Conversational Mandarin Chinese Quiz: Understanding Everyday Texts
10 questions · exam conditions
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Understanding Everyday TextsQuestion 1 of 10

咖啡店黑板菜单： 美式咖啡 ¥25，拿铁 ¥32，卡布奇诺 ¥32，抹茶拿铁 ¥35 今日特饮：南瓜拿铁 ¥38 套餐优惠：任意咖啡+甜点=九折 甜点：蛋糕 ¥28，曲奇 ¥15，松饼 ¥22 会员每日首杯八折（不与套餐优惠叠加）

刘小姐是会员，她想点一杯拿铁和一块蛋糕。她应该选择哪种付款方式最省钱，实际需要付多少？

用会员八折买拿铁，蛋糕原价：¥32×0.8+¥28=¥25.6+¥28=¥53.6，比套餐九折的¥54更省，共付¥53.6。
选套餐九折最省钱：(¥32+¥28)×0.9=¥54，会员折扣只省咖啡部分，套餐覆盖更广，共付¥54。
两种优惠同时使用最省钱：拿铁享会员八折¥25.6，蛋糕再享套餐九折¥25.2，共付¥50.8。
会员八折适用于整个套餐，拿铁和蛋糕均享八折：(¥32+¥28)×0.8=¥48，这是最省钱的方案。
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Conversational Mandarin Chinese Quiz

Conversational Mandarin Chinese Quiz: Understanding Everyday Texts

Practice Understanding Everyday Texts in Conversational Mandarin Chinese with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Understanding Everyday Texts, giving you a quick way to practice the rules, question types, and explanations that matter most for Conversational Mandarin Chinese.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

咖啡店黑板菜单： 美式咖啡 ¥25，拿铁 ¥32，卡布奇诺 ¥32，抹茶拿铁 ¥35 今日特饮：南瓜拿铁 ¥38 套餐优惠：任意咖啡+甜点=九折 甜点：蛋糕 ¥28，曲奇 ¥15，松饼 ¥22 会员每日首杯八折（不与套餐优惠叠加）

刘小姐是会员，她想点一杯拿铁和一块蛋糕。她应该选择哪种付款方式最省钱，实际需要付多少？

  1. 用会员八折买拿铁，蛋糕原价：¥32×0.8+¥28=¥25.6+¥28=¥53.6，比套餐九折的¥54更省，共付¥53.6。 (correct answer)
  2. 选套餐九折最省钱：(¥32+¥28)×0.9=¥54，会员折扣只省咖啡部分，套餐覆盖更广，共付¥54。
  3. 两种优惠同时使用最省钱：拿铁享会员八折¥25.6，蛋糕再享套餐九折¥25.2，共付¥50.8。
  4. 会员八折适用于整个套餐，拿铁和蛋糕均享八折：(¥32+¥28)×0.8=¥48，这是最省钱的方案。
Explanation: When a question involves multiple discount options that cannot be combined, your job is to calculate each scenario separately and compare — don't assume the bigger-sounding discount wins automatically. Here, Liu xiaojie wants a latte (¥32) and a cake (¥28). Two options exist: her member discount (八折, 80% off her first drink only) or the combo deal (套餐九折, 90% off both items together). The menu explicitly states these cannot stack (不与套餐优惠叠加). Option A — member discount on latte only: 32×0.8+28=25.6+28=¥53.632 × 0.8 + 28 = 25.6 + 28 = ¥53.6 Option B — combo deal on both: (32+28)×0.9=60×0.9=¥54(32 + 28) × 0.9 = 60 × 0.9 = ¥54 Comparing: ¥53.6 < ¥54, so A is correct — using the member discount saves more (¥0.40 more than the combo). The key insight is that 八折 on just the coffee still beats 九折 on the total, because the coffee price alone is high enough that the steeper discount outweighs the combo's broader coverage. B is wrong because it assumes the combo is always better when two items are involved — but a deeper single-item discount can win, especially when one item carries significant weight. C is wrong because it tries to split the discounts across both items simultaneously, which directly violates the 不与套餐优惠叠加 rule. D is wrong because it misreads the member policy — 八折 applies to the first drink only, not an entire combo order. Study tip: Always read discount restriction language carefully (不叠加, 仅限首杯, etc.) and calculate every valid scenario before choosing — never assume intuitively which deal wins.

Question 2

药店告示牌： 处方药须凭处方购买。 非处方药（OTC）无需处方。 以下药品本店暂时缺货：感冒灵颗粒、布洛芬片、阿莫西林胶囊（处方药）。 会员购药享九五折，处方药不参与折扣。 本日特价：维生素C ¥12（原价¥18），仅限购买2盒。

孙女士是会员，她有医生处方，需要购买阿莫西林胶囊（处方药），同时想买3盒维生素C。她今天的购物情况是？

  1. 阿莫西林有货，凭处方可购买，享会员九五折优惠；维生素C可以购买3盒，享特价¥12每盒，共花费约¥36。
  2. 阿莫西林有货，凭处方可购买，但不享会员折扣；维生素C限购2盒，她只能买2盒，享特价¥12每盒，共花费¥24加上阿莫西林原价。
  3. 阿莫西林暂时缺货，无法购买；维生素C可以购买3盒，其中2盒享特价¥12，第3盒按原价¥18，共花费¥42。
  4. 阿莫西林暂时缺货，无法购买；维生素C限购2盒，她只能买2盒，享特价¥12每盒，共花费¥24。 (correct answer)
Explanation: Questions like this test your ability to cross-reference multiple rules in a single passage — a common format in conversational Mandarin reading comprehension. Before choosing an answer, you need to mentally check each item against every relevant condition listed. Let's walk through 孙女士's situation. First, 阿莫西林胶囊 is explicitly listed under 本店暂时缺货 ("temporarily out of stock"), which means no matter that she has a valid prescription, the store simply cannot sell it to her today. That eliminates any answer claiming she can successfully purchase it. For the 维生素C, the sign states 仅限购买2盒 — "limited to 2 boxes per purchase." She wants 3 boxes, but the purchase cap applies regardless of membership status. At ¥12 per box (the special price), 2 boxes cost 2×12=¥242 \times 12 = ¥24. That confirms D as the correct answer. Looking at the wrong choices: A incorrectly claims 阿莫西林 is in stock and that it qualifies for the member discount — both are false (it's out of stock, and prescriptions are explicitly excluded from discounts). B correctly notes that prescription drugs don't get the discount, but it still wrongly claims 阿莫西林 is available for purchase. C gets the out-of-stock detail right but says she can buy 3 boxes of vitamin C, ignoring the 2-box limit — and the pricing logic it applies is also unsupported by the sign. A useful strategy: when a passage contains a list of items marked as 缺货 (out of stock), scan that list first before evaluating any other conditions. Shops can have all the policies in the world, but unavailable stock overrides everything.

Question 3

健身房告示： 本月活动：成功介绍新会员入会，老会员可获赠1个月会籍延期（基础奖励）。另外，每成功介绍满3人，可额外再赠1个月，最多额外累计赠送2个月。新会员须在本月31日前完成注册方可计入。

赵先生本月介绍了5位朋友加入健身房，其中4位在31日前完成了注册，1位在下月初才注册。赵先生最多可以获得多少个月的会籍延期？

  1. 3个月，因为他介绍了5人，每人赠1个月共5个月，取上限3个月。
  2. 1个月，因为下月才注册的1位不计入，只有4位有效，但额外奖励须整3人一组，4人中只有一组满足，额外1个月须等5人全部注册后才能计算，本月仅得基础1个月。
  3. 2个月，因为只有4位在期限内注册，可获基础奖励1个月；4人中有一组3人满足额外奖励条件，再赠1个月，共计2个月。 (correct answer)
  4. 4个月，因为4位有效注册者每人各赠1个月，基础奖励共4个月，额外奖励另计后超出上限取最高值4个月。
Explanation: When a question presents a tiered reward system with eligibility conditions, your first step is to filter who actually qualifies, then apply each reward tier separately — don't mix them together. Here, the notice has two distinct reward layers: a base reward of 1 month for any successful referral, plus an extra reward of 1 additional month per complete group of 3 valid referrals, capped at 2 extra months. The critical eligibility rule is that new members must register before the 31st of this month. Since one of 赵先生's five friends registered in early next month, only 4 people count. With 4 valid referrals: the base reward is 1 month (you get this as long as at least one person qualifies — it's a flat bonus, not per person). Then, how many complete groups of 3 fit into 4? Just one — ⌊4÷3⌋=1\lfloor 4 \div 3 \rfloor = 1 — so he earns 1 extra month. Total: 1 + 1 = 2 months, making C the correct answer. A misreads the structure entirely, treating it as 1 month per person up to a cap of 3 — but the base reward is a single flat month, not a per-person multiplier. B correctly identifies 4 valid referrals and correctly applies the group-of-3 logic, but then wrongly withholds the extra month, inventing a rule that all 5 must register before any extra reward counts. D makes the same per-person mistake as A and inflates both tiers. As a study tip: when rules mention "每满X人" (every complete group of X), always use floor division and never award partial groups — and always filter eligibility before doing any calculations.

Question 4

营业时间：周一至周五 上午9:00 – 下午6:00；周六 上午10:00 – 下午3:00；周日休息。节假日另行通知。今日（周六）因店内整修，下午1:00提前关门。

李明今天（周六）下午2:00想去这家店，他会遇到什么情况？

  1. 店还开着，因为周六正常营业到下午3:00，他可以顺利进入。
  2. 店已经关门了，因为今天因整修提前在下午1:00关门，他无法进入。 (correct answer)
  3. 店已经关门了，因为今天是节假日，所以全天休息，他无法进入。
  4. 店还开着，因为节假日另行通知，没有收到通知就按正常时间营业到下午6:00。
Explanation: When reading notices in Mandarin, always prioritize specific exceptions over general rules. A passage may state default hours, but then introduce an override condition — that override takes precedence for the specific situation described. Here, the notice establishes that Saturday hours are 上午10:00 – 下午3:00 (10 AM – 3 PM). However, the final sentence introduces a critical exception: 今日（周六）因店内整修，下午1:00提前关门 — "Today (Saturday), due to in-store renovations, the store closes early at 1:00 PM." Li Ming arrives at 2:00 PM, which is one hour after this early closure. So the store is already shut, making B the correct answer. A is tempting because Saturday's normal closing time is 3:00 PM, and 2:00 PM falls within that window. The trap is ignoring the today-specific exception announced at the end of the passage. Always read to the end — late sentences often contain the most important information. C incorrectly claims today is a holiday (节假日). The passage only says holidays will be announced separately (另行通知); it never states today is a holiday. Don't invent information the passage doesn't provide. D misapplies the 节假日另行通知 clause. That phrase refers to future holiday announcements — it doesn't override the explicitly stated early closure today, nor does it extend hours to 6:00 PM on a Saturday. Study tip: In reading comprehension passages, watch for the word 今日 ("today") or 今天 — it signals a real-time update that overrides any standing schedule. Treat it as the highest-priority piece of information.

Question 5

菜单节选： 红烧肉 ¥48（含米饭） 麻婆豆腐 ¥32（不含米饭） 米饭 ¥5/碗 饮料另计：可乐/雪碧 ¥8，果汁 ¥12 温馨提示：两人以上用餐，主菜九折优惠。

王芳和她的朋友一起用餐，两人各点了一份麻婆豆腐和一碗米饭，另外各点了一杯果汁。他们一共需要付多少钱？

  1. ¥86.4，因为两人以上用餐享九折，折扣适用于全部消费：两份麻婆豆腐¥64、两碗米饭¥10、两杯果汁¥24，合计¥98再打九折共¥88.2，四舍五入约¥86.4。
  2. ¥91.6，因为两份麻婆豆腐打九折共¥57.6，加两碗米饭¥10和两杯果汁¥24，合计¥91.6。 (correct answer)
  3. ¥88.2，因为九折优惠适用于全单，两份麻婆豆腐¥64、两碗米饭¥10、两杯果汁¥24，合计¥98×0.9=¥88.2。
  4. ¥95.6，因为九折优惠仅适用于主菜，但米饭作为套餐附属品也应享受折扣：两份麻婆豆腐打九折¥57.6、两碗米饭打九折¥9、两杯果汁原价¥24，合计¥90.6再加服务附加¥5共¥95.6。
Explanation: When reading Chinese menu problems, your job is to carefully identify which items qualify for each promotion — don't assume discounts apply universally. The menu states clearly: 主菜九折优惠 means the 10% discount applies only to main dishes (主菜). 麻婆豆腐 is the main dish here, while 米饭 (rice) and 饮料 (drinks) are separate items not covered by this promotion. Here's the correct calculation for B: Two servings of 麻婆豆腐 at ¥32 each = ¥64, discounted at 90% gives 64×0.9=¥57.664 \times 0.9 = ¥57.6. Two bowls of rice at ¥5 each = ¥10 (no discount). Two fruit juices at ¥12 each = ¥24 (no discount, since 饮料另计 means drinks are billed separately at full price). Total: 57.6+10+24=¥91.657.6 + 10 + 24 = ¥91.6. That's answer B, the correct choice. Answer A incorrectly applies the 90% discount to the entire bill (¥98 × 0.9), then rounds arbitrarily to ¥86.4 — there is no rounding rule mentioned anywhere on the menu. Answer C makes the same mistake as A, applying the discount to everything including rice and drinks, arriving at ¥88.2. Answer D invents a mysterious "服务附加¥5" (service fee) that appears nowhere on the menu, and also incorrectly discounts the rice. Study tip: In Chinese menu reading questions, watch for scope-limiting words like 主菜 (main dish) or 另计 (billed separately) — these signal that a rule applies only to a specific category, not the whole bill.

Question 6

公交站牌： A路：每20分钟一班，首班6:00，末班22:00，终点站：火车站 B路：每30分钟一班，首班6:30，末班21:30，终点站：机场 注：周末末班提前30分钟。

今天是周日，陈先生需要在21:15左右乘B路公交去机场。他最迟应该在哪个时间前到达公交站？

  1. 21:15前到站即可，因为周末班次不变，B路照常运营，21:15仍有车可乘。
  2. 21:00前到站即可，因为周末末班提前30分钟，B路末班改为21:00，在21:00前到站就能赶上最后一班。
  3. 20:30前到站，因为周末末班提前30分钟，B路末班为21:00；而B路每30分钟一班，21:00前一班为20:30，21:15并无班次，须赶20:30那班。 (correct answer)
  4. 21:30前到站，因为周末提前30分钟仅针对首班，末班21:30不变，21:15可等21:30末班。
Explanation: Questions like this test your ability to apply multiple rules in sequence — a common trap in Chinese reading comprehension passages involving schedules and special conditions. Always extract each rule separately before combining them. Start with the weekend rule: the notice (注) states that on weekends, the last bus (末班) departs 30 minutes earlier. B路's normal last bus is 21:30, so on Sunday (周日), the last bus shifts to 21:00. That rules out A and D immediately — A ignores the weekend adjustment entirely, and D misreads the note as applying only to the first bus (首班), which is simply not what the passage says. Now here's the critical second step that separates B from C: knowing the last bus is 21:00 doesn't mean arriving by 21:00 solves the problem. B路 runs every 30 minutes, so buses depart at 20:00, 20:30, 21:00. Chen arrives "around 21:15" — but the 21:00 bus has already left. The next scheduled bus would be 21:30, which no longer runs on weekends. That means 20:30 is the last bus he can actually catch, making C the correct answer. Option B makes the mistake of stopping the analysis too early — it correctly identifies 21:00 as the new last bus but ignores that 21:15 arrival misses it entirely. Your strategy takeaway: whenever a schedule question has two interacting conditions (a time-shift rule plus a frequency interval), work through them in order. First apply the special rule to reset the timetable, then calculate backwards using the frequency to find the last catchable departure.

Question 7

超市告示： 本店会员积分规则：每消费¥10（以原价计算）积1分。积满100分可兑换¥5优惠券，积满200分可兑换¥15优惠券，积满500分可兑换¥50优惠券。优惠券不可与其他折扣同时使用。本次店庆全场九折。

张女士是会员，她今天选购了原价共¥500的商品，目前已有积分80分。她决定使用店庆九折折扣付款。她完成本次消费后积分达到多少，可以兑换哪种优惠券？该优惠券能在本次消费中使用吗？

  1. 实付¥450（九折后），消费后新增50分，积分共130分，可兑换¥5优惠券；但本次已使用九折折扣，优惠券不可与折扣同时使用，须留待下次使用。 (correct answer)
  2. 实付¥450（九折后），消费后新增45分（按实付¥450计算），积分共125分，可兑换¥5优惠券；但本次已使用九折折扣，优惠券须留待下次使用。
  3. 实付¥450（九折后），消费后新增50分，积分共130分，可兑换¥15优惠券，并可在本次结账时同时使用，实付¥435。
  4. 实付¥500（不打折），这样可同时使用¥5优惠券，消费后新增50分积分共130分，实付¥495，优惠券与折扣不可叠加所以放弃折扣更合算。
Explanation: When a question involves loyalty points, discounts, and coupon rules all at once, slow down and handle each rule separately before combining them. The key rules here are: (1) points are calculated on the original price, not the discounted price, and (2) coupons cannot be combined with other discounts. Since Zhang女士chose the store anniversary 九折 (90%) discount, her actual payment is 500×0.9=¥450500 \times 0.9 = ¥450. However, because the store rule states points accumulate based on 原价 (original price), her new points are calculated on ¥500: 500÷10=50 points500 \div 10 = 50 \text{ points}. Adding her existing 80 points gives 80+50=130 points80 + 50 = 130 \text{ points}, which qualifies for the ¥5 coupon (requires 100 points). Since she already used the 九折 discount on this transaction, the coupon — which cannot be used alongside other discounts — must be saved for next time. This makes A correct. B is wrong because it miscalculates points using the discounted price (¥450 ÷ 10 = 45 points) rather than the original price as the rules specify. C is wrong on two counts: 130 points only qualifies for the ¥5 coupon, not ¥15 (which requires 200 points), and the coupon cannot be used simultaneously with the 九折 discount. D is wrong because it invents a scenario where she abandons the discount to use the coupon — the question clearly states she decided to use the 九折 discount, and forgoing it just to use a ¥5 coupon on a ¥500 purchase would actually cost her more (¥495 vs. ¥450). Study tip: On questions with layered rules like this, always track which price triggers each rule. Points, discounts, and coupons often use different baselines — missing that distinction is exactly the trap these questions are designed to set.

Question 8

地铁站告示： 本站施工通知：A出口即日起关闭，预计关闭3周。B出口限高2米，禁止携带行李箱通行。C出口正常开放。如需无障碍通道，请走D出口（需绕行约5分钟）。

林先生需要通过无障碍通道出站，同时他携带了一个大行李箱。他应该走哪个出口，需要注意什么？

  1. 走B出口，因为B出口没有关闭，行李箱可以通过，只需注意限高2米的要求。
  2. 走C出口，因为C出口正常开放且没有限制，行李箱也可通过，且比D出口近。
  3. 走D出口，因为这是无障碍通道，符合他的需求，但需要注意绕行约5分钟，行李箱可以通过。 (correct answer)
  4. 走A出口，因为虽然在施工，但无障碍需求属于特殊情况，工作人员会协助他通过，行李箱也可携带。
Explanation: When reading signs or notices in Chinese, you need to identify all of a person's requirements and match them against all available options — not just the first one that seems to fit. 林先生 has two needs: (1) he requires an accessible (无障碍) passageway, and (2) he is carrying a large suitcase (大行李箱). The notice clearly states that 无障碍通道 is available at D出口, and while it requires an extra ~5 minutes of walking (绕行约5分钟), there is no restriction mentioned on luggage there. D出口 satisfies both requirements — making C the correct answer. Now let's look at why the other choices fail. A is wrong because B出口 is not an accessible route — it simply hasn't closed. More critically, B出口 prohibits carrying suitcases (禁止携带行李箱通行), so 林先生 couldn't even enter with his luggage. B suggests C出口, which is indeed normally open and has no stated luggage restrictions, but C出口 is not designated as an accessible route. If 林先生 needs 无障碍通道, a standard exit won't meet his mobility needs regardless of how convenient it seems. D suggests A出口, which is completely closed (关闭) — there are no exceptions mentioned for special circumstances, and assuming staff will make exceptions is not supported by the notice. As a study tip: Chinese public notices often contain multiple conditions. Always check that your chosen answer satisfies every stated requirement, not just the most obvious one. Distractors are designed to satisfy only one condition while failing another.

Question 9

图书馆借阅规则： 普通读者：最多借5本，借期14天，可续借一次（续借14天）。 会员读者：最多借10本，借期21天，可续借两次（每次21天）。 逾期罚款：每本每天¥0.5。 注：续借须在到期前3天内办理，且所借书目无人预约。

王同学是普通读者，3周前借了3本书，今天到期（第14天已过，现为第21天）。他想再续借这3本书，可以吗？

  1. 可以续借，因为普通读者可续借一次，他今天办理续借手续即可，续借后再借14天。
  2. 不可以续借，因为续借须在到期前3天内办理，他已经逾期7天（第14天到期，现第21天），错过了续借窗口。 (correct answer)
  3. 可以续借，因为虽然已过14天，但只要在第28天（两倍借期）前办理，图书馆通常允许续借，且须补交逾期罚款。
  4. 不可以续借，因为普通读者借期只有14天，21天已超过借期，且超过了会员的21天借期上限，因此不符合续借条件。
Explanation: When a question gives you a set of rules with multiple conditions, your job is to check every condition — not just the most obvious one. Here, the library rules contain a hidden timing requirement that changes everything. The borrowing rule for regular readers states that renewals must be processed within 3 days before the due date. Wang's due date was Day 14. That means the renewal window was Days 11–14. Today is Day 21 — he's already 7 days past due. The renewal window has closed, making B the correct answer. He didn't just miss the deadline; he missed it by a full week. Choice A focuses only on the fact that regular readers are allowed one renewal, which is true — but it completely ignores the timing condition. Being eligible for renewal and being within the window to request it are two different things. A is the classic trap of finding a rule that sounds right and stopping too early. Choice C invents a "double borrowing period" grace window (28 days) that doesn't exist anywhere in the rules. Never add conditions the passage doesn't state — this is a reading comprehension test, not a guess-what-the-library-might-do test. Choice D's reasoning is flawed in a different way: it compares Wang's situation against the member borrowing period (21 days) as if that's a universal cap. Regular readers and members have separate rules; member limits don't restrict regular readers. Study tip: On rules-based reading questions, build a checklist from every condition stated. A single failed condition can invalidate an otherwise eligible action — always read to the end of the rule.

Question 10

社区通知： 本周六上午10:00将举行社区清洁活动，欢迎居民参加。参与者请在9:45前到达社区广场签到。活动结束后将提供免费午餐（限参与签到的居民）。如遇雨天，活动顺延至下周同一时间。本次活动不接受12岁以下儿童单独参与，须由家长陪同。

陈阿姨想带她10岁的孙子小明一起参加活动。她们在上午10:05到达广场。关于他们参与活动和免费午餐资格，下列说法最准确的是？

  1. 两人都可以参加活动，但因为10:05已过签到时间9:45，两人都无法获得免费午餐资格。
  2. 陈阿姨可以参加活动，小明因未满12岁不可参加，陈阿姨因迟到也无法获得免费午餐资格。
  3. 两人均可参加活动，陈阿姨陪同满足小明的参与条件；陈阿姨因签到截止时间已过无法获得午餐，但小明作为12岁以下儿童属于特殊情况，仍可获得免费午餐。
  4. 小明因未满12岁不可单独参与，但有家长陈阿姨陪同，因此两人均可参加；但两人因10:05错过9:45签到截止时间，均不能获得免费午餐。 (correct answer)
Explanation: When a passage contains multiple conditions, your job is to apply all of them carefully — missing even one changes everything. Here, you need to track two rules simultaneously: the age/accompaniment rule and the sign-in deadline for lunch eligibility. Let's work through the passage systematically. The notice says children under 12 cannot participate alone — they must be accompanied by a parent (家长陪同). Critically, it does not say children under 12 are banned entirely. Since 陈阿姨 is accompanying 小明, his participation is permitted. So both can join the activity. Now for lunch: the free meal is limited to residents who completed sign-in (签到), and sign-in closes at 9:45. They arrived at 10:05 — after the cutoff — meaning neither of them signed in on time. Therefore, neither qualifies for the free lunch. That reasoning confirms D as the correct answer. Choice A is partially right about the lunch issue but wrong to assume both can simply "participate" without acknowledging the under-12 rule — it glosses over why small 明 is even allowed there. Choice B incorrectly concludes that 小明 cannot participate at all, confusing "cannot participate alone" (不可单独参与) with "cannot participate under any circumstances." The notice permits attendance with a guardian. Choice C invents a special exemption for under-12 children regarding lunch — no such exception exists in the passage. This is a classic trap where students create rules the text never states. Your strategy: when a passage has eligibility conditions, list each condition separately and test every person against every rule. Don't stop after one condition matches — keep checking.