Finite Mathematics Quiz: Input Output Models
17 questions · exam conditions
0:00
Input Output ModelsQuestion 1 of 17

In a Leontief input-output model, the technology matrix AA has the property that all column sums are less than 1. A policy maker claims this guarantees the economy is 'productive' and that (IA)1(I-A)^{-1} exists with all positive entries. Which aspect of this claim requires the most careful verification?

Whether all entries of (IA)1(I-A)^{-1} are necessarily positive under this condition
Whether the column sum condition alone ensures that matrix (IA)(I-A) is invertible
Whether column sums less than 1 is equivalent to the economy being productive
Whether the existence of (IA)1(I-A)^{-1} guarantees economically meaningful solutions
← Back to quizzes

Finite Mathematics Quiz

Finite Mathematics Quiz: Input Output Models

Practice Input Output Models in Finite Mathematics with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Input Output Models, giving you a quick way to practice the rules, question types, and explanations that matter most for Finite Mathematics.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

In a Leontief input-output model, the technology matrix AA has the property that all column sums are less than 1. A policy maker claims this guarantees the economy is 'productive' and that (IA)1(I-A)^{-1} exists with all positive entries. Which aspect of this claim requires the most careful verification?

  1. Whether all entries of (IA)1(I-A)^{-1} are necessarily positive under this condition (correct answer)
  2. Whether the column sum condition alone ensures that matrix (IA)(I-A) is invertible
  3. Whether column sums less than 1 is equivalent to the economy being productive
  4. Whether the existence of (IA)1(I-A)^{-1} guarantees economically meaningful solutions
Explanation: When you encounter Leontief input-output models, you're dealing with the fundamental question of whether an economy can produce enough output to meet both intermediate demands (inputs for other sectors) and final demand. The key insight is that column sums less than 1 is a necessary but not sufficient condition for economic productivity. The policy maker's claim contains a critical gap. While column sums less than 1 does guarantee that (IA)1(I-A)^{-1} exists (since it ensures the spectral radius of AA is less than 1), it doesn't automatically guarantee that all entries of (IA)1(I-A)^{-1} are positive. For economic productivity, you need the stronger condition that AA is primitive or that the economy is indecomposable and aperiodic. A matrix can have column sums less than 1 yet still produce some negative entries in (IA)1(I-A)^{-1}, which would be economically meaningless. Option B is incorrect because column sums less than 1 does ensure invertibility of (IA)(I-A). Option C is wrong because the column sum condition is necessary for productivity but not sufficient—you need additional conditions. Option D misses the point since the question is about what the given condition guarantees, not what invertibility implies. The most careful verification needed is whether the inverse matrix has all positive entries, since negative entries would violate the economic interpretation that increased final demand should lead to increased production in all sectors. Study tip: Remember that in input-output models, economic conditions are often stronger than pure mathematical conditions. Always check whether mathematical results make economic sense.

Question 2

A regional input-output study finds that the 'backward linkage' index for the Construction sector is 1.8, while its 'forward linkage' index is 0.6. Based on this information, what development strategy would be most appropriate for this region?

  1. Prioritize Construction expansion since its high backward linkage creates strong demand multipliers
  2. Avoid Construction investment due to its low forward linkage limiting growth transmission
  3. Focus on Construction's supplier industries to maximize the region's economic integration
  4. Treat Construction as a final demand sector requiring support from other regional industries (correct answer)
Explanation: A high backward linkage (1.8 > 1) means Construction has above-average demand for inputs from other sectors, while low forward linkage (0.6 < 1) means other sectors have below-average demand for Construction output. This suggests Construction acts more like a final demand sector - it purchases heavily from others but doesn't supply much to intermediate users. Choice A ignores the low forward linkage problem. Choice B is too negative given the positive backward effects. Choice C misses that Construction itself, not its suppliers, should be the focus.

Question 3

In a two-sector Leontief model, Sector 1 uses $0.30 of its own output and $0.20 of Sector 2's output per dollar produced. Sector 2 uses $0.10 of Sector 1's output and $0.40 of its own output per dollar produced. If Sector 1 increases its final demand by $50 million while Sector 2's final demand remains constant, what is the induced increase in Sector 2's total output?

  1. $18.4 million, reflecting direct input requirements from the demand change
  2. $24.7 million, incorporating both direct and indirect multiplier effects (correct answer)
  3. $31.2 million, accounting for all inter-sector feedback loops and dependencies
  4. $10.0 million, based solely on Sector 2's direct input coefficient
Explanation: The technology matrix is T=(0.30.10.20.4)T = \begin{pmatrix} 0.3 & 0.1 \\ 0.2 & 0.4 \end{pmatrix} , so IT=(0.70.10.20.6)I - T = \begin{pmatrix} 0.7 & -0.1 \\ -0.2 & 0.6 \end{pmatrix} . The inverse is (IT)1=(1.4930.2490.4981.741)(I-T)^{-1} = \begin{pmatrix} 1.493 & 0.249 \\ 0.498 & 1.741 \end{pmatrix} . For demand change (500)\begin{pmatrix} 50 \\ 0 \end{pmatrix}, the output change is $$ \begin{pmatrix} 74.65 \ 24.9 \end{pmatrix}

Question 4

An economist analyzes an input-output model where the technology matrix has been estimated from data spanning five years. She discovers that one sector's input coefficients have been trending upward due to technological change. What is the most significant implication for policy analysis using this model?

  1. The model's predictions become unreliable for long-term structural economic analysis (correct answer)
  2. The Leontief inverse will overestimate future output requirements for economic planning
  3. The affected sector will appear less efficient than it actually is in current operations
  4. The equilibrium solution will not exist if the technological trend continues indefinitely
Explanation: Input-output models rely on a fundamental assumption that technology coefficients remain stable over time. When you encounter questions about changing technology matrices, focus on how this violates the model's core assumptions and affects its reliability for policy decisions. If input coefficients are trending upward over five years, this signals that the technology matrix is not constant—it's evolving. Input-output models assume fixed relationships between inputs and outputs, meaning each sector requires the same amount of inputs from other sectors to produce one unit of output. When these coefficients change systematically, the model can no longer provide reliable predictions about future economic structure or the effects of policy interventions. This makes option A correct: the model becomes unreliable for long-term structural economic analysis because its foundational assumption is violated. Option B incorrectly assumes the Leontief inverse will consistently overestimate—the direction of bias depends on whether coefficients continue rising or stabilize. Option C misses the point entirely; this isn't about current efficiency appearance but about model reliability over time. Option D makes an extreme mathematical claim that's generally false—equilibrium solutions typically exist even with changing coefficients, though they may be less meaningful. The key insight is that input-output analysis requires technological stability. When you see questions about changing technology matrices or evolving input coefficients, immediately think about model assumptions and reliability rather than getting caught up in mathematical details about specific calculations or efficiency measures.

Question 5

A simplified economy has three sectors: Agriculture (A), Manufacturing (M), and Services (S). The technology matrix TT shows the input requirements per dollar of output: T=(0.10.20.30.40.20.10.20.30.2)T = \begin{pmatrix} 0.1 & 0.2 & 0.3 \\ 0.4 & 0.2 & 0.1 \\ 0.2 & 0.3 & 0.2 \end{pmatrix} . If the final demand vector is $$d = \begin{pmatrix} 100 \ 150 \ 200 \end{pmatrix}

  1. $234.8 million, accounting for intermediate demand from all sectors
  2. $198.6 million, based on direct final demand plus internal requirements
  3. $267.3 million, including all inter-sector dependencies and feedback effects (correct answer)
  4. $150.0 million, representing only the direct final demand component
Explanation: To find total output, we solve (IT)x=d(I - T)x = d where IT=(0.90.20.30.40.80.10.20.30.8)I - T = \begin{pmatrix} 0.9 & -0.2 & -0.3 \\ -0.4 & 0.8 & -0.1 \\ -0.2 & -0.3 & 0.8 \end{pmatrix} . Using matrix inversion or elimination, we get $$x = \begin{pmatrix} 223.1 \ 267.3 \ 321.5 \end{pmatrix}

Question 6

An island economy consists of two sectors: Tourism (T) and Agriculture (A). The technology matrix is A=(0.250.400.100.20)A = \begin{pmatrix} 0.25 & 0.40 \\ 0.10 & 0.20 \end{pmatrix}, where rows and columns are in the order T, A. For a particular year, the total production is X=(800500)X = \begin{pmatrix} 800 \\ 500 \end{pmatrix} (in millions of dollars).

What is the external demand for agricultural products from this economy?

  1. $180 million
  2. $320 million (correct answer)
  3. $400 million
  4. $680 million
Explanation: The external demand vector DD can be calculated using the balance equation X=AX+DX = AX + D, which rearranges to D=XAX=(IA)XD = X - AX = (I - A)X. First, calculate IAI-A: IA=(10.250.400.1010.20)=(0.750.400.100.80)I - A = \begin{pmatrix} 1 - 0.25 & -0.40 \\ -0.10 & 1 - 0.20 \end{pmatrix} = \begin{pmatrix} 0.75 & -0.40 \\ -0.10 & 0.80 \end{pmatrix}. Now, multiply by the production vector XX: D=(0.750.400.100.80)(800500)=(0.75(800)0.40(500)0.10(800)+0.80(500))=(60020080+400)=(400320)D = \begin{pmatrix} 0.75 & -0.40 \\ -0.10 & 0.80 \end{pmatrix} \begin{pmatrix} 800 \\ 500 \end{pmatrix} = \begin{pmatrix} 0.75(800) - 0.40(500) \\ -0.10(800) + 0.80(500) \end{pmatrix} = \begin{pmatrix} 600 - 200 \\ -80 + 400 \end{pmatrix} = \begin{pmatrix} 400 \\ 320 \end{pmatrix}. The external demand for agricultural products is the second component of the vector DD, which is $320 million.

Question 7

A two-sector economy consists of Energy (E) and Manufacturing (M). The technology matrix is A=(0.30.40.20.1)A = \begin{pmatrix} 0.3 & 0.4 \\ 0.2 & 0.1 \end{pmatrix}. Suppose that due to a new trade agreement, the external demand for manufactured goods increases by $55 billion, while the external demand for energy remains unchanged.

As a result of this change in demand, what is the required increase in the total output of the Energy sector?

  1. $15 billion
  2. $40 billion (correct answer)
  3. $55 billion
  4. $70 billion
Explanation: The change in production, ΔX\Delta X, is related to the change in demand, ΔD\Delta D, by the formula ΔX=(IA)1ΔD\Delta X = (I - A)^{-1} \Delta D. The change in demand is an increase of $55 billion for Manufacturing (sector 2) and no change for Energy (sector 1). So, $\Delta D = \begin{pmatrix} 0 \ 55 \end{pmatrix}.First,wefind. First, we find (I - A)^{-1}.. I - A = \begin{pmatrix} 1-0.3 & -0.4 \ -0.2 & 1-0.1 \end{pmatrix} = \begin{pmatrix} 0.7 & -0.4 \ -0.2 & 0.9 \end{pmatrix}.. \det(I - A) = (0.7)(0.9) - (-0.4)(-0.2) = 0.63 - 0.08 = 0.55.. (I - A)^{-1} = \frac{1}{0.55} \begin{pmatrix} 0.9 & 0.4 \ 0.2 & 0.7 \end{pmatrix}.Now,wecalculatethechangeinproduction:. Now, we calculate the change in production: \Delta X = \frac{1}{0.55} \begin{pmatrix} 0.9 & 0.4 \ 0.2 & 0.7 \end{pmatrix} \begin{pmatrix} 0 \ 55 \end{pmatrix} = \frac{1}{0.55} \begin{pmatrix} 0.9(0) + 0.4(55) \ 0.2(0) + 0.7(55) \end{pmatrix} = \frac{1}{0.55} \begin{pmatrix} 22 \ 38.5 \end{pmatrix} = \begin{pmatrix} 40 \ 70 \end{pmatrix}.Thevector. The vector \Delta X$ shows the required increase in production for each sector. The increase for the Energy sector (sector 1) is $40 billion.

Question 8

A two-sector economy produces Goods (G) and Services (S). The total annual production is X=(10002000)X = \begin{pmatrix} 1000 \\ 2000 \end{pmatrix} and the external demand is D=(7001200)D = \begin{pmatrix} 700 \\ 1200 \end{pmatrix} (units are in millions of dollars). The technology matrix has the form A=(0.1a12a210.2)A = \begin{pmatrix} 0.1 & a_{12} \\ a_{21} & 0.2 \end{pmatrix}.

What is the value of a12a_{12}, which represents the input from Goods required to produce $1 of Services?

  1. $0.10 (correct answer)
  2. $0.40
  3. $0.60
  4. $0.75
Explanation: The governing equation is X=AX+DX = AX + D. We can write this out for each sector. The question asks for a12a_{12}, which appears in the equation for the first sector (Goods). x1=a11x1+a12x2+d1x_1 = a_{11}x_1 + a_{12}x_2 + d_1. Substitute the given values: 1000=(0.1)(1000)+a12(2000)+7001000 = (0.1)(1000) + a_{12}(2000) + 700. Now, solve for a12a_{12}: 1000=100+2000a12+7001000 = 100 + 2000a_{12} + 700 1000=800+2000a121000 = 800 + 2000a_{12} 200=2000a12200 = 2000a_{12} a12=2002000=0.10a_{12} = \frac{200}{2000} = 0.10.

Question 9

An economy consists of three sectors: Agriculture (A), Biofuels (B), and Construction (C). The technology matrix is given by A=(0.20.10.300.40.2000.5)A = \begin{pmatrix} 0.2 & 0.1 & 0.3 \\ 0 & 0.4 & 0.2 \\ 0 & 0 & 0.5 \end{pmatrix}. The external demand is D=(290140250)D = \begin{pmatrix} 290 \\ 140 \\ 250 \end{pmatrix} (in millions of dollars).

To meet this external demand, what is the required total production for the Biofuels sector?

  1. $260 million
  2. $400 million (correct answer)
  3. $500 million
  4. $600 million
Explanation: We need to solve the system (IA)X=D(I - A)X = D for X=(x1x2x3)X = \begin{pmatrix} x_1 \\ x_2 \\ x_3 \end{pmatrix}. First, find IAI - A: IA=(0.80.10.300.60.2000.5)I - A = \begin{pmatrix} 0.8 & -0.1 & -0.3 \\ 0 & 0.6 & -0.2 \\ 0 & 0 & 0.5 \end{pmatrix}. The system of linear equations is:
  1. 0.8x10.1x20.3x3=2900.8x_1 - 0.1x_2 - 0.3x_3 = 290
  2. 0.6x20.2x3=1400.6x_2 - 0.2x_3 = 140
  3. 0.5x3=2500.5x_3 = 250 Since the system is upper triangular, we can solve by back substitution, starting from the last equation. From equation (3): x3=2500.5=500x_3 = \frac{250}{0.5} = 500. Substitute x3=500x_3 = 500 into equation (2) to find x2x_2 (production for Biofuels): 0.6x20.2(500)=1400.6x_2 - 0.2(500) = 140 0.6x2100=1400.6x_2 - 100 = 140 0.6x2=2400.6x_2 = 240 x2=2400.6=400x_2 = \frac{240}{0.6} = 400. So, the required production for the Biofuels sector is $400 million.

Question 10

For a three-sector economy with sectors R, M, and E, the technology matrix is A=(0.10.40.20.30.20.30.20.20.1)A = \begin{pmatrix} 0.1 & 0.4 & 0.2 \\ 0.3 & 0.2 & 0.3 \\ 0.2 & 0.2 & 0.1 \end{pmatrix} and the total production vector is X=(80010001200)X = \begin{pmatrix} 800 \\ 1000 \\ 1200 \end{pmatrix} (in millions of dollars).

What is the total value of the Energy sector's output that is used as input by all three sectors combined?

  1. $480 million (correct answer)
  2. $720 million
  3. $780 million
  4. $1200 million
Explanation: The total value of a sector's output used as internal input is a component of the internal demand vector, AXAX. The Energy sector is sector 3. We need to calculate the third component of the vector AXAX. This is found by multiplying the third row of AA by the vector XX. Third row of AA: [0.2,0.2,0.1][0.2, 0.2, 0.1]. Calculation: (AX)3=(0.2)(x1)+(0.2)(x2)+(0.1)(x3)(AX)_3 = (0.2)(x_1) + (0.2)(x_2) + (0.1)(x_3) (AX)3=(0.2)(800)+(0.2)(1000)+(0.1)(1200)(AX)_3 = (0.2)(800) + (0.2)(1000) + (0.1)(1200) (AX)3=160+200+120=480(AX)_3 = 160 + 200 + 120 = 480. So, the total value of the Energy sector's output used as input by all sectors is $480 million.

Question 11

An urban economy is modeled with three sectors: Financial Services (F), Real Estate (R), and Technology (T). The Leontief inverse matrix, which relates external demand to total production, is given by:

(Rows and columns are in the order F, R, T)

Which of the following statements is the most accurate interpretation of the entry in row R, column T of the matrix (IA)1(I - A)^{-1}?

  1. To produce $1 of Technology output, the Technology sector requires $0.50 of input from the Real Estate sector.
  2. For every $1 of external demand for Real Estate, a total of $0.50 worth of Technology output is required.
  3. To satisfy $1 of external demand for Technology, a total of $0.50 worth of Real Estate output is required. (correct answer)
  4. The total internal demand for Real Estate is $0.50 for every $1 of total production by the Technology sector.
Explanation: The entry in row ii, column jj of the Leontief inverse matrix (IA)1(I - A)^{-1} represents the total value of output from sector ii that is required to satisfy $1 of external (final) demand for the products of sector $j.Inthiscase,theentryinrowR(row2)andcolumnT(column3)is. In this case, the entry in row R (row 2) and column T (column 3) is 0.5$. This means that to satisfy $1 of external demand for Technology, the economy must produce a total of $0.50 worth of output from the Real Estate sector. This total includes the direct inputs to the Technology sector and all indirect inputs to other sectors that support the production for that final demand.

Question 12

In a Leontief input-output model, the technology matrix is AA. If the external demand changes from D1D_1 to D2D_2, the production level must change from X1X_1 to X2X_2 to maintain balance. Which expression correctly represents the new production level, X2X_2?

  1. X2=X1+(IA)1(D2D1)X_2 = X_1 + (I - A)^{-1}(D_2 - D_1) (correct answer)
  2. X2=X1+(IA)(D2D1)X_2 = X_1 + (I - A)(D_2 - D_1)
  3. X2=(IA)1D1+(D2D1)X_2 = (I - A)^{-1}D_1 + (D_2 - D_1)
  4. X2=X1+A(D2D1)X_2 = X_1 + A(D_2 - D_1)
Explanation: The fundamental equations are X1=(IA)1D1X_1 = (I - A)^{-1}D_1 and X2=(IA)1D2X_2 = (I - A)^{-1}D_2. We want to express X2X_2 in terms of X1X_1 and the change in demand. Let ΔD=D2D1\Delta D = D_2 - D_1 be the change in demand and ΔX=X2X1\Delta X = X_2 - X_1 be the change in production. We have ΔX=X2X1=(IA)1D2(IA)1D1=(IA)1(D2D1)\Delta X = X_2 - X_1 = (I - A)^{-1}D_2 - (I - A)^{-1}D_1 = (I - A)^{-1}(D_2 - D_1). From this, we can solve for X2X_2: X2=X1+ΔX=X1+(IA)1(D2D1)X_2 = X_1 + \Delta X = X_1 + (I - A)^{-1}(D_2 - D_1). This shows that the new production level is the old production level plus the change in production required to meet the change in demand.

Question 13

In a three-sector Leontief input-output model, the matrix (IA)1(I - A)^{-1} is the Leontief inverse matrix. Suppose for a given economy with sectors S1, S2, and S3, this matrix and the external demand vector DD (in billions of dollars) are given by:

What is the total value of output from Sector 2 that is consumed internally by all three sectors of the economy?

  1. $200 billion
  2. $400 billion (correct answer)
  3. $600 billion
  4. $800 billion
Explanation: The internal demand is given by the vector AXAX. The total production vector XX can be found using X=(IA)1DX = (I - A)^{-1}D. After finding XX, the internal demand can be calculated using the identity AX=XDAX = X - D. Step 1: Calculate XX. X=(1.50.50.51.02.01.00.50.51.5)(100200100)=(1.5(100)+0.5(200)+0.5(100)1.0(100)+2.0(200)+1.0(100)0.5(100)+0.5(200)+1.5(100))=(150+100+50100+400+10050+100+150)=(300600300)X = \begin{pmatrix} 1.5 & 0.5 & 0.5 \\ 1.0 & 2.0 & 1.0 \\ 0.5 & 0.5 & 1.5 \end{pmatrix} \begin{pmatrix} 100 \\ 200 \\ 100 \end{pmatrix} = \begin{pmatrix} 1.5(100)+0.5(200)+0.5(100) \\ 1.0(100)+2.0(200)+1.0(100) \\ 0.5(100)+0.5(200)+1.5(100) \end{pmatrix} = \begin{pmatrix} 150+100+50 \\ 100+400+100 \\ 50+100+150 \end{pmatrix} = \begin{pmatrix} 300 \\ 600 \\ 300 \end{pmatrix}. Step 2: Calculate internal demand AXAX. AX=XD=(300600300)(100200100)=(200400200)AX = X - D = \begin{pmatrix} 300 \\ 600 \\ 300 \end{pmatrix} - \begin{pmatrix} 100 \\ 200 \\ 100 \end{pmatrix} = \begin{pmatrix} 200 \\ 400 \\ 200 \end{pmatrix}. The second entry of this vector, $400, represents the total value of output from Sector 2 consumed internally.

Question 14

An economy with two sectors, Agriculture (A) and Industry (I), has the technology matrix A=(0.20.30.40.2)A = \begin{pmatrix} 0.2 & 0.3 \\ 0.4 & 0.2 \end{pmatrix}. The Leontief inverse matrix is calculated to be (IA)1=(20.7512.25)(I - A)^{-1} = \begin{pmatrix} 2 & 0.75 \\ 1 & 2.25 \end{pmatrix}. Initially, the external demand is D1=(100200)D_1 = \begin{pmatrix} 100 \\ 200 \end{pmatrix} (in millions of dollars).

If the external demand for industrial products doubles, what is the resulting percentage increase in the total production of the agricultural sector?

  1. 50.0%
  2. 75.0%
  3. 42.9% (correct answer)
  4. 37.5%
Explanation: This is a multi-step problem. First, find the initial production X1X_1. Second, find the new production X2X_2 after the demand changes. Third, calculate the percentage increase for the agricultural sector. Step 1: Find initial production X1X_1. X1=(IA)1D1=(20.7512.25)(100200)=(2(100)+0.75(200)1(100)+2.25(200))=(200+150100+450)=(350550)X_1 = (I - A)^{-1}D_1 = \begin{pmatrix} 2 & 0.75 \\ 1 & 2.25 \end{pmatrix} \begin{pmatrix} 100 \\ 200 \end{pmatrix} = \begin{pmatrix} 2(100) + 0.75(200) \\ 1(100) + 2.25(200) \end{pmatrix} = \begin{pmatrix} 200 + 150 \\ 100 + 450 \end{pmatrix} = \begin{pmatrix} 350 \\ 550 \end{pmatrix}. The initial agricultural production is xA1=350x_{A1} = 350. Step 2: Find the new demand D2D_2 and new production X2X_2. The demand for industrial products (sector 2) doubles, so dI2=2×200=400d_{I2} = 2 \times 200 = 400. The new demand vector is D2=(100400)D_2 = \begin{pmatrix} 100 \\ 400 \end{pmatrix}. X2=(IA)1D2=(20.7512.25)(100400)=(2(100)+0.75(400)1(100)+2.25(400))=(200+300100+900)=(5001000)X_2 = (I - A)^{-1}D_2 = \begin{pmatrix} 2 & 0.75 \\ 1 & 2.25 \end{pmatrix} \begin{pmatrix} 100 \\ 400 \end{pmatrix} = \begin{pmatrix} 2(100) + 0.75(400) \\ 1(100) + 2.25(400) \end{pmatrix} = \begin{pmatrix} 200 + 300 \\ 100 + 900 \end{pmatrix} = \begin{pmatrix} 500 \\ 1000 \end{pmatrix}. The new agricultural production is xA2=500x_{A2} = 500. Step 3: Calculate the percentage increase. Percentage increase = New ValueOld ValueOld Value×100%=500350350×100%=150350×100%=37×100%42.86%\frac{\text{New Value} - \text{Old Value}}{\text{Old Value}} \times 100\% = \frac{500 - 350}{350} \times 100\% = \frac{150}{350} \times 100\% = \frac{3}{7} \times 100\% \approx 42.86\%. This rounds to 42.9%42.9\%.

Question 15

A simplified economy consists of three sectors: Raw Materials (R), Manufacturing (M), and Energy (E). The technology matrix is given as:

(Rows and columns are in the order R, M, E). The total production of the Manufacturing sector for the year is projected to be $500 million.

Based on this projection, what is the value of Raw Materials that will be consumed by the Manufacturing sector?

  1. $100 million
  2. $150 million
  3. $200 million (correct answer)
  4. $400 million
Explanation: The entry aija_{ij} of the technology matrix AA represents the dollar value of input from sector ii required to produce $1 of output for sector $j.Here,RawMaterialsissector1andManufacturingissector2.WewanttofindthevalueofinputfromRawMaterials(row1)consumedbyManufacturing(column2).Thiscorrespondstotheentry. Here, Raw Materials is sector 1 and Manufacturing is sector 2. We want to find the value of input from Raw Materials (row 1) consumed by Manufacturing (column 2). This corresponds to the entry a_{12}.Fromthematrix,. From the matrix, a_{12} = 0.4. This means $0.40 of Raw Materials are needed for every $1 of Manufacturing output. Since the total production of the Manufacturing sector is $500 million, the value of Raw Materials consumed by this sector is: $a_{12} \times x_2 = 0.4 \times \500 \text{ million} = $200 \text{ million}.

Question 16

An economy is composed of two sectors: Goods and Services. The interaction between the sectors is described by the technology matrix AA, and the external demand is given by the vector DD. All values are in millions of dollars.

Suppose the technology matrix is A=(0.10.60.50.2)A = \begin{pmatrix} 0.1 & 0.6 \\ 0.5 & 0.2 \end{pmatrix} and the external demand vector is D=(4284)D = \begin{pmatrix} 42 \\ 84 \end{pmatrix}. What is the required total production of the entire economy (Goods and Services combined)?

  1. $126 million
  2. $304 million
  3. $90 million
  4. $430 million (correct answer)
Explanation: The relationship between total production XX, the technology matrix AA, and external demand DD is given by the equation X=AX+DX = AX + D. This can be solved for XX as X=(IA)1DX = (I - A)^{-1}D. First, calculate IAI - A: IA=(1001)(0.10.60.50.2)=(0.90.60.50.8)I - A = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix} - \begin{pmatrix} 0.1 & 0.6 \\ 0.5 & 0.2 \end{pmatrix} = \begin{pmatrix} 0.9 & -0.6 \\ -0.5 & 0.8 \end{pmatrix}. Next, find the inverse of (IA)(I - A). The determinant is det(IA)=(0.9)(0.8)(0.6)(0.5)=0.720.30=0.42\det(I - A) = (0.9)(0.8) - (-0.6)(-0.5) = 0.72 - 0.30 = 0.42. The inverse is (IA)1=10.42(0.80.60.50.9)(I - A)^{-1} = \frac{1}{0.42} \begin{pmatrix} 0.8 & 0.6 \\ 0.5 & 0.9 \end{pmatrix}. Now, calculate XX: X=10.42(0.80.60.50.9)(4284)=10.42(0.8(42)+0.6(84)0.5(42)+0.9(84))=10.42(33.6+50.421+75.6)=10.42(8496.6)=(200230)X = \frac{1}{0.42} \begin{pmatrix} 0.8 & 0.6 \\ 0.5 & 0.9 \end{pmatrix} \begin{pmatrix} 42 \\ 84 \end{pmatrix} = \frac{1}{0.42} \begin{pmatrix} 0.8(42) + 0.6(84) \\ 0.5(42) + 0.9(84) \end{pmatrix} = \frac{1}{0.42} \begin{pmatrix} 33.6 + 50.4 \\ 21 + 75.6 \end{pmatrix} = \frac{1}{0.42} \begin{pmatrix} 84 \\ 96.6 \end{pmatrix} = \begin{pmatrix} 200 \\ 230 \end{pmatrix}. The total production is the sum of the components of XX, which is 200+230=430200 + 230 = 430.

Question 17

An economy's input-output analysis reveals that the Leontief inverse matrix (IA)1(I-A)^{-1} has an entry of 1.25 in row 2, column 3. Which statement correctly interprets this coefficient?

  1. Sector 3 directly requires $1.25 of input from Sector 2 per dollar of output produced
  2. A $1 increase in Sector 3's final demand generates $1.25 in total output for Sector 2 (correct answer)
  3. Sector 2 uses 25% more inputs than average when producing for Sector 3's requirements
  4. The multiplier effect between Sectors 2 and 3 creates $0.25 of additional economic activity
Explanation: The Leontief inverse (IA)1(I-A)^{-1} gives total output requirements per unit of final demand. Entry (2,3) = 1.25 means that each $1 of final demand for Sector 3's output requires $1.25 of total output from Sector 2 (including direct, indirect, and induced effects). Choice A confuses this with the technology matrix A. Choice C misinterprets the coefficient as a percentage comparison. Choice D incorrectly describes it as additional activity rather than total requirement.