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Clep

Clep Question of the Day

Practice Clep with the production-style question-of-the-day selection for this public URL.

Question 1

Solve the following equation for y:
log327y + 1 = log352y

  1. 3⁄log325 - 3
  2. log35 - 1
  3. 2
  4. 27-Jan
  5. log35
Explanation: log327 y + 1 = log35 2y Rewrite 27 as 33.
log33 3(y + 1) = log352y
3(y + 1) = 2y · log35
3y + 3 = 2y · log35
3⁄log325 - 3