Geometry Quiz: Theorems About Parallelograms
7 questions · exam conditions
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Theorems About ParallelogramsQuestion 1 of 7

Triangle JKLJKL has medians JMJM, KNKN, and LOLO that intersect at centroid GG. If JM=21JM = 21 and KN=18KN = 18, and the distance from KK to GG is 1212, what is the distance from GG to the midpoint MM of side KLKL?

66 units using centroid division properties of medians
1414 units using centroid division properties of medians
99 units using centroid division properties of medians
77 units using centroid division properties of medians
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Geometry Quiz

Geometry Quiz: Theorems About Parallelograms

Practice Theorems About Parallelograms in Geometry with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Theorems About Parallelograms, giving you a quick way to practice the rules, question types, and explanations that matter most for Geometry.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Triangle JKLJKL has medians JMJM, KNKN, and LOLO that intersect at centroid GG. If JM=21JM = 21 and KN=18KN = 18, and the distance from KK to GG is 1212, what is the distance from GG to the midpoint MM of side KLKL?

  1. 66 units using centroid division properties of medians
  2. 1414 units using centroid division properties of medians
  3. 99 units using centroid division properties of medians
  4. 77 units using centroid division properties of medians (correct answer)
Explanation: When you encounter problems involving medians and centroids, remember that the centroid divides each median in a specific 2:1 ratio, with the longer segment extending from the vertex to the centroid. The centroid GG divides every median so that the distance from any vertex to GG is twice the distance from GG to the opposite midpoint. Since the distance from KK to GG is 12, and GG divides median KNKN in a 2:1 ratio, the distance from GG to midpoint NN must be 12÷2=612 ÷ 2 = 6. We can verify this using the given information: if KG=12KG = 12 and GN=6GN = 6, then the total length KN=12+6=18KN = 12 + 6 = 18, which matches the given median length. Now, for median JMJM with length 21, the centroid divides it the same way. The distance from JJ to GG is 23×21=14\frac{2}{3} × 21 = 14, and the distance from GG to midpoint MM is 13×21=7\frac{1}{3} × 21 = 7. Choice A gives 6 units, which incorrectly applies the distance from GG to NN instead of finding the distance to MM. Choice B gives 14 units, which represents the distance from JJ to GG, not from GG to MM. Choice C gives 9 units, which appears to incorrectly calculate half of the median length JMJM. Study tip: Always remember the centroid's 2:1 division rule: vertex to centroid is 23\frac{2}{3} of the median length, while centroid to midpoint is 13\frac{1}{3} of the median length.

Question 2

Triangle ABCABC has vertices AA, BB, and CC. The centroid GG is located at coordinates (4,3)(4, 3). If vertex AA is at (1,6)(1, 6) and vertex BB is at (5,2)(5, 2), what are the coordinates of vertex CC?

  1. (6,1)(6, 1) using the centroid formula for coordinate geometry (correct answer)
  2. (6,4)(6, 4) using the centroid formula for coordinate geometry
  3. (10,1)(10, 1) using the centroid formula for coordinate geometry
  4. (12,9)(12, 9) using the centroid formula for coordinate geometry
Explanation: The centroid is located at (xA+xB+xC3,yA+yB+yC3)\left(\frac{x_A + x_B + x_C}{3}, \frac{y_A + y_B + y_C}{3}\right). Given G(4,3)G(4,3), A(1,6)A(1,6), and B(5,2)B(5,2): For x-coordinate: 1+5+xC3=4\frac{1 + 5 + x_C}{3} = 4, so 6+xC=126 + x_C = 12, thus xC=6x_C = 6. For y-coordinate: 6+2+yC3=3\frac{6 + 2 + y_C}{3} = 3, so 8+yC=98 + y_C = 9, thus yC=1y_C = 1. Therefore C=(6,1)C = (6,1). Choice B uses incorrect y-calculation. Choice C doubles the x-coordinate. Choice D uses the sum instead of solving for the unknown coordinate.

Question 3

In triangle XYZXYZ, X=65°\angle X = 65° and Y=45°\angle Y = 45°. If triangle XYZXYZ is reflected across the perpendicular bisector of side XZXZ to form triangle XYZX'Y'Z', what is the measure of YXZ\angle Y'X'Z' in the reflected triangle?

  1. 45°45° because reflections preserve all angle measures exactly
  2. 115°115° because the reflection changes the angle orientation significantly
  3. 70°70° because reflections preserve all angle measures exactly
  4. 65°65° because reflections preserve all angle measures exactly (correct answer)
Explanation: When you encounter reflection problems in geometry, remember that reflections are rigid transformations that preserve all distances, angles, and shapes exactly. The reflected figure is congruent to the original, just in a new position. First, let's find all angles in the original triangle. Since angles in a triangle sum to 180°180°, we have Z=180°65°45°=70°\angle Z = 180° - 65° - 45° = 70°. When triangle XYZXYZ is reflected across the perpendicular bisector of side XZXZ, the triangle flips over that line. Points XX and ZZ land on themselves (since they're on the perpendicular bisector), while point YY moves to position YY' on the opposite side. In the reflected triangle XYZX'Y'Z', vertex XX' corresponds to original vertex XX. Since reflections preserve all angle measures, YXZ=YXZ=65°\angle Y'X'Z' = \angle YXZ = 65°. Choice A is incorrect because it gives 45°45°, which was the measure of Y\angle Y in the original triangle, not X\angle X. Choice B is wrong because 115°115° doesn't correspond to any angle in this triangle, and the reasoning about "orientation change" is false—reflections don't change angle measures. Choice C incorrectly gives 70°70°, which was Z\angle Z in the original triangle. Choice D correctly identifies that YXZ=65°\angle Y'X'Z' = 65° because reflections preserve angle measures exactly. Study tip: Remember that all rigid transformations (reflections, rotations, translations) preserve angle measures. When solving reflection problems, identify corresponding vertices carefully, then apply the preservation property.

Question 4

In triangle ABCABC, point MM is the midpoint of side ABAB and point NN is the midpoint of side ACAC. If BC=18BC = 18 and BAC=50°\angle BAC = 50°, what can be concluded about the relationship between segment MNMN and side BCBC?

  1. MNMN is parallel to BCBC and MN=9MN = 9, with AMN=50°\angle AMN = 50° (correct answer)
  2. MNMN is parallel to BCBC and MN=18MN = 18, with AMN=50°\angle AMN = 50°
  3. MNMN is perpendicular to BCBC and MN=9MN = 9, with AMN=40°\angle AMN = 40°
  4. MNMN is parallel to BCBC and MN=9MN = 9, with AMN=130°\angle AMN = 130°
Explanation: By the midpoint theorem, the segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. Therefore, MNBCMN \parallel BC and MN=1218=9MN = \frac{1}{2} \cdot 18 = 9. Since MNBCMN \parallel BC, corresponding angles are equal, so AMN=BAC=50°\angle AMN = \angle BAC = 50°. Choice B incorrectly states MN=18MN = 18 (should be half). Choice C incorrectly claims perpendicularity and wrong angle. Choice D incorrectly calculates the angle as supplementary.

Question 5

In triangle ABC, point D lies on side BC such that AD bisects ∠BAC. If AB = 12 and AC = 15, what is the ratio BD:DC?

  1. 4:5 by the angle bisector theorem and proportional segments (correct answer)
  2. 5:4 by the angle bisector theorem and proportional segments
  3. 3:4 by the angle bisector theorem and proportional segments
  4. 4:3 by the angle bisector theorem and proportional segments
Explanation: By the angle bisector theorem, when AD bisects ∠BAC, the ratio BD:DC = AB:AC = 12:15 = 4:5. Choice B reverses the ratio. Choices C and D use incorrect proportions that don't match the given side lengths.

Question 6

In triangle PQRPQR, the three medians intersect at point GG. If median PSPS has length 1515, where SS is the midpoint of QRQR, what is the distance from GG to vertex PP?

  1. 55 units from PP along the median to the centroid
  2. 7.57.5 units from PP along the median to the centroid
  3. 1010 units from PP along the median to the centroid (correct answer)
  4. 1212 units from PP along the median to the centroid
Explanation: The medians of a triangle meet at the centroid, which divides each median in a 2:1 ratio, with the longer segment being from the vertex to the centroid. Since median PS=15PS = 15, the distance from PP to centroid GG is 2315=10\frac{2}{3} \cdot 15 = 10 units. Choice A gives 13\frac{1}{3} of the median length. Choice B gives half the median length. Choice D gives 45\frac{4}{5} of the median length, incorrectly applying a different ratio.

Question 7

Triangle DEFDEF is isosceles with DE=DFDE = DF. If the measure of the exterior angle at vertex EE is 110°110°, what is the measure of EDF\angle EDF?

  1. 35°35° because the base angles sum to 70°70°
  2. 40°40° because each base angle measures 70°70° (correct answer)
  3. 70°70° because the exterior angle equals the base angle
  4. 110°110° because vertical angles are congruent to exterior angles
Explanation: The exterior angle at EE is 110°110°, so the interior angle at EE is 180°110°=70°180° - 110° = 70°. Since triangle DEFDEF is isosceles with DE=DFDE = DF, the base angles DEF\angle DEF and DFE\angle DFE are congruent, each measuring 70°70°. Using the triangle angle sum theorem: EDF+70°+70°=180°\angle EDF + 70° + 70° = 180°, so EDF=40°\angle EDF = 40°. Choice A incorrectly divides the base angle sum by 2. Choice C confuses the exterior angle with a base angle. Choice D incorrectly applies the exterior angle relationship.