Polynomial Functions - College Algebra
Card 0 of 408
Simplify:

Simplify:

First, factor the numerator of the quotient term by recognizing the difference of squares:

Cancel out the common term from the numerator and denominator:

FOIL (First Outer Inner Last) the first two terms of the equation:

Combine like terms:

First, factor the numerator of the quotient term by recognizing the difference of squares:
Cancel out the common term from the numerator and denominator:
FOIL (First Outer Inner Last) the first two terms of the equation:
Combine like terms:
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Divide the trinomial below by
.

Divide the trinomial below by .

We can accomplish this division by re-writing the problem as a fraction.

The denominator will distribute, allowing us to address each element separately.

Now we can cancel common factors to find our answer.


We can accomplish this division by re-writing the problem as a fraction.
The denominator will distribute, allowing us to address each element separately.
Now we can cancel common factors to find our answer.
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Divide:

Divide:
Divide the leading coefficients to get the first term of the quotient:
, the first term of the quotient
Multiply this term by the divisor, and subtract the product from the dividend:


Repeat these steps with the differences until the difference is an integer. As it turns out, we need to repeat only once:
, the second term of the quotient

, the remainder
Putting it all together, the quotient can be written as
.
Divide the leading coefficients to get the first term of the quotient:
, the first term of the quotient
Multiply this term by the divisor, and subtract the product from the dividend:
Repeat these steps with the differences until the difference is an integer. As it turns out, we need to repeat only once:
, the second term of the quotient
, the remainder
Putting it all together, the quotient can be written as .
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Divide:

Divide:
First, rewrite this problem so that the missing
term is replaced by 

Divide the leading coefficients:
, the first term of the quotient
Multiply this term by the divisor, and subtract the product from the dividend:


Repeat this process with each difference:
, the second term of the quotient


One more time:
, the third term of the quotient

, the remainder
The quotient is
and the remainder is
; this can be rewritten as a quotient of

First, rewrite this problem so that the missing term is replaced by
Divide the leading coefficients:
, the first term of the quotient
Multiply this term by the divisor, and subtract the product from the dividend:
Repeat this process with each difference:
, the second term of the quotient
One more time:
, the third term of the quotient
, the remainder
The quotient is and the remainder is
; this can be rewritten as a quotient of
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Simplify the following expression:

Simplify the following expression:
Simplify the following expression:

First, let's multiply the 3x through:

Next, divide out the x from the bottom:

So our answer is:

Simplify the following expression:
First, let's multiply the 3x through:
Next, divide out the x from the bottom:
So our answer is:
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Simplify the following expression:

Simplify the following expression:
Simplify the following expression:

To begin, we need to recognize the bottom as a difference of squares. Rewrite it as follows.

So our answer is:

Simplify the following expression:
To begin, we need to recognize the bottom as a difference of squares. Rewrite it as follows.
So our answer is:
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Compare your answer with the correct one above
Compare your answer with the correct one above
Compare your answer with the correct one above
Compare your answer with the correct one above
Compare your answer with the correct one above
Compare your answer with the correct one above
Compare your answer with the correct one above
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Perform the following operation: 
Perform the following operation:
Use synthetic division to for this polynomial
The initial set-up is shown below

First, bring down the leading coefficient:


                Â

Multiply 1, by 3, and then add this to the second column:



                    Â

Next, multiply 1, by 1, and add this to the third column:



                    Â

Solution: 
Use synthetic division to for this polynomial
The initial set-up is shown below
First, bring down the leading coefficient:
                Â
Multiply 1, by 3, and then add this to the second column:
                    Â
Next, multiply 1, by 1, and add this to the third column:
                    Â
Solution:
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Simplify the following polynomial: 
Simplify the following polynomial:

Determine if there are any common factors between the numerator and the denominator:

There are no common factors, so we use synthetic division to simplify the polynomial:

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Bring down the 1, from the first column:

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</span>

Multiply 1 by -1, and add the product to -3:


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</span>

Multiply -4 by -1, and add the product to -10:


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</span>

Solution:

Determine if there are any common factors between the numerator and the denominator:
There are no common factors, so we use synthetic division to simplify the polynomial:
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</span>
Bring down the 1, from the first column:
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</span>
Multiply 1 by -1, and add the product to -3:
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</span>
Multiply -4 by -1, and add the product to -10:
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</span>
Solution:
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