What this quiz covers
This quiz focuses on Solve Two Part Logic, giving you a quick way to practice the rules, question types, and explanations that matter most for GMAT.
A pharmaceutical company conducts a two-phase clinical trial. In Phase 1, 60% of participants show positive response to treatment. In Phase 2, only participants who showed positive response in Phase 1 continue, and 75% of these show continued positive response. If 180 participants started Phase 1, and the company needs at least 90 participants with positive responses in both phases for regulatory approval, how many additional Phase 1 participants would be needed if the current number falls short, and what is the current number of participants with positive responses in both phases?
GMAT Quiz
Practice Solve Two Part Logic in GMAT with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.
This quiz focuses on Solve Two Part Logic, giving you a quick way to practice the rules, question types, and explanations that matter most for GMAT.
Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.
A pharmaceutical company conducts a two-phase clinical trial. In Phase 1, 60% of participants show positive response to treatment. In Phase 2, only participants who showed positive response in Phase 1 continue, and 75% of these show continued positive response. If 180 participants started Phase 1, and the company needs at least 90 participants with positive responses in both phases for regulatory approval, how many additional Phase 1 participants would be needed if the current number falls short, and what is the current number of participants with positive responses in both phases?
Explanation: Phase 1 positive: 180 × 0.6 = 108 participants. Phase 2 positive (from those who were Phase 1 positive): 108 × 0.75 = 81 participants. Since 81 < 90, we need 9 more successful participants. If we add n Phase 1 participants, we get n × 0.6 × 0.75 = 0.45n additional successes. To get 9 more: 0.45n = 9, so n = 20. Choice B miscalculates by using only the Phase 2 success rate (9/0.75 = 12). Choice C incorrectly counts Phase 1 successes as the final number. Choice D incorrectly counts all Phase 1 successes plus Phase 2 successes.
In a two-stage quality control process, products must pass both Stage 1 and Stage 2 to be approved. Let p be the probability that a randomly selected product passes Stage 1, and let q be the probability that a product that has passed Stage 1 also passes Stage 2. If the overall approval rate is 0.36 and the Stage 1 pass rate is 0.6, what is the conditional probability q, and what would be the new overall approval rate if Stage 1 pass rate increased to 0.8 while q remained constant?
Explanation: The overall approval rate equals P(Stage 1) × P(Stage 2|Stage 1) = p × q. Given: 0.6 × q = 0.36, so q = 0.36/0.6 = 0.6. With the new Stage 1 rate of 0.8 and q remaining 0.6, the new overall rate = 0.8 × 0.6 = 0.48. Choice B incorrectly adds the improvements rather than multiplying. Choice C miscalculates q as 0.36 - 0.6 = -0.24, then uses |−0.24| = 0.24, but realizes this is wrong and guesses 0.45. Choice D assumes the overall rate cannot change if only one stage changes.
A software company has two development teams working on separate modules of a project. Team Alpha can complete their module in d−3 days, while Team Beta can complete their module in d+2 days, where d represents the baseline development time. The project manager wants both modules completed within 12 days, and Team Alpha must finish at least 2 days before Team Beta to allow for integration testing. What is the maximum value of d that satisfies these constraints, and how many days will Team Beta actually take at this maximum value?
Explanation: We have three constraints: (1) Team Alpha finishes within 12 days: d - 3 ≤ 12, so d ≤ 15. (2) Team Beta finishes within 12 days: d + 2 ≤ 12, so d ≤ 10. (3) Alpha finishes at least 2 days before Beta: (d + 2) - (d - 3) ≥ 2, which gives 5 ≥ 2 (always satisfied). The binding constraint is d ≤ 10, so maximum d = 10. At d = 10: Team Alpha takes 7 days, Team Beta takes 12 days. Choice A violates constraint (2). Choice B violates constraint (2). Choice C violates constraint (2). Only choice D satisfies all constraints.
A consulting firm analyzes the efficiency of two manufacturing processes, Process M and Process N, across different operational scenarios.
Process M produces 4y+3 units per hour while consuming 2y+1 units of raw material per hour. Process N produces 3y+8 units per hour while consuming y+4 units of raw material per hour, where y is an efficiency parameter. If the firm has 45 units of raw material available per hour and needs to produce at least 65 units per hour, what is the minimum value of y required, and what will be the total hourly production at this minimum value?
Explanation: Both processes run simultaneously. Total production = (4y + 3) + (3y + 8) = 7y + 11. Total material consumption = (2y + 1) + (y + 4) = 3y + 5. Constraints: (1) Material limit: 3y + 5 ≤ 45, so 3y ≤ 40, thus y ≤ 13.33. (2) Production requirement: 7y + 11 ≥ 65, so 7y ≥ 54, thus y ≥ 7.71. Since y must be an integer, minimum y = 8. At y = 8: production = 7(8) + 11 = 67, material use = 3(8) + 5 = 29 ≤ 45 ✓. Choice B has y = 6 < 7.71 (insufficient production). Choice C has y = 7 < 7.71 (insufficient production). Choice D has y = 9 > 8 (not minimum).