Middle School Math Quiz: Adding And Subtracting Rational Numbers
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Adding And Subtracting Rational NumbersQuestion 1 of 7

A stock's value changed as follows over four days: Day 1: increased by 38\frac{3}{8}, Day 2: decreased by 56\frac{5}{6}, Day 3: increased by 712\frac{7}{12}, Day 4: decreased by 14\frac{1}{4}. If these changes are measured in dollars per share, what is the total change in the stock's value?

14-\frac{1}{4} dollars per share
+18+\frac{1}{8} dollars per share
524-\frac{5}{24} dollars per share
+524+\frac{5}{24} dollars per share
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Middle School Math Quiz

Middle School Math Quiz: Adding And Subtracting Rational Numbers

Practice Adding And Subtracting Rational Numbers in Middle School Math with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Adding And Subtracting Rational Numbers, giving you a quick way to practice the rules, question types, and explanations that matter most for Middle School Math.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A stock's value changed as follows over four days: Day 1: increased by 38\frac{3}{8}, Day 2: decreased by 56\frac{5}{6}, Day 3: increased by 712\frac{7}{12}, Day 4: decreased by 14\frac{1}{4}. If these changes are measured in dollars per share, what is the total change in the stock's value?

  1. 14-\frac{1}{4} dollars per share
  2. +18+\frac{1}{8} dollars per share
  3. 524-\frac{5}{24} dollars per share (correct answer)
  4. +524+\frac{5}{24} dollars per share
Explanation: Sum all changes: +3/8 - 5/6 + 7/12 - 1/4. Convert to common denominator 24: 3/8 = 9/24, 5/6 = 20/24, 7/12 = 14/24, 1/4 = 6/24. Therefore: 9/24 - 20/24 + 14/24 - 6/24 = (9 - 20 + 14 - 6)/24 = -3/24. Since -3/24 simplifies to -1/8, let me recalculate: 9/24 - 20/24 + 14/24 - 6/24 = -5/24. The stock decreased by 5/24 dollars per share.

Question 2

A submarine starts at sea level and descends 12734127\frac{3}{4} feet. It then ascends 891289\frac{1}{2} feet, descends another 455845\frac{5}{8} feet, and finally ascends 627862\frac{7}{8} feet. What is the submarine's final depth below sea level?

  1. 211821\frac{1}{8} feet below sea level (correct answer)
  2. 211821\frac{1}{8} feet above sea level
  3. 837883\frac{7}{8} feet below sea level
  4. 32534325\frac{3}{4} feet below sea level
Explanation: Let downward be negative and upward be positive, starting at 0. First: 0 - 127¾ = -127¾. Then: -127¾ + 89½ = -127¾ + 89½ = -38¼. Then: -38¼ - 45⅝ = -83⅞. Finally: -83⅞ + 62⅞ = -21⅛. The submarine is 21⅛ feet below sea level. Choice B incorrectly makes the final answer positive. Choice C is the depth after the third movement, before the final ascent. Choice D incorrectly adds all distances regardless of direction.

Question 3

In a card game, positive points are gained and negative points represent losses. Jamie's scores for five rounds were: +24.5+24.5, 17.8-17.8, +9.3+9.3, 31.6-31.6, and +18.2+18.2. If players with negative total scores must pay a 5.55.5 point penalty, what is Jamie's final score?

  1. 8.18.1 points
  2. 2.9-2.9 points
  3. 8.4-8.4 points
  4. 2.62.6 points (correct answer)
Explanation: This problem tests your ability to work with positive and negative numbers (integers and decimals) and apply conditional rules based on calculation results. Start by finding Jamie's total score from the five rounds. Add all the scores together, being careful with the signs: +24.5+(17.8)+(+9.3)+(31.6)+(+18.2)+24.5 + (-17.8) + (+9.3) + (-31.6) + (+18.2). Group the positive and negative values: (24.5+9.3+18.2)+(17.831.6)=52.0+(49.4)=+2.6(24.5 + 9.3 + 18.2) + (-17.8 - 31.6) = 52.0 + (-49.4) = +2.6. Since Jamie's total is +2.6+2.6 points (positive), she doesn't need to pay the 5.55.5 point penalty that only applies to players with negative totals. Therefore, her final score remains +2.6+2.6 points. Answer A (8.18.1) likely comes from incorrectly adding the penalty instead of subtracting it, or from a calculation error in the initial sum. Answer B (2.9-2.9) results from taking the correct total of +2.6+2.6 and mistakenly subtracting the 5.55.5 penalty even though it doesn't apply to positive scores. Answer C (8.4-8.4) appears to come from calculation errors in both the initial sum and penalty application. When working with problems involving conditional penalties or bonuses, always calculate the base result first, then check whether the condition is met before applying any additional changes. Pay close attention to positive and negative signs throughout your calculations, and remember that penalties typically only apply when specific conditions are satisfied.

Question 4

Marcus has a checking account with overdraft protection that charges $25 when the balance goes below zero. His account starts with $156.43. He writes checks for $89.17, $45.82, and $38.76 in that order. After the overdraft fee (if any), he deposits $75.50. What is his final balance?

  1. $58.18
  2. $33.18 (correct answer)
  3. $83.18
  4. $16.82-\$16.82
Explanation: Starting balance: $156.43. After first check: $156.43 - $89.17 = $67.26. After second check: $67.26 - $45.82 = $21.44. After third check: $21.44 - 38.76=38.76 = -17.32 (overdraft occurs). Overdraft fee: -$17.32 - 25.00=25.00 = -42.32. After deposit: -$42.32 + $75.50 = $33.18. Choice A ignores the overdraft fee. Choice C incorrectly calculates when the overdraft occurs. Choice D forgets to add the final deposit.

Question 5

On a coordinate plane, point PP is located at (3.5,2.8)(-3.5, 2.8) and point QQ is located at (1.7,4.2)(1.7, -4.2). If point RR is positioned such that its xx-coordinate equals the sum of the xx-coordinates of PP and QQ, and its yy-coordinate equals the difference of PP's yy-coordinate minus QQ's yy-coordinate, what are the coordinates of point RR?

  1. (5.2,7.0)(5.2, 7.0)
  2. (1.8,7.0)(-1.8, 7.0) (correct answer)
  3. (1.8,1.4)(-1.8, -1.4)
  4. (5.2,1.4)(5.2, -1.4)
Explanation: For point R: x-coordinate = (-3.5) + (1.7) = -1.8. y-coordinate = (2.8) - (-4.2) = 2.8 + 4.2 = 7.0. Therefore R is at (-1.8, 7.0). Choice A uses the wrong sign for the x-coordinate calculation. Choice C incorrectly calculates the y-coordinate as 2.8 - 4.2 = -1.4. Choice D combines the errors from both A and C.

Question 6

A recipe calls for 2342\frac{3}{4} cups of flour, but Sarah only has 1581\frac{5}{8} cups. Later, she borrows 78\frac{7}{8} cups from a neighbor and buys 1121\frac{1}{2} more cups at the store. After making the recipe, how much flour does she have left?

  1. 1781\frac{7}{8} cups
  2. 78\frac{7}{8} cups
  3. 14\frac{1}{4} cups
  4. 1141\frac{1}{4} cups (correct answer)
Explanation: This is a multi-step word problem involving mixed numbers and fractions. You need to track Sarah's flour through several transactions: what she starts with, what she gains, what she uses, and what remains. First, let's find Sarah's total flour before making the recipe. She starts with 1581\frac{5}{8} cups, borrows 78\frac{7}{8} cups, and buys 1121\frac{1}{2} cups. Converting to improper fractions with denominator 8: 158=1381\frac{5}{8} = \frac{13}{8}, 78=78\frac{7}{8} = \frac{7}{8}, and 112=1281\frac{1}{2} = \frac{12}{8}. Adding these: 138+78+128=328=4\frac{13}{8} + \frac{7}{8} + \frac{12}{8} = \frac{32}{8} = 4 cups total. Next, she uses 2342\frac{3}{4} cups for the recipe. Converting: 234=2282\frac{3}{4} = \frac{22}{8}. Her remaining flour is 4234=328228=108=1144 - 2\frac{3}{4} = \frac{32}{8} - \frac{22}{8} = \frac{10}{8} = 1\frac{1}{4} cups. Choice A (1781\frac{7}{8}) likely comes from miscalculating the total flour Sarah had. Choice B (78\frac{7}{8}) might result from forgetting to add one of her flour sources. Choice C (14\frac{1}{4}) could happen if you converted 1141\frac{1}{4} incorrectly or subtracted the wrong amount. The correct answer is D: 1141\frac{1}{4} cups. Study tip: In multi-step fraction problems, convert all mixed numbers to the same denominator early on. This prevents arithmetic errors and makes addition and subtraction much cleaner. Always double-check your conversions between mixed numbers and improper fractions.

Question 7

The temperature at 6 AM was 8.5°F-8.5°F. By noon, it had risen 12.7°F12.7°F. In the afternoon, it dropped 15.3°F15.3°F, and then in the evening it rose again by 6.8°F6.8°F. What was the final temperature?

  1. 4.3°F-4.3°F (correct answer)
  2. 4.3°F4.3°F
  3. 10.1°F-10.1°F
  4. 16.1°F16.1°F
Explanation: Starting at -8.5°F, add 12.7°F: -8.5 + 12.7 = 4.2°F at noon. Then subtract 15.3°F: 4.2 - 15.3 = -11.1°F in the afternoon. Finally add 6.8°F: -11.1 + 6.8 = -4.3°F. Choice B results from incorrectly treating the initial temperature as positive. Choice C comes from calculation errors in the middle steps. Choice D comes from adding all the changes without considering their signs properly.