College Physics Quiz: Magnetic Fields Of Current Carrying Wires

15 questions · exam conditions

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Magnetic Fields Of Current Carrying WiresQuestion 1 of 15

A triangular current loop lies in the xy-plane with vertices at $(0,0)$ , $(a,0)$ , and $(0,a)$ . Current $I$ flows around the perimeter in the counterclockwise direction. Using the Biot-Savart law, which statement about the magnetic field at the origin is correct?

The magnetic field is zero because the origin is at a vertex of the triangle

Only the hypotenuse contributes to the magnetic field at the origin since the other two sides pass through the origin

All three sides contribute equally to the magnetic field magnitude at the origin

The magnetic field points in the +z direction with magnitude

\frac{\mu_0 I}{4\pi a}(\sqrt{2} - 2)

The magnetic field points in the -z direction with magnitude

\frac{\mu_0 I}{2\pi a}

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College Physics Quiz: Magnetic Fields Of Current Carrying Wires

Practice Magnetic Fields Of Current Carrying Wires in College Physics with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

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This quiz focuses on Magnetic Fields Of Current Carrying Wires, giving you a quick way to practice the rules, question types, and explanations that matter most for College Physics.

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Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

The magnetic field is zero because the origin is at a vertex of the triangle
Only the hypotenuse contributes to the magnetic field at the origin since the other two sides pass through the origin (correct answer)
All three sides contribute equally to the magnetic field magnitude at the origin
The magnetic field points in the +z direction with magnitude $\frac{\mu_0 I}{4\pi a}(\sqrt{2} - 2)$
The magnetic field points in the -z direction with magnitude $\frac{\mu_0 I}{2\pi a}$

Explanation: When applying the Biot-Savart law to current loops, you must carefully consider the geometry of each current segment relative to the field point. The Biot-Savart law states that

d\vec{B} = \frac{\mu_0 I}{4\pi} \frac{d\vec{l} \times \vec{r}}{r^3}

, where

d\vec{l}

is the current element and

\vec{r}

is the vector from the current element to the field point. For this triangular loop, let's examine each side's contribution to the magnetic field at the origin. The two sides along the x and y axes both pass directly through the origin. This creates a critical geometric issue: for any current element on these sides, the vector

\vec{r}

pointing from that element to the origin has zero magnitude when the element is at the origin itself. More importantly, the current direction

d\vec{l}

and position vector

\vec{r}

are either parallel or antiparallel along these sides, making their cross product zero. Therefore, these two sides contribute nothing to the magnetic field at the origin. Only the hypotenuse connecting

(a,0)

(0,a)

contributes to the field, as it maintains a non-zero distance from the origin and the current direction is neither parallel nor antiparallel to the position vectors from its elements to the origin. Answer B correctly identifies this geometric relationship. Answer A incorrectly assumes vertex location automatically means zero field. Answer C wrongly claims equal contributions from all sides. Answer D provides a specific calculation that doesn't match the actual geometry. Study tip: When using Biot-Savart law, always check if current segments pass through or are aligned with the field point—these contribute zero to the magnetic field.

Question 2

Two identical circular current loops of radius $R$ are positioned with their centers on the z-axis at $z = +d/2$ and $z = -d/2$ , both carrying current $I$ in the same direction. Using the Biot-Savart law results for single loops, the magnetic field at the origin (midpoint between loops) is:

$\frac{\mu_0 I R^2}{(R^2 + d^2/4)^{3/2}}$ (correct answer)
$\frac{\mu_0 I R^2}{2(R^2 + d^2/4)^{3/2}}$
$\frac{\mu_0 I R^2}{(R^2 + d^2/4)^{1/2}}$
Zero, because the fields from the two loops cancel at the midpoint
$\frac{2\mu_0 I R^2}{(R^2 + d^2/4)^{3/2}}$

Explanation: When you encounter problems involving multiple current-carrying loops, the key principle is superposition: the total magnetic field equals the vector sum of fields from individual loops. Since both loops carry current in the same direction and the setup is symmetric, their fields will add constructively at the origin. For a single circular loop of radius

R

carrying current

I

, the magnetic field at a distance

z

along its axis is given by the Biot-Savart result:

\vec{B} = \frac{\mu_0 I R^2}{2(R^2 + z^2)^{3/2}}\hat{z}

. Each loop in this problem is at distance

z = d/2

from the origin, so each contributes

\frac{\mu_0 I R^2}{2(R^2 + d^2/4)^{3/2}}

to the field at the origin. Since both fields point in the same direction (both loops have the same current direction), you add them:

B_{total} = 2 \times \frac{\mu_0 I R^2}{2(R^2 + d^2/4)^{3/2}} = \frac{\mu_0 I R^2}{(R^2 + d^2/4)^{3/2}}

, confirming answer A. Answer B gives only half the correct result—this would be the contribution from just one loop. Answer C has the wrong exponent (1/2 instead of 3/2), suggesting confusion about the Biot-Savart formula. Answer D incorrectly assumes cancellation; fields only cancel when currents flow in opposite directions. Remember: when currents in symmetric arrangements flow the same way, their magnetic fields add; when they flow opposite ways, they subtract. Always check the current directions carefully in multi-loop problems.

Question 3

A finite straight wire of length $2L$ carries current $I$ and is centered at the origin along the y-axis, extending from $y = -L$ to $y = +L$ . Using the Biot-Savart law, what is the direction of the magnetic field at a point on the positive x-axis?

In the positive x-direction, parallel to the position vector
In the negative y-direction, opposite to the current direction
In the positive z-direction, perpendicular to both the current and position vector (correct answer)
In the negative z-direction, following the left-hand rule for the cross product
The magnetic field is zero at all points on the x-axis due to symmetry

Explanation: When you encounter a Biot-Savart law problem, visualize the geometry carefully and apply the right-hand rule systematically. The Biot-Savart law states that

d\vec{B} = \frac{\mu_0 I}{4\pi} \frac{d\vec{l} \times \vec{r}}{r^3}

, where the magnetic field depends on the cross product of the current element and position vector. Here, current flows along the y-axis from

y = -L

y = +L

, so

d\vec{l}

points in the

+\hat{y}

direction. At any point on the positive x-axis, the position vector

\vec{r}

points from current elements toward your observation point in the

+\hat{x}

direction. Using the right-hand rule for

d\vec{l} \times \vec{r}

: point your fingers along

+\hat{y}

(current direction), curl them toward

+\hat{x}

(position vector), and your thumb points in the

+\hat{z}

direction. Since this cross product direction is consistent for all current elements along the wire, the total magnetic field points in the

+\hat{z}

direction. Option A is wrong because the magnetic field is never parallel to the position vector in Biot-Savart problems—it's always perpendicular due to the cross product. Option B incorrectly suggests the field aligns with coordinate directions related to the current, ignoring the cross product geometry. Option D mentions the "left-hand rule," but electromagnetism consistently uses the right-hand rule for cross products. Study tip: Always sketch the geometry first, then apply the right-hand rule methodically to

d\vec{l} \times \vec{r}

for each current element. The magnetic field is always perpendicular to both the current and position vector.

Question 4

A long straight wire carries current $I$ in the +z direction. A small current loop in the xy-plane carries current $i$ and is located at distance $r$ from the wire. The magnetic field from the straight wire will exert a net force on the current loop only if:

the current loop has a magnetic dipole moment component parallel to the wire's magnetic field
the current loop is positioned such that the wire's magnetic field is non-uniform across the loop's area (correct answer)
the currents $I$ and $i$ flow in the same rotational sense when viewed along the +z direction
the current loop has the same current magnitude as the straight wire ( $i = I$ )
the current loop is oriented perpendicular to the magnetic field lines from the straight wire

Explanation: When analyzing forces between current-carrying conductors, the key principle is that a net force exists only when the magnetic field varies in strength or direction across the object experiencing the force. A straight wire carrying current

I

creates a circular magnetic field around it with strength

B = \frac{\mu_0 I}{2\pi d}

, where

d

is the distance from the wire. This field decreases with distance from the wire. For a net force to act on the current loop, different parts of the loop must experience different magnetic field strengths - this creates an imbalance that produces a net force. Option B correctly identifies this requirement: the wire's magnetic field must be non-uniform across the loop's area. Option A incorrectly focuses on the dipole moment's orientation. While this affects the torque on the loop, it doesn't determine whether a net force exists. A uniform field can exert torque without producing net force. Option C suggests the relative direction of currents matters for net force. However, current direction affects whether the force is attractive or repulsive, not whether a net force exists at all. Even opposite currents can produce net forces if the field is non-uniform. Option D incorrectly implies that equal current magnitudes are necessary for net force. The force magnitude depends on the field gradient and loop current, but there's no requirement for

i = I

. Remember this pattern: uniform fields create torques but no net forces, while non-uniform fields can create both. When you see questions about net forces on extended objects in magnetic fields, always look for field uniformity as the deciding factor.

Question 5

A solenoid with $N$ turns, length $L$ , and radius $R$ carries current $I$ . The magnetic field inside a long solenoid is approximately uniform and given by $B = \mu_0 nI$ where $n = N/L$ . This result can be derived from the Biot-Savart law by treating the solenoid as a collection of current loops. Which assumption is most critical for this approximation to be valid?

The current in each turn must be exactly the same throughout the solenoid
The radius $R$ must be much smaller than the length $L$ of the solenoid (correct answer)
The turns must be wound with zero spacing between adjacent loops
The magnetic permeability of the core material must equal $\mu_0$
The number of turns $N$ must be much greater than unity

Explanation: When analyzing solenoid magnetic fields, you're dealing with an idealized approximation that requires specific geometric conditions to be valid. The key insight is understanding what "long solenoid" means and why this geometry matters. The uniform field formula

B = \mu_0 nI

assumes the solenoid is infinitely long, which eliminates edge effects where field lines curve outward at the ends. For a real solenoid to approximate this behavior, the length must be much greater than the radius (

L \gg R

). This ensures that inside the solenoid, far from the ends, the field lines run parallel to the axis and the field is approximately uniform. Option B correctly identifies this critical geometric requirement. When

L \gg R

, the interior region experiences the idealized uniform field, and edge effects become negligible compared to the solenoid's total length. Option A is incorrect because while current consistency is practically important, small variations don't invalidate the fundamental approximation—you can still apply the formula with average current values. Option C is wrong because the formula works for any reasonable turn spacing; the turns per unit length

n

already accounts for spacing in the calculation. Option D is incorrect because

\mu_0

specifically represents the permeability of free space (vacuum/air core)—if you had a different core material, you'd use that material's permeability instead. Remember: solenoid problems often test whether you understand the "long solenoid approximation." Always check if

L \gg R

when applying the uniform field formula, as this geometric condition is what makes the idealized solution valid.

Question 6

A helical coil (solenoid) with $n$ turns per unit length and radius $R$ carries current $I$ . A student wants to use the Biot-Savart law to derive the field inside the solenoid by modeling it as a collection of circular current loops. Which mathematical technique is essential for this derivation?

Integration over the azimuthal angle to sum contributions from different parts of each circular loop
Integration along the solenoid axis to sum contributions from all the circular loops at different positions (correct answer)
Differentiation to find the field gradient required for determining the force on moving charges
Application of Gauss's law for magnetism to constrain the possible field configurations
Use of complex exponentials to handle the helical geometry of the current path

Explanation: When applying the Biot-Savart law to find the magnetic field inside a solenoid, you're essentially treating the solenoid as a collection of many circular current loops stacked along the axis. Each loop contributes to the total field at any point inside the solenoid, and these contributions must be summed up mathematically. The correct approach requires integration along the solenoid axis (answer B). Here's why: each circular loop at position

z

along the axis contributes a field component at your point of interest. Since the solenoid has

n

turns per unit length, a small segment

dz

contains

n \cdot dz

loops, each carrying current

I

. You integrate these contributions over the entire length of the solenoid to get the total field. Let's examine why the other options miss the mark: A is incorrect because the azimuthal integration around each individual loop is handled when you first derive the field of a single circular loop—that's already built into the Biot-Savart formula for one loop. C is wrong because differentiation finds field gradients, which isn't needed for determining the basic field magnitude inside the solenoid using Biot-Savart law. D is incorrect because while Gauss's law for magnetism (

\nabla \cdot \mathbf{B} = 0

) is always true, it doesn't provide the computational technique needed for this Biot-Savart derivation. Study tip: When using Biot-Savart law for extended current distributions like solenoids, always identify what you're summing over—here it's the axial positions of individual current loops, requiring integration along the solenoid's length.

Question 7

Two infinite parallel wires carry currents $I_1 = 2.0$ A and $I_2 = 6.0$ A in the same direction, separated by distance $d = 0.10$ m. Using the principle of superposition with the Biot-Savart law results, at what distance from the wire carrying $I_1$ is the magnetic field strength minimized?

$0.025$ m, between the two wires (correct answer)
$0.050$ m, between the two wires
$0.033$ m, between the two wires
The field strength is never minimized; it only has a maximum between the wires
$0.075$ m, between the two wires

Explanation: When dealing with magnetic fields from multiple current-carrying wires, you need to apply the principle of superposition: the total magnetic field is the vector sum of individual fields from each wire. For an infinite straight wire, the magnetic field at distance

r

B = \frac{\mu_0 I}{2\pi r}

. Since both currents flow in the same direction, their magnetic fields point in opposite directions in the region between the wires. The field will be minimized (approaching zero) where these opposing fields nearly cancel each other. Let's say the minimum occurs at distance

x

from wire 1, so it's distance

(d-x) = (0.10-x)

from wire 2. At the minimum:

\frac{\mu_0 I_1}{2\pi x} = \frac{\mu_0 I_2}{2\pi (d-x)}

Simplifying:

\frac{I_1}{x} = \frac{I_2}{d-x}

Cross-multiplying:

I_1(d-x) = I_2 x

, so

I_1 d = x(I_1 + I_2)

Therefore:

x = \frac{I_1 d}{I_1 + I_2} = \frac{2.0 \times 0.10}{2.0 + 6.0} = \frac{0.20}{8.0} = 0.025

m Choice A is correct: the field is minimized at 0.025 m from wire 1, between the wires. Choice B (0.050 m) would be the midpoint, which ignores the different current magnitudes. Choice C (0.033 m) might result from incorrectly using ratios. Choice D is wrong because fields from parallel currents in the same direction do create a minimum between them where they nearly cancel. Strategy tip: For parallel wires with same-direction currents, the minimum always occurs between them, closer to the wire with smaller current. The exact position depends on the current ratio, not geometry alone.

Question 8

A square current loop with side length $a$ lies in the xy-plane with one corner at the origin and sides along the positive x and y axes. Current $I$ flows counterclockwise. Using the Biot-Savart law, a student calculates the magnetic field at point $(a/2, a/2, h)$ where $h \gg a$ . Which approximation is most appropriate for this calculation?

Treat the loop as a magnetic dipole and use the far-field dipole formula (correct answer)
Use the exact Biot-Savart integral since no approximations are valid when $h \gg a$
Treat each side as an infinite straight wire since $h$ is much larger than the side length
Ignore contributions from all sides except the one closest to the observation point
Set the magnetic field to zero because the observation point is too far from the current loop

Explanation: When calculating magnetic fields from current loops at distances much larger than the loop dimensions, you need to recognize when approximation methods become both valid and practical. Since the observation point is at distance

h \gg a

from the loop, you're in the far-field regime where the magnetic dipole approximation becomes highly accurate. At large distances, any current loop—regardless of its specific shape—behaves like a point magnetic dipole with moment

\vec{m} = IA\hat{n}

, where

A = a^2

is the loop area and

\hat{n}

points along the loop's normal (positive z-direction for counterclockwise current). The far-field dipole formula

\vec{B} = \frac{\mu_0}{4\pi r^3}[3(\vec{m} \cdot \hat{r})\hat{r} - \vec{m}]

gives excellent accuracy when

r \gg a

, making option A correct. Option B is wrong because approximations are not only valid but essential—the exact Biot-Savart calculation would be unnecessarily complex and wouldn't provide additional insight in the far field. Option C incorrectly suggests treating sides as infinite wires; this approximation fails because infinite wires don't account for the loop's finite geometry, which determines the dipole moment. Option D makes no physical sense—all four sides contribute equally to the magnetic dipole moment, and ignoring three of them would give a completely incorrect result. Remember: when

r \gg

characteristic size of current distribution, always consider the magnetic dipole approximation first. It's both mathematically simpler and physically insightful for far-field problems.

Question 9

Two students use the Biot-Savart law to calculate magnetic fields, but they disagree about the coordinate system. Student A places the current element $d\vec{l}$ at the origin and measures $\vec{r}$ to the field point. Student B places the field point at the origin and measures $\vec{r}$ from the current element. Which approach gives the correct magnetic field direction?

Only Student A's approach is correct because $\vec{r}$ must point away from the current element (correct answer)
Only Student B's approach is correct because the field point should be at the origin by convention
Both approaches are correct if they consistently apply $d\vec{l} \times \vec{r}$ with their chosen coordinate system
Neither approach is correct because $\vec{r}$ should always point from the field point to the current element
Both approaches give the same magnitude but opposite directions, so the results must be averaged

Explanation: When working with the Biot-Savart law, the precise definition of the position vector

\vec{r}

is crucial for getting the correct magnetic field direction. The law states that

d\vec{B} = \frac{\mu_0 I}{4\pi} \frac{d\vec{l} \times \vec{r}}{r^3}

, where

\vec{r}

must point from the current element to the field point where you're calculating the magnetic field. Student A's approach is correct because they properly define

\vec{r}

as pointing away from the current element (at the origin) toward the field point. This matches the standard formulation of the Biot-Savart law and ensures the cross product

d\vec{l} \times \vec{r}

gives the right direction according to the right-hand rule. Looking at why the other options fail: Option B incorrectly suggests that convention requires the field point at the origin, but physics laws don't depend on arbitrary coordinate choices—what matters is the relative direction of

\vec{r}

. Option C might seem reasonable since coordinate systems are flexible, but Student B's setup reverses

\vec{r}

's direction, which would flip the magnetic field direction by 180°—this isn't just a coordinate choice but a fundamental error. Option D has the direction completely backward;

\vec{r}

should point toward the field point, not away from it. Remember this pattern: in the Biot-Savart law,

\vec{r}

always points from the source (current element) to where you're measuring the effect (field point). This source-to-field convention appears throughout electromagnetism, so mastering it here will help with Coulomb's law and other field calculations.

Question 10

A straight wire carrying current $I$ is bent into an L-shape, with one segment of length $L_1$ along the x-axis and another segment of length $L_2$ along the y-axis, meeting at the origin. Using the Biot-Savart law, which statement best describes the magnetic field at a point P located at distance $d$ along the positive z-axis?

The magnetic field has components in both the x and y directions, with magnitudes proportional to $L_1$ and $L_2$ respectively (correct answer)
The magnetic field is zero because the two segments produce fields that cancel each other exactly
The magnetic field has only a z-component because both segments contribute fields perpendicular to the z-axis
The magnetic field is parallel to the xy-plane and makes a 45° angle with both axes regardless of the values of $L_1$ and $L_2$
The magnetic field has equal x and y components only when $L_1 = L_2$ , otherwise it is purely in one direction

Explanation: When analyzing magnetic fields from current-carrying wires using the Biot-Savart law, you need to consider how each segment contributes to the field and apply vector addition. The key insight is that

d\vec{B} = \frac{\mu_0 I}{4\pi} \frac{d\vec{l} \times \vec{r}}{r^3}

, where the cross product determines the field direction. For the L-shaped wire, each segment produces a magnetic field at point P on the positive z-axis. The segment along the x-axis (length

L_1

) creates a field component in the y-direction, while the segment along the y-axis (length

L_2

) creates a field component in the x-direction. This happens because the cross product

d\vec{l} \times \vec{r}

for each segment points perpendicular to both the current element and the position vector. The magnitudes of these components are indeed proportional to

L_1

and

L_2

respectively, since longer segments contribute more current elements to the integral. Choice B is incorrect because there's no symmetry that would cause exact cancellation—the segments are perpendicular, not parallel and opposite. Choice C misunderstands the geometry; both segments actually produce fields that lie in the xy-plane (perpendicular to z), not along z. Choice D is wrong because the angle depends on the ratio of field components, which depends on

L_1

and

L_2

—only when

L_1 = L_2

would you get a 45° angle. Remember: in Biot-Savart problems, always visualize the cross product

d\vec{l} \times \vec{r}

for each current element to determine field directions, then add vectorially.

Question 11

Using the Biot-Savart law, a student calculates the magnetic field at point P due to a straight wire segment of length $L$ carrying current $I$ . The wire extends from $z = -L/2$ to $z = +L/2$ along the z-axis, and point P is at coordinates $(a, 0, 0)$ . Which expression correctly represents the z-component of the magnetic field at P?

$B_z = \frac{\mu_0 I L}{4\pi a^2}$
$B_z = \frac{\mu_0 I}{4\pi a} \ln\left(\frac{L + \sqrt{L^2 + 4a^2}}{L - \sqrt{L^2 + 4a^2}}\right)$
$B_z = 0$ (correct answer)
$B_z = \frac{\mu_0 I L}{4\pi (a^2 + L^2/4)^{3/2}}$
$B_z = \frac{\mu_0 I}{2\pi a}$

Explanation: When applying the Biot-Savart law to find magnetic fields, you must carefully consider the geometry and use vector analysis to determine each component of the resulting field. The Biot-Savart law states that

d\vec{B} = \frac{\mu_0 I}{4\pi} \frac{d\vec{l} \times \vec{r}}{r^3}

, where

d\vec{l}

is along the current direction and

\vec{r}

points from the current element to the field point. Here, the current flows along the z-axis (

d\vec{l} = dz \hat{z}

) and point P is at

(a, 0, 0)

. For any current element at position

(0, 0, z)

, the vector

\vec{r} = a\hat{x} - z\hat{z}

. The cross product

d\vec{l} \times \vec{r} = dz \hat{z} \times (a\hat{x} - z\hat{z}) = a \cdot dz(\hat{z} \times \hat{x}) = -a \cdot dz \hat{y}

points entirely in the y-direction. This means the magnetic field at P has no z-component whatsoever. Therefore,

B_z = 0

. Option A incorrectly assumes a simple dipole-like field that would have a z-component. Option B represents a logarithmic expression that might arise from integrating other field components, but not the z-component. Option D resembles the field magnitude along the axis of a finite wire, which is irrelevant here since P is off-axis. Remember this key insight: when current flows along one axis and your field point lies on a perpendicular axis, symmetry arguments and the cross product in Biot-Savart often eliminate field components parallel to the current direction. Always check the geometry first before diving into complex integrations.

Question 12

A toroidal coil has $N$ turns wound around a doughnut-shaped core with inner radius $a$ , outer radius $b$ , and carries current $I$ . Using Ampère's law (which can be derived from the Biot-Savart law), the magnetic field inside the toroidal core at radius $r$ (where $a < r < b$ ) is:

$\frac{\mu_0 NI}{2\pi r}$ (correct answer)
$\frac{\mu_0 NI}{2\pi (b-a)}$
$\frac{\mu_0 NI}{\pi (b^2-a^2)}$
$\frac{\mu_0 NI r}{2\pi (b^2-a^2)}$
$\frac{\mu_0 NI}{2\pi b}$

Explanation: When you encounter toroidal coil problems, think about the symmetry and how Ampère's law applies to circular paths around the torus axis. To find the magnetic field inside a toroidal core, you apply Ampère's law using a circular Amperian loop of radius

r

centered on the torus axis. Due to the toroidal geometry's symmetry, the magnetic field is constant along this circular path and tangent to it. Ampère's law states:

\oint \vec{B} \cdot d\vec{l} = \mu_0 I_{enc}

For your circular loop of radius

r

, the left side becomes

B \cdot 2\pi r

since

\vec{B}

is parallel to

d\vec{l}

everywhere along the path. The enclosed current is

NI

because the loop threads through all

N

turns of the coil, each carrying current

I

. Therefore:

B \cdot 2\pi r = \mu_0 NI

, giving

B = \frac{\mu_0 NI}{2\pi r}

. Option A is correct. Option B incorrectly uses

(b-a)

in the denominator, which would apply if the field were somehow averaged over the radial width—but that's not how Ampère's law works. Option C uses

(b^2-a^2)

, suggesting an area-based calculation that doesn't apply to this line integral approach. Option D includes an extra factor of

r

in the numerator and uses

(b^2-a^2)

, which would give field strength that increases with radius—physically unreasonable since current density actually decreases with radius in a toroidal geometry. Remember: For toroidal problems, the

1/r

dependence is key—the field weakens as you move away from the central axis.

Question 13

Two parallel wires separated by distance $d$ carry currents $I_1 = 3.0$ A and $I_2 = 4.0$ A in opposite directions. At what distance from the wire carrying $I_1$ (measured perpendicular to both wires) is the net magnetic field equal to zero?

$\frac{3d}{7}$ from the wire carrying $I_1$ , between the two wires (correct answer)
$\frac{4d}{7}$ from the wire carrying $I_1$ , between the two wires
$\frac{3d}{7}$ from the wire carrying $I_1$ , on the side opposite to $I_2$
$3d$ from the wire carrying $I_1$ , on the side opposite to $I_2$
The net magnetic field is never zero because the currents flow in opposite directions

Explanation: When two parallel wires carry currents in opposite directions, their magnetic fields can cancel at certain points. The key insight is understanding where and how these fields interact using the right-hand rule and the magnetic field formula for a long straight wire. For a wire carrying current

I

, the magnetic field at distance

r

B = \frac{\mu_0 I}{2\pi r}

. Since the currents flow in opposite directions, you need to find where their fields have equal magnitudes but opposite directions. Let's say the zero-field point is distance

x

from wire 1 (carrying 3.0 A). If this point is between the wires, it's distance

(d-x)

from wire 2 (carrying 4.0 A). For the fields to cancel:

\frac{\mu_0 \cdot 3.0}{2\pi x} = \frac{\mu_0 \cdot 4.0}{2\pi (d-x)}

Simplifying:

\frac{3.0}{x} = \frac{4.0}{d-x}

Cross-multiplying:

3.0(d-x) = 4.0x

, which gives

3.0d = 7.0x

, so

x = \frac{3d}{7}

Choice A is correct because this point lies between the wires where the opposing currents create fields in opposite directions that can cancel. Choice B uses the wrong fraction—this would be the distance from wire 2, not wire 1. Choice C has the right distance but wrong location; outside the wires, the fields point in the same direction and cannot cancel. Choice D gives an impossible distance that's three times the wire separation. Strategy tip: For parallel wires with opposite currents, the zero-field point always lies between the wires, closer to the wire with smaller current.

Question 14

Two parallel wires carry currents in opposite directions. Wire 1 carries current $I_1 = 3.0$ A to the right, and wire 2 carries current $I_2 = 4.0$ A to the left. The wires are separated by distance $d = 0.20$ m. At what distance from wire 1 (measured perpendicular to the wires) is the net magnetic field equal to zero?

$0.086$ m from wire 1, between the two wires (correct answer)
$0.11$ m from wire 1, between the two wires
$0.075$ m from wire 1, on the side opposite to wire 2
$0.12$ m from wire 1, on the side opposite to wire 2

Explanation: For the magnetic field to be zero, the fields from both wires must be equal in magnitude but opposite in direction. Since the currents flow in opposite directions, the zero-field point must be between the wires where the fields from both wires point in the same direction. Using

B = \frac{\mu_0 I}{2\pi r}

, we set

\frac{\mu_0 I_1}{2\pi r_1} = \frac{\mu_0 I_2}{2\pi r_2}

, where

r_1 + r_2 = 0.20

m. This gives

\frac{3.0}{r_1} = \frac{4.0}{0.20 - r_1}

. Solving:

3.0(0.20 - r_1) = 4.0r_1

, which yields

r_1 = 0.086

m. Choice B uses incorrect algebra. Choices C and D incorrectly assume the zero point is outside the wire region.

Question 15

A thin rod of length $L = 0.80$ m carries a uniform current density, with total current $I = 4.5$ A flowing from one end to the other. What is the magnetic field at a point located at perpendicular distance $a = 0.30$ m from one end of the rod, along the line perpendicular to the rod at its end?

$3.0 \times 10^{-6}$ T, directed parallel to the rod
$4.1 \times 10^{-6}$ T, directed perpendicular to both the rod and the line to the point (correct answer)
$2.4 \times 10^{-6}$ T, directed perpendicular to both the rod and the line to the point
$3.8 \times 10^{-6}$ T, directed parallel to the rod and perpendicular to the observation line

Explanation: Using the Biot-Savart law for a finite straight wire, the magnetic field at perpendicular distance

a

from one end is

B = \frac{\mu_0 I}{4\pi a}\left(\frac{L}{\sqrt{L^2 + a^2}}\right)

. Substituting values:

B = \frac{4\pi \times 10^{-7} \times 4.5}{4\pi \times 0.30} \times \frac{0.80}{\sqrt{0.80^2 + 0.30^2}} = \frac{4.5 \times 10^{-7}}{0.30} \times \frac{0.80}{\sqrt{0.64 + 0.09}} = 1.5 \times 10^{-6} \times \frac{0.80}{0.854} = 4.1 \times 10^{-6}

T. The direction is perpendicular to both the current direction and the vector from the wire to the observation point. Choice A uses wrong direction and magnitude. Choice C has incorrect magnitude calculation. Choice D has wrong direction description.