IB Biology Quiz: Understand Reproduction
20 questions · exam conditions
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Understand ReproductionQuestion 1 of 20

Which of the following describes a significant evolutionary trade-off for species relying on external fertilization compared to those using internal fertilization?

Greater energy expenditure by the male in locating a mate and performing courtship rituals.
A lower probability of fertilization per gamete, compensated by producing a larger number of gametes.
Higher parental investment in protecting and nourishing the offspring after they are born.
Increased genetic diversity in the offspring due to a higher rate of mutation in the aquatic environment.
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IB Biology Quiz

IB Biology Quiz: Understand Reproduction

Practice Understand Reproduction in IB Biology with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Understand Reproduction, giving you a quick way to practice the rules, question types, and explanations that matter most for IB Biology.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Which of the following describes a significant evolutionary trade-off for species relying on external fertilization compared to those using internal fertilization?

  1. Greater energy expenditure by the male in locating a mate and performing courtship rituals.
  2. A lower probability of fertilization per gamete, compensated by producing a larger number of gametes. (correct answer)
  3. Higher parental investment in protecting and nourishing the offspring after they are born.
  4. Increased genetic diversity in the offspring due to a higher rate of mutation in the aquatic environment.
Explanation: In external fertilization, gametes are released into the environment, where the probability of a single sperm meeting an egg is low due to dilution, predation, and environmental hazards. The evolutionary trade-off is that while less energy may be invested in finding a specific mate or in parental care, vast amounts of energy must be invested in producing enormous quantities of gametes to ensure at least some are successfully fertilized.

Question 2

Following the transfer of an embryo during an IVF procedure, the patient is often prescribed progesterone supplements for several weeks. What is the principal biological reason for this supplementation?

  1. The drug protocols used to retrieve eggs prevent the formation of a fully functional corpus luteum. (correct answer)
  2. The supplements are required to trigger the completion of meiosis II in the embryo's cells.
  3. The progesterone directly stimulates the embryo to begin gastrulation and differentiation.
  4. High levels of progesterone are needed to increase the mother's immune response to the embryo.
Explanation: In a natural cycle, the remnant of the ovulated follicle becomes the corpus luteum, which produces progesterone to support the endometrium for implantation. In an IVF cycle, the follicles are aspirated, and the hormonal controls (e.g., GnRH antagonists) disrupt the normal process, so a functional corpus luteum does not form or is insufficient. Progesterone supplements are therefore essential to maintain the uterine lining until the placenta develops enough to take over this function.

Question 3

The human egg is surrounded by a glycoprotein layer called the zona pellucida, which contains sperm receptors. What is the primary role of the specific binding between sperm proteins and these receptors?

  1. To provide the sperm with the final nutrients required for its journey through the zona pellucida.
  2. To ensure species-specificity of fertilization and to trigger the acrosome reaction. (correct answer)
  3. To activate the completion of meiosis I, allowing the primary oocyte to become a secondary oocyte.
  4. To initiate the cortical reaction before the sperm has penetrated the zona pellucida.
Explanation: The proteins on the sperm head must bind to specific receptor glycoproteins (like ZP3) on the zona pellucida. This lock-and-key interaction is species-specific, preventing fertilization by sperm from other species. This binding event is also the trigger for the acrosome reaction, where the sperm releases enzymes that digest a path through the zona pellucida.

Question 4

A hermaphroditic plant species has a genetic self-incompatibility system where pollen will not germinate on a stigma that shares one of its S-alleles. A plant with genotype S1S2 is pollinated by a plant with genotype S2S3. What proportion of the pollen from the S2S3 plant can successfully fertilize the ovules of the S1S2 plant?

  1. 0%
  2. 25%
  3. 50% (correct answer)
  4. 100%
Explanation: The pollen-producing plant (S2S3) produces two types of pollen in equal amounts: S2 and S3. The recipient plant's stigma (S1S2) will reject any pollen that shares an allele, i.e., S1 or S2. Therefore, the S2 pollen from the donor will be rejected. The S3 pollen does not match either S1 or S2, so it will be accepted and can germinate. Since S3 pollen makes up half of the total pollen, 50% is successful.

Question 5

A population of aphids can reproduce both sexually and asexually. Asexual reproduction is dominant in stable summer conditions, while sexual reproduction occurs in autumn as conditions become less predictable. What is the most likely evolutionary advantage of switching to sexual reproduction?

  1. To produce a larger number of offspring more rapidly before the onset of winter.
  2. To ensure all offspring have the same genetic makeup as the successful parents.
  3. To produce diploid zygotes from haploid gametes that are more resistant to cold.
  4. To generate genetically diverse offspring, increasing the chance that some will survive unpredictable conditions. (correct answer)
Explanation: The key advantage of sexual reproduction is the creation of genetic variation through meiosis (crossing over, independent assortment) and the combination of gametes from two parents. In a changing or unpredictable environment, this diversity increases the probability that some offspring will possess traits that allow them to survive and reproduce, whereas a genetically uniform population (from asexual reproduction) risks being wiped out by a single new pressure.

Question 6

The fusion of a sperm and egg cell membrane triggers a rapid increase in intracellular Ca²⁺ concentration within the egg. If a drug that blocks this Ca²⁺ release is applied to eggs before sperm is added, which event is most likely to be inhibited?

  1. The acrosome reaction of the sperm.
  2. The sperm's motility towards the egg.
  3. The cortical reaction in the egg. (correct answer)
  4. The completion of the egg's first meiotic division.
Explanation: The wave of Ca²⁺ released inside the egg after sperm fusion triggers the cortical reaction. In this process, cortical granules fuse with the egg's plasma membrane, releasing enzymes that harden the zona pellucida. This creates the slow block to polyspermy, preventing other sperm from fertilizing the egg. Blocking Ca²⁺ release would inhibit this critical step. The acrosome reaction and sperm motility occur before fusion and are independent of the egg's internal calcium.

Question 7

In the late follicular phase of the menstrual cycle, rising estrogen levels switch from exerting negative feedback to positive feedback on the hypothalamus and anterior pituitary. What is the direct and crucial consequence of this switch?

  1. A sharp decrease in FSH secretion, leading to the degeneration of non-dominant follicles.
  2. A massive surge in LH secretion, which is the primary trigger for ovulation. (correct answer)
  3. An increase in progesterone secretion from the developing follicle before ovulation.
  4. The immediate breakdown of the uterine endometrium, initiating menstruation.
Explanation: Once estrogen levels from the mature follicle reach a high threshold, the feedback effect on the pituitary and hypothalamus becomes positive. This causes a rapid and large release of LH (and to a lesser extent, FSH), known as the LH surge. This surge is the direct trigger for the final maturation of the oocyte and the rupture of the follicle (ovulation) approximately 24-36 hours later.

Question 8

What is the chromosomal state of a human secondary oocyte at the moment of ovulation?

  1. Diploid (2n=46), with each chromosome consisting of one chromatid, arrested in prophase I.
  2. Diploid (2n=46), with each chromosome consisting of two sister chromatids, after completing meiosis I.
  3. Haploid (n=23), with each chromosome consisting of one chromatid, after completing meiosis II.
  4. Haploid (n=23), with each chromosome consisting of two sister chromatids, arrested in metaphase II. (correct answer)
Explanation: A primary oocyte (diploid) completes meiosis I just before ovulation to become a secondary oocyte. This division results in a haploid number of chromosomes (n=23), but each chromosome still consists of two sister chromatids. The secondary oocyte then begins meiosis II but arrests in metaphase II. It will only complete meiosis II if it is fertilized by a sperm.

Question 9

A botanist observes a flower that is large, white, opens only at night, and produces a strong, sweet fragrance. Which pollinator is this plant most likely adapted to attract?

  1. Bees
  2. Hummingbirds
  3. Moths (correct answer)
  4. Wind
Explanation: This suite of characteristics is a classic example of a pollination syndrome for moths. Moths are nocturnal (active at night), so they are attracted to flowers that open at night. White or pale colours are more visible in low light, and a strong, sweet scent helps them locate the flower in the dark. Bees and hummingbirds are diurnal and are attracted to different colours, while wind-pollinated flowers are typically small and lack scent or nectar.

Question 10

In human testes, which sequence correctly represents the ploidy and order of cells during spermatogenesis, starting from the basal compartment of the seminiferous tubule and moving towards the lumen?

  1. Primary spermatocyte (2n) → Secondary spermatocyte (n) → Spermatogonium (2n) → Spermatozoa (n)
  2. Spermatogonium (2n) → Spermatid (n) → Primary spermatocyte (2n) → Spermatozoa (n)
  3. Spermatogonium (n) → Primary spermatocyte (2n) → Secondary spermatocyte (2n) → Spermatid (n)
  4. Spermatogonium (2n) → Primary spermatocyte (2n) → Secondary spermatocyte (n) → Spermatid (n) (correct answer)
Explanation: The process begins at the outer edge (basal compartment) with diploid (2n) spermatogonia. These divide by mitosis and differentiate into diploid (2n) primary spermatocytes. Primary spermatocytes undergo meiosis I to form haploid (n) secondary spermatocytes. These then undergo meiosis II to form haploid (n) spermatids, which mature into spermatozoa in the lumen.

Question 11

A condition impairs the endocrine function of the placenta early in the second trimester, specifically its ability to produce progesterone, while its transport functions remain normal. What is the most likely consequence?

  1. The fetus suffers from malnutrition due to a lack of nutrient transport across the chorionic villi.
  2. The uterine lining (endometrium) is not maintained, potentially leading to miscarriage. (correct answer)
  3. The mother's pituitary gland secretes high levels of FSH and LH, initiating a new ovarian cycle.
  4. The fetus develops without passive immunity due to the lack of maternal antibody transport.
Explanation: During the second and third trimesters, the placenta takes over progesterone production from the corpus luteum. Progesterone's primary role is to maintain the endometrium and suppress uterine contractions. If the placenta fails to produce progesterone, the uterine lining will break down, likely causing a miscarriage, even if nutrient and gas exchange (transport functions) are normal.

Question 12

An athlete with an extremely low body fat percentage experiences amenorrhea (cessation of menstruation). This is often linked to reduced secretion of GnRH from the hypothalamus. What is the most direct cascade of events resulting from reduced GnRH secretion?

  1. Reduced secretion of FSH and LH from the pituitary, leading to a failure of follicular development and ovulation. (correct answer)
  2. Increased secretion of progesterone from the ovaries, leading to a persistent thickening of the endometrium.
  3. Uninhibited estrogen production by the ovaries, causing continuous proliferation of the uterine lining.
  4. A surge in LH without a corresponding FSH surge, resulting in ovulation but no follicular maturation.
Explanation: GnRH (Gonadotropin-releasing hormone) from the hypothalamus stimulates the anterior pituitary to release FSH and LH. A reduction in GnRH directly leads to reduced FSH and LH levels. FSH is required for follicular development and LH is required for ovulation. Therefore, a lack of these hormones prevents the ovarian and uterine cycles from proceeding.

Question 13

An ecologist discovers a plant species whose seeds are small, have a low mass, and possess feathery, hair-like structures. The parent plant is tall and grows in open, windy habitats. Which conclusion about its reproductive strategy is most justified?

  1. The plant relies on wind dispersal (anemochory) to colonize new areas. (correct answer)
  2. The plant relies on water dispersal (hydrochory), with the hairs allowing the seeds to float.
  3. The plant relies on external animal dispersal (epizoochory), with the hairs acting as hooks.
  4. The plant relies on internal animal dispersal (endozoochory) after being ingested.
Explanation: The combination of traits—small size, low mass, and feathery structures—are classic adaptations for wind dispersal (anemochory). These features increase the seed's surface area to mass ratio, allowing it to be carried long distances by wind. The tall stature and open habitat of the parent plant further support this conclusion, as they facilitate the release of seeds into wind currents.

Question 14

In a species of angiosperm, a mutation prevents the fusion of the second male gamete with the central cell containing the polar nuclei. Pollination and fusion of the first male gamete with the egg cell occur normally. What would be the most likely outcome in the resulting seed?

  1. A haploid embryo would develop alongside a diploid endosperm, preventing germination.
  2. A diploid embryo would develop, but the seed would lack a triploid endosperm, likely causing it to be non-viable. (correct answer)
  3. No embryo would form, but a triploid endosperm would develop normally and store nutrients.
  4. Both a diploid embryo and a diploid endosperm would form, resulting in a viable but smaller seed.
Explanation: Double fertilization in angiosperms involves two events: one sperm nucleus fuses with the egg to form the diploid (2n) zygote (embryo), and the second sperm nucleus fuses with the two polar nuclei to form the triploid (3n) endosperm. If the second fusion fails, a diploid embryo still forms, but the nutritive endosperm does not, making the seed unlikely to survive.

Question 15

Which statement accurately distinguishes a key cytological event in human spermatogenesis from the corresponding event in oogenesis?

  1. Meiosis is initiated at puberty in oogenesis, whereas in spermatogenesis it is fully completed before birth.
  2. All four products of meiosis develop into functional gametes in oogenesis, while only one does in spermatogenesis.
  3. Cytokinesis following both meiotic divisions is unequal in oogenesis, conserving cytoplasm for the ovum, whereas it is equal in spermatogenesis. (correct answer)
  4. Spermatogenesis involves two meiotic divisions to produce haploid cells, while oogenesis involves only a single meiotic division.
Explanation: In oogenesis, the meiotic divisions produce one large ovum and smaller polar bodies due to unequal cytokinesis. This ensures the mature egg has ample cytoplasm and organelles. In spermatogenesis, cytokinesis is equal, resulting in four spermatids of similar size. The other options misrepresent the processes: oogenesis begins before birth, only one product is functional in oogenesis (the reverse of B), and both processes involve two meiotic divisions.

Question 16

During an in vitro fertilization (IVF) protocol, a woman is administered a drug that acts as a GnRH antagonist. What is the primary purpose of this step in the overall treatment?

  1. To directly stimulate the ovaries to produce a large number of mature follicles for retrieval.
  2. To cause the immediate breakdown of the endometrium to prepare it for embryo implantation.
  3. To increase the natural production of progesterone by the corpus luteum after ovulation has occurred.
  4. To prevent a premature, endogenous LH surge, which allows for controlled timing of oocyte retrieval. (correct answer)
Explanation: In IVF, follicular growth is stimulated with high doses of FSH. This leads to high estrogen levels, which would normally trigger a natural LH surge and ovulation. A GnRH antagonist blocks the pituitary's ability to release LH, preventing this premature ovulation. This gives physicians control over the timing, allowing them to retrieve the oocytes at peak maturity.

Question 17

The pollen grain in an angiosperm is a critical structure for sexual reproduction. Which statement correctly describes the composition of a mature pollen grain at the time of dispersal?

  1. It is the male gametophyte, containing a tube nucleus and a generative cell. (correct answer)
  2. It is a single male gamete, containing a haploid nucleus that will fertilize the egg cell.
  3. It is a diploid microspore that undergoes meiosis on the stigma to produce gametes.
  4. It is the male sporophyte, containing all genetic material to form a new plant directly.
Explanation: The pollen grain is not a single gamete but a multicellular male gametophyte. It develops from a haploid microspore. At maturity, it contains two cells (or nuclei): the tube cell (which forms the pollen tube) and the generative cell. The generative cell will later divide by mitosis to produce the two sperm nuclei required for double fertilization. It is haploid, not diploid (C), and it is the gametophyte, not the sporophyte (D).

Question 18

During human pregnancy, sustained high levels of progesterone are secreted first by the corpus luteum and then by the placenta. What is a key role of this sustained high progesterone level?

  1. To stimulate strong, regular uterine contractions to facilitate the growth of the fetus.
  2. To trigger the development of the fetal reproductive organs and determine its sex.
  3. To inhibit the secretion of FSH and LH from the pituitary, preventing a new ovarian cycle. (correct answer)
  4. To increase the sensitivity of the uterine wall to oxytocin in preparation for childbirth.
Explanation: High levels of progesterone (and estrogen) exert strong negative feedback on the hypothalamus and anterior pituitary. This inhibits the release of GnRH, FSH, and LH, which prevents the development of new ovarian follicles and ovulation, thus stopping the menstrual cycle for the duration of the pregnancy. Progesterone actively inhibits uterine contractions (A) and estrogen increases oxytocin sensitivity (counter to D).

Question 19

In the alternation of generations life cycle of a fern, which process represents a transition from a diploid (2n) state to a haploid (n) state?

  1. The fusion of sperm and egg to form a zygote.
  2. The development of a prothallus (gametophyte) from a spore.
  3. The growth of the frond-bearing fern (sporophyte) from the zygote.
  4. The production of spores within the sporangium. (correct answer)
Explanation: The mature fern plant is the diploid (2n) sporophyte. On the underside of its fronds, it has structures called sporangia where specialized cells undergo meiosis to produce haploid (n) spores. This meiotic division is the point in the life cycle where the ploidy is halved from diploid to haploid. Fertilization (A) is n -> 2n. Growth of the gametophyte (B) is n -> n. Growth of the sporophyte (C) is 2n -> 2n.

Question 20

Which row correctly matches a method of asexual reproduction with a key feature of the process?

  1. Method: Binary Fission; Feature: Results in two daughter cells of significantly unequal size.
  2. Method: Budding; Feature: Involves the formation of a specialized haploid spore that is dispersed.
  3. Method: Fragmentation; Feature: A parent organism breaks into pieces, each of which can regenerate into a new adult. (correct answer)
  4. Method: Parthenogenesis; Feature: Requires the fusion of two gametes to form a diploid zygote.
Explanation: Fragmentation is a form of asexual reproduction where an organism is split into fragments, and each fragment develops into a new, complete organism (e.g., in sea stars, flatworms). Distractor A is incorrect because binary fission produces two nearly equal cells. Distractor B is incorrect because budding is an outgrowth, not spore formation. Distractor D is incorrect because parthenogenesis is development from an unfertilized egg, without gamete fusion.