IB Mathematics: Analysis and Approaches Quiz: Scientific Notation

2 questions · exam conditions

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Scientific NotationQuestion 1 of 2

If $x = a \times 10^n$ and $y = b \times 10^{n+2}$ , where $1 \le a, b < 10$ and $n$ is a positive integer, which of the following best approximates the value of $x+y$ ?

(a+b) \times 10^n

b \times 10^{n+2}

(a+b) \times 10^{n+2}

a \times 10^n

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IB Mathematics: Analysis and Approaches Quiz

IB Mathematics: Analysis and Approaches Quiz: Scientific Notation

Practice Scientific Notation in IB Mathematics: Analysis and Approaches with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Scientific Notation, giving you a quick way to practice the rules, question types, and explanations that matter most for IB Mathematics: Analysis and Approaches.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

If $x = a \times 10^n$ and $y = b \times 10^{n+2}$ , where $1 \le a, b < 10$ and $n$ is a positive integer, which of the following best approximates the value of $x+y$ ?

$(a+b) \times 10^n$
$b \times 10^{n+2}$ (correct answer)
$(a+b) \times 10^{n+2}$
$a \times 10^n$

Explanation: To add

x

and

y

, we must have the same exponent. We can write

x = a \times 10^n = (a \times 10^{-2}) \times 10^{n+2} = 0.0a \times 10^{n+2}

. The sum is

x+y = (0.0a + b) \times 10^{n+2}

. Since

1 \le b < 10

and

0.01 \le 0.0a < 0.1

, the term

0.0a

is much smaller than

b

. Therefore, the sum is dominated by

y

, and

x+y \approx y = b \times 10^{n+2}

Question 2

If $x = a \times 10^n$ and $y = b \times 10^{n+2}$ , where $1 \le a, b < 10$ and $n$ is a positive integer, which of the following best approximates the value of $x+y$ ?

$(a+b) \times 10^n$
$b \times 10^{n+2}$ (correct answer)
$(a+b) \times 10^{n+2}$
$a \times 10^n$

Explanation: To add

x

and

y

, we must have the same exponent. We can write

x = a \times 10^n = (a \times 10^{-2}) \times 10^{n+2} = 0.0a \times 10^{n+2}

. The sum is

x+y = (0.0a + b) \times 10^{n+2}

. Since

1 \le b < 10

and

0.01 \le 0.0a < 0.1

, the term

0.0a

is much smaller than

b

. Therefore, the sum is dominated by

y

, and

x+y \approx y = b \times 10^{n+2}