College Statistics Quiz: Null And Alternative Hypotheses
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Null And Alternative HypothesesQuestion 1 of 20

A dietitian wants to assess if a particular 4-week meal plan results in a change in cholesterol levels. The dietitian measures the cholesterol level of 30 subjects before the plan starts and again after the plan is completed. Let μd\mu_d represent the true mean of the differences in cholesterol levels, calculated as (levelbefore_{before} - levelafter_{after}). To find evidence of a reduction in cholesterol, what hypotheses should be tested?

H0:μd0H_0: \mu_d \le 0 and Ha:μd>0H_a: \mu_d > 0
H0:μbeforeμafter=0H_0: \mu_{before} - \mu_{after} = 0 and Ha:μbeforeμafter0H_a: \mu_{before} - \mu_{after} \neq 0
H0:μd=0H_0: \mu_d = 0 and Ha:μd<0H_a: \mu_d < 0
H0:μ1μ20H_0: \mu_1 - \mu_2 \le 0 and Ha:μ1μ2>0H_a: \mu_1 - \mu_2 > 0, treating 'before' and 'after' as independent groups.
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College Statistics Quiz

College Statistics Quiz: Null And Alternative Hypotheses

Practice Null And Alternative Hypotheses in College Statistics with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Null And Alternative Hypotheses, giving you a quick way to practice the rules, question types, and explanations that matter most for College Statistics.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A dietitian wants to assess if a particular 4-week meal plan results in a change in cholesterol levels. The dietitian measures the cholesterol level of 30 subjects before the plan starts and again after the plan is completed. Let μd\mu_d represent the true mean of the differences in cholesterol levels, calculated as (levelbefore_{before} - levelafter_{after}). To find evidence of a reduction in cholesterol, what hypotheses should be tested?

  1. H0:μd0H_0: \mu_d \le 0 and Ha:μd>0H_a: \mu_d > 0 (correct answer)
  2. H0:μbeforeμafter=0H_0: \mu_{before} - \mu_{after} = 0 and Ha:μbeforeμafter0H_a: \mu_{before} - \mu_{after} \neq 0
  3. H0:μd=0H_0: \mu_d = 0 and Ha:μd<0H_a: \mu_d < 0
  4. H0:μ1μ20H_0: \mu_1 - \mu_2 \le 0 and Ha:μ1μ2>0H_a: \mu_1 - \mu_2 > 0, treating 'before' and 'after' as independent groups.
Explanation: This is a paired-sample design, so the analysis should focus on the mean of the differences, μd\mu_d. A reduction in cholesterol means the 'after' level is lower than the 'before' level. Since the difference is defined as d=levelbeforelevelafterd = \text{level}_{before} - \text{level}_{after}, a reduction in cholesterol corresponds to a positive difference. The dietitian is looking for evidence of a reduction, so the alternative hypothesis is Ha:μd>0H_a: \mu_d > 0. The null hypothesis is that there is no reduction or an increase, H0:μd0H_0: \mu_d \le 0.

Question 2

A website manager knows that, on average, users used to spend 180 seconds on the homepage. After a major redesign, the manager wants to determine if the average time spent on the homepage has decreased. A random sample of user sessions is collected after the redesign. Let μ\mu be the true mean time users spend on the redesigned homepage. Which hypotheses should the manager test?

  1. H0:xˉ180H_0: \bar{x} \ge 180 and Ha:xˉ<180H_a: \bar{x} < 180
  2. H0:μ=180H_0: \mu = 180 and Ha:μ180H_a: \mu \neq 180
  3. H0:μ180H_0: \mu \le 180 and Ha:μ>180H_a: \mu > 180
  4. H0:μ180H_0: \mu \ge 180 and Ha:μ<180H_a: \mu < 180 (correct answer)
Explanation: When setting up hypothesis tests, you need to carefully translate the research question into statistical language. The manager wants to determine if the average time has decreased from the original 180 seconds, which means they're looking for evidence that the new mean is less than 180. The correct approach is option D: H0:μ180H_0: \mu \ge 180 and Ha:μ<180H_a: \mu < 180. The null hypothesis represents the status quo or "no change" scenario - that the redesign hasn't decreased time (users still spend at least 180 seconds). The alternative hypothesis captures what the manager hopes to prove - that the mean time is now less than 180 seconds. This is a one-tailed test because we're only interested in whether time decreased, not whether it changed in either direction. Option A incorrectly uses the sample mean (xˉ\bar{x}) instead of the population parameter (μ\mu) in the hypotheses. Hypotheses are always statements about population parameters, not sample statistics. Option B sets up a two-tailed test (μ180\mu \neq 180), which would be appropriate if the manager wanted to detect any change in either direction. However, the question specifically asks about a decrease. Option C has the hypotheses backwards. It would test whether time increased after the redesign, which is the opposite of what the manager wants to investigate. Study tip: Always match the alternative hypothesis to the research question's direction. "Decreased," "less than," or "reduced" calls for Ha:μ<valueH_a: \mu < \text{value}, while "increased" needs Ha:μ>valueH_a: \mu > \text{value}, and "changed" or "different" requires Ha:μvalueH_a: \mu \neq \text{value}.

Question 3

An agricultural scientist is comparing the mean yield of three different varieties of corn (A, B, and C). The scientist will conduct an Analysis of Variance (ANOVA) to determine if there is a difference in the true mean yields among the three varieties. Which of the following correctly states the null hypothesis (H0H_0) for this ANOVA test?

  1. H0:μA=μB=μCH_0: \mu_A = \mu_B = \mu_C (correct answer)
  2. H0:μAμBH_0: \mu_A \neq \mu_B or μBμC\mu_B \neq \mu_C or μAμC\mu_A \neq \mu_C
  3. H0:xˉA=xˉB=xˉCH_0: \bar{x}_A = \bar{x}_B = \bar{x}_C
  4. H0:H_0: The mean yield of at least one corn variety is different from the others.
Explanation: In ANOVA, the null hypothesis posits that there is no difference among the group means. For three groups with means μA\mu_A, μB\mu_B, and μC\mu_C, the null hypothesis is that all these population means are equal: H0:μA=μB=μCH_0: \mu_A = \mu_B = \mu_C. The alternative hypothesis (not asked for here) is that at least one mean is different from the others.

Question 4

To gain approval for a generic drug, a pharmaceutical company must provide evidence that its effect is equivalent to the brand-name drug. Equivalence is defined as the true mean difference in a key therapeutic metric (μgenericμbrand\mu_{generic} - \mu_{brand}) being within a small, clinically insignificant margin, Δ\Delta. The null hypothesis for an equivalence test is that the drugs are meaningfully different. Which pair of hypotheses correctly frames the test for equivalence?

  1. H0:μgenericμbrand=0H_0: \mu_{generic} - \mu_{brand} = 0 and Ha:μgenericμbrand0H_a: \mu_{generic} - \mu_{brand} \neq 0
  2. H0:μgenericμbrandΔH_0: |\mu_{generic} - \mu_{brand}| \ge \Delta and Ha:μgenericμbrand<ΔH_a: |\mu_{generic} - \mu_{brand}| < \Delta (correct answer)
  3. H0:μgenericμbrand<ΔH_0: |\mu_{generic} - \mu_{brand}| < \Delta and Ha:μgenericμbrandΔH_a: |\mu_{generic} - \mu_{brand}| \ge \Delta
  4. H0:μgenericμbrand=ΔH_0: \mu_{generic} - \mu_{brand} = \Delta and Ha:μgenericμbrandΔH_a: \mu_{generic} - \mu_{brand} \neq \Delta
Explanation: Equivalence testing reverses the standard hypothesis setup. The goal is to find evidence for equivalence, which means the alternative hypothesis should represent the state of equivalence. Equivalence is defined as the absolute difference in means being within a margin Δ\Delta, so Ha:μgenericμbrand<ΔH_a: |\mu_{generic} - \mu_{brand}| < \Delta. The null hypothesis represents the state of non-equivalence, meaning the absolute difference is greater than or equal to that margin, H0:μgenericμbrandΔH_0: |\mu_{generic} - \mu_{brand}| \ge \Delta. Rejecting the null provides evidence for equivalence.

Question 5

A market researcher is investigating whether there is an association between a consumer's age group (18-34, 35-54, 55+) and their primary method of grocery shopping (in-store, online pickup, online delivery). What are the null and alternative hypotheses for the most appropriate statistical test?

  1. H0:μ1=μ2=μ3H_0: \mu_1 = \mu_2 = \mu_3 and Ha:H_a: At least one mean is different.
  2. H0:H_0: There is no association between age group and primary shopping method. Ha:H_a: There is an association between age group and primary shopping method. (correct answer)
  3. H0:p1=p2=p3H_0: p_1 = p_2 = p_3 and Ha:H_a: At least one proportion is different.
  4. H0:H_0: There is a positive correlation between age and online shopping. Ha:H_a: There is no positive correlation between age and online shopping.
Explanation: The researcher is examining the relationship between two categorical variables (age group and shopping method). The appropriate test for this is a chi-squared test of independence. The null hypothesis for this test is that the two variables are independent (i.e., there is no association between them). The alternative hypothesis is that the variables are dependent (i.e., there is an association).

Question 6

A community activist claims that the median household income in a certain area is $60,000. An economist suspects this claim is too low. The economist knows that the income distribution in this area is heavily right-skewed. To test this suspicion, which set of hypotheses regarding a population parameter is most appropriate?

  1. H0:μ60,000H_0: \mu \le 60,000 and Ha:μ>60,000H_a: \mu > 60,000
  2. H0:M60,000H_0: M \le 60,000 and Ha:M>60,000H_a: M > 60,000 (correct answer)
  3. H0:M=60,000H_0: M = 60,000 and Ha:M60,000H_a: M \neq 60,000
  4. H0:sample median60,000H_0: \text{sample median} \le 60,000 and Ha:sample median>60,000H_a: \text{sample median} > 60,000
Explanation: Because the income distribution is heavily skewed, the median (M) is a more robust measure of central tendency than the mean (μ\mu). Therefore, the hypotheses should be about the population median. The economist suspects the claim of $60,000 is too low, meaning the research hypothesis is that the median is greater than $60,000. This becomes the alternative hypothesis: Ha:M>60,000H_a: M > 60,000. The null hypothesis is that the claim is correct or an overstatement: H0:M60,000H_0: M \le 60,000.

Question 7

A new, less expensive manufacturing process for a medical component is being evaluated. The critical characteristic is its strength. The new process will be adopted if it is not inferior to the old process. Inferiority is defined as the mean strength of new components (μnew\mu_{new}) being more than 2 units below the mean strength of old components (μold\mu_{old}). To gain regulatory approval, the manufacturer must present statistical evidence that the new process is not inferior. Which hypotheses should the manufacturer test?

  1. H0:μnewμold=2H_0: \mu_{new} - \mu_{old} = -2 and Ha:μnewμold2H_a: \mu_{new} - \mu_{old} \neq -2
  2. H0:μnewμold2H_0: \mu_{new} - \mu_{old} \ge -2 and Ha:μnewμold<2H_a: \mu_{new} - \mu_{old} < -2
  3. H0:μnewμold2H_0: \mu_{new} - \mu_{old} \le -2 and Ha:μnewμold>2H_a: \mu_{new} - \mu_{old} > -2 (correct answer)
  4. H0:μnewμold0H_0: \mu_{new} - \mu_{old} \ge 0 and Ha:μnewμold<0H_a: \mu_{new} - \mu_{old} < 0
Explanation: This is a non-inferiority test. The burden of proof is on demonstrating that the new process is not inferior. The 'undesirable' outcome, or the state of inferiority, is that the new mean strength is more than 2 units below the old mean, which translates to μnew<μold2\mu_{new} < \mu_{old} - 2, or μnewμold<2\mu_{new} - \mu_{old} < -2. In hypothesis testing, we seek to reject the null hypothesis. Therefore, the null hypothesis is set as the state of inferiority, H0:μnewμold2H_0: \mu_{new} - \mu_{old} \le -2. The alternative hypothesis, which represents the conclusion the manufacturer wishes to support (non-inferiority), is Ha:μnewμold>2H_a: \mu_{new} - \mu_{old} > -2.

Question 8

An automotive engineer is designing a piston ring. The manufacturing process is specified to produce rings with a diameter variance of no more than 0.03 mm2^2. The engineer suspects that a recent adjustment to the machinery has increased this variance, making the process less precise. A sample of rings is collected to test this suspicion. Let σ2\sigma^2 be the true variance of the diameter of rings produced by the adjusted machinery. What are the appropriate null and alternative hypotheses?

  1. H0:σ20.03H_0: \sigma^2 \le 0.03 and Ha:σ2>0.03H_a: \sigma^2 > 0.03 (correct answer)
  2. H0:μ0.03H_0: \mu \le \sqrt{0.03} and Ha:μ>0.03H_a: \mu > \sqrt{0.03}
  3. H0:s20.03H_0: s^2 \le 0.03 and Ha:s2>0.03H_a: s^2 > 0.03
  4. H0:σ2=0.03H_0: \sigma^2 = 0.03 and Ha:σ20.03H_a: \sigma^2 \neq 0.03
Explanation: The engineer's suspicion is that the variance has increased, so the research hypothesis is σ2>0.03\sigma^2 > 0.03. This becomes the alternative hypothesis (HaH_a). The null hypothesis (H0H_0) represents the condition that the specification is being met or exceeded in terms of precision (i.e., variance is not larger than specified) and includes the equality case. Therefore, H0:σ20.03H_0: \sigma^2 \le 0.03.

Question 9

A city claims that the proportion of its residents who use public transportation daily is 35%. A sociologist believes this figure is inaccurate and decides to test the claim by surveying a random sample of residents. Which statement correctly formulates the sociologist's alternative hypothesis (HaH_a)?

  1. HaH_a: The proportion of city residents in the sample who use public transportation is not equal to 0.35.
  2. HaH_a: The true proportion of city residents who use public transportation is not equal to 0.35. (correct answer)
  3. HaH_a: The true proportion of city residents who use public transportation is equal to 0.35.
  4. HaH_a: The sample proportion of city residents who use public transportation will be equal to the true proportion.
Explanation: The sociologist believes the city's claim is inaccurate, which suggests a difference in either direction (could be higher or lower). Therefore, the test is two-tailed. The alternative hypothesis reflects the researcher's belief and is a statement about the true population proportion (often denoted pp), not the sample proportion (p^\hat{p}). The correct verbal formulation is that the true proportion is not equal to the claimed value.

Question 10

A dietitian wants to assess if a particular 4-week meal plan results in a change in cholesterol levels. The dietitian measures the cholesterol level of 30 subjects before the plan starts and again after the plan is completed. Let μd\mu_d represent the true mean of the differences in cholesterol levels, calculated as (levelbefore_{before} - levelafter_{after}). To find evidence of a reduction in cholesterol, what hypotheses should be tested?

  1. H0:μd0H_0: \mu_d \le 0 and Ha:μd>0H_a: \mu_d > 0 (correct answer)
  2. H0:μbeforeμafter=0H_0: \mu_{before} - \mu_{after} = 0 and Ha:μbeforeμafter0H_a: \mu_{before} - \mu_{after} \neq 0
  3. H0:μd=0H_0: \mu_d = 0 and Ha:μd<0H_a: \mu_d < 0
  4. H0:μ1μ20H_0: \mu_1 - \mu_2 \le 0 and Ha:μ1μ2>0H_a: \mu_1 - \mu_2 > 0, treating 'before' and 'after' as independent groups.
Explanation: This is a paired-sample design, so the analysis should focus on the mean of the differences, μd\mu_d. A reduction in cholesterol means the 'after' level is lower than the 'before' level. Since the difference is defined as d=levelbeforelevelafterd = \text{level}_{before} - \text{level}_{after}, a reduction in cholesterol corresponds to a positive difference. The dietitian is looking for evidence of a reduction, so the alternative hypothesis is Ha:μd>0H_a: \mu_d > 0. The null hypothesis is that there is no reduction or an increase, H0:μd0H_0: \mu_d \le 0.

Question 11

A company claims that the mean lifetime of its light bulbs is at least 1,200 hours. A consumer advocacy group suspects this claim is an overstatement and that the true mean lifetime is less. The group tests a random sample of these bulbs and finds a sample mean lifetime of 1,180 hours. What are the appropriate null and alternative hypotheses for the consumer group's test?

  1. H0:μ1200H_0: \mu \ge 1200 and Ha:μ<1200H_a: \mu < 1200 (correct answer)
  2. H0:μ=1180H_0: \mu = 1180 and Ha:μ<1180H_a: \mu < 1180
  3. H0:μ1200H_0: \mu \ge 1200 and Ha:μ1200H_a: \mu \neq 1200
  4. H0:xˉ1200H_0: \bar{x} \ge 1200 and Ha:xˉ<1200H_a: \bar{x} < 1200
Explanation: Hypotheses are always stated about population parameters (like μ\mu), not sample statistics (like xˉ\bar{x}). The value of 1,180 hours is the sample mean, which is evidence, not part of the hypothesis itself. The consumer group is testing the company's claim. The group's suspicion is that the mean lifetime is less than 1,200 hours, which is the alternative hypothesis (Ha:μ<1200H_a: \mu < 1200). The null hypothesis is the company's claim that is being challenged, H0:μ1200H_0: \mu \ge 1200.

Question 12

A market researcher is investigating whether there is an association between a consumer's age group (18-34, 35-54, 55+) and their primary method of grocery shopping (in-store, online pickup, online delivery). What are the null and alternative hypotheses for the most appropriate statistical test?

  1. H0:μ1=μ2=μ3H_0: \mu_1 = \mu_2 = \mu_3 and Ha:H_a: At least one mean is different.
  2. H0:H_0: There is no association between age group and primary shopping method. Ha:H_a: There is an association between age group and primary shopping method. (correct answer)
  3. H0:p1=p2=p3H_0: p_1 = p_2 = p_3 and Ha:H_a: At least one proportion is different.
  4. H0:H_0: There is a positive correlation between age and online shopping. Ha:H_a: There is no positive correlation between age and online shopping.
Explanation: The researcher is examining the relationship between two categorical variables (age group and shopping method). The appropriate test for this is a chi-squared test of independence. The null hypothesis for this test is that the two variables are independent (i.e., there is no association between them). The alternative hypothesis is that the variables are dependent (i.e., there is an association).

Question 13

A researcher is studying a new cognitive therapy. To test its efficacy, the researcher randomly assigns patients with a specific condition to one of two groups: one receiving the new therapy and a control group receiving the standard therapy. The researcher wants to determine if the new therapy has any effect on a standardized measure of patient wellness compared to the standard therapy. Let μnew\mu_{new} and μstd\mu_{std} be the population mean wellness scores for the two groups. What are the null and alternative hypotheses?

  1. H0:μnewμstd0H_0: \mu_{new} - \mu_{std} \le 0 and Ha:μnewμstd>0H_a: \mu_{new} - \mu_{std} > 0
  2. H0:μnewμstd=0H_0: \mu_{new} - \mu_{std} = 0 and Ha:μnewμstd0H_a: \mu_{new} - \mu_{std} \neq 0 (correct answer)
  3. H0:H_0: The new therapy has a positive effect on wellness, and Ha:H_a: The new therapy has no effect or a negative effect.
  4. H0:xˉnewxˉstd=0H_0: \bar{x}_{new} - \bar{x}_{std} = 0 and Ha:xˉnewxˉstd0H_a: \bar{x}_{new} - \bar{x}_{std} \neq 0
Explanation: The researcher wants to know if the therapy has any effect, which could be positive or negative. This implies a non-directional, or two-tailed, test. The null hypothesis (H0H_0) is that there is no effect, meaning the mean wellness scores for the two groups are the same (μnew=μstd\mu_{new} = \mu_{std}, or μnewμstd=0\mu_{new} - \mu_{std} = 0). The alternative hypothesis (HaH_a) is that there is an effect, meaning the means are different (μnewμstd\mu_{new} \neq \mu_{std}, or μnewμstd0\mu_{new} - \mu_{std} \neq 0).

Question 14

Historically, the proportion of students passing a standardized exam at a certain university was 0.75. After the university implemented a new suite of academic support services, an administrator wants to determine if the passing proportion has changed. Let pp be the true proportion of students who pass the exam after the implementation of the new services. Which set of hypotheses is most appropriate for the administrator's investigation?

  1. H0:p=0.75H_0: p = 0.75 and Ha:p>0.75H_a: p > 0.75
  2. H0:p^=0.75H_0: \hat{p} = 0.75 and Ha:p^0.75H_a: \hat{p} \neq 0.75
  3. H0:p=0.75H_0: p = 0.75 and Ha:p0.75H_a: p \neq 0.75 (correct answer)
  4. H0:μ=0.75H_0: \mu = 0.75 and Ha:μ0.75H_a: \mu \neq 0.75
Explanation: The administrator wants to know if the proportion has changed, which does not imply a specific direction (increase or decrease). This indicates a two-tailed test. The hypotheses must be about the population parameter pp, not the sample statistic p^\hat{p}. The null hypothesis states that there is no change from the historical value, H0:p=0.75H_0: p = 0.75. The alternative hypothesis states that there is a change, Ha:p0.75H_a: p \neq 0.75.

Question 15

An agricultural scientist is comparing the mean yield of three different varieties of corn (A, B, and C). The scientist will conduct an Analysis of Variance (ANOVA) to determine if there is a difference in the true mean yields among the three varieties. Which of the following correctly states the null hypothesis (H0H_0) for this ANOVA test?

  1. H0:μA=μB=μCH_0: \mu_A = \mu_B = \mu_C (correct answer)
  2. H0:μAμBH_0: \mu_A \neq \mu_B or μBμC\mu_B \neq \mu_C or μAμC\mu_A \neq \mu_C
  3. H0:xˉA=xˉB=xˉCH_0: \bar{x}_A = \bar{x}_B = \bar{x}_C
  4. H0:H_0: The mean yield of at least one corn variety is different from the others.
Explanation: In ANOVA, the null hypothesis posits that there is no difference among the group means. For three groups with means μA\mu_A, μB\mu_B, and μC\mu_C, the null hypothesis is that all these population means are equal: H0:μA=μB=μCH_0: \mu_A = \mu_B = \mu_C. The alternative hypothesis (not asked for here) is that at least one mean is different from the others.

Question 16

A pharmaceutical company has developed a new drug to reduce recovery time from a certain illness. The standard drug has a mean recovery time of 8 days. The company will only market the new drug if it can demonstrate with strong evidence that its new drug's mean recovery time is shorter than the standard drug. Let μnew\mu_{new} represent the true mean recovery time for the new drug. Which of the following are the correct null and alternative hypotheses for the company's clinical trial?

  1. H0:μnew8H_0: \mu_{new} \ge 8 and Ha:μnew<8H_a: \mu_{new} < 8 (correct answer)
  2. H0:μnew=8H_0: \mu_{new} = 8 and Ha:μnew8H_a: \mu_{new} \neq 8
  3. H0:xˉnew8H_0: \bar{x}_{new} \ge 8 and Ha:xˉnew<8H_a: \bar{x}_{new} < 8
  4. H0:μnew8H_0: \mu_{new} \le 8 and Ha:μnew>8H_a: \mu_{new} > 8
Explanation: The company wants to find evidence that the new drug's recovery time is shorter than the standard 8 days. This is the research claim and becomes the alternative hypothesis (Ha:μnew<8H_a: \mu_{new} < 8). The null hypothesis (H0H_0) represents the status quo or the situation of no improvement, and it must contain the condition of equality. Therefore, the null hypothesis is that the mean recovery time is greater than or equal to 8 days (H0:μnew8H_0: \mu_{new} \ge 8).

Question 17

An economist is using simple linear regression to study the effect of interest rates (x) on the monthly number of new housing starts (y). The economist wants to determine if there is sufficient evidence to conclude that higher interest rates are associated with a decrease in housing starts. Let β1\beta_1 represent the slope of the population regression line. What are the null and alternative hypotheses for this study?

  1. H0:β1=0H_0: \beta_1 = 0 and Ha:β10H_a: \beta_1 \neq 0
  2. H0:β10H_0: \beta_1 \ge 0 and Ha:β1<0H_a: \beta_1 < 0 (correct answer)
  3. H0:b10H_0: b_1 \ge 0 and Ha:b1<0H_a: b_1 < 0
  4. H0:ρ0H_0: \rho \ge 0 and Ha:ρ<0H_a: \rho < 0
Explanation: The economist is testing for a specific directional relationship: that higher interest rates lead to a decrease in housing starts. In a regression context, this corresponds to a negative slope. The research hypothesis is therefore that the population slope β1\beta_1 is less than 0. This becomes the alternative hypothesis (Ha:β1<0H_a: \beta_1 < 0). The null hypothesis states that there is no negative relationship (i.e., the slope is zero or positive), so H0:β10H_0: \beta_1 \ge 0.

Question 18

A federal agency sets a guideline that the mean concentration of a certain chemical in industrial wastewater should not exceed 50 parts per million (ppm). The agency conducts regular inspections to find evidence of companies that are in violation of this guideline. When the agency inspects a particular plant, what null and alternative hypotheses should its investigators use?

  1. H0:μ=50H_0: \mu = 50 and Ha:μ50H_a: \mu \neq 50
  2. H0:μ50H_0: \mu \ge 50 and Ha:μ<50H_a: \mu < 50
  3. H0:μ50H_0: \mu \le 50 and Ha:μ>50H_a: \mu > 50 (correct answer)
  4. Ha:μ50H_a: \mu \le 50 and H0:μ>50H_0: \mu > 50
Explanation: The agency is looking for evidence of a violation. A violation occurs if the mean concentration μ\mu is greater than the 50 ppm limit. This is the condition the agency seeks to prove, so it becomes the alternative hypothesis: Ha:μ>50H_a: \mu > 50. The null hypothesis represents the state of compliance with the guideline, which is that the mean concentration is less than or equal to the limit: H0:μ50H_0: \mu \le 50. The burden of proof is on the agency to show that the plant is out of compliance.

Question 19

A researcher is studying the correlation between the number of hours a student studies per week and their grade point average (GPA). The researcher wants to determine if there is any statistically significant linear relationship between these two variables, but has no prior belief about whether the relationship is positive or negative. Let ρ\rho be the population correlation coefficient. Which are the appropriate hypotheses?

  1. H0:ρ=0H_0: \rho = 0 and Ha:ρ0H_a: \rho \neq 0 (correct answer)
  2. H0:r=0H_0: r = 0 and Ha:r0H_a: r \neq 0
  3. H0:ρ0H_0: \rho \le 0 and Ha:ρ>0H_a: \rho > 0
  4. H0:β1=0H_0: \beta_1 = 0 and Ha:β10H_a: \beta_1 \neq 0
Explanation: The researcher is testing for any linear relationship, without specifying a direction. This calls for a two-tailed test. The parameter for population correlation is ρ\rho. The null hypothesis for a correlation test is that there is no linear relationship, which corresponds to ρ=0\rho = 0. The alternative hypothesis is that there is some linear relationship, meaning ρ0\rho \neq 0.

Question 20

A researcher sets up the hypotheses H0:μ=50H_0: \mu = 50 and Ha:μ>50H_a: \mu > 50. After collecting data from a sample of 40 individuals, the researcher calculates a sample mean of xˉ=53\bar{x} = 53. Which of the following statements is a correct interpretation of the role of the hypotheses?

  1. The hypotheses are a test of whether the observed sample mean xˉ=53\bar{x}=53 is significantly larger than 50.
  2. Given that xˉ=53\bar{x} = 53, the alternative hypothesis should be updated to Ha:μ>53H_a: \mu > 53 for the test.
  3. The null hypothesis H0:μ=50H_0: \mu = 50 is a statement that the sample mean will be exactly 50.
  4. The hypotheses are a test of whether the true population mean μ\mu is greater than the hypothesized value of 50. (correct answer)
Explanation: When you encounter hypothesis testing questions, remember that hypotheses are always statements about population parameters, not sample statistics. The entire framework is designed to make inferences about unknown population values based on sample evidence. The correct answer is D because hypothesis tests are fundamentally about determining whether there's sufficient evidence to conclude that a population parameter (like μ\mu) differs from a hypothesized value. Here, you're testing whether the true population mean is greater than 50, using the sample mean of 53 as evidence. Let's examine why the other options miss the mark: Option A incorrectly focuses on testing the sample mean itself. The sample mean xˉ=53\bar{x} = 53 is an observed fact from your data—there's nothing to "test" about it. You use this sample statistic to make inferences about the unknown population mean. Option B reflects a fundamental misunderstanding of hypothesis testing. You establish your hypotheses before collecting data, not after. The hypotheses represent competing claims about the population parameter, and changing them based on your sample results would invalidate the entire testing procedure. Option C confuses the null hypothesis's meaning. H0:μ=50H_0: \mu = 50 claims the population mean equals 50, not that your sample mean will be exactly 50. In fact, you expect some sampling variability—your sample mean will likely differ from 50 even if the null hypothesis is true. Key takeaway: Always remember that hypothesis tests make claims about population parameters (μ\mu, pp, etc.), not sample statistics (xˉ\bar{x}, p^\hat{p}, etc.). The sample data serves as evidence for or against these population-level claims.