All questions
Question 1
A student tests the same cart with several net forces and records acceleration.
Which calculation would stay constant for every trial if the cart's mass does not change?
- a/Fnet
- Fnet+a
- Fnet/a (correct answer)
- Fnet×a
Explanation: This question tests understanding that for constant mass, the ratio F_net/a remains constant according to Newton's Second Law: F_net = ma. Rearranging gives F_net/a = m, which means for the same cart (constant mass), every trial should yield the same value when dividing net force by acceleration—this ratio equals the cart's mass. For any data point, F_net/a gives the mass: if F_net = 10 N and a = 5 m/s², then m = 10/5 = 2 kg; if F_net = 20 N and a = 10 m/s², then m = 20/10 = 2 kg—the ratio stays constant at 2 kg regardless of the specific force or acceleration values. Choice C is correct because F_net/a equals mass, which remains constant for the same cart throughout all trials—this is the mathematical expression of Newton's Second Law rearranged to show what stays constant. Choice A (a/F_net) gives 1/m which varies inversely with mass but isn't the mass itself; Choice B (F_net + a) has no physical meaning and changes with each trial; Choice D (F_net × a) also varies with each trial and doesn't represent any fundamental quantity. Understanding constant ratios in physics: (1) F_net/a = m (Newton's Second Law), (2) this ratio reveals the object's inertial mass, (3) larger mass means larger ratio (more force needed per unit acceleration), (4) this constancy allows us to identify objects by their force-acceleration behavior—just as density (mass/volume) identifies materials, the F/a ratio identifies an object's resistance to acceleration.
Question 2
A cart has a constant mass of 2 kg. During a test, the measured acceleration is 6 m/s2. What net force Fnet must be acting on the cart?
- 3 N
- 8 N
- 12 N (correct answer)
- 18 N
Explanation: This question tests direct application of Newton's Second Law: F_net = ma. Given the cart's mass (m = 2 kg) and measured acceleration (a = 6 m/s²), we can calculate the net force by multiplying: F_net = ma = (2 kg)(6 m/s²) = 12 N. This calculation shows that a 12 N net force is required to accelerate a 2 kg mass at 6 m/s². The units work out correctly: kg⋅m/s² = N (Newton), confirming our calculation. We can verify this makes sense: if the same 2 kg cart experienced only 6 N of net force, it would accelerate at 3 m/s² (half the acceleration for half the force), demonstrating the proportional relationship. Choice C is correct because F_net = ma = (2 kg)(6 m/s²) = 12 N. Choice A (3 N) appears to divide mass by acceleration instead of multiplying; Choice B (8 N) might come from adding mass and acceleration instead of multiplying; Choice D (18 N) might come from multiplying all three numbers (2 × 6 × 1.5) or some other calculation error. This problem demonstrates the fundamental relationship between force, mass, and acceleration: knowing any two allows calculation of the third—this principle is used constantly in engineering to determine required forces for desired accelerations (rocket thrust, brake force, etc.) or to predict motion when forces are known.
Question 3
A 2 kg cart is pushed so the net force is 5 N, then 10 N, then 15 N. The measured accelerations are 2.5 m/s2, 5.0 m/s2, and 7.5 m/s2.
Based on this pattern, what acceleration should the cart have if the net force is increased to 20 N (same cart)?
- 10 m/s2 (correct answer)
- 7.5 m/s2
- 5 m/s2
- 40 m/s2
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = ma. The data show a direct proportional relationship between net force and acceleration: when net force increases, acceleration increases by the same factor (double the force → double the acceleration), and when net force decreases, acceleration decreases proportionally—this relationship is linear, meaning if you graph F_net (x-axis) vs acceleration (y-axis), you get a straight line through the origin, and the slope of that line equals 1/m (the reciprocal of the object's mass). This proportionality is Newton's Second Law: F_net = ma, which can be rearranged to a = F_net/m, showing that for constant mass, acceleration is directly proportional to net force. Looking at the data: when net force is 5 N, acceleration is 2.5 m/s², when net force increases to 10 N (doubled), acceleration increases to 5.0 m/s² (also doubled), and when net force increases further to 15 N (tripled from original), acceleration is 7.5 m/s² (also tripled)—this consistent doubling and tripling demonstrates perfect proportionality. The ratio F_net/a is constant throughout: 5/2.5 = 2, 10/5 = 2, 15/7.5 = 2 (this constant ratio equals the object's mass m = 2 kg in this example), confirming Newton's Second Law F_net = ma holds for all data points. Choice A is correct because it properly recognizes the linear pattern in graph or constant ratio in table / correctly predicts that increasing net force will proportionally increase acceleration, so for 20 N (double 10 N or quadruple 5 N), a = 10 m/s² (double 5 or quadruple 2.5). Choice B is wrong because it suggests there's no relationship or that acceleration is independent of force, when the data clearly show acceleration changes systematically with net force / makes incorrect prediction: claims doubling force would triple or halve acceleration, when proportionality means doubling force doubles acceleration. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data. Real investigations might show slight deviations from perfect line (measurement uncertainty, friction variations), but overall pattern should be clear: larger net forces produce larger accelerations proportionally—this relationship F_net = ma is one of the most fundamental in physics, describing how forces cause motion changes in everything from tiny molecules to planets, and collecting data to verify it experimentally (as students can do with carts, ramps, and force sensors) demonstrates how physics laws are not just theoretical but are actually observed patterns in nature that we can measure and test.
Question 4
A student pushes the same 2 kg cart on a smooth track with different net forces and measures the cart's acceleration. The results are shown below.
Force Fnet (N) | Acceleration a (m/s2)
0 | 0
5 | 2.5
10 | 5.0
15 | 7.5
What relationship between net force and acceleration is shown by the data?
- Acceleration decreases as net force increases (inverse relationship).
- Acceleration is directly proportional to net force; doubling Fnet doubles a. (correct answer)
- Acceleration stays the same no matter how large the net force is.
- The cart must have at least 10 N of net force before it can accelerate at all.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = ma. The data show a direct proportional relationship between net force and acceleration: when net force increases, acceleration increases by the same factor (double the force → double the acceleration), and when net force decreases, acceleration decreases proportionally—this relationship is linear, meaning if you graph F_net (x-axis) vs acceleration (y-axis), you get a straight line through the origin, and the slope of that line equals 1/m (the reciprocal of the object's mass). This proportionality is Newton's Second Law: F_net = ma, which can be rearranged to a = F_net/m, showing that for constant mass, acceleration is directly proportional to net force. Looking at the data: when net force is 5 N, acceleration is 2.5 m/s², when net force increases to 10 N (doubled), acceleration increases to 5.0 m/s² (also doubled), and when net force increases further to 15 N (tripled from original), acceleration is 7.5 m/s² (also tripled)—this consistent doubling and tripling demonstrates perfect proportionality. The ratio F_net/a is constant throughout: 5/2.5 = 2, 10/5 = 2, 15/7.5 = 2 (this constant ratio equals the object's mass m = 2 kg in this example), confirming Newton's Second Law F_net = ma holds for all data points. The straight line through the origin shows the proportional relationship clearly—the graph passes through (0,0) because zero net force produces zero acceleration (balanced forces), and increases linearly showing each additional Newton of force produces a consistent amount of additional acceleration. Choice B is correct because it accurately identifies the proportional relationship: F_net ∝ a or F_net = ma / correctly interprets the data showing that doubling force doubles acceleration / properly recognizes the linear pattern in graph or constant ratio in table / correctly predicts that increasing net force will proportionally increase acceleration. Choice A is wrong because it claims an inverse relationship (larger force → smaller acceleration) when the data clearly show the opposite: as force increases from 5 N to 10 N to 15 N, acceleration increases from 2.5 to 5.0 to 7.5 m/s² (both increase together). Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data. Real investigations might show slight deviations from perfect line (measurement uncertainty, friction variations), but overall pattern should be clear: larger net forces produce larger accelerations proportionally—this relationship F_net = ma is one of the most fundamental in physics, describing how forces cause motion changes in everything from tiny molecules to planets, and collecting data to verify it experimentally (as students can do with carts, ramps, and force sensors) demonstrates how physics laws are not just theoretical but are actually observed patterns in nature that we can measure and test.
Question 5
A class wants to collect data to show how net force affects motion for the same cart. They have a spring scale (to measure pulling force) and a motion sensor (to measure acceleration).
Which plan would best test the relationship between Fnet and acceleration while keeping the investigation fair?
- Use the same cart each time, apply several different measured net forces (like 5 N, 10 N, 15 N), and record the acceleration for each force. (correct answer)
- Change to a heavier cart each time and keep the same pulling force so the data are more varied.
- Apply random forces without measuring them, and record only how far the cart goes.
- Keep the net force the same and only change the time of the push to see if acceleration changes.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = m a, and how to design a fair experiment to verify this. To show the relationship, keep mass constant (same cart) and vary only F_net while measuring a—this isolates the effect of force on acceleration, ensuring a fair test. The best plan involves applying different measured net forces to the same cart and recording accelerations, allowing observation of the proportional pattern (e.g., doubling F_net doubles a). Choice A is correct because it uses the same cart each time, applies several different measured net forces, and records acceleration, which fairly tests the F_net-a relationship with controlled variables. Choice B is wrong because it changes to a heavier cart each time (varying mass) while keeping force the same, which would show mass's effect instead of force's, not isolating the F_net-a proportionality. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data.
Question 6
A student gives the same ball different pushes on a smooth floor. During each push, the contact time is about the same, Δt=0.5s. The student measures the ball's change in speed.
Data:
- Fnet=4N → Δv=1m/s
- Fnet=8N → Δv=2m/s
- Fnet=12N → Δv=3m/s
Which statement best describes the pattern between Fnet and the motion change?
- As Fnet increases, Δv increases in direct proportion (double the force gives double the speed change). (correct answer)
- As Fnet increases, Δv decreases.
- Δv is unrelated to Fnet because the contact time is the same.
- Δv increases only after the force passes a threshold of 10 N.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = m a, and since Δv = a Δt with fixed Δt, Δv is also proportional to F_net. The data show a direct proportional relationship between net force and change in speed: when net force doubles from 4 N to 8 N, Δv doubles from 1 to 2 m/s, and to 12 N (tripled from 4 N), Δv triples to 3 m/s—this linear pattern confirms Δv ∝ F_net for constant m and Δt. Looking at the data: the ratio F_net / Δv is constant at 4/1=4, 8/2=4, 12/3=4 (this relates to m / Δt, since Δv = (F_net / m) Δt), verifying the proportionality. Choice A is correct because it accurately describes the proportional relationship: as F_net increases, Δv increases in direct proportion, with doubling force giving double the speed change. Choice B is wrong because it claims Δv decreases as F_net increases, but the data show the opposite: Δv increases with F_net, not inversely. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass and extending to Δv predictions.
Question 7
A cart starts from rest and is pushed with different net forces for the same time interval, Δt=2s. The cart's mass stays the same in every trial.
Measured accelerations:
- Fnet=5N → a=2.5m/s2
- Fnet=10N → a=5.0m/s2
Using Δv=aΔt, what is the cart's change in speed when Fnet=10N is applied for 2s?
- 2.5m/s
- 5.0m/s
- 10.0m/s (correct answer)
- 20.0m/s
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = m a, and how this connects to change in velocity via Δv = a Δt for constant time. The data show a direct proportional relationship between net force and acceleration: for constant mass, a = F_net / m, so Δv = (F_net / m) Δt, meaning Δv is also proportional to F_net when Δt is fixed. Looking at the data: for 5 N, a=2.5 m/s², Δv=2.52=5 m/s; for 10 N, a=5.0 m/s² (doubled), so Δv=5.02=10 m/s (also doubled)—this demonstrates the proportionality extends to velocity change. Choice C is correct because it correctly calculates Δv = a Δt = 5.0 * 2 = 10 m/s for F_net=10 N, matching the pattern where doubling force doubles acceleration and thus doubles Δv. Choice B is wrong because it suggests 5.0 m/s, perhaps confusing Δv with a itself or using the wrong time, but the formula clearly gives 10 m/s. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data and predicting motion changes like Δv.
Question 8
A 2kg cart is pushed along a level track. The net force is changed while the cart's acceleration is measured.
Table: Fnet (N) vs. a (m/s2)
- 5 N → 2.5 m/s2
- 10 N → 5.0 m/s2
- 15 N → 7.5 m/s2
Based on the pattern in the data, what acceleration would you predict for Fnet=20N on the same cart?
- 10m/s2 (correct answer)
- 8m/s2
- 5m/s2
- 40m/s2
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = m a, allowing prediction of acceleration for new forces based on the pattern. The data show a direct proportional relationship between net force and acceleration: when net force doubles from 5 N to 10 N, acceleration doubles from 2.5 to 5.0 m/s², and from 5 N to 15 N (tripled), acceleration triples to 7.5 m/s²—this linear pattern means a = F_net / m, with m constant. Looking at the data: the ratio F_net/a is constant at 5/2.5=2, 10/5=2, 15/7.5=2, so m=2 kg; for 20 N, a = 20 / 2 = 10 m/s², following the same proportionality. Choice A is correct because it properly predicts that increasing net force to 20 N (quadrupled from 5 N) will quadruple the acceleration to 10 m/s², consistent with the linear pattern in the table. Choice B is wrong because it suggests 8 m/s², which would not fit the constant ratio (20/8=2.5, but data show 2); it miscalculates the pattern, perhaps confusing with a different mass or non-linear relationship. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data and predicting for new forces.
Question 9
A student tests the same cart each time and measures the following pairs of values:
Fnet (N): 5, 10, 15
a (m/s2): 2.5, 5.0, 7.5
Which statement is best supported by the constant ratio Fnet/a in the data?
- The mass of the cart is constant and equals Fnet/a for each trial. (correct answer)
- The cart's mass increases as the net force increases.
- The cart accelerates first, and that causes the net force to increase.
- Net force and acceleration are unrelated because the ratio is not useful.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = m a, where the constant ratio F_net / a equals the mass. The data show a direct proportional relationship between net force and acceleration: acceleration increases linearly with net force, and the ratio F_net / a is constant, indicating constant mass—this is F_net = m a rearranged to m = F_net / a. Looking at the data: for 5 N and 2.5 m/s², ratio=2; for 10 N and 5.0 m/s², ratio=2; for 15 N and 7.5 m/s², ratio=2—this constant ratio of 2 kg confirms the mass is unchanging and equals F_net / a each time. Choice A is correct because it accurately identifies that the mass of the cart is constant and equals F_net / a for each trial, directly supported by the data's constant ratio. Choice B is wrong because it claims the cart's mass increases as net force increases, but the constant ratio shows mass is fixed, not changing; this misinterprets the proportionality. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data.
Question 10
A student tests a cart and finds these measurements:
- When Fnet=10N, the cart's acceleration is a=5m/s2.
What does this single data point imply about the cart's mass (assuming Newton's Second Law applies and the net force value is accurate)?
- The mass is 0.5kg because m=a/Fnet.
- The mass is 2kg because m=Fnet/a. (correct answer)
- The mass is 50kg because m=Fnet⋅a.
- The mass cannot be found from force and acceleration.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = m a, allowing mass to be found from m = F_net / a. The data show a direct proportional relationship, and with a single point (10 N, 5 m/s²), we can calculate m = 10 / 5 = 2 kg—this assumes the law holds and measurements are accurate, illustrating how mass quantifies inertia. Looking at the data: the ratio F_net / a = 10 / 5 = 2 kg directly gives the mass, consistent with the proportionality where larger mass would require more force for the same acceleration. Choice B is correct because it correctly calculates the mass as 2 kg using m = F_net / a, the rearrangement of Newton's Second Law. Choice A is wrong because it uses m = a / F_net = 5 / 10 = 0.5 kg, inverting the formula and confusing the proportionality (that would imply inverse relation, but it's direct). Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data even with limited points.
Question 11
A student applies a constant net force to the same cart for 2 seconds each time and measures the change in speed Δv.
Fnet (N) | Δv after 2 s (m/s)
0 | 0
5 | 5
10 | 10
15 | 15
What does the data show about how net force affects the cart's motion (for the same time interval)?
- Larger net force causes a larger change in speed; Δv increases proportionally with Fnet. (correct answer)
- Larger net force causes a smaller change in speed; Δv decreases as Fnet increases.
- Net force and change in speed are unrelated.
- The cart's speed change depends only on mass, not on net force.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = ma. The data show a direct proportional relationship between net force and acceleration: when net force increases, acceleration increases by the same factor (double the force → double the acceleration), and when net force decreases, acceleration decreases proportionally—this relationship is linear, meaning if you graph F_net (x-axis) vs acceleration (y-axis), you get a straight line through the origin, and the slope of that line equals 1/m (the reciprocal of the object's mass). This proportionality is Newton's Second Law: F_net = ma, which can be rearranged to a = F_net/m, showing that for constant mass, acceleration is directly proportional to net force. Looking at the data: when net force is 5 N, Δv is 5 m/s, when net force increases to 10 N (doubled), Δv increases to 10 m/s (also doubled), and when net force increases further to 15 N (tripled from original), Δv is 15 m/s (also tripled)—this consistent doubling and tripling demonstrates perfect proportionality (since Δv = a*t and t is constant, Δv ∝ a ∝ F_net). The ratio F_net/Δv is constant throughout: 5/5 = 1, 10/10 = 1, 15/15 = 1 (related to m/t, since Δv = (F_net/m)*t, so constant ratio confirms proportionality), confirming Newton's Second Law F_net = ma holds for all data points. The straight line through the origin shows the proportional relationship clearly—the graph passes through (0,0) because zero net force produces zero acceleration (balanced forces), and increases linearly showing each additional Newton of force produces a consistent amount of additional acceleration. Choice A is correct because it accurately identifies the proportional relationship: F_net ∝ a ∝ Δv (for constant time) / correctly interprets the data showing that doubling force doubles Δv / properly recognizes the linear pattern in graph or constant ratio in table / correctly predicts that increasing net force will proportionally increase Δv. Choice B is wrong because it claims an inverse relationship (larger force → smaller Δv) when the data clearly show the opposite: as force increases from 5 N to 10 N to 15 N, Δv increases from 5 to 10 to 15 m/s (both increase together) / suggests there's no relationship or that Δv is independent of force, when the data clearly show Δv changes systematically with net force. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data. Real investigations might show slight deviations from perfect line (measurement uncertainty, friction variations), but overall pattern should be clear: larger net forces produce larger accelerations proportionally—this relationship F_net = ma is one of the most fundamental in physics, describing how forces cause motion changes in everything from tiny molecules to planets, and collecting data to verify it experimentally (as students can do with carts, ramps, and force sensors) demonstrates how physics laws are not just theoretical but are actually observed patterns in nature that we can measure and test.
Question 12
A student graphs acceleration a (m/s2) versus net force Fnet (N) for the same cart. The graph is a straight line that goes through the origin.
What does a straight line through the origin on an a vs. Fnet graph show?
- Acceleration is proportional to 1/Fnet (inverse relationship).
- Acceleration is directly proportional to Fnet (linear proportional relationship). (correct answer)
- Acceleration is zero for all values of Fnet.
- Net force depends on acceleration, but acceleration does not depend on net force.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = ma. The data show a direct proportional relationship between net force and acceleration: when net force increases, acceleration increases by the same factor (double the force → double the acceleration), and when net force decreases, acceleration decreases proportionally—this relationship is linear, meaning if you graph F_net (x-axis) vs acceleration (y-axis), you get a straight line through the origin, and the slope of that line equals 1/m (the reciprocal of the object's mass). This proportionality is Newton's Second Law: F_net = ma, which can be rearranged to a = F_net/m, showing that for constant mass, acceleration is directly proportional to net force. The straight line through the origin shows the proportional relationship clearly—the graph passes through (0,0) because zero net force produces zero acceleration (balanced forces), and increases linearly showing each additional Newton of force produces a consistent amount of additional acceleration. Choice B is correct because it accurately identifies the proportional relationship: F_net ∝ a or F_net = ma / properly recognizes the linear pattern in graph or constant ratio in table. Choice A is wrong because it claims an inverse relationship (larger force → smaller acceleration) when the data clearly show the opposite / claims the relationship is non-linear (curved, exponential, quadratic) when the graph is a straight line and data show constant ratio. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data. Real investigations might show slight deviations from perfect line (measurement uncertainty, friction variations), but overall pattern should be clear: larger net forces produce larger accelerations proportionally—this relationship F_net = ma is one of the most fundamental in physics, describing how forces cause motion changes in everything from tiny molecules to planets, and collecting data to verify it experimentally (as students can do with carts, ramps, and force sensors) demonstrates how physics laws are not just theoretical but are actually observed patterns in nature that we can measure and test.
Question 13
In a tug-of-war, two teams pull on a rope attached to a sled on ice. The net force on the sled is the difference between the pulls. A student measures the sled's acceleration for different net forces.
Fnet (N) | a (m/s2)
2 | 0.5
4 | 1.0
6 | 1.5
If the net force is increased from 2 N to 6 N, how does the acceleration change?
- It stays the same.
- It triples (from 0.5 m/s2 to 1.5 m/s2). (correct answer)
- It halves (from 0.5 m/s2 to 0.25 m/s2).
- It becomes zero because the forces are larger.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = ma. The data show a direct proportional relationship between net force and acceleration: when net force increases, acceleration increases by the same factor (double the force → double the acceleration), and when net force decreases, acceleration decreases proportionally—this relationship is linear, meaning if you graph F_net (x-axis) vs acceleration (y-axis), you get a straight line through the origin, and the slope of that line equals 1/m (the reciprocal of the object's mass). This proportionality is Newton's Second Law: F_net = ma, which can be rearranged to a = F_net/m, showing that for constant mass, acceleration is directly proportional to net force. Looking at the data: when net force is 2 N, acceleration is 0.5 m/s², when net force increases to 4 N (doubled), acceleration increases to 1.0 m/s² (also doubled), and when net force increases further to 6 N (tripled from original), acceleration is 1.5 m/s² (also tripled)—this consistent doubling and tripling demonstrates perfect proportionality. The ratio F_net/a is constant throughout: 2/0.5 = 4, 4/1 = 4, 6/1.5 = 4 (this constant ratio equals the object's mass m = 4 kg in this example), confirming Newton's Second Law F_net = ma holds for all data points. Choice B is correct because it correctly interprets the data showing that tripling force triples acceleration / properly recognizes the linear pattern in graph or constant ratio in table / correctly predicts that increasing net force will proportionally increase acceleration. Choice C is wrong because it claims an inverse relationship (larger force → smaller acceleration) when the data clearly show the opposite: as force increases from 2 N to 4 N to 6 N, acceleration increases from 0.5 to 1.0 to 1.5 m/s² (both increase together) / makes incorrect prediction: claims doubling force would triple or halve acceleration, when proportionality means doubling force doubles acceleration. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data. Real investigations might show slight deviations from perfect line (measurement uncertainty, friction variations), but overall pattern should be clear: larger net forces produce larger accelerations proportionally—this relationship F_net = ma is one of the most fundamental in physics, describing how forces cause motion changes in everything from tiny molecules to planets, and collecting data to verify it experimentally (as students can do with carts, ramps, and force sensors) demonstrates how physics laws are not just theoretical but are actually observed patterns in nature that we can measure and test.
Question 14
A student applies different net forces to the same cart and records the acceleration:
Fnet (N): 5, 10, 15
a (m/s2): 2, 4, 6
What happens to the acceleration when the net force increases from 5N to 15N?
- It decreases by 4m/s2.
- It triples from 2m/s2 to 6m/s2. (correct answer)
- It stays the same at 2m/s2.
- It doubles from 2m/s2 to 4m/s2.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = ma. The data show a direct proportional relationship: when net force is 5 N, acceleration is 2 m/s²; when force doubles to 10 N, acceleration doubles to 4 m/s²; when force triples to 15 N, acceleration triples to 6 m/s²—this consistent pattern confirms F_net ∝ a. Looking specifically at the change from 5 N to 15 N: the force increases by a factor of 3 (15/5 = 3), so the acceleration must also increase by a factor of 3, going from 2 m/s² to 6 m/s² (6/2 = 3). Choice B is correct because it accurately states that acceleration triples from 2 m/s² to 6 m/s² when force triples from 5 N to 15 N, maintaining the proportional relationship. Choice A incorrectly claims acceleration decreases when the data clearly show it increases; Choice C wrongly states acceleration stays constant at 2 m/s² when it actually changes to 6 m/s²; Choice D says acceleration only doubles to 4 m/s², but that's the value at 10 N, not 15 N. This proportional relationship means that for constant mass: (1) doubling force doubles acceleration, (2) tripling force triples acceleration, (3) the ratio F_net/a equals the object's mass (here 5/2 = 2.5 kg), (4) graphing the data produces a straight line through the origin—understanding this relationship allows us to predict motion changes for any applied force.
Question 15
A 2kg cart on a track is pushed with a constant net force for 3s. The cart starts from rest.
Trial A: Fnet=5N
Trial B: Fnet=15N
Which statement best compares the change in speed (Δv) in Trial B to Trial A?
- Trial B has one-third the change in speed of Trial A.
- Trial B has the same change in speed as Trial A.
- Trial B has three times the change in speed of Trial A. (correct answer)
- Trial B has nine times the change in speed of Trial A.
Explanation: This question tests understanding that net force and acceleration are directly proportional (F_net = ma) and how this affects velocity change over time (Δv = aΔt). For Trial A: a = F_net/m = 5/2 = 2.5 m/s², so Δv = 2.5 × 3 = 7.5 m/s; for Trial B: a = F_net/m = 15/2 = 7.5 m/s², so Δv = 7.5 × 3 = 22.5 m/s—the velocity change in Trial B (22.5 m/s) is exactly three times that of Trial A (7.5 m/s). Since force in Trial B (15 N) is three times the force in Trial A (5 N), and acceleration is proportional to force, the acceleration is also three times greater (7.5 vs 2.5 m/s²), leading to three times the velocity change over the same time period. Choice C is correct because Trial B has three times the change in speed of Trial A—this follows directly from tripling the force, which triples the acceleration, which triples the velocity change for the same time duration. Choice A incorrectly claims one-third when it's actually three times; Choice B wrongly states equal changes when 22.5 ≠ 7.5 m/s; Choice D suggests nine times (perhaps squaring the force ratio) which doesn't match the linear relationship. This demonstrates how force affects motion over time: (1) larger force → larger acceleration (F = ma), (2) larger acceleration → faster velocity change (a = Δv/Δt), (3) for same time, velocity change is proportional to force, (4) tripling force triples final speed when starting from rest—this principle explains why more powerful engines produce faster acceleration.
Question 16
A 2kg cart starts from rest. For each trial, a constant net force is applied for 2s. Use Δv=aΔt and a=Fnet/m.
What is the cart's change in speed after 2s when Fnet=10N?
- 5m/s
- 10m/s (correct answer)
- 20m/s
- 2.5m/s
Explanation: This question tests understanding that net force and acceleration are directly proportional (F_net = ma) and how to calculate velocity change using Δv = aΔt. First, we find acceleration using a = F_net/m = 10 N / 2 kg = 5 m/s²—this tells us how quickly the cart's velocity changes each second. With constant acceleration for 2 seconds, the change in speed is Δv = aΔt = 5 m/s² × 2 s = 10 m/s, meaning the cart goes from 0 m/s (at rest) to 10 m/s after 2 seconds. Choice B is correct because it gives 10 m/s, which results from proper application of both Newton's Second Law (a = F_net/m = 10/2 = 5 m/s²) and the kinematic equation (Δv = aΔt = 5 × 2 = 10 m/s). Choice A (5 m/s) incorrectly uses only 1 second or forgets to multiply by time; Choice C (20 m/s) might come from incorrectly multiplying force by time (10 × 2) without dividing by mass; Choice D (2.5 m/s) appears to divide force by mass×time (10/4) which has no physical meaning. This calculation demonstrates how forces cause velocity changes: (1) net force determines acceleration through F = ma, (2) acceleration tells us the rate of velocity change, (3) multiplying by time gives total velocity change, (4) starting from rest means final velocity equals the change—this process explains everything from car acceleration to rocket launches.
Question 17
A student wants to design an investigation to show how net force affects acceleration for a cart. Which plan would best test the relationship between Fnet and a?
- Use the same cart, apply several different net forces, measure the acceleration each time, and compare how a changes with Fnet. (correct answer)
- Use different carts with different masses, apply different forces each time, and do not measure acceleration.
- Use the same cart, keep the same force each time, and only measure the cart's color and shape.
- Use the same cart, change the mass each trial, and keep the net force unknown.
Explanation: This question tests understanding of experimental design to investigate the relationship between net force and acceleration. To properly test how F_net affects acceleration, we need to: (1) control variables by keeping mass constant (same cart), (2) systematically vary the independent variable (net force), (3) measure the dependent variable (acceleration), and (4) analyze the pattern in the data. The key principle is isolating variables: to see how F_net affects a, we must keep mass constant while changing only the net force—if we change both force and mass simultaneously, we can't determine which factor caused the observed changes in acceleration. A good investigation would use the same cart (constant mass), apply several different measured net forces (using spring scales, known weights, or force sensors), measure the resulting acceleration for each force (using motion sensors, photogates, or video analysis), record data in a table, and graph a vs F_net to reveal the proportional relationship. Choice A is correct because it properly controls mass (same cart), systematically varies net force (several different forces), measures the outcome (acceleration), and compares results to find the relationship—this is proper experimental design. Choice B fails because it changes multiple variables (both mass and force), making it impossible to isolate the effect of force on acceleration; Choice C doesn't measure acceleration (the dependent variable we're investigating) and measures irrelevant properties instead; Choice D changes mass between trials (should be constant) and doesn't properly control or measure the net force. Good experimental design in physics requires: clear identification of variables, proper control of constants, systematic variation of the independent variable, accurate measurement of the dependent variable, and analysis of patterns in the data—this approach allows us to discover and verify fundamental relationships like Newton's Second Law.
Question 18
A cart's mass stays constant. A student finds that a net force of 6 N produces an acceleration of 3 m/s2. If the student increases the net force to 18 N, what acceleration should the student predict based on the pattern Fnet∝a?
- 6 m/s2
- 9 m/s2 (correct answer)
- 3 m/s2
- 18 m/s2
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = ma. The data show a direct proportional relationship between net force and acceleration: when net force increases by a certain factor, acceleration increases by the same factor—this relationship is linear, meaning the ratio F_net/a is constant for a given mass. From the given data, we can find this constant ratio: F_net/a = 6 N / 3 m/s² = 2 kg (this is the cart's mass), confirming Newton's Second Law F_net = ma where m = 2 kg. Looking at the prediction: when net force increases from 6 N to 18 N (tripled), acceleration must also triple from 3 m/s² to 9 m/s²—we can verify this using F_net = ma: 18 N = (2 kg)(a), so a = 18/2 = 9 m/s². The proportional relationship means that tripling the force triples the acceleration, maintaining the constant ratio F_net/a = 18/9 = 2 kg. Choice B is correct because it accurately predicts that tripling the force (6 N → 18 N) triples the acceleration (3 m/s² → 9 m/s²). Choice A (6 m/s²) would only be doubling the acceleration when force is tripled; Choice C (3 m/s²) incorrectly suggests acceleration stays the same when force changes; Choice D (18 m/s²) incorrectly assumes a = F_net without considering mass, giving an acceleration value equal to the force value. This proportional relationship F_net ∝ a is fundamental to physics and can be verified experimentally by applying known forces to a constant-mass object and measuring the resulting accelerations—the data will always show this direct proportional pattern.
Question 19
A student applies different net forces to the same cart (mass stays constant) and records acceleration. Based on the data, what happens to the acceleration when the net force increases from 4 N to 12 N?
- It stays the same because acceleration does not depend on net force.
- It becomes 3 times larger (from 2 m/s2 to 6 m/s2). (correct answer)
- It becomes 2 times larger (from 2 m/s2 to 4 m/s2).
- It becomes smaller because larger forces reduce acceleration.
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = ma. The data show a direct proportional relationship between net force and acceleration: when net force increases, acceleration increases by the same factor—specifically, when force triples (from 4 N to 12 N, which is a factor of 3), acceleration must also triple. This proportionality is Newton's Second Law: F_net = ma, which can be rearranged to a = F_net/m, showing that for constant mass, acceleration is directly proportional to net force. Looking at the data: when net force is 4 N, we can determine the initial acceleration using the proportional relationship; when net force increases to 12 N (tripled), acceleration must also triple from 2 m/s² to 6 m/s²—this consistent tripling demonstrates perfect proportionality. The ratio F_net/a remains constant throughout, confirming Newton's Second Law F_net = ma holds for all data points. Choice B is correct because it accurately identifies that tripling the force (4 N → 12 N) triples the acceleration (2 m/s² → 6 m/s²). Choice A claims acceleration stays the same when force changes, contradicting the fundamental principle that net force causes acceleration; Choice C suggests doubling when the force actually triples; Choice D claims larger forces reduce acceleration, which is the opposite of what Newton's Second Law predicts and what experimental data show. Real investigations demonstrate this relationship clearly: using a cart with constant mass, applying different net forces, and measuring the resulting accelerations shows that F_net and a are directly proportional—this fundamental relationship describes how forces cause motion changes in everything from laboratory carts to spacecraft.
Question 20
In a tug-of-war, the net force on the rope is the difference between the teams' pulls. A teacher measures the rope's acceleration for different net forces.
Data:
- Fnet=2N → a=0.4m/s2
- Fnet=4N → a=0.8m/s2
- Fnet=6N → a=1.2m/s2
What does the data show happens to acceleration when the net force doubles from 2 N to 4 N?
- Acceleration is cut in half (from 0.4 to 0.2m/s2).
- Acceleration doubles (from 0.4 to 0.8m/s2). (correct answer)
- Acceleration triples (from 0.4 to 1.2m/s2).
- Acceleration stays the same (still 0.4m/s2).
Explanation: This question tests understanding that net force and acceleration are directly proportional, as described by Newton's Second Law: F_net = m a. The data show a direct proportional relationship between net force and acceleration: when net force increases, acceleration increases by the same factor (double the force → double the acceleration)—this relationship is linear, with constant mass implied by the constant ratio F_net / a = 5 kg (e.g., 2/0.4=5, 4/0.8=5, 6/1.2=5). Looking at the data: when net force doubles from 2 N to 4 N, acceleration doubles from 0.4 m/s² to 0.8 m/s²—this consistent doubling demonstrates perfect proportionality. Choice B is correct because it accurately identifies that acceleration doubles when net force doubles, matching the data's proportional pattern. Choice A is wrong because it claims acceleration is cut in half (larger force → smaller acceleration) when the data clearly show the opposite: as force increases, acceleration increases proportionally. Collecting and analyzing force-motion data: (1) set up investigation with constant mass object, (2) apply different net forces (use force sensor or known applied force minus friction), (3) measure resulting acceleration for each force (motion sensor, or calculate from distance and time), (4) record data in table: F_net | a values, (5) graph data: F_net on x-axis, a on y-axis, (6) analyze pattern: should see straight line through origin showing proportionality, (7) calculate slope: slope = Δa/ΔF_net = 1/m, allows determining object's mass from the data.