Elementary School Math Quiz: Solve Fraction Addition Subtraction Word Problems

20 questions · exam conditions

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Solve Fraction Addition Subtraction Word ProblemsQuestion 1 of 20

Maya ate $\frac{2}{8}$ of a pizza. Jamal ate $\frac{3}{8}$ of the same pizza. What fraction of the pizza did they eat altogether?

\frac{5}{16}

of the pizza

\frac{7}{8}

of the pizza

\frac{5}{8}

of the pizza

\frac{4}{8}

of the pizza

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Elementary School Math Quiz

Elementary School Math Quiz: Solve Fraction Addition Subtraction Word Problems

Practice Solve Fraction Addition Subtraction Word Problems in Elementary School Math with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Solve Fraction Addition Subtraction Word Problems, giving you a quick way to practice the rules, question types, and explanations that matter most for Elementary School Math.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Maya ate $\frac{2}{8}$ of a pizza. Jamal ate $\frac{3}{8}$ of the same pizza. What fraction of the pizza did they eat altogether?

$\frac{5}{16}$ of the pizza
$\frac{7}{8}$ of the pizza
$\frac{5}{8}$ of the pizza (correct answer)
$\frac{4}{8}$ of the pizza

Explanation:

\frac{5}{8}

is correct because

\frac{2}{8} + \frac{3}{8} = \frac{5}{8}

\frac{5}{16}

is incorrect because it results from multiplying the denominators instead of keeping a common denominator.

\frac{7}{8}

is incorrect because it does not match the sum of the numerators.

\frac{4}{8}

is incorrect because it drops the numerator of one fraction instead of adding both.

Question 2

Keisha studied for $\tfrac{3}{8}$ hour. Then she studied for $\tfrac{1}{8}$ hour more during the same hour block. What fraction of an hour did she study in all?

$\tfrac{4}{16}$ of an hour
$\tfrac{3}{8}$ of an hour
$\tfrac{5}{8}$ of an hour
$\tfrac{4}{8}$ of an hour (correct answer)

Explanation: Keisha studied 4/8 of an hour in all because 3/8 + 1/8 = 4/8. Choice A results from adding both numerators and denominators together (4/16) instead of keeping the denominator the same. Choice B repeats her first study session instead of the total. Choice C adds an extra eighth beyond the correct sum.

Question 3

Emma poured $\tfrac{1}{6}$ of a pitcher of lemonade into cups. Then she poured $\tfrac{2}{6}$ more from the same pitcher. What fraction of the pitcher did she pour in all?

$\tfrac{3}{6}$ of the pitcher (correct answer)
$\tfrac{4}{6}$ of the pitcher
$\tfrac{2}{6}$ of the pitcher
$\tfrac{3}{12}$ of the pitcher

Explanation: Choice A is correct because 1/6 plus 2/6 equals 3/6 of the pitcher. Choice B is incorrect because it does not match the sum of the two amounts poured. Choice C is incorrect because it only reflects the second amount poured, not the total. Choice D is incorrect because it changes the denominator in a way that does not match sixths.

Question 4

A container was $\tfrac{5}{12}$ full of water. Marcus used $\tfrac{2}{12}$ of the same container. How much water is left in the container?

$\tfrac{2}{12}$ of the container
$\tfrac{3}{12}$ of the container (correct answer)
$\tfrac{7}{12}$ of the container
$\tfrac{5}{24}$ of the container

Explanation: Choice B is correct because 5/12 minus 2/12 equals 3/12 of the container. Choice A is incorrect because it does not match the correct difference. Choice C is incorrect because it adds the two fractions instead of subtracting. Choice D is incorrect because it changes the denominator in a way that does not match twelfths.

Question 5

A hiking path is 9/12 mile long. Amir has walked 4/12 mile on the same path. What fraction of a mile does Amir have left to walk?

4/12 mile
13/12 mile
9/24 mile
5/12 mile (correct answer)

Explanation: Since both fractions refer to the same path and share the denominator 12, subtract: 9 - 4 = 5, giving 5/12 mile remaining. Choice A (4/12) is the distance already walked, not what's left. Choice B (13/12) comes from adding instead of subtracting. Choice C (9/24) results from incorrectly changing the denominator.

Question 6

In a sticker book, 3/6 of the stickers are animals and 2/6 are sports. These fractions are from the same sticker book. What fraction of the stickers are animals or sports altogether?

5/6 of the stickers (correct answer)
3/6 of the stickers
5/12 of the stickers
1/6 of the stickers

Explanation: Since both fractions describe the same sticker book and share the denominator 6, add the numerators: 3 + 2 = 5, giving 5/6. Choice B (3/6) only counts the animal stickers, leaving out the sports stickers. Choice C (5/12) comes from incorrectly changing the denominator. Choice D (1/6) results from subtracting instead of adding.

Question 7

Emma used $\tfrac{3}{12}$ of a yard of ribbon. Then she used $\tfrac{5}{12}$ more of the same yard of ribbon. What fraction of the yard did she use in all?

$\tfrac{15}{12}$ of a yard
$\tfrac{7}{12}$ of a yard
$\tfrac{8}{24}$ of a yard
$\tfrac{8}{12}$ of a yard (correct answer)

Explanation: The correct answer is D, 8/12 of a yard. Adding the two amounts of ribbon means adding the numerators while keeping the same denominator: 3/12 + 5/12 = 8/12. Choices A and C come from also adding the denominators together instead of keeping them the same. Choice B comes from a simple counting error when combining the numerators.

Question 8

A container was filled with $\tfrac{5}{6}$ of a tank of water. Marcus used $\tfrac{2}{6}$ of the water from that same container. How much water is left in the container?

$\tfrac{3}{6}$ of the container (correct answer)
$\tfrac{5}{12}$ of the container
$\tfrac{7}{6}$ of the container
$\tfrac{2}{6}$ of the container

Explanation: Since the container started with 5/6 of a tank and Marcus used 2/6, subtracting gives 5/6 minus 2/6 equals 3/6, making Choice A correct. Choice B, 5/12 of the container, comes from multiplying the denominators instead of subtracting the fractions directly. Choice C, 7/6 of the container, comes from adding the two fractions instead of subtracting them. Choice D, 2/6 of the container, is simply the amount Marcus used, not the amount remaining.

Question 9

A container was $10/12$ full of water. After some water was used, it was $7/12$ full. How much water was used?

$17/12$ of the container
$3/12$ of the container (correct answer)
$10/12$ of the container
$3/24$ of the container

Explanation: Choice B is correct because 10/12 minus 7/12 equals 3/12 of the container. Choice A is incorrect because it results from adding instead of subtracting the two amounts. Choice C is incorrect because it repeats the starting amount instead of finding the difference. Choice D is incorrect because it changes the denominator in a way that does not match twelfths.

Question 10

A hiking trail is 1 mile long. Marcus walked 5/8 of the same mile. How much of the mile does he still have left to walk?

3/16 mile
3/8 mile (correct answer)
2/8 mile
5/8 mile

Explanation: The whole trail is 8/8, so subtracting the 5/8 Marcus already walked leaves 3/8 of a mile. Choice D (5/8) is the distance already walked, not what remains. Choice C (2/8) comes from a subtraction slip. Choice A (3/16) results from incorrectly changing the denominator.

Question 11

A sticker book has one page of stickers. On that page, $\tfrac{2}{8}$ of the stickers are animals and $\tfrac{5}{8}$ are sports. What fraction of the stickers on the page are animals or sports altogether?

$\tfrac{7}{8}$ of the stickers (correct answer)
$\tfrac{7}{16}$ of the stickers
$\tfrac{10}{8}$ of the stickers
$\tfrac{3}{8}$ of the stickers

Explanation: Since both fractions describe the same page, they can be added directly:

\tfrac{2}{8} + \tfrac{5}{8} = \tfrac{7}{8}

. Choice B comes from adding the denominators along with the numerators instead of keeping the denominator the same. Choice C adds the fractions correctly but doesn't recognize that the result is less than one whole page. Choice D subtracts the two fractions instead of adding them. Choice A correctly adds the two fractions of the same whole.

Question 12

Carlos had $\tfrac{6}{8}$ of a cake. He gave away $\tfrac{1}{8}$ of the same cake. What fraction of the cake does Carlos have left?

$\tfrac{5}{16}$ of the cake
$\tfrac{5}{8}$ of the cake (correct answer)
$\tfrac{1}{8}$ of the cake
$\tfrac{7}{8}$ of the cake

Explanation: Choice B is correct because 6/8 minus 1/8 equals 5/8 of the cake. Choice A is incorrect because it changes the denominator in a way that does not match eighths. Choice C is incorrect because it only reflects the amount given away, not what remains. Choice D is incorrect because it does not correctly subtract 1/8 from 6/8.

Question 13

Sofia walked $4/6$ of a mile. Amir walked $1/6$ of the same mile. How much farther did Sofia walk than Amir?

$3/6$ mile (correct answer)
$5/6$ mile
$3/12$ mile
$4/6$ mile

Explanation: Sofia walked 4/6 of a mile and Amir walked 1/6 of the same mile, so the difference is 4/6 minus 1/6, which is 3/6 mile, making Choice A correct. Choice B, 5/6 mile, comes from adding the two distances together instead of subtracting them. Choice C, 3/12 mile, comes from subtracting the denominators as well as the numerators, instead of keeping the denominator the same. Choice D, 4/6 mile, is simply Sofia's distance alone, without subtracting Amir's distance at all. Subtracting the numerators while keeping the same denominator gives how much farther Sofia walked.

Question 14

Maya ate $\frac{2}{8}$ of a pizza for lunch and $\frac{3}{8}$ of the same pizza for dinner. She then gave $\frac{1}{8}$ of the pizza to her brother. What fraction of the original pizza does Maya have left?

$\frac{6}{8}$
$\frac{4}{8}$
$\frac{5}{8}$
$\frac{2}{8}$ (correct answer)

Explanation: Maya ate and gave away 2/8 plus 3/8 plus 1/8, which totals 6/8 of the pizza, so subtracting that from the whole pizza gives 8/8 minus 6/8 equals 2/8, making Choice D correct. Choice A, 6/8, is the total amount eaten and given away, not what remains. Choice B, 4/8, comes from combining only two of the three amounts instead of all three. Choice C, 5/8, comes from a small addition error when combining the three fractions.

Question 15

Refer to the diagram. Sarah shaded $\frac{2}{5}$ of the rectangle on Monday and $\frac{1}{5}$ more on Tuesday. On Wednesday, she erased the shading from $\frac{2}{5}$ of the rectangle. What fraction of the rectangle is shaded now?

$\frac{1}{5}$ of the rectangle remains shaded (correct answer)
$\frac{3}{5}$ of the rectangle remains shaded
$\frac{2}{5}$ of the rectangle remains shaded
$\frac{5}{5}$ of the rectangle remains shaded

Explanation: Sarah shaded

\frac{2}{5} + \frac{1}{5} = \frac{3}{5}

by Tuesday. On Wednesday she erased

\frac{2}{5}

, leaving

\frac{3}{5} - \frac{2}{5} = \frac{1}{5}

shaded. Choice B represents how much was shaded before Wednesday's erasing. Choice C represents either Monday's amount or Wednesday's erased amount. Choice D would mean the entire rectangle is shaded.

Question 16

Sofia walked $\tfrac{4}{5}$ mile on a trail. Amir walked $\tfrac{2}{5}$ mile on the same trail. How much farther did Sofia walk than Amir?

$\tfrac{6}{5}$ mile
$\tfrac{2}{5}$ mile (correct answer)
$\tfrac{4}{5}$ mile
$\tfrac{2}{10}$ mile

Explanation: Choice B is correct because 4/5 minus 2/5 equals 2/5 mile. Choice A is incorrect because it results from adding instead of subtracting the two distances. Choice C is incorrect because it simply repeats Sofia's distance instead of finding the difference. Choice D is incorrect because it changes the denominator in a way that does not match fifths.

Question 17

A recipe calls for $\frac{3}{6}$ cup of flour for the base and $\frac{2}{6}$ cup of flour for the topping. Jake accidentally used $\frac{4}{6}$ cup of flour total. What should Jake do to correct the amount of flour?

$\frac{1}{6}$ cup of flour needs to be removed
$\frac{2}{6}$ cup of flour needs to be added
$\frac{5}{6}$ cup of flour needs to be added
$\frac{1}{6}$ cup of flour needs to be added (correct answer)

Explanation: Jake needs 5/6 cup total (3/6 + 2/6) but used only 4/6 cup, so he needs to add 1/6 cup more. Choice A incorrectly suggests removing flour when more is actually needed. Choice B is short of the full amount still needed. Choice C represents the whole recipe amount, not the amount still missing.

Question 18

A water tank was $\frac{5}{8}$ full at the start of the day. During the morning, $\frac{2}{8}$ of the tank's capacity was used. In the afternoon, $\frac{3}{8}$ of the tank's capacity was added back. What fraction of the tank is full at the end of the day?

The tank is $\frac{6}{8}$ full at day's end (correct answer)
The tank is $\frac{3}{8}$ full at day's end
The tank is $\frac{10}{8}$ full at day's end
The tank is $\frac{0}{8}$ full at day's end

Explanation: Starting with

\frac{5}{8}

, after using

\frac{2}{8}

\frac{5}{8} - \frac{2}{8} = \frac{3}{8}

. After adding

\frac{3}{8}

\frac{3}{8} + \frac{3}{8} = \frac{6}{8}

. Choice B represents the amount after morning use but before afternoon addition. Choice C incorrectly adds all three fractions. Choice D would mean the tank is empty.

Question 19

Luis had $\frac{8}{10}$ of a chocolate bar. He ate $\frac{3}{10}$ of the bar and gave $\frac{2}{10}$ to his sister. Later, his mom gave him $\frac{4}{10}$ of another identical chocolate bar. How much chocolate does Luis have now compared to one whole bar?

Luis now has $\frac{9}{10}$ of a chocolate bar
Luis now has $\frac{3}{10}$ of a chocolate bar
Luis now has $\frac{7}{10}$ of a chocolate bar (correct answer)
Luis now has $\frac{17}{10}$ of a chocolate bar

Explanation: When you see a fraction word problem with multiple steps, you need to carefully track what happens to the amount at each step, just like following money in and out of a piggy bank. Let's follow Luis's chocolate step by step. He starts with

\frac{8}{10}

of a bar. Then he loses some: he eats

\frac{3}{10}

and gives away

\frac{2}{10}

. Since all fractions have the same denominator (10), you can subtract directly:

\frac{8}{10} - \frac{3}{10} - \frac{2}{10} = \frac{3}{10}

. Now Luis has

\frac{3}{10}

left from his original bar. But then his mom gives him

\frac{4}{10}

of another identical bar. Since you're adding chocolate, you add the fractions:

\frac{3}{10} + \frac{4}{10} = \frac{7}{10}

. So Luis ends up with

\frac{7}{10}

of a chocolate bar. Looking at the wrong answers: Choice A (

\frac{9}{10}

) likely comes from forgetting to subtract what Luis ate - maybe only subtracting the

\frac{2}{10}

he gave away. Choice B (

\frac{3}{10}

) stops too early, showing only what Luis had after eating and sharing but before getting more from his mom. Choice D (

\frac{17}{10}

) adds all the numbers together (8 + 3 + 2 + 4 = 17) without paying attention to whether amounts are being added or subtracted. Remember: when solving multi-step fraction problems, work through each action one at a time and pay careful attention to whether each step increases or decreases the total amount.

Question 20

Emma walked 4/7 of the way to school when she realized she forgot her backpack. She turned around and walked the same 4/7 of the way back home, then walked 6/7 of the way to school again before her mom picked her up. What fraction of the distance to school did Emma walk in all?

10/7 of the distance to school
14/7 of the distance to school (correct answer)
6/7 of the distance to school
4/7 of the distance to school

Explanation: Emma walked 4/7 to get partway to school, then 4/7 back home (the same distance), then 6/7 toward school again, for a total of 4/7 + 4/7 + 6/7 = 14/7. Choice A (10/7) leaves out one of the 4/7 legs of the trip. Choices C (6/7) and D (4/7) only account for one part of Emma's total walk.