AutoCAD Quiz: Grip Editing Basics
10 questions · exam conditions
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Grip Editing BasicsQuestion 1 of 10

A horizontal line extends from (0,0)(0,0) to (8,0)(8,0). A drafter activates its midpoint grip and relocates that grip to (4,3)(4,3) without changing grip modes.

What result should the drafter expect?

The entire line moves upward and extends from (0,3)(0,3) to (8,3)(8,3).
Only the right endpoint moves, producing a line from (0,0)(0,0) to (8,3)(8,3).
Both endpoints remain fixed, producing two segments that meet at (4,3)(4,3).
The line rotates about its midpoint and becomes vertical through (4,0)(4,0).
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AutoCAD Quiz: Grip Editing Basics

Practice Grip Editing Basics in AutoCAD with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Grip Editing Basics, giving you a quick way to practice the rules, question types, and explanations that matter most for AutoCAD.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A horizontal line extends from (0,0)(0,0) to (8,0)(8,0). A drafter activates its midpoint grip and relocates that grip to (4,3)(4,3) without changing grip modes.

What result should the drafter expect?

  1. The entire line moves upward and extends from (0,3)(0,3) to (8,3)(8,3). (correct answer)
  2. Only the right endpoint moves, producing a line from (0,0)(0,0) to (8,3)(8,3).
  3. Both endpoints remain fixed, producing two segments that meet at (4,3)(4,3).
  4. The line rotates about its midpoint and becomes vertical through (4,0)(4,0).
Explanation: When working with grips in AutoCAD, the behavior depends entirely on which grip you activate. Each object has multiple grip points, and each one controls the geometry differently. For lines specifically, endpoint grips stretch one end while anchoring the other, but the midpoint grip behaves as a move handle — it repositions the entire line without distorting it. Here's the logic: the line runs from (0,0)(0,0) to (8,0)(8,0), so its midpoint sits at (4,0)(4,0). When you drag the midpoint grip to (4,3)(4,3), AutoCAD calculates the displacement vector — in this case, Δx=0, Δy=3\Delta x = 0,\ \Delta y = 3 — and applies that translation to the whole object. Both endpoints shift upward by 3 units, landing at (0,3)(0,3) and (8,3)(8,3). That makes A the correct answer. B is wrong because it describes what would happen if you dragged the right endpoint grip, not the midpoint. C describes the result of a BREAK or PEDIT operation, not a grip move — grips don't split a line into two segments. D would require activating a rotation grip mode or using the ROTATE command; simply dragging a midpoint grip does not trigger rotation. The key study tip here is to remember that midpoint grip = move the whole line. Endpoint grips stretch; midpoint grips translate. On the exam, if you see "midpoint grip" with no mention of changing grip modes (which would cycle through Stretch → Move → Rotate → Scale → Mirror), default behavior is always Stretch, which for a midpoint acts as a full move.

Question 2

Two horizontal lines each extend from an x-coordinate of 00 to an x-coordinate of 1010. Their right endpoint grips are made hot as a multiple-grip selection. The drafter stretches those hot grips by a displacement of (4,0)(4,0).

What is the expected result?

  1. Both complete lines move so their endpoints become x-coordinates 44 and 1414.
  2. Both right endpoints move to x-coordinate 1414 while both left endpoints remain at 00. (correct answer)
  3. Only the last activated right endpoint moves to x-coordinate 1414; the other remains at 1010.
  4. Both left endpoints move to x-coordinate −4-4 while both right endpoints remain at 1010.
Explanation: Whenever you see a question about grips and stretching in AutoCAD, focus on which grips are hot and what the Stretch command actually does to them — it moves only the selected (hot) grips, leaving unselected grips exactly where they are. Here, both right endpoints are made hot as a multiple-grip selection, meaning AutoCAD treats them together as one collective set of active grips. When you apply a displacement of (4,0)(4, 0), each hot grip shifts 44 units in the positive x-direction. Since both right endpoints started at x=10x = 10, they both move to x=14x = 14. The left endpoints were never selected, so they remain fixed at x=0x = 0. This is exactly what answer B describes — the correct result. Answer A is wrong because it describes the behavior of a Move operation on the entire line objects, not a grip stretch. Moving the complete lines would shift all endpoints, giving x-coordinates of 44 and 1414 — but only the hot grips travel, not the full objects. Answer C reflects a misunderstanding of multiple-grip selection: some students assume only the last activated grip responds, but AutoCAD's multiple-grip mode moves all hot grips simultaneously. Answer D imagines the left endpoints moving instead of the right ones, which would only happen if the left grips were the hot ones — they aren't. The key study tip: always identify which grips are hot before predicting a stretch result. Hot grips move by the displacement; cold grips stay put. Multiple-grip selection means every hot grip moves together — no exceptions.

Question 3

A circle has center (5,5)(5,5) and radius 33. The drafter selects the circle, activates its right quadrant grip at (8,5)(8,5), and relocates that grip to (11,5)(11,5) without changing grip modes.

What circle results from the grip edit?

  1. A circle centered at (5,5)(5,5) with radius 1111
  2. A circle centered at (8,5)(8,5) with radius 33
  3. A circle centered at (11,5)(11,5) with radius 33
  4. A circle centered at (5,5)(5,5) with radius 66 (correct answer)
Explanation: When working with grip edits on circles in AutoCAD, the key concept to understand is which grip you're moving and what geometric property that grip controls. A circle has five grips: one at the center and four at the cardinal quadrant points (top, bottom, left, right). The quadrant grips control the radius, not the position of the center. When you drag a quadrant grip, AutoCAD keeps the center fixed and recalculates the radius based on the new grip position. In this problem, the original circle has center (5,5)(5,5) and radius 33, placing the right quadrant grip at (8,5)(8,5). Moving that grip to (11,5)(11,5) means the new radius equals the distance from the center (5,5)(5,5) to the new grip location (11,5)(11,5), which is 11−5=611 - 5 = 6. The center stays at (5,5)(5,5). That gives you answer D — a circle centered at (5,5)(5,5) with radius 66. Answer A is wrong because a radius of 1111 would result from confusing the grip's new x-coordinate with the radius itself. Answer B moves the center to the original grip position (8,5)(8,5) while keeping the old radius — this confuses a quadrant grip drag with a center grip drag. Answer C places the center at the new grip location (11,5)(11,5), which is the same misunderstanding as B but using the destination point instead. Study tip: Always ask yourself which grip is being moved. Center grip → circle moves, radius unchanged. Quadrant grip → center stays fixed, radius changes.

Question 4

With no command initially active, a drafter selects an object, activates one of its grips, and begins a MOVE grip edit. Before specifying the destination point, the drafter presses Esc once. The object remains selected with its grips displayed.

What should the drafter do to clear the remaining selection and grips without editing the object?

  1. Press the Spacebar to cycle from MOVE back to STRETCH.
  2. Press Enter to accept the previewed move and hide the grips.
  3. Press Esc a second time to clear the current object selection. (correct answer)
  4. Right-click and choose Copy to restore the original object position.
Explanation: Grip editing in AutoCAD uses a two-level escape system, and understanding this hierarchy is the key to answering questions like this one. When you click an object's grip and enter a grip edit mode (like MOVE), you're essentially two steps deep: one step into the grip edit, and one step into the object selection. Pressing Esc the first time exits the active grip edit command — it cancels the MOVE operation and returns you to the "grips displayed" state, where the object is still selected and its blue grips remain visible. This is exactly the state described in the passage. To fully clear everything — deselecting the object and dismissing the grips — you need to press Esc a second time. That second press exits the selection entirely, returning AutoCAD to a neutral, command-free state. So C is correct. A is wrong because the Spacebar cycles through grip edit modes (STRETCH → MOVE → ROTATE → SCALE → MIRROR) rather than clearing the selection. Pressing it would just advance you to the next edit mode, keeping you inside the grip edit cycle. B is wrong because pressing Enter during a grip edit would confirm the operation, not cancel it. If no destination has been specified, Enter won't helpfully dismiss the command — and accepting an unwanted edit is the opposite of what the drafter needs. D is wrong because right-clicking during grip editing opens a context menu with options like Copy, Base Point, and Undo, but "Copy" duplicates the object rather than restoring or clearing the selection. Remember the rule: one Esc exits the grip command, two Esc presses exit the selection entirely.

Question 5

A drafter must rotate a selected symbol about one of its grips while preserving the symbol in its original orientation. The drafter activates the desired grip and cycles to ROTATE.

What should the drafter do before specifying the rotation angle?

  1. Choose Copy from the grip-edit options so the rotated result is added. (correct answer)
  2. Choose Base point from the grip-edit options so the original is retained.
  3. Choose Undo from the grip-edit options so both orientations are displayed.
  4. Choose Reference from the grip-edit options so the original is duplicated.
Explanation: Whenever you see a question about grip editing in AutoCAD, focus on what the drafter wants to preserve — in this case, a copy of the original symbol in its starting orientation while also creating a rotated version. When you activate a grip and enter a grip-edit mode like ROTATE, AutoCAD will transform the object in place by default, meaning the original orientation is lost. To keep the original and add the rotated version as a separate object, you press C (or type "Copy") before specifying the rotation angle. This tells AutoCAD to leave the source object untouched and place a new, rotated copy at the angle you specify — exactly what the drafter needs. Answer A is correct. Answer B is a trap that sounds logical because "Base point" is a real grip-edit sub-option used to relocate the pivot point of the transformation. However, it does nothing to preserve the original object — it only changes where the rotation is anchored. Answer C is wrong because "Undo" within grip editing reverses your last action rather than displaying both orientations; it would simply step you backward, not duplicate anything. Answer D confuses "Reference" with a copy function — Reference is actually a sub-option for specifying rotation by a reference angle (useful when you know the angle from current to desired orientation), not for duplicating the object. A useful pattern to remember: in any grip-edit mode (Move, Rotate, Scale, Mirror, Stretch), typing Copy before confirming the transformation always produces a copy while preserving the original. Memorize this as the "preserve-and-transform" shortcut for grip editing.

Question 6

A line extends from (2,1)(2,1) to (6,1)(6,1). The grip at (2,1)(2,1) is activated, the drafter cycles to SCALE, and a scale factor of 22 is entered.

Assuming the activated grip remains the scale base point, what are the resulting endpoints?

  1. (4,2)(4,2) and (12,2)(12,2), because both coordinates are multiplied by the factor
  2. (−2,1)(-2,1) and (6,1)(6,1), because the line scales about the opposite endpoint
  3. (0,1)(0,1) and (8,1)(8,1), because the line scales about its midpoint
  4. (2,1)(2,1) and (10,1)(10,1), because the line scales about the activated grip (correct answer)
Explanation: When working with AutoCAD grip editing, the critical concept to understand is that the activated grip becomes the base point for whatever operation you cycle to — whether that's Stretch, Move, Rotate, Scale, or Mirror. For Scale specifically, all geometry is scaled relative to that fixed base point, meaning the base point itself never moves. Here, the grip at (2,1)(2,1) is activated and used as the scale base point with a factor of 22. The base point stays locked at (2,1)(2,1). The other endpoint at (6,1)(6,1) is scaled outward from that anchor: its distance from the base point is 6−2=46-2=4 units, and multiplying by 22 gives 88 units. So the new far endpoint lands at 2+8=102+8=10, giving you (10,1)(10,1). The activated grip stays at (2,1)(2,1), making the answer D. Choice A mistakes "scale factor" for direct coordinate multiplication — it multiplies raw coordinate values by 2, which is not how scaling works and would depend arbitrarily on where the origin sits. Choice B describes scaling about the opposite endpoint (6,1)(6,1), which would only be correct if that endpoint were the activated grip. Choice C assumes the midpoint (4,1)(4,1) is the base point, which is not what AutoCAD uses unless you specifically snap to the midpoint grip. A useful rule of thumb: whichever grip you click is the anchor — everything else moves away from or toward it. On exam questions involving grip editing, always identify the base point first, then apply the transformation relative to it.

Question 7

A drafter activates an endpoint grip on a selected line. The command line initially indicates the STRETCH grip mode. Without specifying a point, the drafter presses the Spacebar twice.

Which grip-editing mode should then be active?

  1. MOVE, because both Spacebar presses retain the first alternate mode
  2. ROTATE, because the presses advance through MOVE and then ROTATE (correct answer)
  3. SCALE, because STRETCH is omitted after a grip becomes hot
  4. MIRROR, because each press skips one mode in the grip sequence
Explanation: When working with grip editing in AutoCAD, you need to understand the fixed cycling sequence that governs how modes advance. When a grip becomes "hot" (active), AutoCAD starts in STRETCH mode. Each press of the Spacebar (or Enter) advances you one step forward through this sequence: STRETCH → MOVE → ROTATE → SCALE → MIRROR, then back to STRETCH. Starting at STRETCH, the drafter presses the Spacebar once, advancing to MOVE. A second press advances one more step to ROTATE. That makes B the correct answer — two presses from STRETCH lands you squarely on ROTATE. Choice A is wrong because it misrepresents how cycling works. Each Spacebar press advances the mode by exactly one step; there is no "retention" of a previous mode after multiple presses. Choice C incorrectly claims STRETCH is skipped when a grip becomes hot — in reality, STRETCH is the starting mode for an active grip, not an excluded one. Choice D introduces a false rule about "skipping" modes; no modes are ever skipped in the sequence, and each press moves exactly one position forward. A helpful memory trick is the phrase "Silly Mice Rarely Stay Motionless" — Stretch, Move, Rotate, Scale, Mirror. On the exam, grip-editing questions will often give you a starting mode and a number of Spacebar presses, expecting you to count forward through the sequence precisely. Practice counting from any starting point in the loop, since the sequence wraps around and can start mid-cycle.

Question 8

An object has a hot grip at (2,2)(2,2). In grip MOVE mode, the drafter wants to move the object by the displacement from (0,0)(0,0) to (5,3)(5,3) rather than use the hot grip as the displacement's starting point.

Which workflow produces the intended displacement?

  1. Choose Base point, specify (0,0)(0,0), and then specify (5,3)(5,3). (correct answer)
  2. Accept the hot grip as the base and specify the absolute point (5,3)(5,3).
  3. Choose Copy, specify (0,0)(0,0), and then specify the relative point (5,3)(5,3).
  4. Cycle to ROTATE, specify (0,0)(0,0), and then specify the angle (5,3)(5,3).
Explanation: Whenever you see a grip-editing question that involves controlling the base point of a displacement, focus on one key concept: by default, AutoCAD uses the hot grip itself as the base point for the move. If you want to define a custom displacement vector — say, from (0,0)(0,0) to (5,3)(5,3) — you must explicitly override that default. In grip MOVE mode, AutoCAD provides a Base point option precisely for this purpose. Choosing Base point lets you specify any point as the starting reference of the displacement, completely ignoring the hot grip's location. So the correct workflow is: activate grip MOVE, choose Base point, specify (0,0)(0,0), then specify (5,3)(5,3). AutoCAD calculates the displacement vector Δx=5, Δy=3\Delta x = 5,\ \Delta y = 3 and applies it to the object — exactly the intended result. That makes A correct. B is wrong because accepting the hot grip at (2,2)(2,2) as the base and then targeting (5,3)(5,3) produces a displacement of Δx=3, Δy=1\Delta x = 3,\ \Delta y = 1, not Δx=5, Δy=3\Delta x = 5,\ \Delta y = 3. You'd end up at the wrong location entirely. C is wrong on two counts: the Copy option creates a duplicate rather than moving the original, and mixing Copy with a mismatched workflow doesn't replicate the Base point override behavior. D is wrong because cycling to ROTATE mode changes the operation entirely — you'd be rotating, not translating, and (5,3)(5,3) would be misinterpreted as an angle reference, not a displacement endpoint. As a study tip: anytime a grip-edit question asks you to use a displacement vector rather than an absolute destination, look for the Base point option — it's the dedicated tool for redefining where a displacement originates.

Question 9

A line extends from (2,2)(2,2) to (10,2)(10,2). With no command active, a drafter selects the line, activates the grip at (10,2)(10,2), and specifies (10,6)(10,6) as the new grip location.

Assuming the initial grip mode is accepted, what is the resulting line?

  1. The line extends from (2,2)(2,2) to (10,6)(10,6). (correct answer)
  2. The line extends from (2,6)(2,6) to (10,6)(10,6).
  3. The line extends from (2,2)(2,2) to (10,2)(10,2).
  4. The line extends from (2,−2)(2,-2) to (10,2)(10,2).
Explanation: When working with grips in AutoCAD, it helps to understand the three default grip modes: Stretch, Move, and Rotate. The initial grip mode — the one activated the moment you click a grip — is always Stretch. This is the key concept being tested here. When you activate the grip at (10,2)(10,2) and drag it to (10,6)(10,6), Stretch mode moves only that selected endpoint while leaving all other geometry anchored. The opposite endpoint at (2,2)(2,2) stays fixed, and only the activated grip relocates to (10,6)(10,6). The result is a line from (2,2)(2,2) to (10,6)(10,6), which is answer A — the correct choice. Answer B is tempting but wrong. It assumes both endpoints shifted upward by 4 units, which is what Move mode would do, not Stretch. Move translates the entire object rigidly. Answer C suggests nothing changed at all, which would only happen if you pressed Escape or specified the same coordinates — not a new location. Answer D introduces a point at (2,−2)(2,-2), implying a mirror or reflection occurred, which has no basis in this workflow. A useful strategy: on grip-editing questions, always identify which grip was activated and which mode is in effect. Since the problem says "the initial grip mode is accepted," that locks you into Stretch. Remember: Stretch is always first. If the question mentioned pressing Enter or Space once before specifying the new point, the mode would cycle to Move — a common trap designed to confuse students on this exact topic.

Question 10

A line extends from (1,1)(1,1) to (5,1)(5,1). The drafter activates the grip at (1,1)(1,1), cycles to ROTATE, and enters a positive rotation angle of 90∘90^\circ. No Copy option is used.

Using the standard counterclockwise positive-angle convention, what is the result?

  1. Two lines remain, one horizontal and one ending at (1,5)(1,5).
  2. One line extends from (1,1)(1,1) to (1,−3)(1,-3).
  3. One line extends from (1,1)(1,1) to (1,5)(1,5). (correct answer)
  4. One line extends from (5,1)(5,1) to (5,5)(5,5).
Explanation: When working with AutoCAD grips, the critical concept is identifying the base point of the operation. The activated grip becomes the pivot — the fixed point around which the geometry transforms. Here, the grip at (1,1)(1,1) is the base point, so that endpoint stays anchored while the rest of the line rotates around it. The original line runs from (1,1)(1,1) to (5,1)(5,1), meaning the free endpoint (5,1)(5,1) sits 4 units to the right of the pivot. Rotating (5,1)(5,1) by 90°90° counterclockwise around (1,1)(1,1) means applying the standard rotation: a point 4 units along the positive x-axis becomes 4 units along the positive y-axis. So the free endpoint moves to (1,1+4)=(1,5)(1, 1+4) = (1,5). Since no Copy option was used, the original line is replaced — leaving one line from (1,1)(1,1) to (1,5)(1,5), which is answer C. Answer A is wrong because no Copy was activated, so you cannot end up with two lines. Answer B reflects a −90°-90° (clockwise) rotation, not the positive 90°90° specified — the free endpoint would land at (1,−3)(1,-3) only if the angle were negative. Answer D incorrectly treats (5,1)(5,1) as the pivot instead of (1,1)(1,1); rotating around the wrong grip would shift the entire line, but that's not how grip editing works when you activate a specific endpoint. Study tip: Always ask yourself "which grip is active?" — that point becomes your immovable base. Confusing the pivot with the free endpoint is the most common trap in grip-rotation questions.