Elementary School Math Quiz: Add And Subtract Multi Digit Numbers
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Add And Subtract Multi Digit NumbersQuestion 1 of 20

A school district has 54,00654,006 students. 28,94728,947 students ride the bus. How many students do not ride the bus?

25,059
25,159
26,059
35,059
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Elementary School Math Quiz

Elementary School Math Quiz: Add And Subtract Multi Digit Numbers

Practice Add And Subtract Multi Digit Numbers in Elementary School Math with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Add And Subtract Multi Digit Numbers, giving you a quick way to practice the rules, question types, and explanations that matter most for Elementary School Math.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A school district has 54,00654,006 students. 28,94728,947 students ride the bus. How many students do not ride the bus?

  1. 25,059 (correct answer)
  2. 25,159
  3. 26,059
  4. 35,059
Explanation: 25,059 is correct because 54,006−28,947=25,05954,006 - 28,947 = 25,059. 25,159 is incorrect because it results from a small subtraction slip in the tens place. 26,059 is incorrect because it results from a slip in the thousands place. 35,059 is incorrect because it results from a slip of ten thousand in the subtraction.

Question 2

Find the sum: 3,895+7,4683,895 + 7,468​

  1. 11,363 (correct answer)
  2. 11,253
  3. 10,363
  4. 11,364
Explanation: This question tests 4th grade fluency with adding and subtracting multi-digit whole numbers using the standard algorithm (CCSS.4.NBT.4). The standard algorithm for addition involves aligning numbers by place value, adding each place starting from the ones, and regrouping (carrying) when the sum in a place is 10 or more. The standard algorithm for subtraction involves aligning numbers by place value, subtracting each place starting from the ones, and regrouping (borrowing) when the top digit is less than the bottom digit. Regrouping means taking 10 from the next left place and adding it to the current place. To add 3,895 and 7,468, align the places and add ones (carries if ≥10), tens (including any carried value), hundreds, and so on, requiring proper regrouping to get the correct sum. Choice A is correct because following the standard algorithm with proper regrouping: ones 5+8=13 (write 3, carry 1), tens 9+6+1=16 (write 6, carry 1), hundreds 8+4+1=13 (write 3, carry 1), thousands 3+7+1=11, giving 11,363. Choice B represents forgetting to carry in the tens place, which happens when students add without including the carried value. To help students: Use graph paper or place value columns to align digits correctly. For addition, emphasize checking each column—if sum is 10 or more, write the ones digit and carry the tens digit to the next column. Practice borrowing across zeros (like 5,003 - 2,456) by borrowing from the next non-zero place. Have students estimate first (round to nearest thousand) to check if answer is reasonable. Watch for: forgetting to add carried values, subtracting smaller from larger in each column without borrowing, not reducing the borrowed-from digit, and misaligning place values.

Question 3

A school has 54,006 students. 28,947 students ride the bus. How many students do not ride the bus?

  1. 25,159
  2. 35,059
  3. 25,059 (correct answer)
  4. 26,059
Explanation: Subtracting 28,947 from 54,006 gives 25,059, making Choice C correct. Choice A, 25,159, comes from a regrouping slip in the tens place during subtraction. Choice B, 35,059, comes from a borrowing error in the ten-thousands place. Choice D, 26,059, comes from a small error in the thousands place during regrouping.

Question 4

What is 6,807 + 9,958?

  1. 16,675
  2. 16,665
  3. 15,665
  4. 16,765 (correct answer)
Explanation: Adding 6,807 and 9,958 using place value gives 16,765. Choices A (16,675) and B (16,665) come from small regrouping errors in the tens and hundreds places. Choice C (15,665) is off by a thousand, as if a digit was misplaced during carrying.

Question 5

What is 39,784+6,50939,784 + 6,509?

  1. 46,293 (correct answer)
  2. 46,393
  3. 46,283
  4. 45,293
Explanation: The correct answer is 46,293, since 39,784 + 6,509 = 46,293. Choice B, 46,393, comes from misreading a digit in the hundreds place during addition. Choice C, 46,283, is off by 10 from a small addition slip in the tens place. Choice D, 45,293, comes from forgetting to carry a thousand when adding the thousands digits.

Question 6

What is 81,640−26,87581,640 - 26,875?

  1. 64,765
  2. 54,765 (correct answer)
  3. 55,765
  4. 54,775
Explanation: Subtracting 26,875 from 81,640 gives 54,765, making Choice B correct. Choice A, 64,765, comes from a borrowing error in the ten-thousands place. Choice C, 55,765, comes from a small regrouping slip in the hundreds place. Choice D, 54,775, comes from a small error in the tens place during subtraction.

Question 7

Elena collected 2,6792,679 bottle caps for recycling. She gave 845845 to her brother and 567567 to her sister. Her cousin then gave her 429429 more bottle caps. If Elena needs 2,0002,000 bottle caps for a school project, how many more does she need?

  1. Elena needs 1,696 more bottle caps.
  2. Elena needs 304 more bottle caps. (correct answer)
  3. Elena needs 133 more bottle caps.
  4. Elena needs 429 more bottle caps.
Explanation: Choice B is correct because Elena has 2,679 minus 845 minus 567 plus 429, which equals 1,696 bottle caps, and she needs 2,000 minus 1,696, or 304 more. Choice A is incorrect because it is the number of bottle caps Elena currently has, not the number she still needs. Choice C is incorrect because it does not match the difference between 2,000 and 1,696. Choice D is incorrect because it is the number of bottle caps her cousin gave her, not the number still needed.

Question 8

What is 5,406+3,8955,406 + 3,895?​

  1. 8,301
  2. 9,311
  3. 9,301 (correct answer)
  4. 9,201
Explanation: This question tests 4th grade fluency with adding and subtracting multi-digit whole numbers using the standard algorithm (CCSS.4.NBT.4). The standard algorithm for addition involves aligning numbers by place value, adding each place starting from the ones, and regrouping (carrying) when the sum in a place is 10 or more. The standard algorithm for subtraction involves aligning numbers by place value, subtracting each place starting from the ones, and regrouping (borrowing) when the top digit is less than the bottom digit. Regrouping means taking 10 from the next left place and adding it to the current place. To add 5,406 and 3,895, align the places and add ones (carries if ≥10), tens (including any carried value), hundreds, and so on, requiring proper regrouping to get the correct sum. Choice C is correct because following the standard algorithm with proper regrouping: ones 6+5=11 (write 1, carry 1), tens 0+9+1=10 (write 0, carry 1), hundreds 4+8+1=13 (write 3, carry 1), thousands 5+3+1=9, giving 9,301. This demonstrates fluent use of the standard algorithm with proper place value alignment and regrouping. Choice A represents forgetting to carry over in the hundreds place, which happens when students add 4+8=12 without adding the carried 1. To help students: Use graph paper or place value columns to align digits correctly. For addition, emphasize checking each column—if sum is 10 or more, write the ones digit and carry the tens digit to the next column. For subtraction, check each column—if top digit is less than bottom digit, borrow 10 from the next left column (reducing that column's top digit by 1). Practice borrowing across zeros (like 5,003 - 2,456) by borrowing from the next non-zero place. Have students estimate first (round to nearest thousand) to check if answer is reasonable. Watch for: forgetting to add carried values, subtracting smaller from larger in each column without borrowing, not reducing the borrowed-from digit, and misaligning place values.

Question 9

Find the difference: 600,040−285,967600,040 - 285,967

  1. 314,073 (correct answer)
  2. 314,083
  3. 315,073
  4. 324,173
Explanation: This question tests 4th grade fluency with adding and subtracting multi-digit whole numbers using the standard algorithm (CCSS.4.NBT.4). The standard algorithm for subtraction involves aligning numbers by place value, subtracting each place starting from the ones, and regrouping (borrowing) when the top digit is less than the bottom digit. Regrouping means taking 10 from the next left place and adding it to the current place. To subtract 285,967 from 600,040, align places and subtract ones (0-7 requires borrow, resulting in 10-7=3), tens (3-6 requires borrow across zeros, resulting in 13-6=7 after adjusting), hundreds (9-9=0), thousands (9-5=4), ten thousands (9-8=1), and hundred thousands (5-2=3), requiring proper regrouping to get the correct difference. Choice C is correct because following the standard algorithm with proper regrouping: ones 10-7=3 (after borrow), tens 13-6=7 (after borrow across zeros), hundreds 9-9=0, thousands 9-5=4, ten thousands 9-8=1, hundred thousands 5-2=3, giving 314,073. This demonstrates fluent use of the standard algorithm with proper place value alignment and regrouping. Choice D represents misalignment or incorrect borrowing, which happens when students don't handle zeros properly. To help students: Use graph paper or place value columns to align digits correctly. For subtraction, check each column—if top digit is less than bottom digit, borrow 10 from the next left column (reducing that column's top digit by 1). Practice borrowing across zeros (like 5,003 - 2,456) by borrowing from the next non-zero place. Have students estimate first (round to nearest thousand) to check if answer is reasonable. Watch for: not continuing borrowing across zeros, misaligning places.

Question 10

What is 48,679+27,45848,679 + 27,458?

  1. 76,027
  2. 76,147
  3. 75,137
  4. 76,137 (correct answer)
Explanation: Choice D is correct because 48,679 plus 27,458 equals 76,137. Choice A is incorrect because it does not match the actual sum. Choice B is incorrect because it is close to the correct answer but reflects a small addition error. Choice C is incorrect because it is off by exactly 1,000, suggesting a misplaced digit.

Question 11

What is 81,640−26,87581,640 - 26,875?

  1. 54,765 (correct answer)
  2. 54,775
  3. 64,765
  4. 55,765
Explanation: Subtracting 81,640−26,87581,640 - 26,875 gives 54,76554,765. Choice B has an error in the tens place (54,775 instead of 54,765). Choice C has an error in the ten-thousands place (64,765 instead of 54,765). Choice D has an error in the thousands place (55,765 instead of 54,765).

Question 12

A school library had 3,5083,508 books at the beginning of the year. During the year, they bought 1,2761,276 new books and removed 847847 damaged books. At the end of the year, they counted 3,9253,925 books. How many books were lost or stolen during the year?

  1. 1212 books were lost or stolen (correct answer)
  2. 2424 books were lost or stolen
  3. 3636 books were lost or stolen
  4. 4848 books were lost or stolen
Explanation: Starting with 3,508 books, adding the 1,276 bought and subtracting the 847 removed gives an expected 3,937 books, but only 3,925 were actually counted, meaning 12 books were lost or stolen. Choice B could come from a borrowing error while subtracting 3,925 from the expected 3,937. Choice C compounds a similar subtraction slip, roughly tripling the true difference. Choice D could result from misreading one of the four-digit numbers by a small amount before subtracting. Choice A correctly finds the gap between the expected count and the actual count.

Question 13

A farmer harvested 6,4256,425 apples from his orchard. He sold 2,8472,847 apples at the farmers market and 1,9561,956 apples to a local grocery store. He then picked 834834 more apples from trees he had missed. How many apples does the farmer have now?

  1. The farmer has 1,622 apples now.
  2. The farmer has 3,622 apples now.
  3. The farmer has 2,456 apples now. (correct answer)
  4. The farmer has 2,290 apples now.
Explanation: Choice C is correct because 6,425 minus 2,847 minus 1,956 plus 834 equals 2,456 apples. Choice A is incorrect because it does not account for the apples picked after the sales. Choice B is incorrect because it does not correctly combine all four amounts. Choice D is incorrect because it does not match the result of the full sequence of subtractions and addition.

Question 14

What is 6,807+9,9586,807 + 9,958?

  1. 16,675
  2. 15,665
  3. 16,765 (correct answer)
  4. 16,665
Explanation: The correct sum is 16,765. Choice A, 16,675, has two digits swapped in the hundreds and tens places. Choice B, 15,665, comes from forgetting to carry a 1 into the thousands place. Choice D, 16,665, comes from adding 6 plus 9 as 15 without carrying the 1 into the hundreds place.

Question 15

Find the difference: 50,000−18,74650,000 - 18,746

  1. 31,254 (correct answer)
  2. 32,254
  3. 41,254
  4. 31,364
Explanation: The correct answer is 31,254, because 50,000 minus 18,746 equals 31,254. Choice B, 32,254, comes from a borrowing error of 1,000 during subtraction. Choice C, 41,254, comes from a borrowing error of 10,000 in the ten-thousands place. Choice D, 31,364, comes from transposing two digits in the hundreds and tens places.

Question 16

Marcus is saving money for a bicycle that costs $485. He has already saved $127 and his grandmother gives him $95. His uncle gives him twice as much as his grandmother gave him. How much more money does Marcus need to buy the bicycle?

  1. $95 more is needed for the bicycle
  2. $168 more is needed for the bicycle
  3. $263 more is needed for the bicycle
  4. $73 more is needed for the bicycle (correct answer)
Explanation: This is a multi-step word problem that requires you to track money coming in and then calculate how much more is needed. The key is organizing the information and working through each step carefully. Let's calculate how much money Marcus has total. He starts with $127 that he already saved. His grandmother gives him $95, so now he has $\127 + $95 = $222 . His uncle gives him twice as much as his grandmother, which means 2 \times $95 = $190 . Adding the uncle's money: $222 + $190 = $412 total. Since the bicycle costs 485, Marcus still needs $$\485 - $412 = $73$$ more. This confirms answer choice D is correct. Looking at the wrong answers: Choice A (95)mighttemptyouifyouonlycountedthegrandmother′sgiftandforgotabouttheuncle′scontribution.ChoiceB(95) might tempt you if you only counted the grandmother's gift and forgot about the uncle's contribution. Choice B (168) could result from forgetting to include Marcus's initial savings of 127inyourtotal.ChoiceC(127 in your total. Choice C (263) appears if you only counted Marcus's original $127 and ignored both relatives' gifts entirely. When solving multi-step money problems, write down each amount clearly and add them step by step. Don't try to do all the mental math at once. Also, pay close attention to phrases like "twice as much" – they require an extra calculation that's easy to miss when you're rushing through the problem.

Question 17

Find the sum: 46,785+29,46946,785 + 29,469

  1. 76,254 (correct answer)
  2. 75,254
  3. 76,244
  4. 76,154
Explanation: 46,785 + 29,469 = 76,254. Adding each place with proper regrouping (ones, tens, hundreds, thousands, then ten-thousands) gives this total. Choice B is 1,000 too low, suggesting a missed regrouping in the thousands place. Choice C is 10 too low. Choice D is 100 too low, from a missed carry in the hundreds place.

Question 18

Maya is collecting stickers for a school project. She starts with 1,2471,247 stickers. Her friend gives her 386386 more stickers, but then she uses 529529 stickers for her project. How many stickers does Maya have left?

  1. 1,1041,104 stickers (correct answer)
  2. 1,1621,162 stickers
  3. 1,0141,014 stickers
  4. 1,2041,204 stickers
Explanation: The correct answer is 1,104 stickers, because 1,247 plus 386 equals 1,633, and 1,633 minus 529 equals 1,104. Choice B, 1,162 stickers, comes from adding 1,247 and 386 incorrectly as 1,691 before subtracting 529. Choice C, 1,014 stickers, comes from a subtraction slip after finding the correct sum of 1,633. Choice D, 1,204 stickers, comes from a small addition error in the tens place before subtracting.

Question 19

A toy store received three shipments of toys. The first shipment had 2,3452,345 toys, the second had 1,7891,789 toys, and the third had 1,0561,056 toys. If the store sold 2,8172,817 toys, how many toys are left in the store?

  1. 2,4732,473 toys are left in the store
  2. 2,2832,283 toys are left in the store
  3. 3,1273,127 toys are left in the store
  4. 2,3732,373 toys are left in the store (correct answer)
Explanation: When you see a word problem involving multiple additions and subtractions, break it down into clear steps: first find what came in, then subtract what went out. Start by adding all three shipments to find the total toys received: 2,345+1,789+1,0562,345 + 1,789 + 1,056. Let's add step by step: 2,345+1,789=4,1342,345 + 1,789 = 4,134, then 4,134+1,056=5,1904,134 + 1,056 = 5,190 total toys received. Now subtract the toys sold: 5,190−2,817=2,3735,190 - 2,817 = 2,373 toys remaining. This matches answer choice D. Let's see why the other answers are wrong. Choice A (2,4732,473) likely comes from a calculation error when adding the shipments—perhaps mixing up digits or making an arithmetic mistake. Choice B (2,2832,283) suggests an error in the final subtraction step, possibly subtracting incorrectly or using the wrong total. Choice C (3,1273,127) is too high and might result from forgetting to subtract the sold toys entirely, or making a major addition error. The key strategy for multi-step word problems like this is to organize your work clearly: write down what you're finding at each step (total received, then amount remaining), and double-check your arithmetic. Many students rush and make calculation errors, so take time to verify each step. Remember that "left" or "remaining" always means you need to subtract what was used or sold from what you started with.

Question 20

Keisha had 70,002 tickets. She sold 38,679 tickets. How many tickets are left?​

  1. 31,323 tickets (correct answer)
  2. 32,323 tickets
  3. 42,681 tickets
  4. 31,433 tickets
Explanation: This question tests 4th grade fluency with adding and subtracting multi-digit whole numbers using the standard algorithm (CCSS.4.NBT.4). The standard algorithm for addition involves aligning numbers by place value, adding each place starting from the ones, and regrouping (carrying) when the sum in a place is 10 or more. The standard algorithm for subtraction involves aligning numbers by place value, subtracting each place starting from the ones, and regrouping (borrowing) when the top digit is less than the bottom digit. Regrouping means taking 10 from the next left place and adding it to the current place. This problem requires subtracting 38,679 from 70,002 by aligning places and subtracting ones (borrowing if needed), tens (borrowing if needed), hundreds, and so on to find tickets left, requiring proper regrouping across multiple zeros to get the correct difference. Choice A is correct because following the standard algorithm with proper regrouping: ones 12-9=3 (after borrowing across zeros), tens 9-7=2, hundreds 9-6=3, thousands 9-8=1, ten thousands 6-3=3, giving 31,323. Choice B represents not borrowing across the zeros properly, which happens when students fail to propagate the borrow through multiple zero places. To help students: Use graph paper or place value columns to align digits correctly. For subtraction, check each column—if top digit is less than bottom digit, borrow 10 from the next left column (reducing that column's top digit by 1). Practice borrowing across zeros (like 5,003 - 2,456) by borrowing from the next non-zero place. Have students estimate first (round to nearest thousand) to check if answer is reasonable. Watch for: forgetting to add carried values, subtracting smaller from larger in each column without borrowing, not reducing the borrowed-from digit, and misaligning place values.