Elementary School Math Quiz: Add Four Two Digit Numbers
20 questions · exam conditions
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Add Four Two Digit NumbersQuestion 1 of 20

Add: 63+17+28+4163 + 17 + 28 + 41. What is the total?

149
122
139
76
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Elementary School Math Quiz

Elementary School Math Quiz: Add Four Two Digit Numbers

Practice Add Four Two Digit Numbers in Elementary School Math with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Add Four Two Digit Numbers, giving you a quick way to practice the rules, question types, and explanations that matter most for Elementary School Math.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

Add: 63+17+28+4163 + 17 + 28 + 41. What is the total?

  1. 149 (correct answer)
  2. 122
  3. 139
  4. 76
Explanation: The total is 149, because 63+17+28+41=14963 + 17 + 28 + 41 = 149, grouping as 80+6980 + 69. Choice B (122) and Choice D (76) result from addition errors made while combining the four numbers, such as misaligning ones and tens during column addition. Choice C (139) comes from adding 80+6980 + 69 incorrectly as 139 instead of 149.

Question 2

Add: 58+24+39+1658 + 24 + 39 + 16. What is the sum?

  1. 147
  2. 127
  3. 137 (correct answer)
  4. 98
Explanation: Adding 58, 24, 39, and 16 together gives a sum of 137. 147 is 10 too high for the correct sum. 127 is 10 too low for the correct sum. 98 leaves out one of the four numbers entirely.

Question 3

Maya has 2323 stickers. She buys 33 packs of stickers. The first pack has 1717 stickers, the second pack has 2525 stickers, and the third pack has 1919 stickers. How many stickers does Maya have in total?

  1. 8484 (correct answer)
  2. 6161
  3. 6565
  4. 7474
Explanation: Maya starts with 23 stickers and adds three packs: 17, 25, and 19 stickers. The total is 23 + 17 + 25 + 19 = 84 stickers. Choice B (61) represents adding only the three packs without the original 23. Choice C (65) represents miscounting by adding 23 + 17 + 25 but forgetting the 19. Choice D (74) represents an arithmetic error in the addition process.

Question 4

A farmer counted eggs from four chicken coops. The first coop had 3131 eggs, the second had 2424 eggs, the third had 3535 eggs, and the fourth had 2828 eggs. How many eggs were there altogether?

  1. 108108
  2. 118118 (correct answer)
  3. 128128
  4. 138138
Explanation: Adding all four amounts: 31 + 24 + 35 + 28 = 118 eggs. Choice A (108) represents an error in carrying tens, resulting in 10 fewer. Choice C (128) represents adding an extra 10, possibly from incorrect place value work. Choice D (138) represents adding 20 extra, possibly from double-counting or misalignment in addition.

Question 5

Use place value to add: 39+22+18+4739 + 22 + 18 + 47. What is the sum?

  1. 136
  2. 116
  3. 126 (correct answer)
  4. 87
Explanation: This question tests 2nd grade understanding of adding four two-digit numbers, including using strategies like grouping and regrouping (CCSS 2.NBT.B.6: Add up to four two-digit numbers using strategies based on place value and properties of operations). To add four two-digit numbers like 39 + 22 + 18 + 47, you can use different strategies: (1) Column addition—line up numbers vertically by place value, add ones (9+2+8+7=26, write 6 carry 2), add tens (3+2+1+4=10, plus carried 2=12), get 126; (2) Grouping—pair numbers that are easy to add: 39+47=86, 22+18=40, then 86+40=126; (3) Place value—add all tens (30+20+10+40=100), add all ones (9+2+8+7=26), combine (100+26=126); (4) Partial sums—add sequentially: 39+22=61, 61+18=79, 79+47=126. All methods give same answer. When adding four numbers, the ones often sum to more than 10, requiring regrouping (carrying) to the tens place. In this problem, the student must add 39 + 22 + 18 + 47 using place value to find the sum. To solve, use place value: tens (30+20+10+40=100), ones (9+2+8+7=26), combine (100+26=126). Choice C is correct because using place value—all tens sum to 100, all ones sum to 26, 100+26=126. All four numbers are correctly included and added. Choice A represents a specific error: arithmetic error (miscalculated ones as 16 instead of 26, got 116). This error typically happens when students make calculation mistakes. To help students: Start with column addition—line up four numbers vertically by place value, add ones column (may need to carry), add tens column (include any carried tens). Practice regrouping explicitly: 'Ones: 9+2=11, 11+8=19, 19+7=26. That's 2 tens and 6 ones. Write 6 in ones place, carry 2 to tens.' Teach grouping strategy: 'Look for pairs that make friendly numbers. 39+47? That's easy—86. 22+18? That's 40. Now add 86+40=126.' Use base-ten blocks to show: 3 rods + 9 units + 2 rods + 2 units + 1 rod + 8 units + 4 rods + 7 units → combine rods (3+2+1+4=10 rods), combine units (9+2+8+7=26 units = 2 rods 6 units), total 12 rods 6 units = 126. Emphasize checking work: Add in different order or different groupings, should get same answer (commutative property). For word problems, list all four numbers clearly before adding. Practice partial sums: add first two, add result to third, add that result to fourth—build total step by step. Watch for: not regrouping, forgetting a number, stopping at intermediate step, arithmetic errors, disorganization (losing track of which numbers added).

Question 6

At a bake sale, 2626 cookies were sold in the first hour, 3838 cookies in the second hour, 2929 cookies in the third hour, and 4747 cookies in the fourth hour. What is the total number of cookies sold?

  1. 130130
  2. 140140 (correct answer)
  3. 135135
  4. 145145
Explanation: Adding the cookies from each hour: 26 + 38 + 29 + 47 = 140 cookies. Choice A (130) represents an error where 10 was not carried properly during addition. Choice C (135) represents stopping the addition early or making an error in the ones column. Choice D (145) represents adding an extra 5, possibly from misreading one of the numbers.

Question 7

A library got new books on four days. On Monday, the library got 2222 books. On Tuesday, the library got 3535 books. On Wednesday, the library got 1818 books. On Thursday, the library got 4444 books. How many books did the library get in total?

  1. 109109
  2. 139139
  3. 129129
  4. 119119 (correct answer)
Explanation: Adding all four days together, 22 + 35 + 18 + 44 = 119 books, so Choice D is correct. Choice A is wrong because it is too small to include all four days. Choice B is wrong because it adds too much. Choice C is wrong because it makes a small addition error.

Question 8

Four second-grade classes went on a field trip. Ms. Garcia's class has 2424 students, Mr. Lopez's class has 2626 students, Mrs. Chen's class has 2323 students, and Mr. Jackson's class has 2525 students. How many students went on the field trip altogether?

  1. 8888
  2. 7878
  3. 108108
  4. 9898 (correct answer)
Explanation: When you see a word problem asking "how many altogether" or "in total," you need to add up all the groups being combined. This is an addition problem where you're finding the sum of four different class sizes. Let's add the students from each class step by step. Ms. Garcia's class has 2424 students, Mr. Lopez's class has 2626 students, Mrs. Chen's class has 2323 students, and Mr. Jackson's class has 2525 students. Adding these together: 24+26+23+25=9824 + 26 + 23 + 25 = 98 students total. You can solve this by adding in any order, but one helpful strategy is to look for numbers that make 1010. Notice that 24+26=5024 + 26 = 50 and 23+25=4823 + 25 = 48, so 50+48=9850 + 48 = 98. Looking at the wrong answers: Choice A (8888) is 1010 less than the correct answer—you might get this if you accidentally subtracted 1010 somewhere or made an addition error. Choice B (7878) is 2020 less than correct, which could happen if you miscounted two of the class sizes. Choice C (108108) is 1010 more than correct—this might occur if you accidentally added an extra 1010 or misread one of the numbers. When solving addition word problems, always double-check your work by adding the numbers in a different order or by estimating first. Here, you could estimate: about 2525 students per class times 44 classes equals about 100100 students, which confirms that 9898 makes sense.

Question 9

A parking lot counted cars during four hours. In the first hour, there were 3232 cars. In the second hour, there were 4545 cars. In the third hour, there were 3838 cars. In the fourth hour, there were 2727 cars. How many cars were there in all?

  1. 132132
  2. 152152
  3. 142142 (correct answer)
  4. 162162
Explanation: Adding all four hours together, 32 + 45 + 38 + 27 = 142 cars, so Choice C is correct. Choice A is wrong because it is too small. Choice B is wrong because it adds too much. Choice D is wrong because it also adds too much.

Question 10

Add using column addition: 58+17+26+3958 + 17 + 26 + 39. What is the total?

  1. 150
  2. 101
  3. 130
  4. 140 (correct answer)
Explanation: Adding 58, 17, 26, and 39 together gives a total of 140. 150 is too high for these four numbers. 101 would result from leaving out one of the numbers entirely. 130 is close but comes from a small regrouping error in the tens place.

Question 11

Find the sum of 68+6268 + 62.

  1. 140
  2. 111
  3. 130 (correct answer)
  4. 120
Explanation: Adding 68 and 62 gives 130. Choice A adds 10 too many, from a regrouping mistake. Choice B comes from a mistake that loses a ten while regrouping. Choice D subtracts 10 too many from the correct sum.

Question 12

Four classes collected cans for recycling. Room 1212 collected 3939 cans, Room 1515 collected 2727 cans, Room 1818 collected 4242 cans, and Room 2121 collected 3333 cans. How many cans did all four classes collect together?

  1. 131131
  2. 141141 (correct answer)
  3. 151151
  4. 121121
Explanation: Adding all four amounts: 39 + 27 + 42 + 33 = 141 cans. Choice A (131) represents an error in carrying during addition, resulting in 10 fewer. Choice C (151) represents adding an extra 10, possibly from incorrect regrouping. Choice D (121) represents multiple arithmetic errors or missing one of the addends partially.

Question 13

What is 28+34+41+5228 + 34 + 41 + 52?

  1. 165
  2. 155 (correct answer)
  3. 103
  4. 145
Explanation: Adding 28, 34, 41, and 52 together gives a total of 155. Getting 165 or 145 usually comes from a small addition mistake in one of the columns. Getting 103 would mean leaving out one of the four numbers entirely. Adding all four numbers carefully, regrouping where needed, gives 155.

Question 14

Maya has 36 stickers, Amir has 27 stickers, Yuki has 19 stickers, and Carlos has 44 stickers. How many stickers do they have in all?

  1. 136
  2. 126 (correct answer)
  3. 116
  4. 82
Explanation: Add all four amounts: 36+27+19+44=12636+27+19+44=126. Choice A is ten too many. Choice C is ten too few. Choice D adds only three of the four amounts and forgets Carlos's 44.

Question 15

Keisha has 29 cards, Marcus has 38, Sofia has 16, and Jamal has 67. How many cards altogether?

  1. 150 (correct answer)
  2. 130
  3. 140
  4. 120
Explanation: The correct answer is 150, because 29 + 38 + 16 + 67 = 150. Choice B (130) and Choice C (140) both come from small addition mistakes when combining the four numbers. Choice D (120) leaves out one of the numbers entirely.

Question 16

In four rounds, Keisha scores 22, 45, 31, and 19 points. What is the total score?

  1. 107
  2. 117 (correct answer)
  3. 76
  4. 97
Explanation: Adding 22, 45, 31, and 19 together gives a total of 117 points. 107 is 10 too low for the correct sum. 76 leaves out two of the four scores. 97 is 20 too low for the correct sum.

Question 17

Add using column addition: 47+28+35+16=?47 + 28 + 35 + 16 = ?

  1. 100
  2. 94
  3. 126 (correct answer)
  4. 110
Explanation: Adding 47, 28, 35, and 16 together gives a total of 126. 100 and 94 are both too low to be the sum of these four numbers. 110 is closer but still comes from missing part of a regrouped digit during column addition.

Question 18

What is 55+22+31+1955 + 22 + 31 + 19?

  1. 107
  2. 127 (correct answer)
  3. 137
  4. 117
Explanation: Adding 55, 22, 31, and 19 together gives a total of 127. Getting 107 or 117 usually comes from a small mistake regrouping the tens or ones. Getting 137 usually comes from adding one number incorrectly by 10 too many. Adding all four numbers carefully, regrouping where needed, gives 127.

Question 19

What is 28+34+41+5228 + 34 + 41 + 52?

  1. 145
  2. 155 (correct answer)
  3. 165
  4. 103
Explanation: Adding 28, 34, 41, and 52 together gives a total of 155. Getting 145 or 165 usually comes from a small addition mistake in one of the columns. Getting 103 would mean leaving out one of the four numbers entirely. Adding all four numbers carefully, regrouping where needed, gives 155.

Question 20

What is 58+17+26+3958 + 17 + 26 + 39?

  1. 130
  2. 111
  3. 150
  4. 140 (correct answer)
Explanation: Adding 58, 17, 26, and 39 together gives 140. Choice A, 130, is too small for this total. Choice B, 111, leaves out too much value to be correct. Choice C, 150, is too large for this total.