ISEE Upper Level Quiz: 3 D Volume
20 questions · exam conditions
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3 D VolumeQuestion 1 of 20

A rectangular prism measures 4 cm by 3 cm by 5 cm; using V=lwhV=lwh, what is its volume?

60 cm360\text{ cm}^3
12 cm312\text{ cm}^3
47 cm347\text{ cm}^3
94 cm394\text{ cm}^3
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ISEE Upper Level Quiz

ISEE Upper Level Quiz: 3 D Volume

Practice 3 D Volume in ISEE Upper Level with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on 3 D Volume, giving you a quick way to practice the rules, question types, and explanations that matter most for ISEE Upper Level.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A rectangular prism measures 4 cm by 3 cm by 5 cm; using V=lwhV=lwh, what is its volume?

  1. 60 cm360\text{ cm}^3 (correct answer)
  2. 12 cm312\text{ cm}^3
  3. 47 cm347\text{ cm}^3
  4. 94 cm394\text{ cm}^3
Explanation: This question tests ISEE Upper Level Mathematics Achievement, specifically the ability to calculate the volume of three-dimensional figures. Volume is the measure of space occupied by a 3D object, calculated by using specific formulas for different shapes. In this question, students must apply the volume formula V = l * w * h for a rectangular prism to calculate accurately. The correct answer, choice A, is derived by multiplying the dimensions 4 cm, 3 cm, and 5 cm, resulting in a volume of 60 cm³. Choice B is incorrect because it results from a common mistake of adding the dimensions instead of multiplying them. Teaching strategies include encouraging students to practice identifying the correct formula for each shape and performing step-by-step calculations to avoid errors. Emphasize checking unit consistency and understanding the relationship between volume and dimensions.

Question 2

A cube has a volume of 343 cubic inches. What is the length of each edge?

  1. 6 inches
  2. 7 inches (correct answer)
  3. 8 inches
  4. 9 inches
Explanation: When you encounter cube problems, remember that a cube has all edges of equal length, and volume equals edge length cubed: V=s3V = s^3, where ss is the side length. To find the edge length from a given volume of 343 cubic inches, you need to find the cube root of 343. This means asking: "What number, when multiplied by itself three times, gives 343?" Let's work backwards from the answer choices. For choice B) 7 inches: 73=7×7×7=49×7=3437^3 = 7 \times 7 \times 7 = 49 \times 7 = 343. This matches our given volume exactly, so 7 inches is correct. Let's verify why the other choices don't work: Choice A) 6 inches: 63=6×6×6=2166^3 = 6 \times 6 \times 6 = 216 cubic inches, which is too small. Choice C) 8 inches: 83=8×8×8=5128^3 = 8 \times 8 \times 8 = 512 cubic inches, which is too large. Choice D) 9 inches: 93=9×9×9=7299^3 = 9 \times 9 \times 9 = 729 cubic inches, which is much too large. The key insight is recognizing that 343 is a perfect cube. When you see volume problems with "nice" numbers like 343, the answer is likely a whole number, so testing the given choices by cubing them is often the fastest approach. Memorizing the first several perfect cubes (13=11^3 = 1, 23=82^3 = 8, 33=273^3 = 27, 43=644^3 = 64, 53=1255^3 = 125, 63=2166^3 = 216, 73=3437^3 = 343, etc.) will save you time on cube and cube root problems.

Question 3

A cone has a base radius of 5 inches and a volume of 100π cubic inches. What is the height of the cone?

  1. 4 inches
  2. 12 inches (correct answer)
  3. 20 inches
  4. 25 inches
Explanation: When you encounter cone volume problems, you're working with the formula V=13πr2hV = \frac{1}{3}\pi r^2 h, where V is volume, r is the base radius, and h is the height. The key is identifying which values you know and solving for the unknown. You're given that the base radius is 5 inches and the volume is 100π cubic inches. Substituting these values into the formula: 100π=13π(5)2h100\pi = \frac{1}{3}\pi (5)^2 h Simplifying: 100π=13π(25)h=25πh3100\pi = \frac{1}{3}\pi (25) h = \frac{25\pi h}{3} To solve for h, multiply both sides by 3 and divide by 25π: h=100π×325π=300π25π=12h = \frac{100\pi \times 3}{25\pi} = \frac{300\pi}{25\pi} = 12 The height is 12 inches, which is choice B. Looking at the wrong answers: Choice A (4 inches) would give you a volume of 13π(25)(4)=100π3\frac{1}{3}\pi(25)(4) = \frac{100\pi}{3}, which is too small. Choice C (20 inches) results from incorrectly using the full circle area formula (πr²) instead of the cone volume formula's 13\frac{1}{3} factor. Choice D (25 inches) comes from the common error of confusing the radius squared (25) with the height. Always write out the volume formula first when tackling cone problems, then carefully substitute your known values. Double-check that you're using 13πr2h\frac{1}{3}\pi r^2 h and not the cylinder formula, since forgetting the 13\frac{1}{3} factor is a frequent mistake on geometry problems.

Question 4

A triangular prism has a triangular base with an area of 24 square inches and a height of 10 inches. What is the volume of the prism?

  1. 120 cubic inches
  2. 240 cubic inches (correct answer)
  3. 480 cubic inches
  4. 1,200 cubic inches
Explanation: When you encounter prism volume problems, remember that the volume of any prism equals the area of its base multiplied by its height. This fundamental relationship applies whether you're dealing with rectangular, triangular, or other prismatic shapes. For this triangular prism, you're given that the triangular base has an area of 24 square inches and the prism's height is 10 inches. Using the volume formula: V=Base Area×Height=24×10=240 cubic inchesV = \text{Base Area} \times \text{Height} = 24 \times 10 = 240 \text{ cubic inches} Let's examine why the other answers are incorrect. Choice A (120 cubic inches) represents a common error where students might divide instead of multiply, or perhaps confuse this with a surface area calculation. Choice C (480 cubic inches) suggests doubling the correct answer, which might happen if you mistakenly think you need to account for both triangular faces of the prism. Choice D (1,200 cubic inches) is far too large and likely results from incorrectly applying a pyramid volume formula or making a calculation error with the given measurements. The key insight is recognizing that "height of the prism" refers to the perpendicular distance between the two triangular bases, not any measurement within the triangular base itself. The base area is already calculated for you at 24 square inches. For prism problems, always identify the base shape and its area first, then multiply by the prism's height. Don't overthink it—the volume formula for prisms is straightforward and consistent across all prism types.

Question 5

A cube has a surface area of 150 square feet. What is the volume of the cube?

  1. 125 cubic feet (correct answer)
  2. 216 cubic feet
  3. 343 cubic feet
  4. 729 cubic feet
Explanation: When you encounter cube problems, remember that all edges of a cube are equal, so if you know one measurement, you can find all others using the relationships between edge length, surface area, and volume. A cube has 6 identical square faces. If each edge has length ss, then each face has area s2s^2, making the total surface area 6s26s^2. Since the surface area is 150 square feet, you can write: 6s2=1506s^2 = 150. Solving for ss: s2=25s^2 = 25, so s=5s = 5 feet. Now that you know the edge length is 5 feet, you can find the volume using the formula V=s3V = s^3: V=53=125V = 5^3 = 125 cubic feet. Let's examine why the other answers are incorrect. Answer B (216 cubic feet) would result from an edge length of 6 feet, since 63=2166^3 = 216. However, a 6-foot edge would give a surface area of 6(62)=2166(6^2) = 216 square feet, not 150. Answer C (343 cubic feet) corresponds to 737^3, which would require an edge length of 7 feet and surface area of 294 square feet. Answer D (729 cubic feet) equals 939^3, implying a 9-foot edge and surface area of 486 square feet. The key strategy here is working systematically: surface area → edge length → volume. Don't try to jump directly from surface area to volume. Also, remember that cube problems often test whether you can move between different measurements of the same shape, so practice converting between edge length, surface area, and volume.

Question 6

A hemisphere has a radius of 9 centimeters. What is its volume?

  1. 243π cubic centimeters
  2. 486π cubic centimeters (correct answer)
  3. 729π cubic centimeters
  4. 972π cubic centimeters
Explanation: When you encounter hemisphere volume problems, remember that a hemisphere is exactly half of a sphere, so you'll need the sphere volume formula and then divide by 2. The volume of a sphere is V=43πr3V = \frac{4}{3}\pi r^3. For a hemisphere, this becomes V=12×43πr3=23πr3V = \frac{1}{2} \times \frac{4}{3}\pi r^3 = \frac{2}{3}\pi r^3. With a radius of 9 centimeters, substitute into the hemisphere formula: V=23π(9)3=23π(729)=1458π3=486πV = \frac{2}{3}\pi (9)^3 = \frac{2}{3}\pi (729) = \frac{1458\pi}{3} = 486\pi cubic centimeters. This confirms that B) 486π cubic centimeters is correct. Looking at the wrong answers: A) 243π represents half of what you'd get if you incorrectly used r2r^2 instead of r3r^3 in your calculation. C) 729π would result from forgetting to apply the hemisphere factor entirely—this is actually 729π=(93)π729\pi = (9^3)\pi, suggesting you used just πr3\pi r^3 instead of the proper volume formula. D) 972π is what you'd get if you calculated the full sphere volume incorrectly as 43π(729)=972π\frac{4}{3}\pi (729) = 972\pi, then forgot to divide by 2 for the hemisphere. Study tip: Always write out both formulas when working with hemispheres: sphere volume =43πr3= \frac{4}{3}\pi r^3, then hemisphere volume =23πr3= \frac{2}{3}\pi r^3. This prevents the common mistake of forgetting the "half" factor or misremembering the original sphere formula.

Question 7

A right circular cone has a base area of 49π square centimeters and a volume of 196π cubic centimeters. What is the height of the cone?

  1. 4 centimeters
  2. 8 centimeters
  3. 12 centimeters (correct answer)
  4. 16 centimeters
Explanation: When you encounter cone volume problems, you need to connect three key measurements: base area, volume, and height using the cone volume formula. The volume of a cone is V=13×base area×heightV = \frac{1}{3} \times \text{base area} \times \text{height}. You're given that the base area is 49π49\pi square centimeters and the volume is 196π196\pi cubic centimeters. Substituting these values: 196π=13×49π×h196\pi = \frac{1}{3} \times 49\pi \times h To solve for height, first divide both sides by π\pi: 196=13×49×h196 = \frac{1}{3} \times 49 \times h Multiply both sides by 3: 588=49h588 = 49h Divide by 49: h=58849=12h = \frac{588}{49} = 12 centimeters This confirms answer C is correct. Let's examine why the other answers are wrong. Choice A (4 centimeters) would give a volume of 13×49π×4=196π3\frac{1}{3} \times 49\pi \times 4 = \frac{196\pi}{3}, which is too small. Choice B (8 centimeters) would yield 13×49π×8=392π3\frac{1}{3} \times 49\pi \times 8 = \frac{392\pi}{3}, still incorrect. Choice D (16 centimeters) would produce 13×49π×16=784π3\frac{1}{3} \times 49\pi \times 16 = \frac{784\pi}{3}, which is too large. These wrong answers likely result from computational errors or forgetting the 13\frac{1}{3} factor in the cone volume formula. Study tip: Always double-check your work by substituting your answer back into the original volume formula. This catches calculation mistakes and ensures you used the correct formula components.

Question 8

A spherical balloon has a radius of 6 inches. If the radius is increased by 50%, by what percent does the volume increase?

  1. 50%
  2. 125%
  3. 237.5% (correct answer)
  4. 337.5%
Explanation: When you encounter problems involving percentage changes in volume, remember that volume formulas contain the radius raised to a power, which amplifies the effect of any radius change. The volume of a sphere is V=43πr3V = \frac{4}{3}\pi r^3. With the original radius of 6 inches, the initial volume is V1=43π(6)3=43π(216)=288πV_1 = \frac{4}{3}\pi (6)^3 = \frac{4}{3}\pi (216) = 288\pi cubic inches. When the radius increases by 50%, the new radius becomes 6+0.5(6)=96 + 0.5(6) = 9 inches. The new volume is V2=43π(9)3=43π(729)=972πV_2 = \frac{4}{3}\pi (9)^3 = \frac{4}{3}\pi (729) = 972\pi cubic inches. The percent increase in volume is V2−V1V1×100%=972π−288π288π×100%=684π288π×100%=237.5%\frac{V_2 - V_1}{V_1} \times 100\% = \frac{972\pi - 288\pi}{288\pi} \times 100\% = \frac{684\pi}{288\pi} \times 100\% = 237.5\% Choice A (50%) incorrectly assumes the volume increases by the same percentage as the radius. Choice B (125%) might come from incorrectly thinking volume is proportional to r2r^2 instead of r3r^3, since (1.5)2=2.25(1.5)^2 = 2.25, giving a 125% increase. Choice D (337.5%) represents the ratio of new volume to old volume (972/288 = 3.375), but fails to subtract the original volume when calculating percent increase. Remember: when a linear dimension changes, areas change by the square of that factor, and volumes change by the cube. A 50% radius increase means the new radius is 1.5 times the original, so volume increases by (1.5)3=3.375(1.5)^3 = 3.375 times, representing a 237.5% increase.

Question 9

A pyramid has a rectangular base measuring 12 feet by 9 feet and a height of 20 feet. What is its volume?

  1. 720 cubic feet (correct answer)
  2. 1,080 cubic feet
  3. 1,800 cubic feet
  4. 2,160 cubic feet
Explanation: When you encounter pyramid volume problems, remember that pyramids always have one-third the volume of a prism with the same base and height. This is a fundamental relationship that applies to all pyramids, regardless of their base shape. To find this pyramid's volume, you need the formula: V=13×base area×heightV = \frac{1}{3} \times \text{base area} \times \text{height}. First, calculate the rectangular base area: 12×9=10812 \times 9 = 108 square feet. Then multiply by the height and apply the one-third factor: V=13×108×20=21603=720V = \frac{1}{3} \times 108 \times 20 = \frac{2160}{3} = 720 cubic feet. Looking at the wrong answers: Choice B (1,080) likely comes from forgetting the one-third factor and instead using one-half, as if this were a triangular prism formula. Choice C (1,800) might result from incorrectly calculating the base area or making an arithmetic error in the final division. Choice D (2,160) is the result you'd get if you completely forgot the one-third factor and just multiplied base area times height—this would give you the volume of a rectangular prism, not a pyramid. The correct answer is A) 720 cubic feet. For pyramid problems, always double-check that you've included the one-third factor in your calculation. A helpful way to remember this: imagine filling a pyramid with sand, then pouring that sand into a box with the same base and height—you'd need exactly three pyramids' worth of sand to fill the box completely.

Question 10

The volume of a cone is 84π cubic inches. If the radius is tripled and the height is halved, what is the new volume?

  1. 126π cubic inches
  2. 252π cubic inches
  3. 378π cubic inches (correct answer)
  4. 756π cubic inches
Explanation: When you encounter problems about changing dimensions of geometric shapes, you need to understand how each dimension affects the volume formula differently. The volume of a cone is V=13πr2hV = \frac{1}{3}\pi r^2 h. Starting with 84π cubic inches, let's see what happens when the radius is tripled and height is halved. If the original radius is rr and height is hh, then 13πr2h=84π\frac{1}{3}\pi r^2 h = 84\pi. With the new dimensions: radius becomes 3r3r and height becomes h2\frac{h}{2}. The new volume is: Vnew=13π(3r)2(h2)=13π⋅9r2⋅h2=96πr2h=32πr2hV_{new} = \frac{1}{3}\pi (3r)^2 \left(\frac{h}{2}\right) = \frac{1}{3}\pi \cdot 9r^2 \cdot \frac{h}{2} = \frac{9}{6}\pi r^2 h = \frac{3}{2}\pi r^2 h Since the original volume was 13πr2h=84π\frac{1}{3}\pi r^2 h = 84\pi, we can find πr2h=252π\pi r^2 h = 252\pi. Therefore: Vnew=32⋅252π=378πV_{new} = \frac{3}{2} \cdot 252\pi = 378\pi cubic inches. Choice A (126π) incorrectly assumes the volume increases by only 1.5 times, missing that radius is squared in the formula. Choice B (252π) represents 3×84π3 \times 84\pi, forgetting that tripling radius means multiplying by 32=93^2 = 9, not 3. Choice D (756π) correctly calculates 9×84π9 \times 84\pi for the tripled radius but forgets to divide by 2 for the halved height. Remember: when dimensions change in volume problems, radius affects volume quadratically (r2r^2), while height affects it linearly. Always substitute the new dimensions into the complete formula rather than trying mental shortcuts.

Question 11

A cube and a sphere have the same volume. If the cube has an edge length of 6 units, what is the radius of the sphere?

  1. 162π3\sqrt[3]{\frac{162}{π}} units (correct answer)
  2. 216π3\sqrt[3]{\frac{216}{π}} units
  3. 324π3\sqrt[3]{\frac{324}{π}} units
  4. 648π3\sqrt[3]{\frac{648}{π}} units
Explanation: When you encounter problems involving shapes with equal volumes, you need to set up equations using the volume formulas for each shape and solve for the unknown dimension. Start by finding the cube's volume. With an edge length of 6 units, the volume is 63=2166^3 = 216 cubic units. Since the sphere has the same volume, you can set up the equation: 43πr3=216\frac{4}{3}πr^3 = 216, where r is the sphere's radius. To solve for r, multiply both sides by 34π\frac{3}{4π}: r3=216×34π=6484π=162πr^3 = 216 × \frac{3}{4π} = \frac{648}{4π} = \frac{162}{π}. Taking the cube root gives you r=162π3r = \sqrt[3]{\frac{162}{π}} units. Looking at the wrong answers: Choice B gives 216π3\sqrt[3]{\frac{216}{π}}, which represents the error of forgetting to multiply by 34π\frac{3}{4π} and only dividing the cube's volume by π. Choice C shows 324π3\sqrt[3]{\frac{324}{π}}, which comes from incorrectly multiplying 216 by 32π\frac{3}{2π} instead of 34π\frac{3}{4π}. Choice D gives 648π3\sqrt[3]{\frac{648}{π}}, representing the mistake of multiplying by 3 but forgetting to divide by 4. The correct answer is A. Strategy tip: In equal volume problems, always write out both volume formulas completely, set them equal, and carefully track each step when isolating the unknown variable. The most common errors involve arithmetic mistakes when manipulating fractions with π.

Question 12

A composite solid consists of a cylinder topped with a hemisphere. The cylinder has a radius of 5 meters and height of 12 meters. What is the total volume?

  1. 300π+125π3300π + \frac{125π}{3} cubic meters
  2. 300π+250π3300π + \frac{250π}{3} cubic meters (correct answer)
  3. 400π+250π3400π + \frac{250π}{3} cubic meters
  4. 500π+500π3500π + \frac{500π}{3} cubic meters
Explanation: When you encounter composite solids, you need to find the volume of each individual shape and add them together. This problem combines a cylinder and a hemisphere, both sharing the same radius of 5 meters. For the cylinder, use the formula V=πr2hV = πr^2h. With radius 5 meters and height 12 meters: Vcylinder=π(5)2(12)=π(25)(12)=300πV_{cylinder} = π(5)^2(12) = π(25)(12) = 300π cubic meters. For the hemisphere, remember it's half of a sphere. The sphere volume formula is V=43πr3V = \frac{4}{3}πr^3, so a hemisphere is V=23πr3V = \frac{2}{3}πr^3. With radius 5 meters: Vhemisphere=23π(5)3=23π(125)=250π3V_{hemisphere} = \frac{2}{3}π(5)^3 = \frac{2}{3}π(125) = \frac{250π}{3} cubic meters. Total volume: 300π+250π3300π + \frac{250π}{3} cubic meters, which is answer choice B. Looking at the wrong answers: Choice A uses 125π3\frac{125π}{3} for the hemisphere volume, which would result from forgetting to multiply by 2 in the hemisphere formula—a common error when students use 13πr3\frac{1}{3}πr^3 instead of 23πr3\frac{2}{3}πr^3. Choice C incorrectly calculates the cylinder volume as 400π400π, possibly from using the wrong height. Choice D calculates the cylinder volume as 500π500π and uses 500π3\frac{500π}{3} for the hemisphere—both calculations contain significant computational errors. Remember: for composite solids, break down each component, apply the correct volume formulas, and carefully track your arithmetic. Double-check that you're using the hemisphere formula, not the full sphere formula.

Question 13

A sphere has the same volume as a cube with edge length 12 inches. What is the radius of the sphere to the nearest tenth of an inch?

  1. 8.7 inches
  2. 9.3 inches (correct answer)
  3. 9.8 inches
  4. 10.4 inches
Explanation: When you encounter problems involving equal volumes between different shapes, you need to set up an equation using the volume formulas for each shape and solve for the unknown dimension. First, find the volume of the cube. With edge length 12 inches, the cube's volume is 123=1,72812^3 = 1,728 cubic inches. Since the sphere has the same volume, you can set up the equation using the sphere volume formula V=43πr3V = \frac{4}{3}\pi r^3: 43πr3=1,728\frac{4}{3}\pi r^3 = 1,728 Solving for the radius: r3=1,728×34π=5,1844π=1,296πr^3 = \frac{1,728 \times 3}{4\pi} = \frac{5,184}{4\pi} = \frac{1,296}{\pi} r3=1,2963.14159...≈412.7r^3 = \frac{1,296}{3.14159...} \approx 412.7 r=412.73≈9.3r = \sqrt[3]{412.7} \approx 9.3 inches Looking at the wrong answers: Choice A (8.7 inches) results from calculation errors, likely in the cube root step. Choice C (9.8 inches) might come from using an incorrect value of π or making arithmetic mistakes in the division. Choice D (10.4 inches) could result from forgetting the 43\frac{4}{3} coefficient in the sphere volume formula, using just πr3\pi r^3 instead. The correct answer is B) 9.3 inches. Study tip: For volume comparison problems, always write down both volume formulas clearly before substituting values. Double-check that you're using the complete formulas—sphere volume problems often trip students up with that 43\frac{4}{3} coefficient.

Question 14

A cylinder has diameter 8 cm and height 10 cm; using V=πr2hV=\pi r^2h, what is its volume?

  1. 640π cm3640\pi\text{ cm}^3
  2. 160π cm3160\pi\text{ cm}^3 (correct answer)
  3. 320π cm3320\pi\text{ cm}^3
  4. 80π cm380\pi\text{ cm}^3
Explanation: This question tests ISEE Upper Level Mathematics Achievement, specifically the ability to calculate the volume of three-dimensional figures. Volume is the measure of space occupied by a 3D object, calculated by using specific formulas for different shapes. In this question, students must apply the volume formula V = π r² h for a cylinder to calculate accurately. The correct answer, choice B, is derived by halving the diameter to get radius 4 cm, squaring to 16, then multiplying by height 10 cm and π, resulting in 160π cm³. Choice A is incorrect because it results from a common mistake of using diameter instead of radius in squaring. Teaching strategies include encouraging students to practice identifying the correct formula for each shape and performing step-by-step calculations to avoid errors. Emphasize checking unit consistency and understanding the relationship between volume and dimensions.

Question 15

A rectangular prism has dimensions 6 cm by 4 cm by 9 cm. If each dimension is doubled, by what factor does the volume increase?

  1. 2
  2. 4
  3. 6
  4. 8 (correct answer)
Explanation: When you encounter problems about scaling three-dimensional objects, remember that volume changes more dramatically than you might expect because it involves all three dimensions. Let's calculate the original volume first. For a rectangular prism, volume equals length × width × height: 6×4×9=216 cm36 \times 4 \times 9 = 216 \text{ cm}^3. When each dimension is doubled, the new dimensions become 12 cm by 8 cm by 18 cm. The new volume is 12×8×18=1,728 cm312 \times 8 \times 18 = 1,728 \text{ cm}^3. To find the factor of increase, divide the new volume by the original: 1,728216=8\frac{1,728}{216} = 8. Here's why each wrong answer represents a common misconception: Choice A (2) assumes the volume doubles because each dimension doubles—but this ignores that volume is three-dimensional. Choice B (4) might come from thinking that doubling two dimensions gives you four times the volume, forgetting about the third dimension. Choice C (6) could result from incorrectly adding the scaling factor (2) for each of the three dimensions: 2 + 2 + 2 = 6. Choice D (8) is correct because when you scale all three dimensions by a factor of 2, the volume scales by 23=82^3 = 8. Key strategy: For any scaling problem involving three-dimensional objects, remember that the volume scaling factor equals the linear scaling factor raised to the third power. If each dimension increases by factor kk, volume increases by factor k3k^3. This pattern appears frequently on geometry problems involving similar solids.

Question 16

A rectangular swimming pool is 20 feet long, 15 feet wide, and has an average depth of 6 feet. How many cubic feet of water are needed to fill the pool completely?

  1. 1,200 cubic feet
  2. 1,500 cubic feet
  3. 1,800 cubic feet (correct answer)
  4. 2,400 cubic feet
Explanation: When you encounter a problem asking for the amount of water needed to fill a three-dimensional container, you're finding the volume of that shape. For rectangular pools, this means calculating the volume of a rectangular prism. To find the volume of a rectangular prism, you multiply length × width × height (or depth). Here, you have all three dimensions: 20 feet long, 15 feet wide, and 6 feet deep on average. Volume=20 ft×15 ft×6 ft=1,800 cubic feet\text{Volume} = 20 \text{ ft} \times 15 \text{ ft} \times 6 \text{ ft} = 1,800 \text{ cubic feet} Let's work through this step by step: 20×15=30020 \times 15 = 300, then 300×6=1,800300 \times 6 = 1,800 cubic feet. Looking at the wrong answers: Choice A (1,200) represents what you'd get if you mistakenly used 4 feet instead of 6 feet for the depth, or made an arithmetic error. Choice B (1,500) is the result if you only multiplied length times width (20 × 15 = 300) and then somehow got confused with the depth calculation. Choice D (2,400) occurs if you accidentally used 8 feet for depth instead of 6, or made another calculation error. Remember that volume problems always require three dimensions, and the units will be cubic (cubic feet, cubic inches, etc.). When you see a rectangular container and need to find capacity, immediately think "length × width × height." Double-check your arithmetic, especially when multiplying three numbers together.

Question 17

A cylindrical water tank has a radius of 3 feet and a height of 8 feet. If the tank is filled to 75% of its capacity, how many cubic feet of water does it contain?

  1. 54π cubic feet (correct answer)
  2. 72π cubic feet
  3. 216π cubic feet
  4. 288π cubic feet
Explanation: When you encounter a cylinder volume problem involving partial filling, you need to find the total volume first, then calculate the specified percentage of that volume. The volume of a cylinder is V=πr2hV = \pi r^2 h, where r is the radius and h is the height. With a radius of 3 feet and height of 8 feet, the total volume is V=π(3)2(8)=π(9)(8)=72πV = \pi(3)^2(8) = \pi(9)(8) = 72\pi cubic feet. Since the tank is filled to 75% capacity, you multiply the total volume by 0.75: 72π×0.75=54π72\pi \times 0.75 = 54\pi cubic feet. Looking at the wrong answers: Choice B (72π) represents the tank's total capacity, not the 75% filled amount. This is a common trap where students calculate the full volume but forget to apply the percentage. Choice C (216π) likely comes from miscalculating the radius squared as 33=273^3 = 27 instead of 32=93^2 = 9, then applying the 75% correctly: 27×8×0.75=16227 \times 8 \times 0.75 = 162, though the exact path to 216π isn't clear. Choice D (288π) appears to result from using 333^3 for the radius calculation without applying the 75% reduction: 27×8×π=216π27 \times 8 \times \pi = 216\pi, or possibly other calculation errors. Remember this two-step approach for partial volume problems: always calculate the full capacity first using the standard volume formula, then multiply by the given percentage. Don't try to incorporate the percentage into the volume formula itself, as this often leads to calculation errors.

Question 18

A pyramid has a square base with side length 8 meters and a height of 15 meters. What is its volume?

  1. 160 cubic meters
  2. 320 cubic meters (correct answer)
  3. 480 cubic meters
  4. 960 cubic meters
Explanation: When you encounter a pyramid volume problem, remember that pyramids have one-third the volume of a prism with the same base and height. The formula is V=13×base area×heightV = \frac{1}{3} \times \text{base area} \times \text{height}. Since this pyramid has a square base with side length 8 meters, you first calculate the base area: 82=648^2 = 64 square meters. Then apply the pyramid volume formula: V=13×64×15=9603=320V = \frac{1}{3} \times 64 \times 15 = \frac{960}{3} = 320 cubic meters. Let's examine why the other answers are incorrect. Choice A (160 cubic meters) represents a calculation error where someone might have used 16\frac{1}{6} instead of 13\frac{1}{3}, perhaps confusing pyramid and cone formulas. Choice C (480 cubic meters) suggests someone calculated 23×64×15\frac{2}{3} \times 64 \times 15, incorrectly using two-thirds instead of one-third. Choice D (960 cubic meters) is what you'd get if you forgot the 13\frac{1}{3} factor entirely and calculated 64×1564 \times 15—this would be the volume of a rectangular prism, not a pyramid. The correct answer is B (320 cubic meters). For pyramid problems, always remember the key fraction: 13\frac{1}{3}. A helpful way to remember this is that pyramids "taper to a point," so they hold much less volume than a full rectangular box with the same base and height. Double-check that you're using one-third, not mistakenly calculating the full prism volume.

Question 19

A hexagonal prism has a base with an area of 36 square meters and a height of 8 meters. What is the volume of the prism?

  1. 144 cubic meters
  2. 216 cubic meters
  3. 288 cubic meters (correct answer)
  4. 432 cubic meters
Explanation: When you encounter prism volume problems, remember that the volume of any prism equals the area of its base multiplied by its height. The shape of the base doesn't matter – whether it's triangular, rectangular, hexagonal, or any other polygon, this formula always applies. Here, you have a hexagonal prism with a base area of 36 square meters and a height of 8 meters. Using the volume formula: V=Base Area×Height=36×8=288 cubic metersV = \text{Base Area} \times \text{Height} = 36 \times 8 = 288 \text{ cubic meters} Looking at the wrong answers reveals common calculation errors. Choice A (144 cubic meters) comes from accidentally dividing instead of multiplying: 36×8÷2=14436 \times 8 ÷ 2 = 144. This might happen if you confuse prism volume with triangle area formulas. Choice B (216 cubic meters) results from using 6 as the height instead of 8, possibly because you focused on the "hexa" prefix meaning six: 36×6=21636 \times 6 = 216. Choice D (432 cubic meters) comes from incorrectly multiplying by an extra factor, perhaps thinking you need to account for the hexagon having 6 sides: 36×8×1.5=43236 \times 8 \times 1.5 = 432. The key insight is that the base area is already given to you – you don't need to calculate anything about the hexagon's sides or angles. Whether the base is a triangle, square, or 20-sided polygon, if you're told the area, simply multiply by the height. This makes prism problems much more straightforward than they initially appear.

Question 20

A cone and cylinder have the same base radius and height. If the cylinder has a volume of 180π cubic units, what is the volume of the cone?

  1. 45π cubic units
  2. 60π cubic units (correct answer)
  3. 90π cubic units
  4. 120π cubic units
Explanation: When you encounter problems comparing volumes of different 3D shapes with the same dimensions, focus on the relationship between their volume formulas. A cylinder's volume formula is V=πr2hV = \pi r^2 h, while a cone's volume formula is V=13πr2hV = \frac{1}{3}\pi r^2 h. Notice that both formulas contain πr2h\pi r^2 h, but the cone's volume is exactly one-third of the cylinder's volume when they have identical base radius and height. Since the cylinder has a volume of 180π cubic units, you can find the cone's volume by multiplying by 13\frac{1}{3}: 13×180π=60π\frac{1}{3} \times 180\pi = 60\pi cubic units. Looking at the wrong answers: Choice A (45π) results from incorrectly thinking the cone is one-fourth the cylinder's volume, possibly confusing cone and pyramid relationships. Choice C (90π) comes from assuming the cone is half the cylinder's volume, which is a common misconception. Choice D (120π) might result from subtracting some arbitrary amount from the cylinder's volume without using the proper fractional relationship. The key insight here is recognizing that a cone's volume is always exactly one-third of a cylinder's volume when they share the same base and height. This 13\frac{1}{3} factor appears directly in the cone's volume formula and creates a predictable relationship you can use on similar problems. Remember this fraction rather than trying to derive the formulas from scratch during the exam.