All questions
Question 1
Elena writes the equation y=−3x+12 to model her distance from home while walking to school. After checking her work, she realizes the y-intercept should be 8, not 12. If she keeps the same slope, what point will now represent her location after walking for 2 minutes?
- (2, 2), because the corrected equation gives y = -3(2) + 8 = 2 (correct answer)
- (2, 6), because reducing the y-intercept by 4 changes this y-value by 4
- (2, 10), because the slope adjustment compensates for the y-intercept change
- (2, 14), because the original equation gave y = 6, plus the intercept gives 14
Explanation: The corrected equation is y=−3x+8 (same slope of -3, but y-intercept changed to 8). At x=2 minutes: y=−3(2)+8=−6+8=2. So the point is (2, 2). Choice B incorrectly applies the y-intercept change to the point rather than recalculating. Choice C incorrectly suggests slope adjustment. Choice D misapplies the original equation and adds values incorrectly. Question 2
A water tank starts with 500 gallons and drains at a constant rate. After 3 hours, it contains 350 gallons. Which equation represents the relationship between gallons remaining G and time t in hours?
- G=50t+500, because the tank gains 50 gallons per hour from the initial amount
- G=−150t+500, because the tank loses 150 gallons total over 3 hours
- G=−50t+500, because the tank loses 50 gallons per hour from 500 gallons (correct answer)
- G=150t+350, because the tank starts at 350 and increases by 150 per hour
Explanation: When you see a problem about something changing at a constant rate over time, you're dealing with a linear relationship. The key is identifying the rate of change and the starting value to write the equation in the form y=mx+b.
First, let's find the rate at which the tank drains. The tank goes from 500 gallons to 350 gallons in 3 hours, so it loses 500−350=150 gallons total. Since this happens over 3 hours, the rate is 150÷3=50 gallons per hour. Because the tank is draining (losing water), this rate is negative: −50 gallons per hour.
The equation follows the pattern G=(rate)×t+(starting amount), which gives us G=−50t+500. This matches choice C.
Choice A incorrectly shows the tank gaining 50 gallons per hour with a positive rate, but the tank is draining. Choice B uses the correct starting value and negative direction, but mistakenly uses the total loss (150 gallons) as the hourly rate instead of dividing by 3 hours. Choice D completely misunderstands the problem by treating 350 as the starting point and showing the tank filling rather than draining.
Study tip: For constant rate problems, always calculate the rate by finding the total change and dividing by the time interval. Pay careful attention to whether the quantity is increasing (positive rate) or decreasing (negative rate). Question 3
A movie theater charges a $6 ticket fee plus $2 per snack. The total cost is modeled by y=2x+6, where x is the number of snacks and y is the total cost in dollars. What do m and b represent in y=mx+b for this situation?
- m=6 is the starting number of snacks and b=2 is the total cost
- m=6 is the cost per snack and b=2 is the ticket fee
- m=2 is the ticket fee and b=6 is the cost per snack
- m=2 is the cost per snack and b=6 is the ticket fee (correct answer)
Explanation: This question tests interpreting y=mx+b as defining a linear function (straight-line graph, constant slope m, y-intercept b) and distinguishing from non-linear functions (curved graphs, variable squared/in denominator/in absolute value/as exponent), specifically in a real-world context. Linear function y=mx+b: m is slope (rate of change: y increases by m per unit x), b is y-intercept (initial value when x=0, where line crosses y-axis), graph is straight line through (0,b) with constant slope m. Non-linear functions have x with exponent ≠1, or in denominator, or in other function: y=x² graphs as parabola (curved, points (1,1),(2,4),(3,9) not on straight line), y=1/x graphs as hyperbola (curved), y=|x| is V-shape (not single straight line)—all have non-constant slopes (curvature indicates slope varies). For example, y=3x+2 is linear with a straight graph where m=3 means y rises by 3 per x, b=2 is the start, versus y=x² with points showing varying increases like from 1 to 4 then to 9. The correct choice is B, where m=2 is the cost per snack (rate) and b=6 is the ticket fee (fixed cost when x=0), matching the model's interpretation. A common error is interpreting m and b backwards, like thinking the fixed fee is the slope, or confusing them with non-cost elements like starting snacks. To identify and interpret: (1) check form y=mx+b for linearity, (2) confirm x to power 1, (3) graph if needed for straight line, (4) calculate constant slope; here, m is the per-unit rate (2/snack),bisinitialvalue(6 ticket), with mistakes like ignoring context or claiming non-linear due to positive values. Question 4
A movie theater charges a $6 membership fee plus $3 per ticket. The total cost is modeled by y=3x+6, where x is the number of tickets and y is the total cost in dollars. What do m and b represent in y=mx+b for this situation?
- m=3 is the membership fee; b=6 is the cost per ticket
- m=3 is the cost per ticket; b=6 is the membership fee (correct answer)
- m=6 is the cost per ticket; b=3 is the membership fee
- m=6 is the membership fee; b=3 is the cost per ticket
Explanation: This question tests interpreting y=mx+b as defining a linear function with a straight-line graph, constant slope m, and y-intercept b, and applying it to real-world contexts like costs, distinguishing from non-linear scenarios. In y=mx+b, m is the slope representing the constant rate of change, such as cost per item, and b is the y-intercept, the fixed initial value like a membership fee when x=0; non-linear functions, like y=x² for accelerating costs or y=1/x for decreasing rates, have varying slopes and curved graphs, e.g., points (1,1), (2,4) for y=x² not aligning straight. For example, y=3x+2 models a scenario with $2 fixed plus $3 per unit, graphing as a straight line from (0,2) rising steadily, versus y=x² which curves and doesn't fit constant-rate situations like ticket pricing. Here, in y=3x+6, m=3 is the cost per ticket (rate) and b=6 is the membership fee (fixed when x=0), correctly identified in choice B, as it matches the description of $6 fee plus $3 per ticket. A common mistake is reversing m and b, like thinking m=6 is the per-ticket cost (choice D), or confusing which is fixed versus variable, ignoring that b is when x=0. To interpret: identify m as the variable rate (slope) and b as the constant (intercept); check by plugging x=0 to find b, and slope as change in y over change in x. Avoid errors like assuming m is fixed because it's first in the equation, or thinking non-linear forms could model constant rates.
Question 5
A student says, "y=∣x∣+2 is linear because it looks like straight lines." Which response is best?
- Correct; ∣x∣ is the same as x, so it is in y=mx+b form.
- Incorrect; linear functions must have b=0.
- Correct; any graph made of straight pieces is linear.
- Incorrect; it is not a single straight line and cannot be written as one equation y=mx+b for all x. (correct answer)
Explanation: This question tests interpreting y=mx+b as defining a linear function (straight-line graph, constant slope m, y-intercept b) and distinguishing from non-linear functions (curved graphs, variable squared/in denominator/in absolute value/as exponent). Linear function y=mx+b: m is slope (rate of change: y increases by m per unit x), b is y-intercept (initial value when x=0, where line crosses y-axis), graph is straight line through (0,b) with constant slope m. Non-linear functions have x with exponent ≠1, or in denominator, or in other function: y=x² graphs as parabola (curved, points (1,1),(2,4),(3,9) not on straight line), y=1/x graphs as hyperbola (curved), y=|x| is V-shape (not single straight line)—all have non-constant slopes (curvature indicates slope varies). For example, y=3x+2 is linear with single straight graph, versus y=|x| with V-shape from two lines, not fitting one y=mx+b. The correct choice is C, incorrect because it's not a single straight line and can't be one y=mx+b for all x, due to the absolute value causing a bend. A common error is calling y=|x| linear because it's straight pieces (wrong, linearity requires one constant slope, not V-shaped), or thinking b=0 is required. To identify: (1) check if one y=mx+b works for all x, (2) exponent or function like absolute value, (3) graph single straight line, (4) constant slope everywhere; mistakes include equating piecewise straight to linear.
Question 6
Which equation represents a linear function (a straight-line graph) written in the form y=mx+b?
- y=x2+3
- y=∣x∣−1
- y=x1+4
- y=−3x+2 (correct answer)
Explanation: This question tests interpreting y=mx+b as defining a linear function (straight-line graph, constant slope m, y-intercept b) and distinguishing from non-linear functions (curved graphs, variable squared/in denominator/in absolute value/as exponent). Linear function y=mx+b: m is slope (rate of change: y increases by m per unit x), b is y-intercept (initial value when x=0, where line crosses y-axis), graph is straight line through (0,b) with constant slope m. Non-linear functions have x with exponent ≠1, or in denominator, or in other function: y=x² graphs as parabola (curved, points (1,1),(2,4),(3,9) not on straight line), y=1/x graphs as hyperbola (curved), y=|x| is V-shape (not single straight line)—all have non-constant slopes (curvature indicates slope varies). For example, y=3x+2 is linear with a straight graph passing through (0,2) and (1,5), while y=x² has points (0,0), (1,1), (2,4) demonstrating curvature as the slope increases. The correct choice is C, y=-3x+2, which is linear with slope m=-3 and y-intercept b=2, while A is quadratic (curved), B is reciprocal (curved), and D is absolute value (V-shaped). A common error is calling y=x² linear because it has a variable (wrong, the squared term makes it non-linear), or not recognizing that absolute value or denominators prevent a single straight line. To identify linear functions: (1) check if it can be written as y=mx+b (yes→linear), (2) ensure exponent on x is 1 only (x² or x⁻¹→non-linear), (3) visualize the graph (straight→linear, curved→non-linear), (4) verify constant slope between points. Interpreting m and b: m is the constant rate, b is the starting value; mistakes include confusing m and b or thinking any equation with x is linear.
Question 7
Which equation represents a linear function (a straight-line graph) in the form y=mx+b?
- y=1/x+4
- y=x2+3
- y=∣x∣−2
- y=3x+2 (correct answer)
Explanation: A linear function can be written as y=mx+b, where x appears only to the first power, giving a straight-line graph with constant slope m. Choice D, y=3x+2, fits this form exactly, with slope 3 and y-intercept 2. Choice A is wrong because x1 places x in a denominator, producing a curved graph, a hyperbola, not a straight line. Choice B is wrong because x2 is a squared term, producing a parabola whose slope changes at every point. Choice C is wrong because ∣x∣ creates a V-shaped graph whose slope changes abruptly at x=0, even though each piece is straight. Question 8
For x>0, a graph shows a curve that gets steeper as x increases (it is not a straight line). Which type of equation could match that graph?
- y=4x−1
- y=−x+6
- y=x2 (correct answer)
- y=53x+2
Explanation: A linear equation y=mx+b has a constant slope m, so its graph is a straight line that never gets steeper or flatter. For y=x2, the slope at any point is 2x, so for x>0, the slope increases as x increases, making the curve get steeper. This matches a graph that curves and steepens. Choices A, B, and D are all linear equations with constant slopes, so their graphs are straight lines, not curves that steepen. Question 9
A student says y=∣x∣ is linear because its graph has straight pieces. Which statement best describes the function y=∣x∣?
- It is linear because it passes through the origin.
- It is linear because it can be written as y=mx+b with one slope for all x.
- It is non-linear because its graph is not a single straight line. (correct answer)
- It is non-linear only when x is negative.
Explanation: A linear function must have the form y=mx+b with a single, constant slope across its entire domain. While y=∣x∣ is made of straight pieces, it has slope −1 for x<0 and slope +1 for x>0, so the slope changes at x=0. The graph forms a V-shape rather than a single straight line, so the function is non-linear. Choice B is incorrect because having individually straight pieces does not make the whole function linear if the slope changes between pieces. Choice A is incorrect because passing through the origin does not determine linearity. Choice D is incorrect because the non-linearity applies to the function as a whole; there is no single slope that works across the entire domain. Question 10
Marcus tracks his savings account balance over several months. The balance can be modeled by the equation B=45m+120, where B is his balance in dollars and m is the number of months since he opened the account. Which statement best describes what happens if Marcus changes his monthly deposit from $45 to $60?
- The graph becomes steeper and the y-intercept increases to 135
- The graph becomes steeper but the y-intercept remains at 120 (correct answer)
- The graph shifts upward by 15 units but keeps the same slope
- The graph becomes less steep and shifts right by 15 units
Explanation: In the linear function B=45m+120, the slope 45 represents the monthly deposit amount, and 120 is the initial balance (y-intercept). Changing the monthly deposit to $60 changes the slope from 45 to 60, making the graph steeper, but the initial balance remains $120. Choice A incorrectly changes the y-intercept. Choice C confuses slope change with vertical shift. Choice D incorrectly describes the slope change and adds an irrelevant horizontal shift. Question 11
A scientist observes that the population P of bacteria in a petri dish can be modeled by P=100⋅2t, where t is time in hours. She claims this is a linear function because it can be written as P=200t when t=1. What is the main flaw in her reasoning?
- She should test multiple input values to verify the function produces a straight line (correct answer)
- Linear functions cannot have coefficients greater than 100 in biological applications
- The original equation has too many variables to be considered a linear function
- She incorrectly calculated the equivalent equation; it should be P=100t+100
Explanation: To determine if a function is linear, you must verify it produces a straight line for ALL input values, not just one. The equation P=100⋅2t is exponential (due to the variable in the exponent), giving points like (0,100), (1,200), (2,400), (3,800) which don't form a straight line. Testing only one point is insufficient. Choice B makes a false claim about coefficient limits. Choice C incorrectly focuses on variable count. Choice D attempts an irrelevant calculation correction. Question 12
Which function is not linear (does not have a constant rate of change)?
- y=−2x+7
- y=21x−4
- y=x2 (correct answer)
- y=9x
Explanation: This question tests interpreting y=mx+b as defining a linear function with a straight-line graph and constant slope m, while identifying non-linear functions with curved graphs or non-constant rates, such as those with x squared, in denominators, absolute values, or exponents. Linear functions like y=mx+b have constant slope m (y changes by m per unit x) and y-intercept b, graphing straight through (0,b); non-linear ones vary, e.g., y=x² is a parabola with increasing slope (points (1,1),(2,4),(3,9) show y-differences 3,5—not constant), y=1/x hyperbola, y=|x| V-shape with slope shift. For instance, y=3x+2 is linear with constant rate 3 and straight graph, but y=x² curves with points not collinear, demonstrating variable rate (slope between (0,0)-(1,1) is 1, but (1,1)-(2,4) is 3). The non-linear function here is C, y=x², lacking constant rate and straight graph, while A, B, D are linear in y=mx+b form. Common errors include calling y=x² linear because it has x (ignoring exponent 2 causing curvature) or misinterpreting m and b in linear ones, like swapping slope and intercept. Identifying linear: (1) rewrite as y=mx+b, (2) check x exponent=1, (3) graph for straightness, (4) confirm constant slope via points. Interpreting: m is rate/steepness, b starting value; mistakes: assuming all variable equations are linear or claiming curved graphs have constant rates.
Question 13
Which comparison is correct?
- y=2x and y=x2 are both linear because both graphs pass through (0,0).
- y=2x is non-linear because it has a variable; y=x2 is linear because it has an x.
- y=2x is linear because x is to the first power; y=x2 is non-linear because x is squared. (correct answer)
- y=2x is non-linear because it has no b term; y=x2 is linear because it has a constant rate of change.
Explanation: This question tests interpreting y=mx+b as defining a linear function (straight-line graph, constant slope m, y-intercept b) and distinguishing from non-linear functions (curved graphs, variable squared/in denominator/in absolute value/as exponent). Linear function y=mx+b: m is slope (rate of change: y increases by m per unit x), b is y-intercept (initial value when x=0, where line crosses y-axis), graph is straight line through (0,b) with constant slope m. Non-linear functions have x with exponent ≠1, or in denominator, or in other function: y=x² graphs as parabola (curved, points (1,1),(2,4),(3,9) not on straight line), y=1/x graphs as hyperbola (curved), y=|x| is V-shape (not single straight line)—all have non-constant slopes (curvature indicates slope varies). For example, y=3x+2 is linear (x to power 1, straight graph), versus y=x² (x squared, curved with non-constant rate). The correct choice is B, y=2x is linear because x is to the first power (fits y=mx+b with m=2, b=0), y=x² is non-linear because x is squared (curved parabola). A common error is thinking y=2x non-linear for lacking b (wrong, b can be 0) or claiming y=x² linear for passing through (0,0). To compare: (1) check form and exponent, (2) graph shape, (3) rate constancy, (4) fit to y=mx+b; mistakes include confusing origins or variables alone as linear.
Question 14
A line passes through the points (0,−4) and (2,2). Which equation is the linear function for this line in the form y=mx+b?
- y=3x+4 (correct answer)
- y=−3x+4
- y=−3x−4
- y=3x−4
Explanation: This question tests interpreting y=mx+b as defining a linear function (straight-line graph, constant slope m, y-intercept b) and distinguishing from non-linear functions (curved graphs, variable squared/in denominator/in absolute value/as exponent), by finding the equation from points. Linear function y=mx+b: m is slope (rate of change: y increases by m per unit x), b is y-intercept (initial value when x=0, where line crosses y-axis), graph is straight line through (0,b) with constant slope m. Non-linear functions have x with exponent ≠1, or in denominator, or in other function: y=x² graphs as parabola (curved, points (1,1),(2,4),(3,9) not on straight line), y=1/x graphs as hyperbola (curved), y=|x| is V-shape (not single straight line)—all have non-constant slopes (curvature indicates slope varies). For example, y=3x+2 is linear with straight graph through (0,2) and say (1,5), slope (5-2)/(1-0)=3, versus y=x² through (0,0),(1,1),(2,4) with varying slopes. The correct choice is A, y=3x-4, as b=-4 from (0,-4), m=(2-(-4))/(2-0)=3, fitting y=mx+b with straight line. A common error is interpreting m and b backwards or with wrong signs, like choosing negative slope despite positive rise. To find: (1) use points to calculate m=(y2-y1)/(x2-x1), (2) plug x=0 for b, (3) verify straight line, (4) check constant slope; mistakes include confusing rise/run or thinking points imply non-linear.
Question 15
Which equation has slope m=−4 and y-intercept b=7?
- y=7x−4
- y=−4x+7 (correct answer)
- y=4x−7
- y=−7x+4
Explanation: This question tests interpreting y=mx+b as defining a linear function (straight-line graph, constant slope m, y-intercept b) and distinguishing from non-linear functions (curved graphs, variable squared/in denominator/in absolute value/as exponent), by identifying m and b. Linear function y=mx+b: m is slope (rate of change: y increases by m per unit x), b is y-intercept (initial value when x=0, where line crosses y-axis), graph is straight line through (0,b) with constant slope m. Non-linear functions have x with exponent ≠1, or in denominator, or in other function: y=x² graphs as parabola (curved, points (1,1),(2,4),(3,9) not on straight line), y=1/x graphs as hyperbola (curved), y=|x| is V-shape (not single straight line)—all have non-constant slopes (curvature indicates slope varies). For example, y=3x+2 is linear with m=3 (slope) and b=2 (intercept), graphing straight through (0,2), versus y=x² with no constant m. The correct choice is B, y=-4x+7, where m=-4 is the slope and b=7 is the y-intercept, matching the given values. A common error is switching m and b, like choosing y=7x-4, or confusing signs. To interpret: (1) identify coefficient of x as m, constant as b, (2) confirm linear form, (3) graph to verify, (4) check slope sign for direction; mistakes include thinking negative m makes it non-linear.
Question 16
On a coordinate plane, a line passes through the points (0,−3) and (2,1). Which equation matches this line?
- y=2x−3 (correct answer)
- y=2x+3
- y=21x−3
- y=−2x−3
Explanation: This question tests interpreting y=mx+b as defining a linear function with straight-line graph, constant slope m from points, and y-intercept b, distinguishing from non-linear not fitting straight lines. Linear y=mx+b: m=(y2-y1)/(x2-x1) constant, b=y when x=0; non-linear like y=x² don't have constant m between points, curving instead of straight. For example, points (0,2),(1,5) give m=3, y=3x+2 linear straight; versus (0,0),(1,1),(2,4) for y=x² with varying m=1 then 3, curved. Here, points (0,-3),(2,1) give m=(1-(-3))/(2-0)=2, b=-3, so y=2x-3 (A) matches the line. Common errors: wrong m like -2 (B) or 1/2 (C), or sign flip to +3 (D), miscalculating slope or intercept. Identifying: (1) compute m from points, (2) find b at x=0, (3) write y=mx+b, (4) verify other points. Interpreting: m rate between points, b start; mistakes: swapping signs or confusing rise/run.
Question 17
A student says y=∣x∣ is linear because it looks like two straight lines. Which statement best describes whether y=∣x∣ is linear?
- It is linear because it can be written as y=mx+b using one m value.
- It is not linear because its slope changes at x=0. (correct answer)
- It is linear because any graph made of straight pieces is linear.
- It is not linear only because it has a y-intercept of 0.
Explanation: A linear function must be written as y=mx+b with one constant slope for every x. For y=∣x∣, the slope is +1 when x≥0 and −1 when x<0, so the slope changes at x=0 and no single equation y=mx+b works for all x. Choice A is wrong because no single value of m works everywhere. Choice C is wrong because a graph made of straight pieces isn't automatically linear; linearity requires one constant slope throughout. Choice D is wrong because the y-intercept has nothing to do with whether the slope is constant.