Elementary School Math Quiz: Multiply Multi Digit Numbers
20 questions · exam conditions
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Multiply Multi Digit NumbersQuestion 1 of 20

Maya drives 286 miles each day for 4 days. How many miles does she drive in all?

1,024 miles
864 miles
1,144 miles
290 miles
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Elementary School Math Quiz

Elementary School Math Quiz: Multiply Multi Digit Numbers

Practice Multiply Multi Digit Numbers in Elementary School Math with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Multiply Multi Digit Numbers, giving you a quick way to practice the rules, question types, and explanations that matter most for Elementary School Math.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Maya drives 286 miles each day for 4 days. How many miles does she drive in all?

  1. 1,024 miles
  2. 864 miles
  3. 1,144 miles (correct answer)
  4. 290 miles
Explanation: The correct answer is 1,144 miles, because 286 times 4 equals 1,144. Choice A, 1,024 miles, comes from a multiplication error in the tens place. Choice B, 864 miles, comes from multiplying 286 by 3 instead of 4. Choice D, 290 miles, mistakenly adds 4 to 286 instead of multiplying.

Question 2

Multiply 5858 by 3434. What is the product?

  1. 1,872
  2. 1,522
  3. 1,972 (correct answer)
  4. 92
Explanation: Using partial products, 50 times 30 is 1,500, 50 times 4 is 200, 8 times 30 is 240, and 8 times 4 is 32; adding these together gives 1,972, so Choice C is correct. Choice A, 1,872, may come from a small error in one of the partial products, such as miscalculating 8 times 30. Choice B, 1,522, is close to 1,500 plus a small amount, as if some of the partial products were left out of the total. Choice D, 92, comes from adding 58 and 34 together, 58 plus 34 equals 92, instead of multiplying them. Adding all four partial products together gives the complete and correct product.

Question 3

Multiply 6363 by 4545. What is the product?

  1. 2,835 (correct answer)
  2. 28,350
  3. 108
  4. 2,745
Explanation: Multiplying 63 by 45 gives 2,835. Choice B is ten times too large, as if an extra zero were added. Choice C is far too small to reflect multiplying two two-digit numbers. Choice D reflects a small error in one of the partial products during multiplication.

Question 4

A car costs $4,208. A truck costs 33 times as much. How much does the truck cost?

  1. $12,624 (correct answer)
  2. $1,402
  3. $4,211
  4. $12,224
Explanation: This question tests 4th grade ability to multiply a whole number of up to four digits by a one-digit whole number, and multiply two two-digit numbers, using strategies based on place value and properties of operations (CCSS.4.NBT.5). Multiplication can be understood using place value strategies like the partial products method, where you break numbers into place values (456 = 400 + 50 + 6), multiply each part separately, then add. For 2-digit × 2-digit, you can use the standard algorithm (multiply by ones digit, then tens digit, aligning by place value) or an area model (break rectangle into smaller sections). Visual models like rectangular arrays and area models help show how multiplication works by organizing quantities into rows and columns or length and width. To find the truck cost as 3 times $4,208, students can use the standard algorithm with regrouping or break into partial products by place value, demonstrating understanding of place value in multiplication. Choice A is correct because using the standard algorithm: 8 × 3 = 24 (write 4, carry 2), 0 × 3 = 0 + 2 = 2 (write 2), 2 × 3 = 6 (write 6), 4 × 3 = 12 (write 12), resulting in $12,624. This demonstrates fluent multiplication using place value understanding. Choice B represents not carrying in the ones place, which happens when students forget to carry when the product is 10 or more. To help students: Use graph paper to align place values in standard algorithm. For partial products, explicitly break numbers by place value (4,208 = 4,000 + 200 + 8) and multiply each part, labeling (4,000 × 3 = 12,000, 200 × 3 = 600, 8 × 3 = 24, sum = 12,624). Ensure students understand multiplication as repeated addition or equal groups. Watch for: not carrying in standard algorithm, adding factors instead of multiplying, forgetting to add all partial products, misaligning place values, and weak basic multiplication facts preventing fluency.

Question 5

Multiply 4848 by 2727. What is the product?

  1. 1,096
  2. 12,960
  3. 75
  4. 1,296 (correct answer)
Explanation: Choice D is correct because 48 multiplied by 27 equals 1,296. Choice A is incorrect because it does not match the product of 48 and 27. Choice B is incorrect because it is ten times too large, likely from a misplaced digit. Choice C is incorrect because it is far too small to be the product of two two-digit numbers.

Question 6

What is 3,472×63,472 \times 6?

  1. 2,082
  2. 3,478
  3. 20,832 (correct answer)
  4. 20,432
Explanation: Choice C is correct because 3,472 multiplied by 6 equals 20,832. Choice A is incorrect because it is far too small to be this product. Choice B is incorrect because it does not result from multiplying 3,472 by 6. Choice D is incorrect because it is close to the correct answer but reflects a small multiplication error.

Question 7

The array has 2323 rows and 1414 columns. How many squares are there in all?

  1. 322 squares (correct answer)
  2. 37 squares
  3. 312 squares
  4. 3,220 squares
Explanation: This question tests 4th grade ability to multiply a whole number of up to four digits by a one-digit whole number, and multiply two two-digit numbers, using strategies based on place value and properties of operations (CCSS.4.NBT.5). Multiplication can be understood using place value strategies like the partial products method, where you break numbers into place values (23 = 20 + 3, 14 = 10 + 4), multiply each part separately, then add. For 2-digit × 2-digit, you can use the standard algorithm (multiply by ones digit, then tens digit, aligning by place value) or an area model (break rectangle into smaller sections). Visual models like rectangular arrays and area models help show how multiplication works by organizing quantities into rows and columns or length and width. To find the total squares in an array with 23 rows and 14 columns, students can count the total in the array with 23 rows of 14 items each or use an area model. Choice A is correct because using partial products: (20×10=200, 20×4=80, 3×10=30, 3×4=12, sum = 322), demonstrating fluent multiplication using place value understanding. Choice D represents a place value error — multiplying correctly but misreading the result as 3,220 instead of 322, which happens when students lose track of place value during calculation. To help students: For 2-digit × 2-digit, the area model helps visualize: draw a rectangle divided into four sections (tens × tens, tens × ones, ones × tens, ones × ones), find each area, add together. Connect to arrays: 23×14 means 23 rows of 14 items. Ensure students understand multiplication as repeated addition or equal groups. Watch for: not carrying in the standard algorithm, calculating partial products but not adding them, and weak basic multiplication facts preventing fluency.

Question 8

A rectangular array has 2828 rows and 1414 columns. How many objects are in the array?

  1. 292 objects
  2. 382 objects
  3. 392 objects (correct answer)
  4. 42 objects
Explanation: This question tests 4th grade ability to multiply a whole number of up to four digits by a one-digit whole number, and multiply two two-digit numbers, using strategies based on place value and properties of operations (CCSS.4.NBT.5). Multiplication can be understood using place value strategies like the partial products method, where you break numbers into place values, multiply each part separately, then add. For 2-digit × 2-digit, you can use the standard algorithm (multiply by ones digit, then tens digit, aligning by place value) or an area model (break rectangle into smaller sections). Visual models like rectangular arrays and area models help show how multiplication works by organizing quantities into rows and columns or length and width. For a rectangular array with 28 rows of 14 items each, students can count the total or use an area model showing (20 + 8) × (10 + 4). Choice C is correct because using partial products: (20×10=200), (20×4=80), (8×10=80), (8×4=32), sum = 392. This demonstrates fluent multiplication using place value understanding. Choice A (292) represents a partial products error — likely dropping one of the four partial products. Choice B (382) represents an arithmetic error in one of the partial products. To help students: For 2-digit × 2-digit, the area model helps visualize: draw a rectangle divided into four sections (tens × tens, tens × ones, ones × tens, ones × ones), find each area, add together. Connect to arrays: 28×14 means 28 rows of 14 items. Watch for: not carrying in the standard algorithm, adding factors instead of multiplying, forgetting to add all partial products, misaligning place values, and weak basic multiplication facts preventing fluency.

Question 9

Find the product: 2,764×52,764 \times 5​

  1. 13,820 (correct answer)
  2. 13,220
  3. 1,382
  4. 2,769
Explanation: This question tests 4th grade ability to multiply a whole number of up to four digits by a one-digit whole number, and multiply two two-digit numbers, using strategies based on place value and properties of operations (CCSS.4.NBT.5). Multiplication can be understood using place value strategies like the partial products method, where you break numbers into place values (456 = 400 + 50 + 6), multiply each part separately, then add. For 2-digit × 2-digit, you can use the standard algorithm (multiply by ones digit, then tens digit, aligning by place value) or an area model (break rectangle into smaller sections). Visual models like rectangular arrays and area models help show how multiplication works by organizing quantities into rows and columns or length and width. To multiply 2,764 × 5, students can use the standard algorithm with regrouping or break into partial products by place value, demonstrating understanding of place value in multiplication. Choice A is correct because using the standard algorithm: 4 × 5 = 20 (write 0, carry 2), 6 × 5 = 30 + 2 = 32 (write 2, carry 3), 7 × 5 = 35 + 3 = 38 (write 8, carry 3), 2 × 5 = 10 + 3 = 13 (write 13), resulting in 13,820. This demonstrates fluent multiplication using place value understanding. Choice B represents not carrying in the thousands place, which happens when students forget to add the carried amount during regrouping. To help students: Use graph paper to align place values in standard algorithm. For partial products, explicitly break numbers by place value (2,764 = 2,000 + 700 + 60 + 4) and multiply each part, labeling (2,000 × 5 = 10,000, 700 × 5 = 3,500, 60 × 5 = 300, 4 × 5 = 20, sum = 13,820). Ensure students understand multiplication as repeated addition or equal groups. Watch for: not carrying in standard algorithm, adding factors instead of multiplying, forgetting to add all partial products, misaligning place values, and weak basic multiplication facts preventing fluency.

Question 10

A factory makes 2,3052,305 widgets each hour for 77 hours. How many widgets are made in all?

  1. 2,312 widgets
  2. 16,105 widgets
  3. 16,135 widgets (correct answer)
  4. 14,035 widgets
Explanation: Multiplying 2,305 widgets per hour by 7 hours gives 16,135 widgets. Choice A is far too small to reflect multiplying by 7 hours. Choice B reflects a small error in one of the partial products during multiplication. Choice D reflects using a different number of hours than the 7 given in the problem.

Question 11

What is 2,345×82,345 \times 8?

  1. 18,760 (correct answer)
  2. 1,876
  3. 2,353
  4. 18,860
Explanation: Multiplying 2,345 by 8 gives 18,760, so Choice A is correct. Choice B, 1,876, is close to the correct digits but shifted one place value, as if a zero were dropped from the final product. Choice C, 2,353, is close to the original number 2,345 with a small addition, as if 8 were added rather than used to multiply. Choice D, 18,860, has a small error in one of the place-value columns during multiplication, likely from miscalculating the hundreds digit. Multiplying each digit of 2,345 by 8 and combining the place values correctly gives the full product.

Question 12

Using the rectangular array shown, which equation correctly represents the total number of dots?

  1. (50+3)×(20+7)=53×27=1,431(50 + 3) \times (20 + 7) = 53 \times 27 = 1,431 (correct answer)
  2. (50+3)+(20+7)=53+27=80(50 + 3) + (20 + 7) = 53 + 27 = 80
  3. 50×20=1,00050 \times 20 = 1,000
  4. (50×3)+(20×7)=150+140=290(50 \times 3) + (20 \times 7) = 150 + 140 = 290
Explanation: The correct answer is A because breaking 53 into 50 + 3 and 27 into 20 + 7, then multiplying the two full sums, gives the true total of 1,4311{,}431 dots. Choice B adds instead of multiplying the two factors. Choice C only multiplies the tens parts and ignores the ones. Choice D multiplies mismatched parts of each factor instead of every combination needed for the full array.

Question 13

Find the product: 5,608×75,608 \times 7

  1. 35,256 (correct answer)
  2. 39,256
  3. 3,926
  4. 5,615
Explanation: This question tests 4th grade ability to multiply a whole number of up to four digits by a one-digit whole number, and multiply two two-digit numbers, using strategies based on place value and properties of operations (CCSS.4.NBT.5). Multiplication can be understood using place value strategies like the partial products method, where you break numbers into place values (456 = 400 + 50 + 6), multiply each part separately, then add. For 2-digit × 2-digit, you can use the standard algorithm (multiply by ones digit, then tens digit, aligning by place value) or an area model (break rectangle into smaller sections). Visual models like rectangular arrays and area models help show how multiplication works by organizing quantities into rows and columns or length and width. To multiply 5,608 × 7, students can use the standard algorithm with regrouping or break into partial products by place value, demonstrating understanding of place value in multiplication. Choice A is correct because using the standard algorithm: 7 × 8 = 56 (write 6, carry 5), 7 × 0 = 0 + 5 = 5 (write 5), 7 × 6 = 42 (write 2, carry 4), 7 × 5 = 35 + 4 = 39 (write 39), resulting in 39,256. This demonstrates fluent multiplication using place value understanding. Choice B represents not carrying when regrouping needed, which happens when students forget to carry when product ≥ 10 in a place. To help students: Use graph paper to align place values in standard algorithm. For partial products, explicitly break numbers by place value (5,608 = 5,000 + 600 + 0 + 8) and multiply each part, labeling (5,000 × 7 = 35,000, 600 × 7 = 4,200, 0 × 7 = 0, 8 × 7 = 56, sum = 39,256). Ensure students understand multiplication as repeated addition or equal groups. Watch for: not carrying in standard algorithm, adding factors instead of multiplying, forgetting to add all partial products, misaligning place values, and weak basic multiplication facts preventing fluency.

Question 14

Chen buys 24 packs of stickers. Each pack has 15 stickers. How many stickers does he have in all?

  1. 360 stickers (correct answer)
  2. 39 stickers
  3. 240 stickers
  4. 345 stickers
Explanation: This question tests 4th grade ability to multiply a whole number of up to four digits by a one-digit whole number, and multiply two two-digit numbers, using strategies based on place value and properties of operations (CCSS.4.NBT.5). Multiplication can be understood using place value strategies like the partial products method, where you break numbers into place values (456 = 400 + 50 + 6), multiply each part separately, then add. For 2-digit × 2-digit, you can use the standard algorithm (multiply by ones digit, then tens digit, aligning by place value) or an area model (break rectangle into smaller sections). Visual models like rectangular arrays and area models help show how multiplication works by organizing quantities into rows and columns or length and width. To find total stickers for 24 packs × 15 stickers, students can use the standard algorithm with regrouping or an area model showing (20 + 4) × (10 + 5), demonstrating understanding of place value in multiplication. Choice A is correct because using partial products: (20 × 10 = 200, 20 × 5 = 100, 4 × 10 = 40, 4 × 5 = 20), sum = 360. This demonstrates fluent multiplication using place value understanding. Choice B represents adding instead of multiplying, which happens when students confuse operations. To help students: For 2-digit × 2-digit, the area model helps visualize: draw rectangle divided into four sections (tens × tens, tens × ones, ones × tens, ones × ones), find each area, add together. Connect to arrays: 24 × 15 means 24 rows of 15 items. Ensure students understand multiplication as repeated addition or equal groups. Watch for: not carrying in standard algorithm, adding factors instead of multiplying, forgetting to add all partial products, misaligning place values, and weak basic multiplication facts preventing fluency.

Question 15

Find the product: 2,709×42,709 \times 4

  1. 10,836 (correct answer)
  2. 10,806
  3. 2,713
  4. 8,036
Explanation: Multiplying 2,709 by 4 gives 10,836, making Choice A correct. Choice B, 10,806, comes from a regrouping slip where the tens digit drops to 0 instead of carrying correctly. Choice C, 2,713, looks like only the ones digit was multiplied while the rest of the number was left the same. Choice D, 8,036, comes from multiplying only the thousands and ones digits by 4 and skipping the hundreds place.

Question 16

What is 1,839×41,839 \times 4?

  1. 736
  2. 7,256 (correct answer)
  3. 7,356
  4. 1,843
Explanation: This question tests 4th grade ability to multiply a whole number of up to four digits by a one-digit whole number, and multiply two two-digit numbers, using strategies based on place value and properties of operations (CCSS.4.NBT.5). Multiplication can be understood using place value strategies like the partial products method, where you break numbers into place values (456 = 400 + 50 + 6), multiply each part separately, then add. For 2-digit × 2-digit, you can use the standard algorithm (multiply by ones digit, then tens digit, aligning by place value) or an area model (break rectangle into smaller sections). Visual models like rectangular arrays and area models help show how multiplication works by organizing quantities into rows and columns or length and width. To multiply 1,839 × 4, students can use the standard algorithm with regrouping or break into partial products by place value, demonstrating understanding of place value in multiplication. Choice B is correct because using the standard algorithm: 9×4=369 \times 4 = 36 (write 6, carry 3), 3×4=12+3=153 \times 4 = 12 + 3 = 15 (write 5, carry 1), 8×4=32+1=338 \times 4 = 32 + 1 = 33 (write 3, carry 3), 1×4=4+3=71 \times 4 = 4 + 3 = 7 (write 7), resulting in 7,356. This demonstrates fluent multiplication using place value understanding. Choice A represents not carrying in the hundreds place, which happens when students forget to add the carried amount during regrouping. To help students: Use graph paper to align place values in standard algorithm. For partial products, explicitly break numbers by place value (1,839 = 1,000 + 800 + 30 + 9) and multiply each part, labeling (1,000×4=4,0001,000 \times 4 = 4,000, 800×4=3,200800 \times 4 = 3,200, 30×4=12030 \times 4 = 120, 9×4=369 \times 4 = 36, sum = 7,356). Ensure students understand multiplication as repeated addition or equal groups. Watch for: not carrying in standard algorithm, adding factors instead of multiplying, forgetting to add all partial products, misaligning place values, and weak basic multiplication facts preventing fluency.

Question 17

Multiply 5858 by 3434. What is the product?

  1. 92
  2. 1,522
  3. 1,872
  4. 1,972 (correct answer)
Explanation: The correct answer is 1,972, because using partial products, 50 times 30 is 1,500, 50 times 4 is 200, 8 times 30 is 240, and 8 times 4 is 32, and adding all four partial products gives 1,972. Choice A, 92, comes from adding 58 and 34 instead of multiplying them. Choice B, 1,522, comes from a partial-products error where one of the four pieces is calculated incorrectly. Choice C, 1,872, comes from a smaller multiplication slip in one of the partial products.

Question 18

Keisha's warehouse packs crayons into cases for shipping. She packs 88 cases, and each case holds 2,1352,135 crayons. How many crayons are there in all?

  1. 2,143 crayons
  2. 10,680 crayons
  3. 17,080 crayons (correct answer)
  4. 17,800 crayons
Explanation: 17,080 is correct because 8×2,135=17,0808 \times 2,135 = 17,080. 2,143 is incorrect because it does not represent a product of these two numbers. 10,680 is incorrect because it results from a partial or incomplete multiplication. 17,800 is incorrect because it reverses two digits in the correct product.

Question 19

A cargo plane makes the same 1,2561,256-mile flight each day for 77 days. How many miles does it fly in all?

  1. 17,592 miles
  2. 8,792 miles (correct answer)
  3. 1,263 miles
  4. 8,742 miles
Explanation: 8,792 miles is correct because 1,256×7=8,7921,256 \times 7 = 8,792. 17,592 miles is incorrect because it is roughly double the correct product. 1,263 miles is incorrect because it looks like an addition of the two given numbers rather than a product. 8,742 miles is incorrect because it results from a small computation slip in the multiplication.

Question 20

A rectangle is 3434 units long and 1616 units wide. What is the total area?

  1. 544 square units (correct answer)
  2. 50 square units
  3. 5,440 square units
  4. 424 square units
Explanation: The correct answer is A, 544 square units, because the area of a rectangle equals length times width: 34 times 16 equals 544. Choice B, 50 square units, comes from adding the length and width instead of multiplying. Choice C, 5,440 square units, comes from an extra factor of ten in the multiplication. Choice D, 424 square units, comes from a multiplication error.