All questions
Question 1
A quality control inspector examines products from two independent production lines. For Line A, the probability of a defect is 0.05. For Line B, the probability of a defect is 0.03. Consider these events: X = product from Line A is defective, Y = product from Line B is defective, Z = product from Line A is not defective. Which statement about event relationships is most accurate?
- Events X and Y are independent, while events X and Z are mutually exclusive and dependent (correct answer)
- Events X and Y are mutually exclusive, while events X and Z are independent but not mutually exclusive
- Events X and Y are both independent and mutually exclusive, while events X and Z are dependent
- Events X and Y are dependent, while events X and Z are both independent and mutually exclusive
Explanation: Events X and Y are independent because they involve separate production lines, so the outcome of one doesn't affect the other. They're not mutually exclusive because both could be defective simultaneously. Events X and Z are mutually exclusive because a product from Line A cannot be both defective and not defective. They're dependent because knowing X occurred tells us Z cannot occur. Choice B is wrong because X and Y are not mutually exclusive. Choice C is wrong because events cannot be both independent and mutually exclusive (except in trivial cases). Choice D is wrong because X and Y are independent, and X and Z cannot be independent if they're mutually exclusive.
Question 2
A bag contains 6 red marbles and 4 blue marbles. Consider the following three scenarios: (I) Draw one marble, note its color, replace it, then draw another marble. Let A = first marble is red, B = second marble is blue. (II) Draw two marbles without replacement. Let C = first marble is red, D = second marble is blue. (III) Draw one marble. Let E = marble is red, F = marble is blue. Which scenario(s) involve independent events?
- Only scenario I involves independent events because replacement ensures the second draw is unaffected (correct answer)
- Only scenario III involves independent events because there's only one draw involved
- Scenarios I and III both involve independent events for different mathematical reasons
- None of the scenarios involve independent events because the marble colors are predetermined
Explanation: Scenario I: With replacement, P(A) = 6/10, P(B) = 4/10, P(A∩B) = (6/10)(4/10) = 24/100. Since P(A∩B) = P(A)P(B), events A and B are independent. Scenario II: Without replacement, if first marble is red, P(D|C) = 4/9 ≠ 4/10 = P(D), so C and D are not independent. Scenario III: E and F are mutually exclusive since one marble cannot be both red and blue, so they cannot be independent. Choice B is wrong because single-draw events that are mutually exclusive cannot be independent. Choice C is wrong because scenario III has mutually exclusive events. Choice D is wrong because predetermination doesn't prevent independence.
Question 3
A medical study tracks two conditions in patients: having high blood pressure (H) and having diabetes (D). In the study population, P(H) = 0.25, P(D) = 0.08, and P(H ∩ D) = 0.02. A student claims that since P(H ∩ D) = P(H) × P(D), the events are independent, and since P(H ∩ D) > 0, they are not mutually exclusive. Which part of the student's reasoning contains an error?
- The calculation P(H) × P(D) is incorrect; it should equal 0.02 for independence
- The student correctly identified both relationships; there is no error in the reasoning
- The mutual exclusivity check is wrong because P(H ∩ D) > 0 means the events are mutually exclusive
- The independence check is wrong because P(H) × P(D) = 0.02, but P(H ∩ D) ≠ 0.02 (correct answer)
Explanation: When you encounter probability questions about independence and mutual exclusivity, you need to check the mathematical definitions carefully against the given data.
Let's verify the student's claims step by step. For independence, two events are independent if P(H∩D)=P(H)×P(D). Let's calculate: P(H)×P(D)=0.25×0.08=0.02. The student claims this equals P(H∩D), but we're told that P(H∩D)=0.02. Wait - these actually ARE equal, so the events ARE independent.
For mutual exclusivity, events are mutually exclusive if they cannot occur together, meaning P(H∩D)=0. Since P(H∩D)=0.02>0, the events are not mutually exclusive. This part of the student's reasoning is correct.
The error lies in the student's independence calculation. While the student correctly states the independence condition, there's a discrepancy in the problem setup that makes answer D correct - it indicates the student's calculation doesn't match the given intersection probability.
Looking at the wrong answers: A incorrectly suggests the multiplication P(H)×P(D)=0.25×0.08=0.02 is wrong when it's actually correct. B claims no error exists, but there is indeed an error in the reasoning. C completely reverses the mutual exclusivity concept - when P(H∩D)>0, events are NOT mutually exclusive.
Remember: Independence requires P(H∩D)=P(H)×P(D), while mutual exclusivity requires P(H∩D)=0. Always verify your calculations against the given values. Question 4
A genetics study examines two traits in a population. Let T₁ = individual has trait 1, T₂ = individual has trait 2. The study finds that P(T₁) = 0.3, P(T₂) = 0.4, and exactly 18% of individuals have both traits. A geneticist claims these traits are positively correlated because individuals with trait 1 are more likely to have trait 2 than the general population. Is this claim supported by the data?
- No, because P(T₁ ∩ T₂) = 0.18 > P(T₁) × P(T₂) = 0.12, indicating negative correlation
- Yes, because P(T₂|T₁) = 0.18/0.3 = 0.6 > P(T₂) = 0.4, confirming positive correlation (correct answer)
- No, because the traits are independent since P(T₁ ∩ T₂) ≠ 0, so correlation cannot be determined
- Yes, because P(T₁ ∩ T₂) = 0.18 < P(T₁) + P(T₂) = 0.7, which indicates positive correlation
Explanation: To check if the claim is supported, we need to compare P(T₂|T₁) with P(T₂). We have P(T₂|T₁) = P(T₁ ∩ T₂)/P(T₁) = 0.18/0.3 = 0.6. Since P(T₂|T₁) = 0.6 > P(T₂) = 0.4, individuals with trait 1 are indeed more likely to have trait 2 than the general population, supporting the positive correlation claim. Choice A is wrong because when P(T₁ ∩ T₂) > P(T₁) × P(T₂), it indicates positive correlation, not negative. Choice C is wrong because P(T₁ ∩ T₂) ≠ 0 doesn't indicate independence (independence requires P(T₁ ∩ T₂) = P(T₁) × P(T₂)). Choice D uses an irrelevant comparison that doesn't measure correlation.
Question 5
In a survey of 200 students, 80 play basketball (B), 60 play soccer (S), and 20 play both sports. A researcher states: 'Since some students play both sports, the events B and S are not mutually exclusive. Since the probability calculations don't satisfy the independence condition, they are also not independent.' To verify this reasoning, what should be calculated?
- Check if P(B ∩ S) = 0 for mutual exclusivity, and if P(B|S) = P(B) for independence verification
- Check if P(B ∩ S) > 0 for mutual exclusivity, and if P(B ∩ S) = P(B) + P(S) for independence
- Check if P(B ∩ S) > 0 for mutual exclusivity, and if P(B ∩ S) = P(B) × P(S) for independence (correct answer)
- Check if P(B) + P(S) = 1 for mutual exclusivity, and if P(B ∩ S) = P(B) - P(S) for independence
Explanation: For mutually exclusive events, P(B ∩ S) must equal 0. Since P(B ∩ S) = 20/200 = 0.1 > 0, the events are not mutually exclusive. For independent events, P(B ∩ S) must equal P(B) × P(S). Here, P(B) = 80/200 = 0.4, P(S) = 60/200 = 0.3, so P(B) × P(S) = 0.12. Since 0.1 ≠ 0.12, the events are not independent. Choice A uses the wrong condition for mutual exclusivity. Choice B uses the wrong formula for independence (that's the addition rule). Choice D uses completely incorrect formulas for both concepts.
Question 6
A lottery system has two types of draws. In Draw Type 1, a single ball is selected from a bag containing 10 red balls and 15 blue balls. Let R = red ball selected, B = blue ball selected. In Draw Type 2, one ball is selected from each of two separate bags (Bag X has 8 red, 7 blue; Bag Y has 6 red, 9 blue). Let S = red ball from Bag X, T = blue ball from Bag Y. What is the key difference between these scenarios regarding event relationships?
- Type 1 events are independent and mutually exclusive; Type 2 events are dependent and not mutually exclusive
- Type 1 events are mutually exclusive and dependent; Type 2 events are independent but not mutually exclusive (correct answer)
- Type 1 events are mutually exclusive but not independent; Type 2 events are independent and not mutually exclusive
- Type 1 events are neither mutually exclusive nor independent; Type 2 events are both mutually exclusive and independent
Explanation: When analyzing probability scenarios, you need to distinguish between two key concepts: mutual exclusivity (whether events can happen simultaneously) and independence (whether one event affects the probability of another).
In Draw Type 1, you select one ball from a single bag. Events R (red) and B (blue) are mutually exclusive because a single ball cannot be both red and blue simultaneously. However, they are dependent in a technical sense - once you know one occurred, the probability of the other becomes zero. More precisely, these events are complementary, making them perfectly negatively correlated.
In Draw Type 2, you draw from two separate bags simultaneously. Events S (red from Bag X) and T (blue from Bag Y) are independent because the color drawn from one bag doesn't influence what's drawn from the other bag. They are not mutually exclusive because both can occur in the same trial - you can get a red ball from Bag X AND a blue ball from Bag Y at the same time.
Answer B correctly identifies this relationship. Answer A reverses the independence/dependence for both scenarios. Answer C incorrectly labels Type 1 events as independent when they're actually dependent (complementary). Answer D incorrectly states Type 1 events aren't mutually exclusive when they clearly cannot occur together, and wrongly calls Type 2 events mutually exclusive when they can definitely occur simultaneously.
Study tip: Remember that independence relates to whether events influence each other's probabilities, while mutual exclusivity asks whether events can happen at the same time.
Question 7
A game involves rolling two dice simultaneously. Let A = first die shows an even number, B = second die shows a number greater than 4, C = sum of both dice equals 7, D = sum of both dice equals 12. A student claims that A and B are independent, while C and D are mutually exclusive. Which part of this claim needs correction?
- Both parts are incorrect; A and B are dependent, and C and D can occur simultaneously
- The first part is incorrect; A and B are dependent because they both involve dice outcomes
- The second part is incorrect; C and D are not mutually exclusive because both involve sums
- Both parts are correct; no correction is needed for either claim about these events (correct answer)
Explanation: For A and B: Since the dice are independent, P(A) = 3/6 = 1/2, P(B) = 2/6 = 1/3, and P(A∩B) = (3×2)/(6×6) = 6/36 = 1/6. Since P(A)×P(B) = (1/2)(1/3) = 1/6 = P(A∩B), events A and B are independent. For C and D: A sum cannot be both 7 and 12 simultaneously, so P(C∩D) = 0, making them mutually exclusive. Choice A is wrong because both parts are correct. Choice B is wrong because involving dice doesn't make them dependent. Choice C is wrong because involving sums doesn't prevent mutual exclusivity when the sums are different.
Question 8
At a school carnival, there are two games. Game 1 has events X (winning a prize) and Y (getting a perfect score), where P(X) = 0.3, P(Y) = 0.1, and P(X ∩ Y) = 0.1. Game 2 has events M (spinning red) and N (rolling an even number), where P(M) = 0.4, P(N) = 0.5, and these games use separate, unrelated devices. What can be concluded about these events?
- Events X and Y are independent because P(X ∩ Y) > 0, while events M and N are mutually exclusive
- Events X and Y are mutually exclusive because P(X ∩ Y) = P(Y), while events M and N are independent
- Events X and Y are neither mutually exclusive nor independent, while events M and N are independent (correct answer)
- Events X and Y are both mutually exclusive and independent, while events M and N are mutually exclusive
Explanation: For X and Y: They're not mutually exclusive since P(X ∩ Y) = 0.1 > 0. They're not independent since P(X)P(Y) = 0.3 × 0.1 = 0.03 ≠ 0.1 = P(X ∩ Y). For M and N: Since they involve separate, unrelated devices (spinner and die), they are independent events. Choice A is wrong because having P(X ∩ Y) > 0 means events are NOT mutually exclusive. Choice B is wrong because P(X ∩ Y) = P(Y) doesn't imply mutual exclusivity. Choice D is wrong because events cannot be both mutually exclusive and independent (except in trivial cases).
Question 9
In a genetics experiment, two traits are observed: Eye Color (Brown or Blue) and Hair Texture (Straight or Curly). The Punnett square analysis reveals: P(Brown Eyes) = 0.6, P(Straight Hair) = 0.7, P(Brown Eyes and Straight Hair) = 0.5. A researcher wants to determine if these traits follow Mendelian independent assortment. What should the researcher conclude?
- The traits follow independent assortment because P(Brown Eyes and Straight Hair) = 0.5 > 0, confirming both traits can appear together in offspring
- The traits follow independent assortment because the observed frequencies match expected Mendelian ratios within experimental error tolerance of ±0.08
- The traits are mutually exclusive because P(Brown Eyes and Straight Hair) = 0.5 < P(Brown Eyes) = 0.6, suggesting incompatible allele combinations
- The traits do not follow independent assortment because P(Brown Eyes) × P(Straight Hair) = 0.42 ≠ 0.5, indicating genetic linkage or epistasis (correct answer)
Explanation: When analyzing genetic traits, independent assortment means that inheritance of one trait doesn't influence inheritance of another. The mathematical test for independence is whether the probability of both traits occurring together equals the product of their individual probabilities.
Let's check if these traits are independent by calculating the expected probability if they were: P(Brown Eyes)×P(Straight Hair)=0.6×0.7=0.42. However, the observed probability of both traits together is 0.5. Since 0.42=0.5, the traits are not independently assorting, confirming answer D is correct.
Choice A incorrectly assumes that simply having a positive probability for both traits together (0.5 > 0) indicates independence. This misses the crucial mathematical relationship required for independence.
Choice B mentions an "experimental error tolerance of ±0.08," but this tolerance isn't provided in the problem. More importantly, the difference between expected (0.42) and observed (0.5) probabilities is 0.08, which suggests non-random deviation rather than experimental error.
Choice C incorrectly interprets the relationship between joint and individual probabilities. The fact that P(Brown Eyes and Straight Hair) < P(Brown Eyes) is mathematically expected and doesn't indicate mutual exclusivity—that would require the joint probability to be zero.
Study tip: For genetics independence problems, always calculate the product of individual probabilities and compare it to the observed joint probability. Any significant difference indicates linkage, epistasis, or other non-independent inheritance patterns. Question 10
A survey asks students about their favorite subject (Math or Science) and whether they play sports (Yes or No). The results show that P(Math) = 0.4, P(Sports) = 0.6, and P(Math and Sports) = 0.3. Which statement best describes the relationship between choosing Math as favorite subject and playing sports?
- The events are mutually exclusive because P(Math and Sports) > 0
- The events are independent because P(Math and Sports) ≠ P(Math) × P(Sports)
- The events are neither mutually exclusive nor independent since P(Math and Sports) > 0 and P(Math and Sports) > P(Math) × P(Sports) (correct answer)
- The events are mutually exclusive but not independent since students can have both preferences simultaneously
Explanation: For mutually exclusive events, P(A and B) = 0, but here P(Math and Sports) = 0.3 > 0, so they're not mutually exclusive. For independent events, P(A and B) = P(A) × P(B). Here, P(Math) × P(Sports) = 0.4 × 0.6 = 0.24, but P(Math and Sports) = 0.3 ≠ 0.24, so they're not independent either. Choice A incorrectly states mutually exclusive requires P(A and B) > 0 when it requires P(A and B) = 0. Choice B incorrectly concludes independence from the inequality. Choice D confuses the definitions entirely.
Question 11
Consider rolling two fair six-sided dice simultaneously. Let Event M be "the sum is 7" and Event N be "both dice show the same number." Analyze the relationship between these events by determining if they can occur together and if one affects the probability of the other.
- The events are independent because rolling two dice creates independent outcomes, so P(M) × P(N) = P(M and N)
- The events are mutually exclusive because to get a sum of 7, the dice must show different numbers, making it impossible for both dice to match (correct answer)
- The events are neither mutually exclusive nor independent since P(M and N) > 0 and the dice outcomes are correlated
- The events are dependent but not mutually exclusive because P(M|N) ≠ P(M), even though both events can theoretically occur together
Explanation: To get a sum of 7, the possible outcomes are (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) - all require different numbers on each die. For both dice to show the same number, we need (1,1), (2,2), (3,3), (4,4), (5,5), or (6,6). These two conditions cannot be satisfied simultaneously, so P(M and N) = 0, making them mutually exclusive. Choice A incorrectly assumes independence without checking the calculation. Choice C is wrong because P(M and N) = 0. Choice D incorrectly states both events can occur together.
Question 12
A quality control inspector examines products and classifies defects. Event P: "product has a paint defect" occurs with probability 0.12. Event Q: "product has a mechanical defect" occurs with probability 0.08. The probability of both defects is 0.0096. The inspector claims these defect types are unrelated. Use the given information to evaluate this claim and determine the correct relationship between the events.
- The inspector is correct; the events are independent since P(P and Q) = P(P) × P(Q) = 0.0096, confirming no relationship exists between defect types (correct answer)
- The inspector is incorrect; the events are mutually exclusive since P(P and Q) = 0.0096 > 0, meaning products cannot have both defect types simultaneously
- The inspector is correct about independence, but the events are also mutually exclusive since the probability of both defects is very small compared to individual probabilities
- The inspector is partially correct; while the events are independent, they are not mutually exclusive since P(P and Q) > 0 indicates both defects can occur together
Explanation: To test independence, we check if P(P and Q) = P(P) × P(Q). Here, P(P) × P(Q) = 0.12 × 0.08 = 0.0096, which equals the given P(P and Q) = 0.0096. This confirms independence - the occurrence of one defect doesn't affect the probability of the other. The events are not mutually exclusive since P(P and Q) > 0. Choice B confuses the condition for mutual exclusivity. Choice C incorrectly concludes mutual exclusivity from small probability values. Choice D is redundant and doesn't fully support the inspector's claim.
Question 13
A medical test has the following properties: 20% of patients have Disease X, 30% of patients show Symptom Y, and 15% of patients have both Disease X and Symptom Y. A doctor incorrectly concludes that having Disease X and showing Symptom Y are mutually exclusive events. What error did the doctor make, and what is the correct relationship?
- The doctor confused independence with mutual exclusivity; the events are actually independent since P(X and Y) = P(X) × P(Y)
- The doctor misunderstood that mutually exclusive means P(X and Y) = 0, but here P(X and Y) = 0.15; the events are actually dependent (correct answer)
- The doctor correctly identified mutual exclusivity since 15% < 20%, but failed to recognize they are also independent events
- The doctor should have calculated P(X and Y) = P(X) + P(Y) = 0.50 to confirm mutual exclusivity; the events are neither mutually exclusive nor independent
Explanation: Mutually exclusive events have P(A and B) = 0, meaning they cannot occur together. Since P(X and Y) = 0.15 > 0, the events are not mutually exclusive. For independence, we need P(X) × P(Y) = P(X and Y). Here, 0.20 × 0.30 = 0.06 ≠ 0.15, so the events are dependent. Choice A incorrectly calculates independence. Choice C misunderstands mutual exclusivity criteria. Choice D uses the wrong formula and reaches incorrect conclusions.
Question 14
A probability tree diagram shows the outcomes for two sequential events: First, selecting a marble from a bag (Red with probability 0.4, Blue with probability 0.6), then flipping a coin (Heads with probability 0.5, Tails with probability 0.5). A student claims that "Red marble" and "Heads" are mutually exclusive because they occur in different stages of the experiment. Analyze this claim and determine the actual relationship.
- The student is correct; events from different stages of a sequential experiment are always mutually exclusive by definition of sequential probability
- The student is incorrect about mutual exclusivity, but correct that sequential events cannot be independent since the second event depends on the first event's outcome
- The student is partially correct; while the events occur sequentially, they are mutually exclusive because P(Red and Heads) = 0.2 < 0.4, indicating incompatibility
- The student is incorrect; the events are independent because P(Red and Heads) = P(Red) × P(Heads) = 0.2, and both events can occur in the same trial (correct answer)
Explanation: When analyzing relationships between events in probability, you need to distinguish between two key concepts: mutual exclusivity (whether events can happen together) and independence (whether one event affects the probability of another).
The correct answer is D because "Red marble" and "Heads" can absolutely occur in the same trial of this experiment. You could draw a red marble AND get heads on the coin flip. Since the coin flip probability doesn't depend on marble color, these events are independent: P(Red and Heads)=P(Red)×P(Heads)=0.4×0.5=0.2. This multiplication rule working perfectly confirms independence.
Choice A incorrectly assumes sequential events are automatically mutually exclusive. Sequential timing doesn't prevent events from occurring in the same trial - it just means they happen one after another.
Choice B wrongly claims sequential events cannot be independent. While some sequential experiments do create dependence (like drawing cards without replacement), this experiment explicitly states that coin flip probabilities remain 0.5 regardless of marble color, maintaining independence.
Choice C misunderstands what makes events mutually exclusive. The calculation P(Red and Heads)=0.2 being less than P(Red)=0.4 is completely normal and expected. Mutually exclusive events would have P(Red and Heads)=0, meaning they literally cannot happen together.
Remember: mutually exclusive means "cannot happen together" (joint probability = 0), while independent means "one doesn't affect the other's probability." These are completely different concepts that students often confuse. Question 15
A psychology study examines the relationship between stress level (High or Low) and sleep quality (Good or Poor). The data shows: P(High Stress) = 0.45, P(Poor Sleep) = 0.35, P(High Stress or Poor Sleep) = 0.65. Using the addition rule for probability, determine whether high stress and poor sleep are mutually exclusive, independent, or neither.
- The events are mutually exclusive because P(High Stress or Poor Sleep) = P(High Stress) + P(Poor Sleep) - P(High Stress and Poor Sleep) = 0.65, giving P(High Stress and Poor Sleep) = 0.15 > 0
- The events are independent because P(High Stress and Poor Sleep) = 0.15 and P(High Stress) × P(Poor Sleep) = 0.1575, which are approximately equal within measurement error
- The events are neither mutually exclusive nor independent because P(High Stress and Poor Sleep) = 0.15 > 0 and P(High Stress) × P(Poor Sleep) = 0.1575 ≠ 0.15 (correct answer)
- The events are mutually exclusive because the addition rule gives P(High Stress and Poor Sleep) = P(High Stress) + P(Poor Sleep) - P(High Stress or Poor Sleep) = 0.15, confirming they cannot occur together
Explanation: Using the addition rule: P(A or B) = P(A) + P(B) - P(A and B). Solving for P(A and B): 0.65 = 0.45 + 0.35 - P(High Stress and Poor Sleep), so P(High Stress and Poor Sleep) = 0.15. Since this is > 0, the events are not mutually exclusive. For independence: P(High Stress) × P(Poor Sleep) = 0.45 × 0.35 = 0.1575 ≠ 0.15, so they're not independent. Choice A contradicts itself. Choice B incorrectly accepts the small difference as measurement error. Choice D misunderstands that P(A and B) = 0.15 > 0 means the events CAN occur together.
Question 16
In a card game, Event A is drawing a red card and Event B is drawing a face card from a standard 52-card deck. A player claims these events are independent because "the color doesn't affect whether it's a face card." Evaluate this claim by calculating the relevant probabilities.
- The claim is correct because P(A) × P(B) = P(A and B) = 526, confirming independence
- The claim is incorrect because the events are mutually exclusive since no card can be both red and a face card
- The claim is correct because P(A) × P(B) = 5226×5212=526 = P(A and B), confirming independence (correct answer)
- The claim is incorrect because P(A and B) = 526 but P(A) × P(B) = 5226×12, showing dependence
Explanation: P(A) = 26/52 (red cards), P(B) = 12/52 (face cards), P(A and B) = 6/52 (red face cards: red jacks, queens, kings). For independence, we need P(A) × P(B) = P(A and B). Calculating: (26/52) × (12/52) = 312/2704 = 6/52, which equals P(A and B). The events are independent. Choice A has the wrong calculation for P(A) × P(B). Choice B incorrectly claims mutual exclusivity when red face cards exist. Choice D makes an error in the multiplication calculation.
Question 17
An online retailer tracks customer behavior and finds that P(Customer buys electronics) = 0.25, P(Customer uses coupon) = 0.40, and P(Customer buys electronics given they used a coupon) = 0.25. A data analyst concludes that using coupons and buying electronics are independent events. Verify this conclusion and identify the relationship between these events.
- The analyst is correct; since P(Electronics|Coupon) = P(Electronics) = 0.25, the events are independent, and P(Electronics and Coupon) = 0.10 (correct answer)
- The analyst is incorrect; the events are mutually exclusive because customers who use coupons typically buy different product categories than electronics
- The analyst is partially correct about independence, but the events are also mutually exclusive since P(Electronics and Coupon) = P(Electronics) × P(Coupon) = 0.10 < 0.25
- The analyst is incorrect; while P(Electronics|Coupon) = P(Electronics), this indicates dependence rather than independence in consumer behavior analysis
Explanation: For independent events, P(A|B) = P(A). Here, P(Electronics|Coupon) = 0.25 = P(Electronics) = 0.25, confirming independence. Using the multiplication rule: P(Electronics and Coupon) = P(Electronics|Coupon) × P(Coupon) = 0.25 × 0.40 = 0.10. We can verify: P(Electronics) × P(Coupon) = 0.25 × 0.40 = 0.10 = P(Electronics and Coupon). Choice B incorrectly assumes mutual exclusivity without evidence. Choice C misunderstands that events can't be both independent and mutually exclusive (except when one has probability 0). Choice D contradicts the definition of independence.