IB Biology Quiz: Concluding And Evaluating
20 questions · exam conditions
0:00
Concluding And EvaluatingQuestion 1 of 20

An ecologist conducted a chi-squared test to determine if the distribution of a certain species of snail on a rocky shore was associated with the presence of a specific alga. The null hypothesis was that there is no association between the snail and the alga. The calculated chi-squared value resulted in a probability value of p = 0.04.

Based on this probability value, what is the most appropriate conclusion?

The null hypothesis is accepted, indicating the distribution of the snail is random and not associated with the alga.
The null hypothesis is rejected, suggesting there is a statistically significant association between the snail and the alga.
The experiment has a 4% chance of being incorrect, so the results are inconclusive and should be repeated with a larger sample size.
The alternative hypothesis is accepted, proving that the snail's presence is directly caused by the availability of the alga.
← Back to quizzes

IB Biology Quiz

IB Biology Quiz: Concluding And Evaluating

Practice Concluding And Evaluating in IB Biology with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Concluding And Evaluating, giving you a quick way to practice the rules, question types, and explanations that matter most for IB Biology.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

An ecologist conducted a chi-squared test to determine if the distribution of a certain species of snail on a rocky shore was associated with the presence of a specific alga. The null hypothesis was that there is no association between the snail and the alga. The calculated chi-squared value resulted in a probability value of p = 0.04.

Based on this probability value, what is the most appropriate conclusion?

  1. The null hypothesis is accepted, indicating the distribution of the snail is random and not associated with the alga.
  2. The null hypothesis is rejected, suggesting there is a statistically significant association between the snail and the alga. (correct answer)
  3. The experiment has a 4% chance of being incorrect, so the results are inconclusive and should be repeated with a larger sample size.
  4. The alternative hypothesis is accepted, proving that the snail's presence is directly caused by the availability of the alga.
Explanation: In biology, the standard significance level is p < 0.05. Since p = 0.04 is less than 0.05, the null hypothesis is rejected. This means the observed distribution is unlikely to be due to chance, indicating a significant association. Distractor A incorrectly accepts the null hypothesis. Distractor C misinterprets the p-value; it represents the probability of observing the results if the null hypothesis were true, not the error rate of the experiment. Distractor D makes a leap to causation, which statistical association alone does not prove.

Question 2

A study investigated the effect of a new fertilizer on the yield of wheat. Two fields were used: Field A received the new fertilizer, and Field B received no fertilizer. At the end of the season, the average yield in Field A was 15% higher than in Field B. The researchers concluded that the new fertilizer caused the increase in yield.

Which statement represents the most significant limitation in evaluating the researchers' conclusion?

  1. The percentage increase of 15% is not high enough to be considered statistically significant without a p-value.
  2. The experiment should have included a third field using a traditional, well-established fertilizer for comparison.
  3. Potential confounding variables, such as differences in soil composition or water drainage between the fields, were not controlled. (correct answer)
  4. The conclusion is invalid because the experiment was not repeated over multiple growing seasons to ensure reliability of the results.
Explanation: The conclusion attributes the entire yield difference to the fertilizer. However, any pre-existing differences between Field A and Field B (confounding variables) could also account for the result. Without controlling for these variables, causation cannot be confidently established. Distractor A is incorrect because significance depends on sample size and variation, not just the percentage. Distractor B suggests a good addition to the experiment but isn't the primary flaw in the existing conclusion. Distractor D addresses reliability over time, but the immediate threat to the validity of the conclusion is the lack of controlled variables.

Question 3

An experiment investigates an enzyme inhibitor. When the inhibitor is present, the reaction's Vmax is significantly reduced, but the Km remains unchanged, regardless of substrate concentration. The researchers conclude that the substance is a non-competitive inhibitor.

How does the evidence provided support this conclusion?

  1. An unchanged Km indicates the inhibitor does not bind to the active site, and a reduced Vmax shows the enzyme's catalytic efficiency is lowered. (correct answer)
  2. A reduced Vmax suggests the inhibitor binds irreversibly to the active site, while an unchanged Km indicates saturation is still possible at high substrate concentrations.
  3. The unchanged Km shows that the substrate's binding affinity is unaffected, while the reduced Vmax is because high substrate levels can outcompete the inhibitor.
  4. A reduced Vmax means fewer enzyme molecules are available, and an unchanged Km shows the inhibitor has the same shape as the substrate, fitting the active site.
Explanation: The defining characteristics of non-competitive inhibition are a decrease in Vmax (because the inhibitor binds to an allosteric site and reduces the efficiency of the enzyme) and no change in Km (because the inhibitor does not compete with the substrate for the active site, so the substrate's binding affinity is unaffected). Option A correctly links these two pieces of evidence to the conclusion. Option B incorrectly links reduced Vmax to irreversible binding. Option C is contradictory; if high substrate levels could outcompete the inhibitor, it would be competitive inhibition, and Vmax would not be reduced. Option D confuses non-competitive inhibition with competitive inhibition (inhibitor having a similar shape to the substrate).

Question 4

A paleontologist studies a lineage of marine molluscs in a well-preserved fossil record spanning 5 million years. The record shows that species morphologies remain stable for long periods (over 1 million years) and then change relatively rapidly in the geological record, followed by another long period of stasis. An article claims this is conclusive proof of punctuated equilibrium and refutes the model of gradualism.

What is the most accurate evaluation of this claim? [HL]

  1. The claim is fully supported, as the evidence of stasis followed by rapid change is the defining feature of punctuated equilibrium and contradicts gradualism.
  2. The claim is weak because gradual changes could have occurred in soft tissues that were not fossilized, so the true evolutionary pattern is unknown.
  3. The claim is an overstatement; while the evidence strongly supports punctuated equilibrium in this specific lineage, it does not invalidate gradualism as a possible mode of evolution in other lineages. (correct answer)
  4. The claim is false because 'rapid' geological change can still represent thousands of years of gradual evolution that only appears abrupt in the fossil record.
Explanation: Scientific models are not necessarily mutually exclusive. This evidence is a strong case for punctuated equilibrium operating in this particular lineage. However, concluding that it refutes gradualism entirely is an overstatement. Evolution is not governed by a single mode; different patterns can occur in different lineages and at different times. Option C correctly identifies this nuance. Option A is too absolute. Option B is speculative and doesn't address the interpretation of the existing evidence. Option D is a valid point about geological time scales, but it doesn't negate that the pattern observed fits the model of punctuated equilibrium better than gradualism in this context; C provides a better evaluation of the claim's scope.

Question 5

In a variation of the Hershey-Chase experiment, bacteriophages were grown in a medium containing a radioactive isotope of nitrogen (¹⁵N). These phages were then used to infect E. coli. After centrifugation, the bacterial pellet was found to be highly radioactive.

What is the most logical conclusion from this specific result? [HL]

  1. DNA is the genetic material because nucleotides contain nitrogen, which was incorporated into the bacterial pellet.
  2. Protein is the genetic material because amino acids contain nitrogen, which was incorporated into the bacterial pellet.
  3. The experiment is inconclusive because both DNA (in bases) and protein (in amino acids) contain nitrogen. (correct answer)
  4. The experiment proves that the phage coat, not the genetic material, is injected into the bacterium during infection.
Explanation: The strength of the original Hershey-Chase experiment was its use of isotopes that specifically label one macromolecule but not the other: ³²P for DNA (present in phosphate groups) and ³⁵S for protein (present in some amino acids). Nitrogen (¹⁵N) is a component of both the nitrogenous bases in DNA and the amino groups in proteins. Therefore, finding ¹⁵N in the bacterial pellet does not allow one to distinguish whether DNA, protein, or both were injected. The experiment is inconclusive for its intended purpose.

Question 6

A study measured the concentration of a persistent pesticide, dichlorodiphenyltrichloroethane (DDT), in a marine food web. The results were as follows: seawater (0.00005 ppm), zooplankton (0.04 ppm), small fish (0.5 ppm), large fish (2.0 ppm), and fish-eating birds (25.0 ppm).

What conclusion is best supported by this data regarding DDT in this ecosystem?

  1. Fish-eating birds are more susceptible to the toxic effects of DDT than organisms at lower trophic levels.
  2. The concentration of DDT increases at successively higher trophic levels, demonstrating the process of biomagnification. (correct answer)
  3. DDT is a biodegradable substance that is gradually broken down as it moves up the food chain.
  4. Organisms at each trophic level bioaccumulate DDT from their environment at approximately the same rate.
Explanation: The data clearly show a stepwise increase in the concentration of DDT as one moves up the trophic levels (seawater -> zooplankton -> small fish -> large fish -> birds). This process, where the concentration of a substance increases in organisms at successive levels in a food chain, is the definition of biomagnification. Option A is a plausible biological effect but is not a conclusion drawn directly from the concentration data itself. Option C is directly contradicted by the data. Option D is incorrect; if the accumulation rate were the same, the concentrations would not differ so dramatically between trophic levels.

Question 7

A patient exposed to a neurotoxin exhibits muscle paralysis. Further investigation reveals that although action potentials are successfully propagating down the motor neurons and neurotransmitters are released into the synapse, the postsynaptic muscle cells do not depolarize.

Based on this evidence, what is the most likely mechanism of action of this neurotoxin? [HL]

  1. The toxin blocks voltage-gated sodium channels on the axon of the motor neuron.
  2. The toxin blocks the influx of calcium ions into the presynaptic terminal.
  3. The toxin inhibits the enzyme acetylcholinesterase in the synaptic cleft.
  4. The toxin binds to and blocks the neurotransmitter receptors on the postsynaptic membrane. (correct answer)
Explanation: The evidence states that action potentials arrive and neurotransmitters are released, meaning the presynaptic neuron is functioning correctly. The failure is at the postsynaptic membrane, which does not depolarize despite the presence of neurotransmitter. This strongly indicates that the receptors are being blocked, preventing the neurotransmitter from binding and opening ion channels. Blocking sodium channels on the axon (A) or calcium influx (B) would prevent neurotransmitter release. Inhibiting acetylcholinesterase (D) would cause prolonged depolarization, leading to spastic paralysis, not the observed paralysis.

Question 8

A geneticist is analyzing a pedigree for a rare genetic disorder. She observes that the trait appears in every generation. Furthermore, she notes several instances where an affected father has an unaffected daughter. There are no instances of an unaffected parent having an affected child.

Based on this description, what conclusion can be made about the mode of inheritance?

  1. The disorder is autosomal recessive because it appears in every generation.
  2. The disorder is autosomal dominant, and X-linked dominant inheritance can be conclusively ruled out. (correct answer)
  3. The disorder is X-linked dominant because affected fathers pass the trait to all their daughters.
  4. The disorder is X-linked recessive, but the possibility of it being autosomal recessive cannot be eliminated.
Explanation: The trait appearing in every generation and affected individuals having at least one affected parent strongly suggests a dominant pattern. The key piece of evidence is an affected father having an unaffected daughter. If the trait were X-linked dominant, an affected father (XᴬY) would pass his affected X chromosome (Xᴬ) to all his daughters, making them all affected. Since there is an unaffected daughter, X-linked dominant inheritance is ruled out. Therefore, the most likely mode is autosomal dominant.

Question 9

A student uses a respirometer to measure the rate of oxygen consumption by germinating peas at 25°C. After 30 minutes, the volume of consumed oxygen is less than half of the expected value based on published data for the same mass of peas. The potassium hydroxide (KOH) solution used to absorb CO₂ is confirmed to be effective.

What is the most plausible evaluation of this discrepancy? [HL]

  1. The peas may have been conducting both aerobic and anaerobic respiration, thus consuming less oxygen than predicted. (correct answer)
  2. The temperature of the water bath may have been lower than 25°C, reducing the metabolic rate of the peas.
  3. The amount of potassium hydroxide was insufficient, allowing CO₂ pressure to counteract the drop in O₂ pressure.
  4. The respirometer was not properly sealed, allowing atmospheric oxygen to leak into the apparatus during the experiment.
Explanation: If oxygen is limited within the sealed respirometer, or if the peas have a very high initial metabolic demand, they may switch to or supplement with anaerobic respiration. Anaerobic respiration produces ATP without consuming oxygen, which would lead to a lower-than-expected rate of O₂ consumption. B and D are possible experimental errors, but a switch in metabolic pathways (A) is a very plausible biological explanation for this specific result. C is ruled out by the problem statement.

Question 10

A monozygotic twin study investigated the heritability of type 2 diabetes. The concordance rate, which is the probability that the other twin will have the disease if one twin has it, was found to be approximately 60%.

What is the most valid conclusion that can be drawn from this 60% concordance rate? [HL]

  1. Type 2 diabetes is primarily a genetic disease, with environmental factors playing only a minor role in its development.
  2. Environmental factors are the main cause of type 2 diabetes, as the concordance rate is not 100%.
  3. The expression of genes related to diabetes is controlled by epigenetic markers that differ between the twins.
  4. The development of type 2 diabetes is influenced by both a significant genetic predisposition and significant environmental factors. (correct answer)
Explanation: Monozygotic twins are genetically identical. If a disease were purely genetic, the concordance rate would be 100%. If it were purely environmental, the rate would be similar to that of the general population. A rate of 60% is substantially higher than the general population rate but significantly less than 100%. This indicates a strong genetic component (it's not random) but also a major role for non-genetic factors (since 40% of identical twins do not share the trait). Option C is the only one that correctly reflects this dual influence. Options A and B incorrectly assign primary blame to one factor. Option D suggests a specific mechanism (epigenetics) which is plausible but is not the most general and certain conclusion from the concordance rate alone.

Question 11

Following a severe drought on an island, researchers observed that the population of a species of finch declined, and the average beak depth of the surviving birds was significantly greater than the average before the drought. The drought had reduced the availability of small, soft seeds, leaving mainly large, hard seeds.

What is the most cautious and scientifically valid conclusion from these observations?

  1. The finches with larger beaks evolved through natural selection in a single generation in response to the drought.
  2. The drought induced mutations in the finches, causing them to develop larger beaks to eat the available seeds.
  3. The change in seed availability acted as a selection pressure, favouring the survival of pre-existing finches with larger beaks. (correct answer)
  4. All finches with small beaks died during the drought, leaving only large-beaked finches to reproduce.
Explanation: This is a classic example of natural selection. The key is that the variation (different beak sizes) already existed in the population. The environmental change (drought) created a selection pressure that favored the survival and reproduction of individuals with a specific trait (larger beaks). Option A incorrectly implies evolution happens in a single generation. Option B wrongly suggests that mutations are directed by environmental needs (Lamarckian idea). Option D is an over-generalization; it's likely that some small-beaked finches survived, but at a lower rate than large-beaked ones.

Question 12

A study on island biogeography shows that larger islands have more species than smaller islands. A researcher concludes that this is because larger islands have a greater variety of habitats, allowing for more ecological niches.

While plausible, what alternative explanation for the species-area relationship must also be evaluated?

  1. Larger islands may have higher rates of mutation, leading to faster speciation and greater biodiversity.
  2. Larger islands present a larger target for colonization by new species from the mainland, leading to higher immigration rates. (correct answer)
  3. Smaller islands have harsher environmental conditions, leading to greater competition among the species that live there.
  4. Smaller islands have higher rates of extinction because their coastlines are more exposed to natural disasters.
Explanation: The theory of island biogeography, developed by MacArthur and Wilson, explains the species-area relationship through two main factors: immigration rates and extinction rates. The researcher's conclusion focuses on habitat diversity, which relates to lower extinction rates. The equally important alternative explanation is the 'target effect': larger islands are simply more likely to be encountered and colonized by migrating species, leading to higher immigration rates. This must be considered alongside the habitat diversity hypothesis. A is speculative. C and D are aspects of why smaller islands have higher extinction rates, but B presents the distinct, core alternative mechanism related to immigration.

Question 13

In an osmosis experiment, identical potato cylinders were placed in sucrose solutions of varying concentrations. After 24 hours, the percentage change in mass was measured. For solutions from 0.0 M to 0.6 M, the mass change followed a predictable linear trend from positive to negative. However, the cylinder in the 0.8 M solution showed a slight increase in mass, contrary to the expected large decrease.

Which is the most likely evaluation of this anomalous result?

  1. The principles of osmosis are reversed at very high solute concentrations, causing water to move against its concentration gradient.
  2. The anomalous data point is likely due to a systematic error in the experimental procedure, such as incorrect solution preparation for all samples.
  3. This result suggests that potato cells actively transport sucrose inwards when the external concentration exceeds a certain threshold.
  4. The potato cylinder used for the 0.8 M solution may have had a significantly different initial water potential or was not properly blotted. (correct answer)
Explanation: When a single data point deviates significantly from a clear trend, it is most often due to a random error affecting that specific sample. Differences in the starting material (initial water potential) or inconsistent technique (improper blotting) are plausible random errors. Option A contradicts fundamental physical laws. Option B suggests a systematic error, which would likely affect all data points, not just one. Option D proposes a complex biological mechanism that is less likely than a simple experimental error to explain a single anomaly.

Question 14

A large-scale epidemiological study found a strong positive correlation (r = 0.82) between high consumption of processed meats and the incidence of colorectal cancer. The study tracked over 100,000 individuals for 20 years and controlled for age and smoking status.

What is the most scientifically sound conclusion that can be drawn solely from these results?

  1. High consumption of processed meats is a major cause of colorectal cancer in the studied population.
  2. Individuals who consume less processed meat are guaranteed to have a lower risk of developing colorectal cancer.
  3. There is a significant statistical association, suggesting that lifestyle factors related to meat consumption may influence cancer risk. (correct answer)
  4. The chemicals used to preserve processed meats have been proven to be carcinogenic by this correlational study.
Explanation: The study demonstrates a strong correlation, which is a statistical association. However, correlation does not equal causation. While it suggests a link, it does not prove that processed meat consumption directly causes cancer. Other lifestyle factors associated with high processed meat intake could be the actual cause. Distractor A claims causation, which is an overstatement. Distractor B makes a guarantee, which is not possible in biology. Distractor D assumes the specific cause (preservatives) has been proven, which the study did not do.

Question 15

A biotechnology company announces a new gene therapy using CRISPR-Cas9 that has successfully corrected the mutated gene responsible for cystic fibrosis in cultured human lung cells. They claim this is a cure for the disease.

To evaluate the claim that this therapy is a viable cure for patients, what is the most critical question that must be answered next?

  1. Can the therapy be delivered efficiently and safely to the target lung cells in a living human organism? (correct answer)
  2. Is the CRISPR-Cas9 system capable of correcting other genetic diseases besides cystic fibrosis?
  3. What is the precise molecular mechanism by which the Cas9 enzyme cuts the target DNA sequence?
  4. Can the corrected lung cells be grown in sufficient quantities in the lab to be commercially viable?
Explanation: Success in a petri dish (in vitro) is very different from success in a whole organism (in vivo). The biggest hurdle for many gene therapies is developing a safe and effective delivery system (e.g., a viral vector) to get the therapeutic agent to the correct cells in the body without causing harmful side effects. This is the most critical next step in evaluating its potential as a cure. The therapy's effect on other diseases (B), the fine details of the mechanism (C), and commercial viability (D) are all relevant questions, but they are secondary to the fundamental challenge of in vivo delivery and safety.

Question 16

To investigate the role of insulin, a researcher injects a group of 10 healthy individuals with a standard dose of insulin and measures their blood glucose levels every 15 minutes for two hours. They observe a rapid decrease in blood glucose in all subjects. They conclude that insulin's primary function is to lower blood glucose.

What is the main weakness in the evaluation of this experimental conclusion?

  1. The sample size of 10 individuals is too small to draw any meaningful conclusions about human physiology.
  2. The two-hour time frame is insufficient to observe the long-term homeostatic effects of the insulin injection.
  3. The absence of a control group receiving a saline injection makes it impossible to attribute the change solely to insulin. (correct answer)
  4. Measuring blood glucose every 15 minutes is not frequent enough to accurately capture the dynamics of glucose change.
Explanation: A fundamental principle of experimental design is the use of a control group to isolate the effect of the independent variable. Without a control group (e.g., receiving a placebo like saline), one cannot be certain that the observed effect is due to the insulin and not some other factor, such as the body's natural response to the injection procedure or fasting. While other options might be minor limitations, the lack of a control group is the most critical flaw affecting the validity of the conclusion.

Question 17

Researchers found that spraying the leaves of a well-watered plant with abscisic acid (ABA) caused a rapid closure of its stomata. They concluded that ABA is the primary signal that induces stomatal closure in response to water stress.

Which statement represents a potential flaw in this conclusion based on the experimental design?

  1. The experiment only demonstrates a correlation; it does not prove that the plant naturally produces ABA in response to water stress. (correct answer)
  2. The ABA was applied externally, which may not accurately mimic the internal physiological concentration and transport within the plant.
  3. The use of a well-watered plant is inappropriate, as the effects of ABA should only be tested on plants already experiencing drought.
  4. The conclusion is invalid because stomatal closure could have been caused by other environmental factors in the laboratory.
Explanation: The experiment shows that ABA can cause stomatal closure. However, to conclude it is the primary signal in response to water stress, one must also show that water stress leads to increased endogenous production of ABA, which in turn causes the closure. The experiment as described does not establish this crucial link in the causal chain. B is a valid methodological concern, but A points to a larger logical gap in the conclusion. C is incorrect; using a well-watered plant effectively isolates the effect of ABA itself. D is a general concern, but less specific than the logical flaw in A.

Question 18

Scientists discover a new unicellular, eukaryotic organism. Microscopic examination reveals it has a cell wall containing chitin and mitochondria, but no chloroplasts. It reproduces by budding. Its ribosomal RNA (rRNA) sequence is analyzed and found to be more similar to the rRNA of fungi than to that of any other kingdom.

How should a biologist evaluate all this evidence to classify the organism?

  1. The rRNA evidence should be prioritized as it reflects evolutionary lineage, supporting classification as a fungus. (correct answer)
  2. The presence of a cell wall and lack of chloroplasts means it must be a plant that has lost its photosynthetic ability.
  3. The organism should be placed in a new kingdom because it shares features of both fungi (chitin) and protists (unicellular).
  4. The mode of reproduction (budding) is the most important feature, confirming its classification within the yeasts.
Explanation: In modern cladistics, molecular evidence like rRNA sequencing is considered fundamental for determining evolutionary relationships (phylogeny) because it is less subject to convergent evolution than morphological traits. The presence of a chitin cell wall, lack of chloroplasts, and budding are all consistent with the organism being a fungus (specifically, a yeast). Therefore, prioritizing the molecular data, which aligns with the morphological data, is the correct scientific approach. B is incorrect because plant cell walls are made of cellulose, not chitin. C is unnecessary when the evidence consistently points to an existing group. D is too specific; yeast is a type of fungus, and the broader classification as fungus is supported by all the evidence.

Question 19

In a large clinical trial for a new vaccine, the vaccinated group had an incidence rate of 0.5% for the disease, while the placebo group had an incidence rate of 5.0%. The vaccine efficacy was calculated to be 90%.

What is the correct evaluation of the 90% efficacy rate? [HL]

  1. 90% of individuals who receive the vaccine will be completely immune to the disease.
  2. Receiving the vaccine reduces an individual's risk of contracting the disease by 90% compared to being unvaccinated. (correct answer)
  3. There is a 10% chance that a vaccinated person will contract the disease during the trial period.
  4. The vaccine is effective in only 90% of the population, while 10% of people will not respond to it at all.
Explanation: Vaccine efficacy is a measure of relative risk reduction. It is calculated as ((Incidence in placebo - Incidence in vaccinated) / Incidence in placebo) * 100%. Here, ((5.0 - 0.5) / 5.0) * 100% = 90%. This means the vaccine reduced the risk of disease by 90% in the vaccinated group compared to the placebo group under trial conditions. It does not mean 90% of people are immune (A) or that an individual's absolute risk is 10% (C). It is a population-level statistic, not a prediction of individual response (D).

Question 20

An action spectrum for photosynthesis shows peaks of activity in the blue-violet and red regions of the visible spectrum. However, a significant amount of photosynthesis, about 40% of the maximum rate, still occurs in the green-yellow region, where chlorophyll a and b show minimal absorption.

What conclusion about the photosynthetic apparatus is best supported by this observation?

  1. Chlorophyll a and b are less efficient at converting light energy into chemical energy in the green-yellow region.
  2. Accessory pigments, such as carotenoids, must be absorbing light in the green-yellow region and transferring the energy to the reaction centers. (correct answer)
  3. The experimental measurement of oxygen production is an inaccurate method for determining the rate of photosynthesis in green-yellow light.
  4. Photosynthesis is primarily driven by light intensity, not wavelength, and the green-yellow light used must have been of a higher intensity.
Explanation: The discrepancy between the absorption spectrum of chlorophylls and the action spectrum of photosynthesis is key evidence for the role of accessory pigments. These pigments (like carotenoids and xanthophylls) absorb light at wavelengths where chlorophylls are inefficient and pass that energy on to the primary chlorophyll molecules. This broadens the range of light that can be used for photosynthesis. Option A is incorrect; the issue is absorption, not conversion efficiency. Option C questions the method without a valid reason. Option D is a confounding variable, but the consistent pattern observed across many experiments supports the accessory pigment hypothesis.