constraint level k. The Lagrange multiplier λ is precisely the instantaneous rate of change of this optimal value with respect to k. The rate of change of M(k) with respect to k is its derivative, M'(k). Thus, λ = M'(k).
Question 10
When minimizing f(x,y) subject to g(x,y)=k, the Lagrange multiplier λ is positive. When maximizing the same function f(x,y) subject to the same constraint g(x,y)=k, the Lagrange multiplier μ is also positive. What can be concluded if the constraint is relaxed by increasing k to k+Δk where Δk > 0?
- The minimum value of
f will increase, and the maximum value of f will increase. (correct answer) - The minimum value of
f will increase, and the maximum value of f will decrease. - The minimum value of
f will decrease, and the maximum value of f will increase. - The minimum value of
f will decrease, and the maximum value of f will decrease.
Explanation: The Lagrange multiplier λ represents the rate of change of the optimal value with respect to the constraint constant k. For the minimization problem, λ = df_{min}/dk > 0. This means that as k increases, f_{min} increases. For the maximization problem, μ = df_{max}/dk > 0. This means that as k increases, f_{max} also increases. Therefore, relaxing the constraint by increasing k causes both the minimum and maximum values to increase.
Question 11
A function f(x,y,z) is maximized subject to two constraints: g(x,y,z) = 20 and h(x,y,z) = 30. The corresponding Lagrange multipliers are λ_1 = 8 (for g) and λ_2 = -5 (for h). What is the approximate change in the maximum value of f if the first constraint is changed to 19.5 and the second constraint is changed to 30.2?
- An increase of 3.0
- A decrease of 3.0
- A decrease of 5.0 (correct answer)
- An increase of 5.0
Explanation: When you encounter a constrained optimization problem asking about changes in constraints, you're dealing with the geometric interpretation of Lagrange multipliers. The key insight is that Lagrange multipliers tell you how sensitive the optimal value is to small changes in the constraint levels.
The Lagrange multiplier λ1=8 means that if you increase the constraint g(x,y,z)=20 by a small amount, the maximum value of f increases by approximately 8 times that amount. Similarly, λ2=−5 means that increasing h(x,y,z)=30 decreases the maximum value by approximately 5 times the change.
For the given changes: the first constraint changes from 20 to 19.5 (a decrease of 0.5), and the second changes from 30 to 30.2 (an increase of 0.2). The total approximate change in f is:
Δf≈λ1(−0.5)+λ2(0.2)=8(−0.5)+(−5)(0.2)=−4−1=−5
This confirms answer C: a decrease of 5.0.
Answer A incorrectly adds the magnitudes without considering signs. Answer B uses the wrong magnitude, possibly from miscalculating one of the constraint changes. Answer D has both the wrong sign and wrong reasoning about how multipliers work.
Remember: Lagrange multipliers are rates of change. Positive multipliers mean the objective function increases when that constraint level increases, while negative multipliers indicate the opposite relationship. Question 12
A constrained optimization problem yields λ=12 at the optimal solution. When the constraint constant increases by 0.1, the actual change in the objective function is 1.15, while the Lagrange multiplier predicts a change of 1.2. When the constraint constant decreases by 0.1, the actual change is -1.25. What does this pattern suggest about the relationship between the objective function and constraint?
- The objective function is linear in the constraint, so the discrepancies indicate computational errors
- The objective function has positive curvature, making the linear approximation optimistic for increases and pessimistic for decreases
- The objective function has negative curvature, making the linear approximation pessimistic for increases and optimistic for decreases (correct answer)
- The Lagrange multiplier interpretation only applies to constraint increases, not decreases
Explanation: The Lagrange multiplier gives a linear approximation. For increases: predicted = 1.2, actual = 1.15 (less than predicted). For decreases: predicted = -1.2, actual = -1.25 (more negative than predicted). This suggests the function curves downward (negative curvature/concavity), making the linear tangent an overestimate for increases and underestimate for decreases. Choice A ignores systematic pattern. Choice B has curvature backwards. Choice D incorrectly limits the multiplier's applicability.
Question 13
A manufacturer wants to minimize the cost C(x,y)=2x2+3y2+xy subject to the constraint x+2y=100, where x and y represent quantities of two materials. At the optimal solution, the Lagrange multiplier is λ=15. If the constraint were changed to x+2y=101, what would be the approximate new minimum cost?
- The cost would increase by approximately 15 units (correct answer)
- The cost would decrease by approximately 15 units
- The cost would increase by approximately 30 units
- The cost would remain approximately the same
Explanation: The Lagrange multiplier λ represents the rate of change of the objective function with respect to changes in the constraint constant. Since λ = 15 and the constraint increased from 100 to 101 (change of +1), the cost increases by approximately λ × (change) = 15 × 1 = 15 units. Choice B has the wrong sign. Choice C incorrectly doubles the multiplier. Choice D ignores the multiplier interpretation.
Question 14
For the optimization problem: maximize f(x,y)=xy subject to x2+y2=50, the Lagrange multiplier at the optimal solution is λ=0.5. If we instead optimize subject to x2+y2=49, and then subject to x2+y2=51, which statement about the optimal values is most accurate?
- Both new optimal values will be approximately 0.5 units different from the original
- The constraint x2+y2=49 gives optimal value about 0.5 less, x2+y2=51 gives about 0.5 more (correct answer)
- The constraint x2+y2=49 gives optimal value about 0.5 more, x2+y2=51 gives about 0.5 less
- The Lagrange multiplier interpretation doesn't apply since this involves a quadratic constraint
Explanation: The Lagrange multiplier λ=0.5 represents df/dc where c is the constraint constant. For x²+y²=49, c decreases by 1, so f decreases by approximately λ×(-1) = -0.5. For x²+y²=51, c increases by 1, so f increases by approximately λ×(+1) = +0.5. Choice A ignores direction. Choice C has the directions reversed. Choice D incorrectly claims the interpretation doesn't apply to quadratic constraints.
Question 15
A production function P(L,K)=10L0.3K0.7 is maximized subject to the budget constraint 20L+50K=1000, where L is labor and K is capital. At the optimal allocation, λ=0.25. The firm's economist claims that hiring one additional unit of labor (changing the constraint to 20L+50K=1020) would increase production by approximately 0.25 units. What is wrong with this analysis?
- The economist correctly identified the constraint change but miscalculated the production increase (correct answer)
- The economist should have multiplied λ by the price of labor, not used λ directly
- The economist correctly applied the multiplier but ignored diminishing returns
- The economist failed to account for the simultaneous change in capital that the budget increase allows
Explanation: To hire one additional unit of labor at price $20, the budget must increase by $20, changing the constraint to 20L + 50K = 1020. The economist correctly identified this budget change. However, with λ = 0.25, the production increase would be approximately λ × (budget change) = 0.25 × 20 = 5 units, not 0.25 units. The economist used λ directly instead of multiplying by the constraint change.
Question 16
A utility maximization problem has the form: maximize U(x,y)=x0.6y0.4 subject to 3x+2y=100. At the optimal solution, the Lagrange multiplier is λ=0.15. An economist interprets this as "the marginal utility of income is 0.15." If a consumer's budget increases from $100 to $105, by how much should their maximum utility change?
- The utility should increase by a factor of approximately e0.75
- The utility should increase by a factor of approximately 1.75
- The utility should increase by approximately 0.75 units (correct answer)
- The utility should increase by approximately 0.15 units per dollar, so 0.75 units total
Explanation: The Lagrange multiplier represents the rate of change of the objective function (utility) with respect to the constraint constant (budget). With λ = 0.15 and budget increase of $5, the utility increases by approximately 0.15 × 5 = 0.75 units. This is an additive change, not multiplicative. Choice A incorrectly applies exponential growth. Choice B confuses multiplicative vs additive change. Choice D restates the calculation correctly but is unnecessarily verbose compared to the direct answer in C.
Question 17
For the problem: maximize f(x,y)=2ln(x)+3ln(y) subject to x+2y=20, the optimal solution has λ=0.4. Two scenarios are considered: (A) changing the constraint to x+2y=22, and (B) changing the constraint to x+2y=18. The Lagrange multiplier interpretation predicts that scenario A increases the objective by 0.8 and scenario B decreases it by 0.8. Why might this approximation be less reliable for scenario B than scenario A?
- Scenario B involves a larger percentage change in the constraint constant
- Logarithmic functions have different curvature properties for increases vs decreases
- Negative changes in constraint constants invalidate the Lagrange multiplier interpretation
- The constraint in scenario B might force the solution closer to the boundary where x or y approaches zero (correct answer)
Explanation: When you encounter Lagrange multiplier problems with changing constraints, you need to understand that λ represents the marginal rate of change of the objective function with respect to the constraint constant. However, this linear approximation becomes less reliable when changes push the solution toward problematic regions.
The correct answer is D because scenario B reduces the constraint from x+2y=20 to x+2y=18, forcing the optimization to work with a smaller feasible region. Since we're maximizing f(x,y)=2ln(x)+3ln(y), the logarithmic functions are undefined when x or y approach zero. As the constraint becomes tighter, the optimal solution gets pushed closer to these boundaries where the logarithms become problematic. Near these boundaries, the function's behavior becomes highly nonlinear, making the linear approximation Δf≈λ⋅Δb much less accurate.
A is incorrect because both scenarios involve the same absolute change (2 units), so percentage considerations don't explain the asymmetry. B is wrong because logarithmic functions have the same mathematical properties regardless of whether inputs increase or decrease—the curvature doesn't change directionally. C is false because negative changes in constraint constants are perfectly valid in Lagrange multiplier analysis; the method works for both increases and decreases.
Study tip: When analyzing Lagrange multiplier approximations, always check whether constraint changes push solutions toward regions where the objective function becomes undefined or highly nonlinear. The approximation breaks down fastest near these problematic boundaries. Question 18
A Lagrange multiplier problem has two constraints: g1(x,y,z)=x+y+z−15=0 and g2(x,y,z)=x2+y2+z2−50=0. At the optimal solution, λ1=8 and λ2=1.2. If both constraint constants change simultaneously to x+y+z=16 and x2+y2+z2=48, what is the approximate change in the optimal objective function value?
- An increase of approximately 9.2 units
- An increase of approximately 5.6 units (correct answer)
- A decrease of approximately 2.4 units
- A decrease of approximately 1.6 units
Explanation: For multiple constraints, the total change is approximately Σ(λᵢ × Δcᵢ). Here: Δc₁ = 16-15 = +1, Δc₂ = 48-50 = -2. Total change ≈ λ₁×Δc₁ + λ₂×Δc₂ = 8×(+1) + 1.2×(-2) = 8 - 2.4 = 5.6. Choice A adds the magnitudes incorrectly (8 + 1.2 = 9.2). Choice C uses only the second term (1.2×(-2) = -2.4). Choice D makes a sign error.
Question 19
While maximizing f(x,y) subject to g(x,y)=k, the Lagrange multiplier is found to be λ=0. What is the most direct implication for the function f at the solution point?
- The unconstrained optimum of
f lies on the constraint curve g(x,y)=k. (correct answer) - The function
f has a value of zero at the solution point. - The constraint
g(x,y)=k is a line. - No solution to the constrained optimization problem exists.
Explanation: The Lagrange multiplier equation is ∇f = λ∇g. If λ=0, this implies ∇f = 0 at the solution point. ∇f = 0 is the condition for an unconstrained local extremum. Therefore, a Lagrange multiplier of zero means that the constraint is not active; the unconstrained extremum of f happens to satisfy the constraint g(x,y)=k.