ISEE Middle Level Mathematics Achievement Quiz
Practice Table And Graph Interpretation in ISEE Middle Level Mathematics Achievement with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.
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A report on city parks provides the following data on the number of trees in four parks: Park A has 150 trees, Park B has 200, Park C has 120, and Park D has 180. What is the median number of trees in these four parks?
This quiz focuses on Table And Graph Interpretation, giving you a quick way to practice the rules, question types, and explanations that matter most for ISEE Middle Level Mathematics Achievement.
Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.
A report on city parks provides the following data on the number of trees in four parks: Park A has 150 trees, Park B has 200, Park C has 120, and Park D has 180. What is the median number of trees in these four parks?
Explanation: To find the median of a data set, first arrange the numbers in order: 120, 150, 180, 200. Since there is an even number of data points (four), the median is the average of the two middle numbers. The two middle numbers are 150 and 180. Their average is (150 + 180) / 2 = 330 / 2 = 165. Distractor C is the mean (650/4 = 162.5, close but not quite). A and D are the middle two values themselves.
A table displays the amount of rainfall, in inches, for two cities over a three-month period. City X: May 3.2, June 2.8, July 4.0. City Y: May 2.5, June 3.5, July 3.0. For the entire three-month period, what was the difference in total rainfall between the two cities?
Explanation: First, calculate the total rainfall for City X: 3.2 + 2.8 + 4.0 = 10.0 inches. Next, calculate the total rainfall for City Y: 2.5 + 3.5 + 3.0 = 9.0 inches. The difference between their total rainfall is 10.0 - 9.0 = 1.0 inch. Distractors are based on differences in single months (e.g., May difference is 0.7).
A graph shows a company's profit over five years. Year 1: 50,000,Year2:65,000, Year 3: 60,000,Year4:75,000, Year 5: $80,000. Which of the following statements is best supported by the data?
Explanation: Let's check each statement. A is false because profit decreased from Year 2 to Year 3 (65,000to60,000). B is false; the increase from Year 1 to 2 was 15,000,fromYear3to4was15,000, and from Year 4 to 5 was only 5,000.ThegreatestincreaseswereY1−Y2andY3−Y4.Cisfalse;thetotalprofitis50+65+60+75+80 = 330,000.Theaverageis330,000 / 5 = 66,000.Distrue,asthesumoftheprofitsis330,000.
A survey of 50 students asked them to rate a new school lunch on a scale of 1 to 5. The results were recorded in a frequency table: 5 students gave a rating of 1, 10 students gave a rating of 2, 15 students gave a rating of 3, 12 students gave a rating of 4, and 8 students gave a rating of 5. What was the average rating for the new school lunch?
Explanation: To find the average rating, we calculate a weighted average. Multiply each rating by the number of students who gave that rating, sum these products, and then divide by the total number of students. The calculation is: (51 + 102 + 153 + 124 + 8*5) / 50 = (5 + 20 + 45 + 48 + 40) / 50 = 158 / 50 = 3.16. The closest answer is 3.2.
A library tracks the number of books checked out each day. Monday: 150, Tuesday: 180, Wednesday: 210, Thursday: 160, Friday: 240, Saturday: 260. What is the average number of books checked out per day from Monday to Saturday?
Explanation: To find the average, sum the number of books for all six days and divide by 6. Total books = 150 + 180 + 210 + 160 + 240 + 260 = 1200. Average = 1200 ÷ 6 = 200 books per day. Distractors represent common calculation errors or using only certain days.
A data table shows the number of minutes two students, Maya and Liam, spent on homework each day for a week. Maya's times were: 45, 60, 50, 70, 55. Liam's times were: 60, 50, 55, 40, 70. What is the difference between the medians of their homework times?
Explanation: To find the median, first order the data for each student. Maya's times in order are: 45, 50, 55, 60, 70. The median (middle value) is 55. Liam's times in order are: 40, 50, 55, 60, 70. The median is 55. The difference between their medians is 55 - 55 = 0 minutes.
A table shows the results of a survey on students' favorite sports. Out of 120 students surveyed, 40% chose basketball, 25% chose soccer, 15% chose baseball, and the rest chose swimming. How many more students chose basketball than swimming?
Explanation: First, find the number of students who chose basketball: 40% of 120 is 0.40 * 120 = 48. Next, find the percentage who chose swimming. The total percentage is 100%. So, 100% - 40% - 25% - 15% = 20% chose swimming. The number of students who chose swimming is 20% of 120, which is 0.20 * 120 = 24. The difference is 48 - 24 = 24. Distractor A is the percentage for swimming. D is the number of students who chose basketball. C is the number who chose soccer.
A table compares the populations of Town A and Town B over three decades. In 1990, Town A had 5,200 people and Town B had 6,000. In 2000, Town A had 5,800 and Town B had 6,700. In 2010, Town A had 6,600 and Town B had 7,400. In which decade was the absolute population growth of Town A greater than that of Town B?
Explanation: Calculate the population growth for each town in each decade. From 1990 to 2000: Town A grew by 5,800 - 5,200 = 600 people. Town B grew by 6,700 - 6,000 = 700 people. Here, Town B's growth was greater. From 2000 to 2010: Town A grew by 6,600 - 5,800 = 800 people. Town B grew by 7,400 - 6,700 = 700 people. Here, Town A's growth was greater. Therefore, Town A's growth was greater than Town B's only in the decade from 2000 to 2010.
A pie chart for a school's 200-member band is described. 35% of members play brass instruments, 40% play woodwinds, 15% play percussion, and the rest are in the color guard. How many members are in the color guard?
Explanation: First, calculate the percentage of members in the color guard. The total must be 100%. So, 100% - (35% + 40% + 15%) = 100% - 90% = 10%. Next, calculate the number of members this percentage represents. The total number of members is 200. So, 10% of 200 is 0.10 * 200 = 20. There are 20 members in the color guard. Distractor A is the percentage. C is the number of percussion members. D is a calculation error.
A table lists the number of students enrolled in four clubs: Chess club has 25 students, Debate club has 30, Science club has 40, and Art club has 25. If a circle graph is made to represent this data, what would be the central angle for the sector representing the Debate club?
Explanation: First, find the total number of students: 25 + 30 + 40 + 25 = 120 students. The fraction of students in the Debate club is 30/120 = 1/4. A circle has 360 degrees. To find the central angle for the Debate club sector, multiply this fraction by 360°. So, (1/4) * 360° = 90°. Distractor A is the angle for the Chess or Art clubs (25/120 * 360). D is the angle for the Science club (40/120 * 360).
A bar graph displays the monthly sales for a small bookstore. In January, sales were 4,000.InFebruary,saleswere3,500. In March, they were 5,000,andinApril,theywere4,500. What were the average monthly sales for this four-month period?
Explanation: To find the average monthly sales, sum the sales for the four months and divide by 4. The total sales are 4,000+3,500 + 5,000+4,500 = 17,000.Theaverageis17,000 / 4 = $4,250. Distractor A is the minimum value. Distractor B is the mode. Distractor D is the maximum value.
A survey of 80 middle school students asked whether they preferred to read fiction or non-fiction books. A two-way table shows the results: 26 of the 48 boys preferred fiction. In total, 50 students preferred fiction. How many girls preferred non-fiction?
Explanation: First, organize the data. Total students = 80. Total boys = 48, so Total girls = 80 - 48 = 32. Total fiction = 50, so Total non-fiction = 80 - 50 = 30. We know 26 boys preferred fiction. Since 50 students in total preferred fiction, the number of girls who preferred fiction is 50 - 26 = 24. Since there are 32 girls in total, and 24 preferred fiction, then 32 - 24 = 8 girls preferred non-fiction.
A table shows the scores for three students on a test with a maximum score of 120. Aria scored 82, Ben scored 78, and Cara scored 92. What was the group's average score as a percentage of the maximum possible score?
Explanation: First, calculate the average score of the three students: (82 + 78 + 92) / 3 = 252 / 3 = 84. This is the average score. The question asks for this average score as a percentage of the maximum possible score, which is 120. To find this percentage, divide the average score by the maximum score and multiply by 100: (84 / 120) * 100%. This simplifies to (7 / 10) * 100% = 0.7 * 100% = 70%. Distractor C is the average score itself.
A line graph shows the temperature in a city at different times of the day. At 8 a.m., it was 52°F. At 12 p.m., it was 65°F. At 4 p.m., it was 68°F. At 8 p.m., it was 58°F. What was the range of the temperatures recorded?
Explanation: The range is the difference between the highest and lowest values. The recorded temperatures are 52°F, 65°F, 68°F, and 58°F. The highest temperature is 68°F and the lowest is 52°F. The range is 68 - 52 = 16°F. Distractor A is the difference between 8am and 8pm. Distractor B is the drop from 4pm to 8pm. C is the increase from 8am to 12pm.
The results of a class fundraiser are shown in a table. The four grades in a school raised the following amounts: 6th grade raised 450,7thgraderaised600, 8th grade raised 500,and9thgraderaised450. The total amount raised was what fraction of the 7th grade's total?
Explanation: First, calculate the total amount raised by all grades: 450+600 + 500+450 = 2000.Thequestionasksfortheratioofthetotalamounttothe7thgrade′samount.Thisis2000 / $600. Simplifying this fraction gives 20/6, which further simplifies to 10/3. A common mistake is to calculate the 7th grade's contribution as a fraction of the total (600/2000 = 3/10), which is distractor C.
A line graph tracks the height of a plant in centimeters over five weeks. The recorded heights were: Week 1: 4 cm, Week 2: 7 cm, Week 3: 10 cm, Week 4: 13 cm, Week 5: 16 cm. If this linear growth continues, what would be the expected height of the plant in Week 7?
Explanation: First, determine the rate of growth from the data. The height increases by 3 cm each week (7-4=3, 10-7=3, etc.). This is a constant rate. To find the height in Week 7, continue the pattern. Week 6 would be 16 + 3 = 19 cm. Week 7 would be 19 + 3 = 22 cm. Alternatively, the height in Week 5 is 16 cm. Week 7 is two weeks later, so the height will increase by 2 * 3 = 6 cm. The expected height is 16 + 6 = 22 cm.
A table shows the number of visitors to a museum for the first three months of the year: January had 800 visitors, February had 1,000 visitors, and March had 1,300 visitors. What was the approximate percent increase in visitors from January to March?
Explanation: To calculate the percent increase, use the formula: ((New Value - Old Value) / Old Value) * 100%. The new value is March's visitors (1,300) and the old value is January's visitors (800). The increase in visitors is 1,300 - 800 = 500. The percent increase is (500 / 800) * 100%. This simplifies to (5/8) * 100%, which is 0.625 * 100% = 62.5%. The closest answer is 63%. Distractor A is (500 / 1300). Distractor B is (500 / 1000). Distractor D adds 100% to the correct answer.
A table shows the number of red and blue marbles in two jars. Jar 1 has 12 red and 18 blue marbles. Jar 2 has 15 red and 25 blue marbles. What is the difference in the percentage of red marbles between Jar 1 and Jar 2?
Explanation: First, find the percentage of red marbles in Jar 1. Total marbles in Jar 1 = 12 + 18 = 30. Percentage of red = (12/30) * 100% = 0.4 * 100% = 40%. Next, find the percentage of red marbles in Jar 2. Total marbles in Jar 2 = 15 + 25 = 40. Percentage of red = (15/40) * 100% = 0.375 * 100% = 37.5%. The difference in percentages is 40% - 37.5% = 2.5%.