Microbiology Quiz: Fermentation Vs Respiration
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Fermentation Vs RespirationQuestion 1 of 20

A culture of Saccharomyces cerevisiae (a facultative anaerobe) is grown in a glucose-rich medium. The culture is first incubated aerobically, allowing the population to grow, then the flask is sealed to create anaerobic conditions. How will the rate of glucose consumption and the primary mechanism of ATP synthesis change after the flask is sealed?

The rate of glucose consumption will decrease, and the primary ATP synthesis mechanism will shift to oxidative phosphorylation.
The rate of glucose consumption will increase, and the primary ATP synthesis mechanism will shift from oxidative phosphorylation to substrate-level phosphorylation.
The rate of glucose consumption will decrease, and the primary ATP synthesis mechanism will shift from substrate-level phosphorylation to oxidative phosphorylation.
The rate of glucose consumption will increase, and the primary ATP synthesis mechanism will remain oxidative phosphorylation.
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Microbiology Quiz

Microbiology Quiz: Fermentation Vs Respiration

Practice Fermentation Vs Respiration in Microbiology with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

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This quiz focuses on Fermentation Vs Respiration, giving you a quick way to practice the rules, question types, and explanations that matter most for Microbiology.

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Question 1

A culture of Saccharomyces cerevisiae (a facultative anaerobe) is grown in a glucose-rich medium. The culture is first incubated aerobically, allowing the population to grow, then the flask is sealed to create anaerobic conditions. How will the rate of glucose consumption and the primary mechanism of ATP synthesis change after the flask is sealed?

  1. The rate of glucose consumption will decrease, and the primary ATP synthesis mechanism will shift to oxidative phosphorylation.
  2. The rate of glucose consumption will increase, and the primary ATP synthesis mechanism will shift from oxidative phosphorylation to substrate-level phosphorylation. (correct answer)
  3. The rate of glucose consumption will decrease, and the primary ATP synthesis mechanism will shift from substrate-level phosphorylation to oxidative phosphorylation.
  4. The rate of glucose consumption will increase, and the primary ATP synthesis mechanism will remain oxidative phosphorylation.
Explanation: This scenario describes the Pasteur effect. Under aerobic conditions, yeast performs respiration, which has a high ATP yield (~32 ATP/glucose), primarily through oxidative phosphorylation. Under anaerobic conditions, it switches to fermentation, which has a low ATP yield (2 ATP/glucose) entirely from substrate-level phosphorylation. To produce the same amount of ATP to sustain life, the rate of glycolysis and therefore glucose consumption must dramatically increase. Thus, the rate of glucose consumption increases, and the dominant ATP synthesis mechanism switches from oxidative phosphorylation to substrate-level phosphorylation.

Question 2

A researcher is designing an enrichment culture to isolate a novel obligately fermentative bacterium that metabolizes glucose from a complex soil sample. Which of the following strategies would be most effective for selecting for this specific type of organism?

  1. Incubate anaerobically in a medium with glucose as the sole carbon source and nitrate as a potential electron acceptor.
  2. Incubate aerobically in a glucose-rich medium to allow rapid growth of all glucose metabolizers.
  3. Incubate anaerobically in a medium containing only complex proteins and lipids, with no added carbohydrates.
  4. Incubate anaerobically in a glucose-rich medium that also contains oligomycin, a specific inhibitor of F₁F₀ ATP synthase. (correct answer)
Explanation: When you encounter questions about enrichment cultures, think about creating selective conditions that favor your target organism while inhibiting competitors. The goal is to design an environment where only organisms with specific metabolic capabilities can thrive. An obligately fermentative bacterium can only generate ATP through substrate-level phosphorylation during fermentation—it cannot use aerobic respiration or anaerobic respiration. To isolate such an organism, you need conditions that eliminate respiratory competitors while providing the fermentable substrate it requires. Choice D is correct because it creates the perfect selective environment. The anaerobic conditions prevent aerobic respirers from growing, while glucose provides the fermentable substrate. Most importantly, oligomycin specifically inhibits the F₁F₀ ATP synthase complex, which is essential for oxidative phosphorylation in respiration but not needed for fermentation. This drug will kill respiratory organisms while leaving fermentative bacteria unharmed, since they generate ATP through substrate-level phosphorylation. Choice A fails because nitrate serves as an electron acceptor for anaerobic respiration, allowing respiratory bacteria to outcompete the slow-growing fermentative organism you want. Choice B uses aerobic conditions, which directly contradicts the anaerobic requirements for enriching fermentative bacteria. Choice C eliminates glucose entirely, removing the preferred substrate for your target organism and instead favoring proteolytic bacteria. Remember: effective enrichment requires both providing what your target organism needs AND eliminating its competition. Look for selective agents that exploit specific metabolic differences between your target and unwanted organisms.

Question 3

A suspension of bacteria actively performing aerobic respiration in a glucose medium is treated with rotenone, a potent inhibitor of NADH dehydrogenase (Complex I) of the electron transport chain. Assuming the bacteria can also perform fermentation, what is the most immediate metabolic consequence?

  1. The rate of oxygen consumption will increase as the cell attempts to bypass the blocked complex.
  2. The proton motive force will be completely eliminated, and all ATP synthesis will cease.
  3. The oxidation of FADH₂ will be unaffected, allowing for continued, albeit reduced, ATP synthesis via oxidative phosphorylation. (correct answer)
  4. The cell will immediately switch all metabolic activity to fermentation, and the citric acid cycle will shut down.
Explanation: Rotenone specifically inhibits Complex I, preventing the transfer of electrons from NADH to the electron transport chain. However, electrons from FADH₂ (generated in the citric acid cycle by succinate dehydrogenase) enter the ETC at Complex II, downstream of the block. Therefore, the ETC can still operate using FADH₂ as an electron source, generating a proton motive force and ATP, although the total yield per glucose will be significantly reduced because the contribution from NADH is lost. Oxygen consumption will decrease, not increase. The PMF is not completely eliminated. The cell might eventually increase fermentation, but the most immediate consequence for the ETC is the continued oxidation of FADH₂.

Question 4

In the process of wine making, Saccharomyces cerevisiae converts grape sugars to ethanol. The process is initiated in the presence of air and then proceeds in a sealed, anaerobic vessel. What is the primary metabolic reason for the initial aerobic phase?

  1. To allow the yeast to produce a small amount of acetic acid, which is critical for the flavor profile of the wine.
  2. To ensure that all glucose is first converted to pyruvate before the anaerobic fermentation pathway begins.
  3. To allow the yeast to perform aerobic respiration, generating abundant ATP to support rapid cell division and biomass increase. (correct answer)
  4. To eliminate any competing obligate anaerobic bacteria that may be present on the grapes.
Explanation: The initial aerobic phase is crucial for building up a large and healthy yeast population. Aerobic respiration yields far more ATP per glucose molecule than fermentation. This high energy yield allows the yeast to grow and multiply rapidly. Once a large population is established, the vessel is sealed. The yeast then depletes the remaining oxygen and switches to anaerobic fermentation, and the large population can efficiently convert the remaining sugars to ethanol.

Question 5

A wild-type strain of E. coli generates approximately 30 ATP per molecule of glucose via aerobic respiration. A mutant strain is created that can only perform mixed-acid fermentation, which yields a net of 2 ATP per glucose. To produce an identical, large quantity of ATP required for synthesizing new biomass, what would be the approximate ratio of glucose molecules consumed by the mutant strain compared to the wild-type strain?

  1. 1:1
  2. 2:1
  3. 8:1
  4. 15:1 (correct answer)
Explanation: This question requires calculating the ratio of glucose needed to produce the same amount of ATP. The wild-type strain produces 30 ATP/glucose, while the fermentative mutant produces 2 ATP/glucose. To find out how many times more glucose the mutant needs, we divide the yield of the efficient process by the yield of the inefficient process: 30 ATP / 2 ATP = 15. Therefore, the mutant strain must consume 15 molecules of glucose to generate the same amount of ATP that the wild-type strain generates from just one molecule of glucose. The ratio is 15:1.

Question 6

A microbiologist is attempting to differentiate between two obligately anaerobic bacteria, Strain A and Strain B, both growing on glucose. Strain A produces H₂S gas as a byproduct, and its growth is completely inhibited by cyanide, an inhibitor of cytochrome c oxidase. Strain B produces propionic acid and CO₂, and its growth is unaffected by cyanide. What is the most likely conclusion?

  1. Strain A performs anaerobic respiration, while Strain B performs fermentation. (correct answer)
  2. Strain B performs anaerobic respiration, while Strain A performs fermentation.
  3. Both strains are performing different types of fermentation.
  4. Both strains are performing different types of anaerobic respiration.
Explanation: Strain A is performing anaerobic respiration. The production of H₂S indicates the use of an external inorganic electron acceptor like sulfate (SO₄²⁻) or sulfur (S), which is reduced to H₂S. Furthermore, its sensitivity to cyanide indicates the presence of a cytochrome-containing electron transport chain, a key feature of respiration. Strain B is performing fermentation. It produces organic acids (propionic acid) as end products and is unaffected by cyanide, which implies it lacks a cytochrome-based ETC and relies on substrate-level phosphorylation for ATP.

Question 7

A novel obligate anaerobe is discovered that metabolizes glucose. Its sole metabolic products are ethanol and CO₂. Analysis confirms that all its ATP is generated via substrate-level phosphorylation. Which of the following is a necessary consequence of this metabolic strategy?

  1. The organism requires a membrane-bound electron transport chain to generate a proton motive force.
  2. The organism utilizes an external inorganic molecule, such as sulfate, as a terminal electron acceptor.
  3. The organism must regenerate NAD⁺ by reducing an organic intermediate derived from glucose. (correct answer)
  4. The organism must possess a complete and functional citric acid cycle to process pyruvate.
Explanation: This organism is performing ethanol fermentation. A key requirement of fermentation is to sustain glycolysis by regenerating the NAD⁺ consumed by the glyceraldehyde-3-phosphate dehydrogenase reaction. This is accomplished by using the electrons from NADH to reduce an endogenous organic molecule (in this case, acetaldehyde, which is derived from pyruvate). This replenishes the pool of NAD⁺, allowing glycolysis and substrate-level phosphorylation to continue. The other options describe respiration, not fermentation.

Question 8

A facultative anaerobe like E. coli tightly regulates its metabolism in response to oxygen. In the presence of oxygen, genes for fermentation pathways are repressed, while genes for the TCA cycle and ETC are induced. What is the primary evolutionary advantage of this complex regulation?

  1. It conserves cellular resources by prioritizing the metabolic pathway that yields the maximum amount of ATP per mole of substrate. (correct answer)
  2. It prevents the accumulation of toxic fermentation end-products like mixed acids when they are not needed for redox balance.
  3. It allows the cell to grow much faster under anaerobic conditions than under aerobic conditions.
  4. It ensures the complete oxidation of glucose to CO₂, which is less damaging to the cell's membrane than organic acids.
Explanation: The primary driver for this regulation is energy efficiency. Aerobic respiration yields significantly more ATP (~30-32) per glucose than fermentation (2-3 ATP). By prioritizing respiration when oxygen is available, the cell maximizes its energy gain from each molecule of food. This allows for more efficient growth and better competition for limited resources. While preventing toxin accumulation is a benefit, it is secondary to the main goal of maximizing energy yield.

Question 9

A facultative anaerobe, Paracoccus denitrificans, is cultured in a bioreactor with glucose as the carbon source. The culture is initially sparged with air. After 12 hours, the air supply is stopped, the system is purged with N₂ gas, and a sterile solution of nitrate (NO₃⁻) is added. Which metabolic shift is most likely to occur?

  1. A shift from aerobic respiration to lactic acid fermentation.
  2. A shift from fermentation to aerobic respiration.
  3. A shift from aerobic respiration to anaerobic respiration. (correct answer)
  4. A shift from substrate-level phosphorylation to exclusive use of oxidative phosphorylation.
Explanation: Initially, with air (oxygen), the organism performs aerobic respiration. When oxygen is removed and nitrate (NO₃⁻) is added, P. denitrificans can use nitrate as an alternative terminal electron acceptor for its electron transport chain. This process is called anaerobic respiration. It is not fermentation because it still uses an electron transport chain and an external, inorganic electron acceptor. The organism prioritizes this more energy-efficient strategy over fermentation when a suitable acceptor is available.

Question 10

A key function of both fermentation and respiration is the regeneration of NAD⁺ from NADH, which is essential for the continuation of glycolysis. How does the ultimate fate of the electrons from NADH differ between these two processes?

  1. In respiration, electrons are passed to an external inorganic acceptor; in fermentation, they are passed to an endogenous organic acceptor. (correct answer)
  2. In respiration, electrons are used to reduce CO₂; in fermentation, they are used to reduce O₂.
  3. In both processes, electrons are passed to pyruvate, but the final products differ.
  4. In respiration, electrons are used to generate ATP directly; in fermentation, they are used to generate a proton motive force.
Explanation: This question highlights the fundamental difference in redox balancing. In respiration (both aerobic and anaerobic), electrons from NADH are passed through an electron transport chain to an external terminal electron acceptor, which is an inorganic molecule (like O₂, NO₃⁻, or SO₄²⁻). In fermentation, there is no external electron acceptor; instead, electrons from NADH are transferred to an endogenous organic molecule that is derived from the original substrate (e.g., pyruvate is reduced to lactate, or acetaldehyde is reduced to ethanol).

Question 11

Consider the complete oxidation of glucose in aerobic respiration (C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O) and the fermentation of glucose to two molecules of lactic acid (C₆H₁₂O₆ → 2C₃H₆O₃). What is a key difference regarding the oxidation state of the carbon atoms in the final products?

  1. In respiration, carbon is fully oxidized, whereas in fermentation, the average oxidation state of carbon in the products is the same as in the substrate. (correct answer)
  2. In respiration, carbon is fully reduced, whereas in fermentation, it is fully oxidized.
  3. In both processes, the carbon atoms are partially oxidized, but to a greater extent in respiration.
  4. In respiration, the carbon products are inorganic, while in fermentation, the carbon products are always more reduced than the starting glucose.
Explanation: Respiration is a process of complete oxidation. The average oxidation state of carbon in glucose (C₆H₁₂O₆) is 0. In the final product, CO₂, the oxidation state of carbon is +4. Fermentation, however, is a redox-neutral process overall with respect to the carbon substrate. The average oxidation state of carbon in lactic acid (C₃H₆O₃) is also 0. Essentially, fermentation involves internal redox balancing where some carbons are oxidized and others are reduced, but the net oxidation level of the products equals that of the starting substrate.

Question 12

A researcher is studying a bacterium that performs anaerobic respiration using fumarate as the terminal electron acceptor, reducing it to succinate. The bacterium is grown in a medium with a carbon source that is fully deuterated (all ¹H atoms are replaced by ²H). Where would the deuterium atoms carried by NADH (formed as NADD) ultimately be found?

  1. They would be transferred directly to fumarate to form deuterated succinate.
  2. They would be pumped across the membrane and ultimately incorporated into the cellular water pool as D₂O. (correct answer)
  3. They would be covalently attached to ATP molecules produced by oxidative phosphorylation.
  4. They would be incorporated into CO₂ as a waste product of the citric acid cycle.
Explanation: In anaerobic respiration, electrons from NADD are passed through the electron transport chain to fumarate (the terminal electron acceptor), while the deuterons (²H⁺) are pumped across the membrane to create the proton motive force. These deuterons become part of the cellular proton pool and ultimately equilibrate with the water in the cell, forming D₂O. The electrons alone are transferred to fumarate to form succinate, while the deuterons follow the standard chemiosmotic pathway.

Question 13

A novel obligate anaerobe is discovered that metabolizes glucose. Its sole metabolic products are ethanol and CO₂. Analysis confirms that all its ATP is generated via substrate-level phosphorylation. Which of the following is a necessary consequence of this metabolic strategy?

  1. The organism requires a membrane-bound electron transport chain to generate a proton motive force.
  2. The organism utilizes an external inorganic molecule, such as sulfate, as a terminal electron acceptor.
  3. The organism must regenerate NAD⁺ by reducing an organic intermediate derived from glucose. (correct answer)
  4. The organism must possess a complete and functional citric acid cycle to process pyruvate.
Explanation: This organism is performing ethanol fermentation. A key requirement of fermentation is to sustain glycolysis by regenerating the NAD⁺ consumed by the glyceraldehyde-3-phosphate dehydrogenase reaction. This is accomplished by using the electrons from NADH to reduce an endogenous organic molecule (in this case, acetaldehyde, which is derived from pyruvate). This replenishes the pool of NAD⁺, allowing glycolysis and substrate-level phosphorylation to continue. The other options describe respiration, not fermentation.

Question 14

The generation of a proton motive force (PMF) is a central feature of respiration but not fermentation. Which of the following processes is the direct driver for establishing the PMF during aerobic respiration?

  1. The direct hydrolysis of ATP molecules by membrane-bound pumps to transport protons out of the cell.
  2. The movement of electrons through the membrane-bound complexes of the electron transport chain. (correct answer)
  3. The substrate-level phosphorylation of ADP in the cytoplasm, which releases protons as a byproduct.
  4. The reduction of NAD⁺ to NADH during the reactions of the citric acid cycle within the mitochondrial matrix or cytoplasm.
Explanation: The proton motive force is generated as high-energy electrons from NADH and FADH₂ are passed along the series of protein complexes in the electron transport chain. Several of these complexes use the energy released during electron transfer to actively pump protons (H⁺) from the cytoplasm (or mitochondrial matrix) to the outside of the membrane (or intermembrane space), creating an electrochemical gradient. This gradient, the PMF, is then used by ATP synthase to make ATP. The other options describe processes that are either unrelated or are not the direct cause of PMF generation.

Question 15

A microbiologist is studying a mutant strain of Escherichia coli with a deletion in the atp operon, rendering its ATP synthase complex non-functional. All components of its electron transport chain are otherwise intact. How will this mutation affect the cell's ability to produce ATP under aerobic versus anaerobic conditions (in a glucose medium)?

  1. The cell cannot produce any ATP under either condition and will not survive.
  2. The cell can produce ATP only by fermentation under aerobic conditions and by respiration under anaerobic conditions.
  3. The cell can produce ATP via substrate-level phosphorylation under both conditions but cannot perform oxidative phosphorylation. (correct answer)
  4. The cell can produce ATP normally under aerobic conditions but must rely on fermentation under anaerobic conditions.
Explanation: ATP synthase is the enzyme that produces ATP using the proton motive force generated by the electron transport chain (oxidative phosphorylation). Without a functional ATP synthase, the cell cannot perform oxidative phosphorylation. However, it can still generate ATP via substrate-level phosphorylation, which occurs during glycolysis. Therefore, the mutant can survive by performing glycolysis and fermentation (under anaerobic conditions) or glycolysis followed by an uncoupled ETC (under aerobic conditions), with all ATP coming from substrate-level phosphorylation.

Question 16

A microbiologist is attempting to differentiate between two obligately anaerobic bacteria, Strain A and Strain B, both growing on glucose. Strain A produces H₂S gas as a byproduct, and its growth is completely inhibited by cyanide, an inhibitor of cytochrome c oxidase. Strain B produces propionic acid and CO₂, and its growth is unaffected by cyanide. What is the most likely conclusion?

  1. Strain A performs anaerobic respiration, while Strain B performs fermentation. (correct answer)
  2. Strain B performs anaerobic respiration, while Strain A performs fermentation.
  3. Both strains are performing different types of fermentation.
  4. Both strains are performing different types of anaerobic respiration.
Explanation: Strain A is performing anaerobic respiration. The production of H₂S indicates the use of an external inorganic electron acceptor like sulfate (SO₄²⁻) or sulfur (S), which is reduced to H₂S. Furthermore, its sensitivity to cyanide indicates the presence of a cytochrome-containing electron transport chain, a key feature of respiration. Strain B is performing fermentation. It produces organic acids (propionic acid) as end products and is unaffected by cyanide, which implies it lacks a cytochrome-based ETC and relies on substrate-level phosphorylation for ATP.

Question 17

An organism's respiratory quotient (RQ) is the ratio of CO₂ produced to O₂ consumed. For glucose (C₆H₁₂O₆), the RQ for aerobic respiration is 1.0. An organism is grown in a sealed container with glucose and a fixed amount of oxygen. Initially, its RQ is 1.0. As oxygen is depleted, the RQ value begins to rise sharply above 1.0. What does this change indicate?

  1. The organism is switching from glucose to lipid metabolism, which has a lower RQ.
  2. The organism is switching from respiration to a fermentation pathway that produces CO₂. (correct answer)
  3. The organism has increased the efficiency of its electron transport chain, producing more CO₂ per O₂.
  4. The organism is performing anaerobic respiration, which consumes CO₂ and releases O₂.
Explanation: An RQ of 1.0 indicates complete aerobic respiration of a carbohydrate. A sharp rise in the RQ above 1.0 means that CO₂ is being produced at a much higher rate than O₂ is being consumed. This occurs when the organism, a facultative anaerobe, depletes the oxygen and switches to a fermentation pathway that still produces CO₂ (like ethanol fermentation: C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂). In this fermentative state, CO₂ is still being produced, but O₂ consumption has dropped to zero, causing the ratio (CO₂ produced / O₂ consumed) to approach infinity. Switching to lipids would decrease the RQ below 1.0.

Question 18

An organism's respiratory quotient (RQ) is the ratio of CO₂ produced to O₂ consumed. For glucose (C₆H₁₂O₆), the RQ for aerobic respiration is 1.0. An organism is grown in a sealed container with glucose and a fixed amount of oxygen. Initially, its RQ is 1.0. As oxygen is depleted, the RQ value begins to rise sharply above 1.0. What does this change indicate?

  1. The organism is switching from glucose to lipid metabolism, which has a lower RQ.
  2. The organism is switching from respiration to a fermentation pathway that produces CO₂. (correct answer)
  3. The organism has increased the efficiency of its electron transport chain, producing more CO₂ per O₂.
  4. The organism is performing anaerobic respiration, which consumes CO₂ and releases O₂.
Explanation: An RQ of 1.0 indicates complete aerobic respiration of a carbohydrate. A sharp rise in the RQ above 1.0 means that CO₂ is being produced at a much higher rate than O₂ is being consumed. This occurs when the organism, a facultative anaerobe, depletes the oxygen and switches to a fermentation pathway that still produces CO₂ (like ethanol fermentation: C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂). In this fermentative state, CO₂ is still being produced, but O₂ consumption has dropped to zero, causing the ratio (CO₂ produced / O₂ consumed) to approach infinity. Switching to lipids would decrease the RQ below 1.0.

Question 19

A researcher is designing an enrichment culture to isolate a novel obligately fermentative bacterium that metabolizes glucose from a complex soil sample. Which of the following strategies would be most effective for selecting for this specific type of organism?

  1. Incubate anaerobically in a medium with glucose as the sole carbon source and nitrate as a potential electron acceptor.
  2. Incubate aerobically in a glucose-rich medium to allow rapid growth of all glucose metabolizers.
  3. Incubate anaerobically in a medium containing only complex proteins and lipids, with no added carbohydrates.
  4. Incubate anaerobically in a glucose-rich medium that also contains oligomycin, a specific inhibitor of F₁F₀ ATP synthase. (correct answer)
Explanation: When you encounter questions about enrichment cultures, think about creating selective conditions that favor your target organism while inhibiting competitors. The goal is to design an environment where only organisms with specific metabolic capabilities can thrive. An obligately fermentative bacterium can only generate ATP through substrate-level phosphorylation during fermentation—it cannot use aerobic respiration or anaerobic respiration. To isolate such an organism, you need conditions that eliminate respiratory competitors while providing the fermentable substrate it requires. Choice D is correct because it creates the perfect selective environment. The anaerobic conditions prevent aerobic respirers from growing, while glucose provides the fermentable substrate. Most importantly, oligomycin specifically inhibits the F₁F₀ ATP synthase complex, which is essential for oxidative phosphorylation in respiration but not needed for fermentation. This drug will kill respiratory organisms while leaving fermentative bacteria unharmed, since they generate ATP through substrate-level phosphorylation. Choice A fails because nitrate serves as an electron acceptor for anaerobic respiration, allowing respiratory bacteria to outcompete the slow-growing fermentative organism you want. Choice B uses aerobic conditions, which directly contradicts the anaerobic requirements for enriching fermentative bacteria. Choice C eliminates glucose entirely, removing the preferred substrate for your target organism and instead favoring proteolytic bacteria. Remember: effective enrichment requires both providing what your target organism needs AND eliminating its competition. Look for selective agents that exploit specific metabolic differences between your target and unwanted organisms.

Question 20

A wild-type strain of E. coli generates approximately 30 ATP per molecule of glucose via aerobic respiration. A mutant strain is created that can only perform mixed-acid fermentation, which yields a net of 2 ATP per glucose. To produce an identical, large quantity of ATP required for synthesizing new biomass, what would be the approximate ratio of glucose molecules consumed by the mutant strain compared to the wild-type strain?

  1. 1:1
  2. 2:1
  3. 8:1
  4. 15:1 (correct answer)
Explanation: This question requires calculating the ratio of glucose needed to produce the same amount of ATP. The wild-type strain produces 30 ATP/glucose, while the fermentative mutant produces 2 ATP/glucose. To find out how many times more glucose the mutant needs, we divide the yield of the efficient process by the yield of the inefficient process: 30 ATP / 2 ATP = 15. Therefore, the mutant strain must consume 15 molecules of glucose to generate the same amount of ATP that the wild-type strain generates from just one molecule of glucose. The ratio is 15:1.